Get name of last two months in SQL - mysql

Question

I have a query that compares this month's numbers to last month and upper month. The only issue is that colleagues complain about the labelling.
I have used M1 = last month and M2 = upper month, but some people still get it mixed up. I want to put in the actual month instead of M1, M2 and so on. Any ideas would help. This is my code
SELECT *,
CONCAT(FORMAT((current_downloads/M_1)*100,2),'%') AS `M_1_Ratio`,
CONCAT(FORMAT((current_downloads/M_2)*100,2),'%') AS `M_2_Ratio`
FROM
(SELECT count(*) AS current_downloads
FROM `purchase`
WHERE date(`purchase`.`timestamp`) >= DATE_FORMAT(NOW() ,'%Y-%m-01')) t1
JOIN
(SELECT count(*) AS M_1
FROM `purchase`
WHERE date(`purchase`.`timestamp`) BETWEEN DATE_SUB(DATE_FORMAT(NOW(),'%Y-%m-01'), INTERVAL 1 MONTH) AND DATE_SUB(DATE(NOW()), INTERVAL 1 MONTH)) t2
JOIN
(SELECT count(*) AS M_2
FROM `purchase`
WHERE date(`purchase`.`timestamp`) BETWEEN DATE_SUB(DATE_FORMAT(NOW(),'%Y-%m-01'), INTERVAL 2 MONTH) AND DATE_SUB(DATE(NOW()), INTERVAL 2 MONTH)) t3
That gives something like this.
I need the header names to be actual months.

Answer 1

This is a horrible hack (and will only work if your output is purely for presentation), but you could just add another line of data to the table which includes the month names by using a UNION:
SELECT DATE_FORMAT(NOW(), '%b %y') as Current_Downloads, DATE_FORMAT(NOW() - INTERVAL 1 MONTH, '%b %y') as M_1, DATE_FORMAT(NOW() - INTERVAL 2 MONTH, '%b %y') as M_2, DATE_FORMAT(NOW() - INTERVAL 1 MONTH, '%b %y') as M_1_Ratio, DATE_FORMAT(NOW() - INTERVAL 2 MONTH, '%b %y') as M_2_Ratio
UNION ALL
... your query ...
This will give you something that looks like this:
Current Downloads M_1 M_2 M_1_Ratio M_2_Ratio
Mar 18 Feb 18 Jan 18 Feb 18 Jan 18
12,168 12,121 13,345 100.39% 91.18%