mysql> select ordering, dst from alist where ordering=2 and dst like '%10.1.1.2%';
+----------+---------------------+
| ordering | dst |
+----------+---------------------+
| 2 | 10.1.1.1-10.1.1.254 |
+----------+---------------------+
1 row in set (0.00 sec)
If you want to match the literal path 10.1.1.2, and not things like 10.1.1.254, then you may try using REGEXP here:
SELECT ordering, dst
FROM alist
WHERE ordering = 2 AND dst REGEXP '[[:<:]]10.1.1.2[[:>:]]';
This corresponds to looking for the regex pattern \b10.1.1.2\b, i.e. there are word boundaries around your path.
The demo below correctly shows that there is no result set for your query as tested against the single row of sample data you provided.
Demo
Related
The below query is not updating records in mysql.
update audit_login set used_by=null where used_by = "test1\suri";
select is also not fetching the records, but mysql workbench shows 2 records when queried on a different column.
When the following is run:
SELECT * FROM audit_login WHERE used_by like 'test%\suri`;
I get records back with used_by of test1\suri.
Please help
The backslash (\) is used as an escape character. To use a literal backslash, you must escape it:
mysql> SELECT * FROM audit_login WHERE used_by = "test1\\suri";
+--------+------------+
| seq_no | used_by |
+--------+------------+
| 1234 | test1\suri |
+--------+------------+
1 row in set (0.00 sec)
I have product tables in my database
Product table structure:
product_id | testid
------------------------------------
1 11,12,13
2 2,4
Below is my FIND_IN_SET query:
SELECT product_id FROM product
WHERE FIND_IN_SET(3, testid) > 0;
Output
0
Below is my LOCATE query:
SELECT product_id FROM product
WHERE LOCATE(3, testid) > 0;
output
1
My question
What is difference between FIND_IN_SET and LOCATE and what is the best way to find id in column
To put it in simple technical terms(PHP terminology), find_in_set is like substring function of PHP. It will accept a substring and a string as parameters, and return 1 if the substring is found within the string. It will return 0 if substring is not found.
On the contrary, LOCATE() returns the position of the first occurrence of a string within a string. It accepts, a substring and a string as parameters.
I think in your use case, find_in_set is the one you should go for. Because this is the one. find_in_set will return 1 if 3 is found in a row, where as locate will first occurance of 3 in the string even if it finds 31 or 300 as first element.
Difference between LOCATE() and FIND_IN_SET() Function
When using LOCATE() function for integers, suppose we need 1 to return from LOCATE() if integer 3 is in the set 1,2,3,4,5,.. the following MySQL commands can be written:
mysql> SELECT IF(LOCATE(3,'1,2,3,4,5,6,7,8,9')>0,1,0);
+-----------------------------------------+
| IF(LOCATE(3,'1,2,3,4,5,6,7,8,9')>0,1,0) |
+-----------------------------------------+
| 1 |
+-----------------------------------------+
1 row in set (0.06 sec)
The above command working rightly because the set contains the number 3 , but if we write the following commands, look what happened
mysql> SELECT IF(LOCATE(3,'11,12,13,14,15')>0,1,0);
+--------------------------------------+
| IF(LOCATE(3,'11,12,13,14,15')>0,1,0) |
+--------------------------------------+
| 1 |
+--------------------------------------+
1 row in set (0.02 sec)
Above the 3 is not present as a number three(3) in the given set, though the LOCATE() returns 1.
To avoid this type of situation you can use the FIND_IN_SET() function. Here is the example below:
mysql> SELECT IF(FIND_IN_SET(3,'11,12,13,4,5,6,7,8,9')>0,1,0);
+-------------------------------------------------+
| IF(FIND_IN_SET(3,'11,12,13,4,5,6,7,8,9')>0,1,0) |
+-------------------------------------------------+
| 0 |
+-------------------------------------------------+
1 row in set (0.05 sec)
So, LOCATE() function is very much suitable for string but not as much suitable for integer.
Examples, credits and some more information you can find here
So in your example FIND_IN_SET return 0 because there is no 3 in the given set, but LOCATE() returns 1 it treat the given set as a string but not a comma separated value, and the 3 present in the number 13
I have one search box that I would like to have search 6 columns in my schools database when an input is made. So far the search box searches the name field only and returns a match for exact or partial inputs.
I would like to search for a specific city and have all results show up from the name AND city columns (instead of just the name column) and so on.
Say I wanted to search with a zip code, I would like the listings to be all schools in that zip code. And finally if I input 2 words (e.g. penn Philadelphia) I would like all penn schools to show that are in the name column AND city column only. (not just all the penns in the name or every school in Philadelphia) and so on. These may be an elementary questions on the matter but I've been searching for days with no success. Maybe better use of wildcards and the "AND" "OR" clauses would benefit me.
Can someone help me structure a sql query to accomplish this?
this is what I have so far:
SELECT * FROM schools
WHERE (name='%name%' OR address='%name%' OR city='%name%'OR zip='%name%')
There are few ways to do that-
The very basic strategy is to match input with our table columns by the query like as you mentioned -
1. SELECT * FROM table WHERE (name='%name%' or zip='%name%' or city='%name%');
2. SELECT * FROM table WHERE LOCATE(name, GROUP_CONCAT(name,city,zip)) > 0;
3.
SELECT * FROM table WHERE name like '%name%'
UNION
SELECT * FROM table WHERE name like '%name%'
UNION
SELECT * FROM table WHERE name like '%name%';
but suppose the case where input box have the string- "varun bharti" but actual name in database is "varun bal bharti" So when you search you will missed the record. for that case you should break the string by space in to array elements and use these queries for elements or either you can replace the space in name column and match.
set #var=REPLACE ('varun bharti', ' ', '%');
SELECT * FROM table WHERE name like concat('%',#var,'%') or
zip like concat('%',#var,'%') or
city like concat('%',#var,'%');
You can also use regualar expressions for that.
For example input string the day boss get
Hitesh> select * from test;
+--------------------+
| name |
+--------------------+
| i am the boss |
| You will get soon |
| Happy birthday bro |
| the beautiful girl |
| oyee its sunday |
+--------------------+
5 rows in set (0.00 sec)
Hitesh> set #var=CONCAT('.*',REPLACE('the day boss get',' ','.*|.*'),'.*');
Query OK, 0 rows affected (0.00 sec)
Hitesh> select #var;
+----------------------------------+
| #var |
+----------------------------------+
| .*the.*|.*day.*|.*boss.*|.*get.* |
+----------------------------------+
1 row in set (0.00 sec)
Hitesh> select * from test where name REGEXP #var;
+--------------------+
| name |
+--------------------+
| i am the boss |
| You will get soon |
| Happy birthday bro |
| the beautiful girl |
| oyee its sunday |
+--------------------+
5 rows in set (0.00 sec)
For example, I am having a column storing data like this.
Apple
12.5.126.40
Smite
Abby
127.0.0.1
56.5.4.8
9876543210
Notes
How to select out only the rows with data in IP format?
I have tried with '^[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}$'
but I have no idea why it also matches 9876543210
You're going to need to use REGEXP to match the IP address dotted quad pattern.
SELECT *
FROM yourtable
WHERE
thecolumn REGEXP '^[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}$'
Technically, this will match values that are not valid IP addresses, like 999.999.999.999, but that may not be important. What is important, is fixing your data such that IP addresses are stored in their own column separate from whatever other data you have in here. It is almost always a bad idea to mix data types in one column.
mysql> SELECT '9876543210' REGEXP '^[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}$';
+---------------------------------------------------------------------------+
| '9876543210' REGEXP '^[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}$' |
+---------------------------------------------------------------------------+
| 0 |
+---------------------------------------------------------------------------+
1 row in set (0.00 sec)
mysql> SELECT '987.654.321.0' REGEXP '^[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}$';
+------------------------------------------------------------------------------+
| '987.654.321.0' REGEXP '^[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}$' |
+------------------------------------------------------------------------------+
| 1 |
+------------------------------------------------------------------------------+
Another method is to attempt to convert the IP address to a long integer via MySQL's INET_ATON() function. An invalid address will return NULL.
This method is likely to be more efficient than the regular expression.
You may embed it in a WHERE condition like: WHERE INET_ATON(thecolumn) IS NOT NULL
SELECT INET_ATON('127.0.0.1');
+------------------------+
| INET_ATON('127.0.0.1') |
+------------------------+
| 2130706433 |
+------------------------+
SELECT INET_ATON('notes');
+--------------------+
| INET_ATON('notes') |
+--------------------+
| NULL |
+--------------------+
SELECT INET_ATON('56.99.9999.44');
+----------------------------+
| INET_ATON('56.99.9999.44') |
+----------------------------+
| NULL |
+----------------------------+
IS_IPV4() is a native mysql function that lets you check whether a value is a valid IP Version 4.
SELECT *
FROM ip_containing_table
WHERE IS_IPV4(ip_containing_column);
I don't have data, but I reckon that this must be the most solid and efficient way to do this.
There are also similar native functions that check for IP Version 6 etc.
This may not be the most efficient way, and it's not technically regex, but it should work:
SELECT col1 FROM t1 WHERE col1 LIKE '%.%.%.%';
you could also use the useful function inet_aton()
SELECT *
FROM yourtable
WHERE inet_aton(thecolumn) is not null
Lengthy but works fine:
mysql> SELECT '1.0.0.127' regexp '^([0-1]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])\\.([0-1]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])\\.([0-1]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])\\.([0-1]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])$';
My table filed's value is "<script type="text/javascript"src="http://localhost:8080/db/widget/10217EN/F"></script>",
I want to analyse this string and fetch the id 10217,how to do use mysql regex?
I know python regex group function can return the id 10217,but i'm not familiar with mysql regex.
Please help me,Thank you very much.
MySQL regular expressions do not support subpattern extraction. You will probably have better luck iterating over all of the rows in your database and storing the results in a new column.
As far as I know, you can't use MySQL's REGEXP for substring retrieval; it is designed for use in WHERE clauses and is limited to returning 0 or 1 to indicate failure or success at a match.
Since your pattern is pretty well defined, you can probably retrieve the id with a query that uses SUBSTR and LOCATE. It will be a bit of a mess since SUBSTR wants the start index and the length of the substring (it would be easier if it took the end index). Perhaps you could use TRIM to chop off the unwanted trailing part.
This query get the Id from the field
SELECT substring_index(SUBSTRING_INDEX(testvar,'/',-3),'EN',1) from testtab;
where as testtab - is table name , testvar - is field name
inner substring get string starts with last 3 / which is
mysql> SELECT SUBSTRING_INDEX(testvar,'/',-3) from testtab;
+----------------------------+
| SUBSTRING_INDEX(testvar,'/',-3) |
+----------------------------+
| 10217EN/F"> |
| 10222EN/F"> |
+----------------------------+
2 rows in set (0.00 sec)
outer substring get
mysql> SELECT substring_index(SUBSTRING_INDEX(testvar,'/',-3),'EN',1) from testtab;
+----------------------------------------------------+
| substring_index(SUBSTRING_INDEX(testvar,'/',-3),'EN',1) |
+----------------------------------------------------+
| 10217 |
| 10222 |
+----------------------------------------------------+
2 rows in set (0.00 sec)