I have a mysql table, which is as follows:
image_id imagename brandname x y
143 00003.jpg Pirelli 147 265
125 00003.jpg Pirelli 500 259
Through mouse clicks I am generating x and y positions on a html canvas which I want to use to subset the table. For example, if the clicked position of x and y were 510 and 262, I want to retrieve the image id 125 as both the parameters are matching.
Suppose if the x value generated with mouse click is 510, i want to select the line with image_id 125.
I tried the following:
select * from table where imagename='00003.jpg' and 510 < max(x);
I am getting this error:
invalid use of group function.
Max is a group function... You can't use it without having group by in it.
You are comparing X and y value so use them directly, no need for using Max
As #user769889 already mentioned, you can't use aggregate functions like Min, Max etc without using Group By that's why you are getting that error.
I think you need this :
select * from table where imagename='00003.jpg' and x < 510 and y < 262
Max is a grouping function, you cannot use it like that. You can achieve what you need by using the followind nested query:
select * from table where imagename='00003.jpg' and 510 < (select max(x) from table where imagename = '00003.jpg')
This will run the inner query that gives back the maximum value for the x column for the image, then runs the outer query using the result in its where clause!
This is what worked for me:
select * from annotations where imagename='00003.jpg' x <= 510 order by x desc limit 1;
Related
My problem is how to loop through a table and extract information from another table.
I have a table - X with 470 records:
A B C
111 12 18
121 21 29
127 37 101
I would like to write the following query:
create or replace view NEW as
For j = 1-3
Select * from Y
where imei = X.A(j) and id > X.B(j) and id < X.C(j)
Apologies, I am a matlab programmer so I have used that syntax above to explain what I want. How can I do this in MySql? I have looked up For Loops but mostly it loops through within the same table. I need to loop through a different table and use those criteria in the where statement of a different table.
To get 3 rows from a table, use LIMIT 3 in a subquery. To get related rows in another table, use JOIN.
CREATE OR REPLACE VIEW new AS
SELECT Y.*
FROM Y
JOIN (SELECT *
FROM X
LIMIT 3) AS X ON Y.ime1 = X.a AND Y.id > X.b AND Y.id < X.c
To make LIMIT 3 produce predictable results, you should have an ORDER BY clause in the subquery. Otherwise, it will select an arbitrary set of 3 rows from X.
i need to run query which do the following:
order the table by x , so the result will be.
then it do a multiple order by for a groups according to the following x range.
so userId_1 will be before userId_2 , because both are in 90-100 x range.
and userId_1 y value > userId_2 y value.
How to implement that ? thanks
You should be able to get the desired effect by dropping the last digit of x for ordering, i.e.
SELECT *
FROM MyTable
ORDER BY x DIV 10, y
Trying to wrap my head around how to do this query - I want to return a list of client records and need to exclude clients if they had only a specific value and no other values.
For example
c# value
1 X
1 Y
2 X
3 Y
I want all the records for clients 1 and 3, since they had a value other than X. I do not want client 2, because that client had ONLY X.
I for example want returned in this case:
1 X
1 Y
3 Y
Of course, I could have lots of other records with other client id's and values, but I want to eliminate only the ones that have a single "X" value and no other values.
Maybe using a sub-query?
Try this:
SELECT client, value FROM myTable where `client` in
(select distinct(client) from myTable where value !='X');
Returns:
Client Value
1 X
1 Y
3 Y
Something like this
SELECT ABB2.*
FROM
mytable AS ABB2
JOIN
(SELECT c
FROM mytable
WHERE value <> "X"
GROUP BY c) AS ABB1 ON ABB1.c = ABB2.c
GROUP BY ABB2.c, ABB2.value
It's faster than using a WHERE clause to identify the sub query results (as in Mike's answer)
I have a database column like this:
id
50
55
56
62
63
64
65
68
70
72
80
etc...
I want to iterate through the id column with the following formula to find if the result of the formula is an id number in the same column. I want to compute all the possible combinations of the set of basically 3 records in the id column.
First loop:
Does ((second_id_number - first_id_number) * variable decimal) + second_id_number equal a number in the id column?
Per the formula, the first loop is
(55-50)*2.00(as an example of variable decimal) + 55 = 65. 65 is in the list => 65 is tagged with the 2 records which equal it
Second loop:
Does ((third_id_number - first_id_number) * variable decimal) + second_id_number equal a number in the id column?
(56-50)*2.00(as an example of variable decimal) + 56 = 78. 78 is not in the list => 78 is not tagged
Third loop:
Does ((fourth_id_number - first_id_number) * variable decimal) + second_id_number equal a number in the id column?
etc...
I want the results to show all the tagged records. A tagged record is the set of the 3 records where the third record is the result from the formula.
Anyone got any ideas? Is it possible in mysql?
Thank you
If I'm understanding your requirements properly, it sounds like you'd want to use a self-join on the table, e.g.
SELECT ...
FROM yourtable AS parent
LEFT JOIN yourtable AS child ON
FLOOR((parent.second_id_number - parent.first_id_number) * variable) + parent.second_id) = child.id
You could potentially carry something like this forward, which satisfies your first "loop"
select a.id as first_id_number
, b.id as second_id_number
, ((b.id - a.id) * 2) + b.id as third_id_number
from my_table as a
join my_table as b on a.id = (select max(id) from my_table where id < b.id)
where ((b.id - a.id) * 2) + b.id in (select id from my_table)
According to your description and test data, this would show 65 as "tagged" with first_id_number 50 and 62.
Warning: done on SQL Server using what I think is fairly standard syntax. I would understand if some would rather phrase this as a cross join with the select max... bit in the where clause rather than in the join predicate.
Let's say I have a list of values, like this:
id value
----------
A 53
B 23
C 12
D 72
E 21
F 16
..
I need the top 10 percent of this list - I tried:
SELECT id, value
FROM list
ORDER BY value DESC
LIMIT COUNT(*) / 10
But this doesn't work. The problem is that I don't know the amount of records before I do the query. Any idea's?
Best answer I found:
SELECT*
FROM (
SELECT list.*, #counter := #counter +1 AS counter
FROM (select #counter:=0) AS initvar, list
ORDER BY value DESC
) AS X
where counter <= (10/100 * #counter);
ORDER BY value DESC
Change the 10 to get a different percentage.
In case you are doing this for an out of order, or random situation - I've started using the following style:
SELECT id, value FROM list HAVING RAND() > 0.9
If you need it to be random but controllable you can use a seed (example with PHP):
SELECT id, value FROM list HAVING RAND($seed) > 0.9
Lastly - if this is a sort of thing that you need full control over you can actually add a column that holds a random value whenever a row is inserted, and then query using that
SELECT id, value FROM list HAVING `rand_column` BETWEEN 0.8 AND 0.9
Since this does not require sorting, or ORDER BY - it is O(n) rather than O(n lg n)
You can also try with that:
SET #amount =(SELECT COUNT(*) FROM page) /10;
PREPARE STMT FROM 'SELECT * FROM page LIMIT ?';
EXECUTE STMT USING #amount;
This is MySQL bug described in here: http://bugs.mysql.com/bug.php?id=19795
Hope it'll help.
I realize this is VERY old, but it still pops up as the top result when you google SQL limit by percent so I'll try to save you some time. This is pretty simple to do these days. The following would give the OP the results they need:
SELECT TOP 10 PERCENT
id,
value
FROM list
ORDER BY value DESC
To get a quick and dirty random 10 percent of your table, the following would suffice:
SELECT TOP 10 PERCENT
id,
value
FROM list
ORDER BY NEWID()
I have an alternative which hasn't been mentionned in the other answers: if you access from any language where you have full access to the MySQL API (i.e. not the MySQL CLI), you can launch the query, ask how many rows there will be and then break the loop if it is time.
E.g. in Python:
...
maxnum = cursor.execute(query)
for num, row in enumerate(query)
if num > .1 * maxnum: # Here I break the loop if I got 10% of the rows.
break
do_stuff...
This works only with mysql_store_result(), not with mysql_use_result(), as the latter requires that you always accept all needed rows.
OTOH, the traffic for my solution might be too high - all rows have to be transferred.