Google Scripts: Match Range and Update corresponding Value - google-apps-script

Question

Sheet1: DashBoard | Range: A7:B17
(B7: Has a Filter Function that displays results of all Open Tasks from BackEnd Sheet)
Sheet2: BackEnd | Range: J56:M
Match B7:B17 with M56:M
if there is a match then
Paste values from A7:A17 to J56:J
Click here for Sample Sheet
The below script does the above operation but ONLY on the first instance of running it. Trying to repeat the process does not do anything. No errors on the code.
I'm a beginner to any form of coding and the below code was scripted by referring to various solutions on the forum. I might be missing some logic here and not in a position to de-code it in order to achieve the desired end result.
Thanks in advance
function updateToDo2() {
var sh, toDo, status, update, i;
sh = SpreadsheetApp.getActive().getSheetByName('DashBoard')
toDo = sh.getRange('B7:B17').getValues();
status = sh.getRange('A7:A17').getValues();
update = SpreadsheetApp.getActive().getSheetByName('BackEnd').getRange('J56:M');
update.setValues(update.getValues()
.map(function(r, i) {
if (r[3] == toDo[i]) {
r[0] = status[i];
}
return r;
})
)
}
EDIT: Working Code but very slow. Needs optimization.
Please help!
function rowOfStatus(status) {
var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('BackEnd');
var data = sheet.getRange('M56:M60').getValues();
for (var i = 0; i < data.length; i++) {
if (data[i][0] == status) { //[1] because column B
return i + 1;
}
}
}
function updateToDo() {
var sh, sh1, dashboard, results, noteText, status, i, counter;
sh = SpreadsheetApp.getActive().getSheetByName('DashBoard');
sh1 = SpreadsheetApp.getActive().getSheetByName('BackEnd');
dashboard = sh.getRange('A7:B11');
results = dashboard.getDisplayValues();
results.forEach(function(row) {
status = row[0];
noteText = row[1];
counter = Number(rowOfStatus(noteText));
if (counter > 0 && status != '') {
counter = 55 + Number(rowOfStatus(noteText));
sh1.getRange('J' + counter).setValue(status);
}
});
}

Answer 1

I'm not completely understanding what your doing but I thought I'd take a stab and trying to help you. So this might not be what you want. In that case sorry to bother you.
function updateToDo2() {
var sh=SpreadsheetApp.getActive().getSheetByName('DashBoard')
var toDo=sh.getRange('B7:B17').getValues();
var status=sh.getRange('A7:A17').getValues();
var update=SpreadsheetApp.getActive().getSheetByName('BackEnd').getRange('J56:M'+SpreadsheetApp.getActive().getSheetByName('BackEnd').getLastRow());
var vA=update.getValues();
for(var i=0;i<vA.length;i++){
if(vA[i][3]==toDo[i]){
vA[i][0]=status[i];
}
}
update.setValues(vA);
}

Answer 2

I got help in optimizing this code from Google Docs Help Forum and was provided by Jean-Pierre. Since I first posted my query on that Forum and was advised to post my query on StackOverflow by it's community member. Hence, here is the solution just in case it helps someone here. It's short & pretty fast!
Google Forum Link
Code:
function updateToDo() {
var ss, arr, values, colB, backendValues, backendColM;
ss = SpreadsheetApp.getActive();
arr = [];
values = ss.getSheetByName('DashBoard').getRange('A7:B17').getValues()
colB = values.map(function (v) {
return v[1];
})
backendValues = ss.getSheetByName('BackEnd').getRange('J56:M').getValues()
backendColM= backendValues.map(function (bv) {return bv[3]}).forEach(function (el, i) {
arr[i] = (el && colB.indexOf(el) > -1) ? ['Closed', 'Cancelled'].indexOf(values[colB.indexOf(el)][0]) > -1 ? [values[colB.indexOf(el)][0]] : [backendValues[i][0]]
: [backendValues[i][0]];
})
ss.getSheetByName('BackEnd').getRange(56, 10, arr.length, 1).setValues(arr)
ss.getSheetByName('DashBoard').getRange('A7:A17').setValue(null);
}