jq split string by a pattern - json

Question

I have a json object with one of field having values for example "countries-sapi-1.0", "inventory-list-api-1.0-snapshot"
Note that the first one has sapi and the other one has api.
Using jq, how can i get countries-sapi or inventory-list-api I mean whatever is there before the version. the version can be as simple as 1.0 or 1.0.1-snapshot etc..

Answer 1

I got here searching for how to split by regex instead of substring in jq, but I found out that you have to give two arguments to the split function (where the second argument contains flags for the regex, but it can be just an empty string).
$ jq -n '"axxbxxxc"|split("x+";"")'
[
"a",
"b",
"c"
]
From the manual:
split
Splits an input string on the separator argument.
jq 'split(", ")'
"a, b,c,d, e, "
=> ["a","b,c,d","e",""]
[...]
split(regex; flags)
For backwards compatibility, split splits on a string, not a regex.

Answer 2

It looks like you need to study up on regular expressions (regex); see for example https://regexone.com/ or https://github.com/zeeshanu/learn-regex or dozens of others.
Using jq, in your particular case, you could start with:
sub(" *- *[0-9]+\\.[0-9]+.*$"; "")
Note that two backslashes are required here because the "from" expression must be (or evaluate to) a valid JSON string.

Answer 3

For input "countries-sapi-1.0", use: .[] | match( "\\d"; "ig") which will give you the following output:
{
"offset": 15,
"length": 1,
"string": "1",
"captures": []
}
{
"offset": 17,
"length": 1,
"string": "0",
"captures": []
}
This uses the first object's offset value and tries to slice it from the starting position to the received offset.
Slice from beginning: $ jq -c '.[:15]'
In our case we got 15 as the offset for the first object so we used :15 for the slice.