This is my model definition of Room table
sequelize.define("room", {
id: { type: DataTypes.INTEGER, primaryKey: true, autoIncrement: true },
name: DataTypes.STRING,
business_id: {
type: DataTypes.INTEGER,
references: {
model:"business,
key: "id"
}
}
});
And this is of business
sequelize.define("business", {
id: { type: DataTypes.INTEGER, primaryKey: true, autoIncrement: true },
name: DataTypes.STRING,
});
Now consider I have id of the room with me and I want to get business related to that using the foreign key. In normal SQL I would easily do this using inner join
I know that there is something like Association used in Sequelize but then what is the use of defining a reference in the model definition?
As per the DOC :
Sometimes you may want to reference another table, without adding any
constraints, or associations. In that case you can manually add the
reference attributes to your schema definition, and mark the relations
between them.
Association :
Creating associations in sequelize is done by calling one of the
belongsTo / hasOne / hasMany / belongsToMany functions on a model (the
source), and providing another model as the first argument to the
function (the target).
hasOne - adds a foreign key to the target and singular association
mixins to the source.
belongsTo - add a foreign key and singular association mixins to the source.
hasMany - adds a foreign key to target and plural association mixins to the source.
belongsToMany - creates an N:M association with a join table and adds plural association mixins to the source. The junction table is
created with sourceId and targetId.
Creating an association will add a foreign key constraint to the
attributes. All associations use CASCADE on update and SET NULL on
delete, except for n:m, which also uses CASCADE on delete.
I think this will clear your doubts.
Related
i am new in Loopback 4
I followed this tutorial to get started and everything worked fine.
I tried to create my own models Category and SubCategory using a MySQL database, with one to many relation (one category has many sub categories), i have noticed that it did create a field in subcategory table (categoryId) but the foreign key index is missing.
can someone help?
LoopBack 4 does not implicitly add foreign key constraints. This is to allow weak cross-datasource relations (e.g. a relation between PostgreSQL & Oracle).
Hence, the responsibility falls on the connectors to provide an interface to define these constraints. This however, means that there isn't a consistent interface across different connectors. There is an open issue to track this.
In the case of MySQL:
#model({
settings: {
foreignKeys: {
categorySubCategoryFK: {
name: 'categorySubCategoryFK',
entity: 'Category',
entityKey: 'id',
foreignKey: 'categoryId',
},
},
},
})
In case auto-migration is used (which it should not be used in production!), migrate.ts would need to be updated to define explicit ordering of the schemas:
await app.migrateSchema({
existingSchema,
models: ['Category', 'SubCategory'],
});
Further reading
https://loopback.io/doc/en/lb4/todo-list-tutorial-sqldb.html#specify-the-foreign-key-constraints-in-todo-model
https://loopback.io/doc/en/lb4/MySQL-connector.html
found the answer here, besides adding the settings to #model annotation, like so
#model({
settings: {
foreignKeys: {
categorySubCategoryFK: {
name: 'categorySubCategoryFK',
entity: 'Category',
entityKey: 'id',
foreignKey: 'categoryId',
},
},
},
})
you have to change to specify in which order tables should be created in migrate.ts and change this
await app.migrateSchema({existingSchema});
to this
await app.migrateSchema({
existingSchema,
models: ['Category', 'SubCategory'],
});
more details here
Loopback 4 creates relation on models and Api's not on database. Thus it won't get reflected on your mysql database
I'm using Sails and Waterline for my model associations and I'm not sure what to do in order to fix this error I'm receiving when trying to update a PageChild object.
module.exports = {
tableName: 'Page',
adapter: 'mysql',
autoCreatedAt: false,
autoUpdatedAt: false,
attributes: {
Id: {type: 'integer', autoIncrement: true, primaryKey: true},
pageChildren: {
collection: 'PageChild',
via: 'Page'
}
},
};
module.exports = {
tableName: 'PageChild',
adapter: 'mysql',
attributes: {
Id: {type: 'integer', autoIncrement: true, primaryKey: true},
Page: {
model: 'Page',
columnName: 'PageId'
}
}
};
The model associations work perfectly fine for populating pageChildren from the Page object or for returning the Page object from any of the pageChildren. However, I encounter this foreign key issue when attempting to create or update a PageChild object.
In the mysql db, the Page table has an "Id" attribute while the PageChild table has "Id" and "PageId" attributes.
The error is self explanatory:
foreign key constraint fails CONSTRAINT `PageChild_Page_Id_fk` FOREIGN KEY (`PageId`) REFERENCES `Page` (`Id`)
The rule is, you can only add or update a value in child table which are already present in parent table. So at the time of insertion make sure the value you are trying to insert in child table, already exist in parent table.
What this means is that the ParentId that you add or update on the child row needs to exist on the Parent table.
So, this constraint means that you can't insert a row into PageChild with PageId = 50 if you don't have a row in Page that has an id with a value of 50.
For example, if you want to create a new page, you have to first create an entry in the Page table, then retrieve it's id value and only then can you start doing your inserts into the PageChild table using the id of the Page you made earlier.
Using sequelize, I expect this line:
m.User.belongsToMany(m.Company, {through: 'UserCompany'});
to generate a new table in my database called 'user_company' that would link the 'user' table and the 'company' table together. However, it isn't doing that. Am I misunderstanding the documentation when it says
This will create a new model called UserProject with with the
equivalent foreign keys ProjectId and UserId. Whether the attributes
are camelcase or not depends on the two models joined by the table (in
this case User and Project).
or am I doing something wrong?
Here are the relations I am setting up
m.Company.hasMany(m.User);
m.User.belongsToMany(m.Company, {
through: m.UserCompany
});
m.User.sync({force: true, match: /_test$/});
m.Company.sync({force: true, match: /_test$/});
m.UserCompany.sync({force: true, match: /_test$/});
Looks like I needed to create the UserCompany model manually. So, UserCompany.js looks like:
module.exports = function(sequelize, DataTypes) {
return sequelize.define('UserCompany', {
}, {
freezeTableName: true,
paranoid: true
});
}
Then the belongsToMany automatically adds the correct columns to the table.
When using Sequelize.js, the following code doesn't add any foreign key on tables.
var MainDashboard = sequelize.define('main_dashboard', {
title: Sequelize.STRING
}, {
freezeTableName: true
})
MainClient.hasOne(MainDashboard, { foreignKey: 'idClient' })
MainDashboard.hasOne(MainClient, { foreignKey: 'clientId' })
sequelize.sync({ force: true })
Is there any way to force Sequelize.js to add these foreign key constraints?
Before I had the same problem, and solved when I understood the functioning of settings Sequelize.
Straight to the point!
Suppose we have two objects: Person and Father
var Person = sequelize.define('Person', {
name: Sequelize.STRING
});
var Father = sequelize.define('Father', {
age: Sequelize.STRING,
//The magic start here
personId: {
type: Sequelize.INTEGER,
references: 'persons', // <<< Note, its table's name, not object name
referencesKey: 'id' // <<< Note, its a column name
}
});
Person.hasMany(Father); // Set one to many relationship
Maybe it helps you
Edit:
You can read this to understand better:
http://docs.sequelizejs.com/manual/tutorial/associations.html#foreign-keys
For Sequelize 4 this has been updated to the following:
const Father = sequelize.define('Father', {
name: Sequelize.STRING
});
const Child = sequelize.define('Child', {
age: Sequelize.STRING,
fatherId: {
type: Sequelize.INTEGER,
references: {
model: 'fathers', // 'fathers' refers to table name
key: 'id', // 'id' refers to column name in fathers table
}
}
});
Father.hasMany(Child); // Set one to many relationship
Edit:
You can read more on associations at https://sequelize.org/master/manual/assocs.html
You need to add foreignKeyConstraint: true
Try:
MainClient.hasOne(MainDashboard, { foreignKey: 'idClient', foreignKeyConstraint: true })
I just tried to run your code, and the rows seem to be created fine:
CREATE TABLE IF NOT EXISTS `main_dashboard` (`title` VARCHAR(255), `id` INTEGER NOT NULL auto_increment , `idClient` INTEGER, PRIMARY KEY (`id`)) ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS `main_client` (`id` INTEGER NOT NULL auto_increment, `clientId` INTEGER, PRIMARY KEY (`id`)) ENGINE=InnoDB;
clientId is added to main_client, and idClient is added to main_dashboard
It seems you have slightly confused what the hasOne method does. Each time you call hasOne an association is created, so your code effectively associates the two tables twice. The method you are looking for is belongsTo
If you want each client to have one dashboard, the code would be the following:
MainClient.hasOne(MainDashboard, { foreignKey: 'clientId' })
MainDashboard.belongsTo(MainClient, { foreignKey: 'clientId' })
This creates a clientId field on the main_dashboard table, which relates to the id field of the main_client table
In short belongsTo adds the relation to the table that you are calling the method on, hasOne adds it on the table that is given as argument.
It's amazingly simple.
const MainDashboard = this.sequelize.define('main_dashboard', {/* attributes */}),
MainClient = this.sequelize.define('main_client', {/* attributes */});
MainDashboard.belongsTo(MainClient, { foreignKey: 'clientId' }); // Adds clientId to MainDashboard
It will link this as a foreign key and you may use it as an association. Let me know if I'm missing anything.
I have an error trying to build a model from an existing database in a symfony project using the Propel ORM.
The error is this:
build-propel.xml:474:20: The 1:1 relationship expressed by foreign key a_table_on_my_schema_FK_1 is defined in both directions; Propel does not currently support this (if you must have both foreign key constraints, consider adding this constraint with a custom SQL file.)
the schema.yml file is really extensive but the description of the table that causes the error (the first not correctly created) is like this:
self_referenced_table:
_attributes: { phpName: SelfReferencedTable }
[...]
JERARQUIC_CODE: { phpName: JerarquicCode, type: INTEGER, size: '8', required: false, foreignTable: self_referenced_table, foreignReference: JERARQUIC_CODE, onDelete: RESTRICT, onUpdate: RESTRICT }
[...]
I think this error is because of the self referenced table.
I need to implement a jerarquic relation between many elements so this implementation is a good way to do it. But causes me this problem on construction.
Can you give me some clues? have someone had this error? what would you do?
thank you!! :D
Solved: It was not a self referencing table error, as said by #Colin Fine. The error was on the source database. I generated the schema.yml from an existing database on mysql. The error was there: the target attribute of the reference was not the identifier of the table, was the reference attribute itself. So, the generated schema.yml contained wrong definitions. I think i havn't explained well enough:
self_referenced_table was that:
_attributes: { phpName: SelfReferencedTable }
[...]
JERARQUIC_CODE: { phpName: JerarquicCode, type: INTEGER, size: '8', required: false, foreignTable: self_referenced_table, foreignReference: JERARQUIC_CODE, onDelete: RESTRICT, onUpdate: RESTRICT }
[...]
self_referenced_table should be:
_attributes: { phpName: SelfReferencedTable }
[...]
JERARQUIC_CODE: { phpName: JerarquicCode, type: INTEGER, size: '8', required: false, foreignTable: self_referenced_table, foreignReference: TABLE_CODE, onDelete: RESTRICT, onUpdate: RESTRICT }
[...]