How to use group by and count in mysql - mysql

Question

Here I am having 3 table using I have to take the count
trip_details
id allocationId tripId
1 7637 aIz2o
2 7626 osseC
3 7536 01LEC
4 7536 78w2w
5 7640 S60zF
6 7548 ruaoR
7 7548 Qse6s
escort_allocation
id allocationId escortId
3 7637 1
4 7626 1
5 7627 1
6 7536 1
7 7640 1
7 7548 1
cab_allocation
allocationId allocationType
7637 Daily Trip
7626 Daily Trip
7627 Daily Trip
7536 Adhoc Trip
7640 Adhoc Trip
7548 Daily Trip
Using above table I have to get the count, I tried but it is not happening my expected results.
I tried sql query
SELECT a.`tripId`
FROM `trip_details` a
INNER JOIN escort_allocation b ON a.`allocationId` = b.`allocationId`
GROUP BY a.`allocationId`
LIMIT 0 , 30
I am getting like this
tripId
01LEC
ruaoR
osseC
aIz2o
S60zF
total 6 tripId i got ,so now I want to take the count so I am using this query
SELECT COUNT(*)
FROM `trip_details` a
INNER JOIN escort_allocation b ON a.`allocationId` = b.`allocationId`
GROUP BY a.`allocationId`
LIMIT 0 , 30
but this query is not working.I am getting results like below
2
2
1
1
1
MY MYSQL TABLES AND VALUES LOOK LIKE THIS
CREATE TABLE `trip_details` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`allocationId` int(11) NOT NULL,
`tripId` varchar(100) NOT NULL,
PRIMARY KEY (`id`),
KEY `tripId` (`tripId`),
KEY `allocationId` (`allocationId`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1 ;
INSERT INTO trip_details
(id, allocationId, tripId)
VALUES
(1, 7637, '00SwM'),
(2, 7626, '00SwM'),
(3, 7536, '00SwM'),
(4, 7536, '01hEU'),
(5, 7640, '01hEU'),
(6, 7548, 'IRZMS'),
(7, 7548, 'IRZMS');
CREATE TABLE `escort_allocation` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`allocationId` int(11) NOT NULL,
`escortId` varchar(100) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1 ;
INSERT INTO escort_allocation
(id, allocationId, escortId)
VALUES
(1, 7637, 'ssda'),
(2, 7626, 'adad'),
(3, 7627, 'sfsaf'),
(4, 7536, 'ssaf'),
(5, 7640, 'asf'),
(6, 7548, 'a3r');
CREATE TABLE `cab_allocation` (
`allocationId` int(11) NOT NULL AUTO_INCREMENT,
`allocationType` enum('Daily Trip','Adhoc Trip') NOT NULL,
PRIMARY KEY (`allocationId`)
) ENGINE=InnoDB AUTO_INCREMENT=7695 DEFAULT CHARSET=latin1;
INSERT INTO cab_allocation
(allocationId, allocationType)
VALUES
(7637, 'Daily Trip'),
(7626, 'Daily Trip'),
(7627, 'Daily Trip'),
(7536, 'Adhoc Trip'),
(7640, 'Adhoc Trip'),
(7548, 'Daily Trip');

Answer 1

You can try this
SELECT COUNT(DISTINCT (a.`tripId`))
FROM `trip_details` a
INNER JOIN escort_allocation b ON a.`allocationId`=b.`allocationId`
LIMIT 0 , 30
because of GROUP BY there is separate count for all allocationId.

Answer 2

With this, you should get the tripid and the amount:
SELECT COUNT(a.tripId) as total, a.tripId as tripId
FROM trip_details a INNER JOIN escort_allocation b
ON a.allocationId = b.allocationId
GROUP BY a.allocationId LIMIT 0 , 30

Answer 3

You may use:
SELECT COUNT(DISTINCT a.allocationId)
FROM
trip_details a
INNER JOIN
escort_allocation b
ON a.allocationId = b.allocationId
Previously you used COUNT(*) and also used GROUP BY so the counts of rows you were getting are from individual groups.
Update-2:
SELECT
(
SELECT COUNT(*) FROM trip_details
) AS Total_Trip_Count,
COUNT(T.tripId) as Escort_Count,
(
SELECT COUNT(*) FROM
(
SELECT a.allocationId
FROM escort_allocation a
INNER JOIN cab_allocation c ON a.allocationId = c.allocationId
WHERE c.allocationType = 'Adhoc Trip'
GROUP BY a.allocationId
) AS Ad
) AS Adhoc_Trip_Count
FROM
(
SELECT a.tripId FROM
trip_details a
INNER JOIN
escort_allocation b
ON a.allocationId = b.allocationId
GROUP BY a.allocationId
) AS T