as everyone knows LIKE is too slow, but when I try to use MATCH AGAINST instead, its useless.
I need some operand that give the result such as LIKE '%part%' When "part" is part of the word not a complete word.
I have already tried
SELECT * FROM `table` WHERE MATCH (title) AGAINST ('*part*' IN BOOLEAN MODE)
SELECT * FROM `table` WHERE MATCH (title) AGAINST ('+*part*' IN BOOLEAN MODE)
and its not working
any solution?
You can only match words with a wildcard from the beginning of the word. As the documentation explains:
*
The asterisk serves as the truncation (or wildcard) operator. Unlike
the other operators, it is appended to the word to be affected. Words
match if they begin with the word preceding the * operator.
Related
I would like to get the First 100 characters of an found column "text".
SELECT * FROM article WHERE MATCH (title,text) AGAINST ("*das*" IN BOOLEAN MODE)
Is there a way to do it in 1 command?
So thanks to the Help of njzk2 and spencer7593 and Shaharyar i found this solution:
SELECT id,title,SUBSTR(text,1,100) FROM article WHERE MATCH (title,text) AGAINST ("*das*" IN BOOLEAN MODE)
I have a problem with the MATCH AGAINST query. i am getting 0 result in query when i pass onlu numeric value here is my query :
SELECT * FROM tbl1 WHERE MATCH(Sub_Name) AGAINST('+praga*' IN BOOLEAN MODE) AND MATCH(Sub_Address) AGAINST('+203*' IN BOOLEAN MODE) // result 0 row found
SELECT * FROM tbl1 WHERE MATCH(Sub_Name) AGAINST('+praga*' IN BOOLEAN MODE) AND MATCH(Sub_Address) AGAINST('+203 s*' IN BOOLEAN MODE) // result found
when i use any numeric in (203) then i get 0 result but i use any char with 203 s then result found,
and my address field value is "203 surat"
its because wildcard * IN BOOLEAN MODE returns matches that start with the word they are appended to. In your case no word starts with 203 I suppose. Hence you have to specify the word/letter which acts as a starting part of the Match. in your case 'S'
Refer The asterisk serves as the truncation (or wildcard) operator. Unlike the other operators, it should be appended to the word to be affected. Words match if they begin with the word preceding the * operator.
I am facing difficulty in sorting the result based on field in mysql. Say for example I am searching the word "Terms" then I should get the results which starts with 'Terms' first and then 'Terms and' as next and then 'Terms and conditions' and so on.
Any one please help out who to fetch the search result based on my requirements in efficient manner using mysql query.
SELECT * FROM your_table WHERE your_column LIKE "Terms%" ORDER BY your_column;
Based on the storage engine and mysql version you probably can use the full text search capabilities of MySQL. For example:
SELECT *, MATCH (your_column) AGAINST ('Terms' IN BOOLEAN MODE) AS relevance
FROM your_table
WHERE MATCH (your_column) AGAINST ('Terms' IN BOOLEAN MODE)
ORDER BY relevance
You can find more info here: http://dev.mysql.com/doc/refman/5.5/en/fulltext-boolean.html
Or if you don't want FTS another possible solution where ordering is strictly based on the length (difference) of the strings.
SELECT * FROM your_table WHERE your_column LIKE "Terms%" ORDER BY ABS(LENGTH(your_column) - LENGTH('Terms'));
You are looking for fulltext search. Below a very simple example
SELECT id,name MATCH (name) AGAINST ('string' > 'string*' IN BOOLEAN MODE) AS score
FROM tablename WHERE MATCH (name) AGAINST ('string' > 'string*' IN BOOLEAN MODE)
ORDER BY score DESC
The advantage of this is that you can control the value of words. This is very basic, you can 'up' some matches or words (or 'down' them)
In my example an exact match ('string') would get a higher score than the string with something attached ('string*'). The following line is even one step broader:
'string' > 'string*' > '*string*'
This documentation about fulltextsearch explains allot. It's a long read, but worth it and complete.
Don't use fulltext index if you search for prefix string!
Using LIKE "Term%" the optimizer will be able to use a potential index on your_column:
SELECT * FROM your_table
WHERE your_column LIKE "Terms%"
ORDER BY CHAR_LENGTH(your_column),your_column
Note the ORDER BY clause: it first sorts by string length, and only use alphabetcal order to sort strings of equal length.
And please, use CHAR_LENGTH and not LENGTH as the first count the number of characters, whereas the later count number of bytes. Using a variable length encoding such as utf8, this would made a difference.
I can search for all rows with foo in the col1/col2 using match against:
SELECT col1, col2
FROM some_table
WHERE MATCH (col1,col2)
AGAINST ('foo' IN BOOLEAN MODE);
But suppose I want to search for all rows with foo. (i.e. foo with a full-stop as the next character). On the docs page for Boolean Full-Text Searches, it doesn't mention full-stop being an operator, so I thought I could use either of these:
AGAINST ('foo.' IN BOOLEAN MODE);
AGAINST ('"foo."' IN BOOLEAN MODE);
AGAINST ('"foo\."' IN BOOLEAN MODE);
However, this returns the same results as:
AGAINST ('foo.couldBeAnything' IN BOOLEAN MODE);
AGAINST ('foo' IN BOOLEAN MODE);
AGAINST ('foo*' IN BOOLEAN MODE);
.
What is the . operator in this context? and how can I match-against foo.?
Note: I first asked this question about match-against foo.bar which led me to ask this follow up.
Full-stop, or indeed any punctuation, is treated like a space in a FULL-TEXT SEARCH, unfortunately this means there is no way to search for punctuation. The reasoning behind this is that text search is for finding "words" (which don't include punctuation).
To do such a search against punctuation, you could match against regular expressions, e.g. by using preg_match.
I have the following MySQL query:
SELECT title, description
FROM some_table
WHERE MATCH (title,description) AGAINST ('+denver (REGEXP "[[:<:]]colorado[s]*[[:>:]]")' IN BOOLEAN MODE);
the "regexp" here looks for a "complete word" colorado (with or without the ending "s").
I want to actually select only those rows that have ("denver") AND ("colorado" or "colorados"). But I cannot put a "+" for the REGEXP. I tried but got 0 results, although there are rows in the table that match the requirement.
Any ideas on how I can get the "+" to work within against using a REGEXP?
I am constructing this from within a PHP script where "denver" and "colorado" are values of variables I use to construct the select statement.
My PHP/MySQL script would look somewhat like this:
SELECT title, description
FROM some_table
WHERE MATCH (title,description) AGAINST ('+$var1 (REGEXP "[[:<:]]$var2[s]*[[:>:]]")' IN BOOLEAN MODE);
I don't think it's possible to combine regular expressions and MATCH ... IN BOOLEAN MODE. You need to use the syntax for writing boolean expressions.
Boolean Full-Text Searches
Try something like this:
SELECT title, description
FROM some_table
WHERE MATCH (title,description)
AGAINST ('+denver +(colorado colorados)' IN BOOLEAN MODE);