How can we search for a domain, without the TLD in mysql, so for e.g. testdomain.com, I would want to search only testdomain not the .com, so a search for test would return row, but a search for com would not.
I assume it would be similar to below with some regex, but no idea how to achieve that.
SELECT * FROM domains WHERE domain_name LIKE '%$search%'
Any idea on how to to search just that part of the domain?
You can do something like:
SELECT * FROM domains
WHERE SUBSTRING_INDEX(domain_name, '.', 1) LIKE '%$search%'
if you are looking for search a name starting with a string your query must be:
SELECT * FROM domains WHERE domain_name LIKE '$search%'
this query is a good query because it use indexes.
adding the "." character at the end you will find only the full name,
also this query is a good query because it use indexes.
SELECT * FROM domains WHERE domain_name LIKE '$search.%'
Else if you want to make a partial search you need to add the % before and after the term but in this case the "com" search will match, this search is not good becouse it do not use indexes.
At last this expressions search for a string containing the name excluding the TLD, this is not a good query because it do not use indexes.
SELECT * FROM domains WHERE domain_name LIKE '%$search%' and not like '%.$search%'
A good idea could be to split fields in your database, make a column (or an additional colunm) for the domain name without TLD and search in this new coloumn.
Related
What is the best way to search a database for a phrase such as "Almond Anise Cookie" and return the result?
If I
SELECT *
FROM recipes
WHERE name LIKE '%".$query."%'
and use the phrase "Almond Cookie", nothing is returned as expected. But if I search for "Anise Cookie" the result above is returned.
I've also tried
SELECT *
FROM recipes
WHERE name LIKE '%".$query."%'
OR name LIKE '".$query."%'
OR name LIKE '%".$query."'
with the same failed result.
Using MATCH AGAINST returns everything that contains "Almond" and everything that contains "Cookie" also not a good result. Is there a happy middle in returned results?
You can try using REPLACE. Something like this should work:
SELECT *
FROM recipes
WHERE NAME LIKE REPLACE(' ".$query." ',' ','%');
Note that I purposely add spaces between .$query. to ensure that the replace operation will make your term filled with the wildcard symbol. In the example above:
If $query='almond cookies' then REPLACE(' ".$query." ',' ','%') will become %almond%cookies%.
You can test the fiddle here : https://www.db-fiddle.com/f/kMzp99S8ENbTkYcW5FVdYN/0
I am trying to search domain names ending in particular keywords. e.g. "car" would bring up buycar.com, but not carbuy.com.
So if my query is
SELECT * FROM domains WHERE LIKE '%car'
Will not show any results at all, obviously because the domains dont end in car, they end in .com, or .co, or something.
I think I need to do some sort of regex replace to search the domain, until the first .
Or whatever would do the equivalent of this in sql for php:
$pos = strpos($domain,'.');
$search = substr($domain,0,$pos);
So it would just search the actual domain without the TLD. Is this possible with sql?
How about using:
SELECT *
FROM domains
WHERE domain LIKE '%car.%'
You could remove characters like .com, .IR, .co after car and run own query.
Please try this:
SELECT *
FROM domains
WHERE
REVERSE(SUBSTRING(REVERSE(domain),CHARINDEX('.',REVERSE(domain))+1,LEN(domain
))) LIKE '%car'
if you don't remove that character and use Like '%car.%' maybe get some thing like this: car.site.com
I have been writing a REGEX in MySQL to identify those domains that have a .com TLD. The URLs are usually of the form
http://example.com/
The regex I came up with looks like this:
REGEXP '[[.colon.]][[.slash.]][[.slash.]]([:alnum:]+)[[...]]com[[./.]]'
The reason we match the :// is so that we don't pick up URLs such as http://example.com/error.com/wrong.com
Therefore my query is
SELECT DISTINCT name
FROM table
WHERE name REGEXP '[[.colon.]][[.slash.]][[.slash.]]([:alnum:]+)[[...]]com[[./.]]'"
However, this is returning only a single row when it should really be returning many more (upwards of a thousand). What mistake am I making with the query?
Not sure if that's the problem, but it should be [[:alnum:]], not [:alnum:]
Your current query only matches names that end with .com/ rather than .com followed by anything that starts with a slash. Try the following:
SELECT DISTINCT name
FROM table
WHERE name REGEXP '[[.colon.]][[.slash.]][[.slash.]]([:alnum:]+)[[...]]com([[./.]].*)?'"
It might be clearer to split the URL rather than regexing it
SELECT DISTINCT name FROM table
WHERE SUBSTRING_INDEX((SUBSTRING_INDEX(name,'/',3),'.',-1)='com';
My user table has a column "name" which contains information like this:
Joe Lee
Angela White
I want to search for either first name or last name efficiently. First name is easy, I can do
SELECT * FROM user WHERE name LIKE "ABC%"
But for last name, if I do
SELECT * FROM user WHERE name LIKE "%ABC"
That would be extremely slow.
So I am thinking about counting the characters of the input, for example, "ABC" has 3 characters, and if I can search only the last three characters in name column, that would be great. So I want something like
SELECT * FROM user WHERE substring(name, end-3, end) LIKE "ABC%"
Is there anything in MySQL that can do this?
Thanks so much!
PS. I cannot do fulltext because our search engine doesn't support that.
The reason that
WHERE name LIKE '%ith'
is a slow way to look for 'John Smith' by last name is the same reason that
WHERE Right(name, InStr(name, ' ' )) LIKE 'smi%'
or any other expression on the column is slow. It defeats the use of the index for quick lookup and leaves the MySQL server doing a full table scan or full index scan.
If you were using Oracle (that is, if you worked for a formerly wealthy employer) you could use function indexes. As it is you have to add some extra columns or some other helping data to accelerate your search.
Your smartest move is to split your first and last names into separate columns. Several other people have pointed out good reasons for doing that.
If you can't do that you could try creating an extra column which contains the name string reversed, and create an index on that column. That column will have, for example, 'John Smith' stored as 'htimS nhoJ'. Then you can search as follows.
WHERE nameReversed LIKE CONCAT(REVERSE('ith'),'%')
This search will use the index and be decently fast. I've had good success with it.
You're close. In MySQL you should be able to use InStr(str, substr) and Right(str, index) to do the following:
SELECT * FROM user WHERE Right(name, InStr(name, " ")) LIKE "ABC%"
InStr(name, " ") returns the index of the Space character (you may have to play with the " " syntax). This index is then used in the Right() function to search for only the last name (basically; problems arise when you have multiple names, multiple spaces etc). LIKE "ABC%" would then search for a last name starting with ABC.
You cannot use a fixed index as names that are more than 3 or less than 3 characters long would not return properly as you suggest.
However, as Zane said, it's a much better practise to use seperate fields.
If it is a MyIsam table, you may use Free text search to do the same.
You can use the REGEXP operator:
SELECT * FROM user WHERE name REGEXP "ABC$"
http://dev.mysql.com/doc/refman/5.1/en/regexp.html
I have the following query :
SELECT * FROM `user`
WHERE MATCH (user_login) AGAINST ('supriya*' IN BOOLEAN MODE)
Which outputs all the records starting with 'supriya'.
Now I want something that will find all the records ending with e.g. 'abc'.
I know that * cannot be preappended and it doesn't work either and I have searched a lot but couldn't find anything regarding this.
If I give query the string priya ..it should return all records ending with priya.
How do I do this?
Match doesn't work with starting wildcards, so matching with *abc* won't work. You will have to use LIKE to achieve this:
SELECT * FROM user WHERE user_login LIKE '%abc';
This will be very slow however.
If you really need to match for the ending of the string, and you have to do this often while the performance is killing you, a solution would be to create a separate column in which you reverse the strings, so you got:
user_login user_login_rev
xyzabc cbazyx
Then, instead of looking for '%abc', you can look for 'cba%' which is much faster if the column is indexed. And you can again use MATCH if you like to search for 'cba*'. You will just have to reverse the search string as well.
I believe the selection of FULL-TEXT Searching isn't relevant here. If you are interested in searching some fields based on wildcards like:
%word% ( word anywhere in the string)
word% ( starting with word)
%word ( ending with word)
best option is to use LIKE clause as GolezTrol has mentioned.
However, if you are interested in advanced/text based searching, FULL-TEXT search is the option.
Limitations with LIKE:
There are some limitations with this clause. Let suppose you use something like '%good' (anything ending with good). It may return irrelevant results like goods, goody.
So make sure you understand what you are doing and what is required.