I'm trying to get the last completed task id of the child table while counting all the child records and completed child records:
set #tmp := 0;
select
count(*) total,
count(if(completed=1, 1, null)) completed,
#tmp:=if(completed=1, task_id, #tmp) last_completed_task_id
from child_table where parent_id = 6
order by sequence
Here is some sample data:
id parent_id completed task_id sequence
526 6 1 1 1
1653 6 0 5 2
2749 6 0 20 3
3840 6 0 21 4
4913 6 1 22 5
5983 6 0 23 6
7063 6 0 25 7
7183 6 0 26 8
8241 6 1 27 9
9317 6 0 28 10
10380 6 0 29 11
So final result should be like that:
total: 11
completed: 3
last_completed_task_id: 27
I know how to get it with separate queries, but I wish to get it with one query if possible.
You could use a cros join between the count and the max task_id eg:
select
count(*) total,
count(if(completed=1, 1, null)) completed,
t.last_completed_task_id
from child_table
cross join (
select max(task_id) last_completed_task_id
from child_table
where parent_id = 6
and completed=1 ) t
where parent_id = 6
You can easily get the last completed id using conditional aggregation:
select count(*),
sum(is_completed = 1),
max(case when is_completed = 1 then id end) as last_completed_id
from child_table ct
where parent_id = 6;
If task_id is increasing -- as in your sample data -- you can just use task_id rather than id in the max().
Otherwise, just join the table back in:
select cnt, cnt_completed, ct2.task_id
from (select count(*) as cnt,
sum(is_completed = 1) as cnt_completed,
max(case when is_completed = 1 then id end) as last_completed_id
from child_table ct
where parent_id = 6
) x join
child_table ct2
on x.last_completed_id = ct2.id
You could try this :
select count(*) total,
count(if(completed=1, 1, null)) completed,
(select task_id from child_table where parent_id = 6 and completed = 1 order by sequence desc limit 1) as last_completed_task_id
from child_table
where parent_id = 6
Related
I'm trying to write a select statement in MySQL to get 5 rows after I get my match then sum how many times those numbers were repeated.
Example:
Raw Table
id
number
1
1
2
0
3
9
4
14
5
11
6
0
7
3
8
4
9
10
10
9
11
0
12
5
13
3
14
11
15
0
I need to find every row with the number 0, then after that select and show 5 rows after and counting the appearance of the numbers.
How can I select the numbers and get the count as a result?
The result of the first select should be like this:
id
number
3
9
4
14
5
11
6
0
7
3
7
3
8
4
9
10
10
9
11
0
12
5
13
3
14
11
15
0
The result of the count for every number in the last query.
Number
Count
9
2
14
1
11
2
0
3
3
3
4
1
10
1
5
1
This is a demo to get expected results:
Select numbers:
SELECT id, number
FROM (
SELECT b.id, b.number, ROW_NUMBER() OVER(PARTITION BY a.id ORDER BY b.id ASC) r
FROM numbers a
JOIN numbers b ON a.id < b.id
WHERE a.number = 0
) t WHERE t.r <= 5
ORDER BY id
Count numbers:
WITH n AS (
SELECT id, number
FROM (
SELECT b.id, b.number, ROW_NUMBER() OVER(PARTITION BY a.id ORDER BY b.id ASC) r
FROM numbers a
JOIN numbers b ON a.id < b.id
WHERE a.number = 0
) t WHERE t.r <= 5
)
SELECT number, COUNT(*) counts
FROM n
GROUP BY number
Sample data:
CREATE TABLE numbers (
id INT PRIMARY KEY auto_increment,
number INT NOT NULL
);
INSERT INTO numbers ( number ) VALUES (1),(0),(9),(14),(11),(0),(3),(4),(10),(9),(0),(5),(3),(11),(0);
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=1fe71080cfb27680eb2a37b721e5de2d
Update for MySQL v5.7
SELECT n.*
FROM numbers n
JOIN (
SELECT a.id, SUBSTRING_INDEX(GROUP_CONCAT(b.id ORDER BY b.id SEPARATOR ','), ',', 5) selections
FROM numbers a
JOIN numbers b ON a.id < b.id
WHERE a.number = 0
GROUP BY a.id
) t ON FIND_IN_SET(n.id, t.selections)
ORDER BY n.id
SELECT n.number, COUNT(*) counts
FROM numbers n
JOIN (
SELECT a.id, SUBSTRING_INDEX(GROUP_CONCAT(b.id ORDER BY b.id SEPARATOR ','), ',', 5) selections
FROM numbers a
JOIN numbers b ON a.id < b.id
WHERE a.number = 0
GROUP BY a.id
) t ON FIND_IN_SET(n.id, t.selections)
GROUP BY n.number
ORDER BY n.number
https://dbfiddle.uk/?rdbms=mysql_5.7&fiddle=3be09acab5cd696ec4b01585eb5c32ed
I have two table
ORDER
prod_id qty gst gst_rate
1 25 yes 18
1 25 no 0
2 10 yes 12
3 5 no 0
RETURN
prod_id add less gst_rate
1 5 0 0
1 10 0 18
3 0 2 0
About the table ORDER
Product 1 have order 25 with gst 18% and order 25 without gst. Product
2 have order 10 with gst 12%. Product 3 have order 5 without gst.
About the table Return
Product 1 without gst have extra qty 5. Product 1 with gst have extra
qty 10. Product 3 (no gst) have less qty 2. Product 2 have no extra or
less qty.
So I have to create a VIEW for each entry in ORDER table
Result should look like this
prod_id qty gst_rate add less
1 25 18 10 0
1 25 0 5 0
2 10 12 0 0
3 5 0 0 2
What I tried is:
SELECT ord.prod_id, ord.qty, ord.gst_rate, ret.add, ret.less FROM order ord LEFT JOIN (SELECT case when ord.gst='no' then (select sum(add) from return,order where order.prod_id=return.prod_id and return.gst_rate=0) else (select sum(add) from return,order where order.prod_id=return.prod_id and return.gst_rate!=0) end as add FROM return) as ret ON ret.prod_id=ord.prod_id
But it is not working..
you query could be refactored avoiding subquery ..
SELECT ord.prod_id, ord.qty, ord.gst_rate,
case when rd.gst='no' then t1.sum_add else t2.sum_add end as add
FROM order ord
LEFT JOIN (
select prod_id, sum(add) as sum_add
from return
INNER JOIN order ON order.prod_id=return.prod_id and return.gst_rate=0
GROUP BY prod_id
) t1 on t1.prod_id = ord.prod_id
LEFT JOIN (
select prod_id, sum(add) as sum_add
from return
INNER JOIN order ON order.prod_id=return.prod_id and return.gst_rate!=0
GROUP BY prod_id
) t2 on t2.prod_id = ord.prod_id
(the less was not in you code so i have omitted by select )
I have a query like below, it is working fine but not optimized, since it takes 1.5 sec to run. How to make this to an optimized result?
select h.keyword_id,
( select count(DISTINCT(user_id)) from history where category_id = 6
and h.keyword_id=keyword_id group by keyword_id ) as cat_6,
( select count(DISTINCT(user_id)) from history where category_id = 7
and h.keyword_id = keyword_id group by keyword_id ) as cat_7
from
history h group by h.keyword_id
History table
his_id keyword_id category_id user_id
1 1 6 12
2 1 6 12
3 1 7 12
4 1 7 12
5 2 6 13
6 2 6 13
7 2 7 13
8 3 6 13
Result:
keyword_id cat_6 cat_7
1 2 2 (unique users)
2 2 1
3 1 0
You can rewrite your query like this:
select h.keyword_id,
count(distinct if(category_id = 6, user_id, null)) as cat_6,
count(distinct if(category_id = 7, user_id, null)) as cat_7
from
history h
group by h.keyword_id
Your desired result based on the sample data is by the way false. In each keyword_id there's always just one distinct user_id.
you can see the query in action in an sqlfiddle here
For more optimization, you'd have to post the result of show create table history and the output of explain <your_query>;
I have two days trying to do this query with no luck.
I have two tables 'DEMAND' and 'DEMAND_STATE' (one to many relation). The table DEMAND_STATE have millions entries.
CREATE TABLE DEMAND
(
ID INT NOT NULL,
DESTINY_ID INT NOT NULL
)
CREATE TABLE DEMAND_STATE
(
ID INT NOT NULL,
PRIORITY INT NOT NULL,
QUANTITY DOUBLE NOT NULL,
CASE_ID INT NOT NULL,
DEMAND_ID INT NOT NULL,
PHASE_ID INT NOT NULL
)
The QUANTITY of the DEMAND_STATE is given according to a CASE_ID and PHASE_ID. We have 'N' PHASES in 'M' CASES. Always the same number of Phases in all Cases. We always have a initial Base Quantity called 'BASE CASE' in the Case with CASE_ID = 1.
For example to obtain quantity for Case (id=2) and Case Base (id=1)
select D.*, S.PRIORITY, S.QUANTITY, S.CASE_ID, S.DEMAND_ID, S.PHASE_ID
FROM DEMAND D
join DEMAND_STATE S on (D.ID = S.DEMAND_ID)
WHERE (S.CASE_ID = 2 OR S.CASE_ID = 1)
(paste only for id=8)
ID PRIORITY QUANTITY CASE_ID DEMAND_ID PHASE_ID
8 0 85 1 8 1
8 0 83 1 8 2
8 0 88 1 8 3
8 0 89 1 8 4
8 10 85 2 8 1
8 10 84 2 8 2
8 10 86 2 8 3
8 10 89 2 8 4
We need to obtain for all Demand in 'DEMAND' only the Quantity for Each Phase with MAX priority. The idea is no duplicate DEMAND_STATE data for each new Case creation. Only create new state rows when Demand-Case-Phase is different to Case Base. This is a new project and we accept changes in model for better performance.
I also tried with the MAX calculation. This query over DEMAND_STATE works fine but only obtain data for a concrete DEMAND_ID. Further i think this solution can be so expensive.
SELECT P.ID, P.QUANTITY, P.CASE_ID, P.DEMAND_ID, P.PHASE_ID
FROM DEMAND_STATE P
JOIN (
SELECT PHASE_ID, MAX(PRIORITY) max_priority, S.DEMAND_ID
from DEMAND_STATE S
WHERE S.DEMAND_ID = 1
AND (S.CASE_ID=1 OR S.CASE_ID=2)
GROUP BY S.PHASE_ID
) SUB
ON (SUB.PHASE_ID = P.PHASE_ID AND SUB.max_priority = P.PRIORITY)
WHERE P.DEMAND_ID = 1
GROUP BY P.PHASE_ID
The result:
ID QUANTITY CASE_ID DEMAND_ID PHASE_ID
1 86 1 1 1
2 85 1 1 2
3 81 1 1 3
8 500 2 1 4
This is the result expected:
ID ID PRIORITY QUANTITY CASE_ID PHASE_ID
8 1 0 86 1 1 (data from Case Base id=1 priority 0)
8 2 10 85 1 2 (data from Case Baseid=1 priority 0)
8 3 10 81 1 3 (data from Case Base id=1 priority 0)
8 64 10 500 2 4 (data from Case id=2 priority 10)
thank for help :)
Edit:
Result of Simon proposal:
ID QUANTITY CASE_ID DEMAND_ID PHASE_ID
1 86 1 1 1
2 85 1 1 2
3 81 1 1 3
4 84 1 1 4 (this row shouldnt exist)
8 500 2 1 4 (this is the correct row)
Also would have to join it with DEMAND
#didierc response:
ID ID MAX(S.PRIORITY) QUANTITY CASE_ID PHASE_ID
1 8 10 500 2 4
2 13 10 81 2 1
2 14 10 83 2 2
2 15 10 84 2 3
3 21 10 81 2 1
4 31 10 86 2 3
4 32 10 80 2 4
4 29 10 85 2 1
4 30 10 81 2 2
we need for each DEMAND four rows with the quantity Value. In Case Base we have four quantity and in Case 2 we only change the quantity for phase 4. We need always four rows for each demand.
Database DEMAND_STATE data:
ID PRIORITY QUANTITY CASE_ID DEMAND_ID PHASE_ID
1 0 86 1 1 1
2 0 85 1 1 2
3 0 81 1 1 3
4 0 84 1 1 4
8 10 500 2 1 4
We need to obtain for all Demand in 'DEMAND' only the Quantity for Each Phase with MAX priority
I translate the above, according to your sample result set, as:
SELECT
D.ID, S.ID, MAX(S.PRIORITY), S.QUANTITY, S.CASE_ID, S.PHASE_ID
FROM DEMAND D
LEFT JOIN DEMAND_STATE S
ON D.ID = S.DEMAND_ID
GROUP BY S.PHASE_ID, S.DEMAND_ID
Update:
To get the maximum priority for each pair(demand_id,phase_id)n we use the following query:
SELECT
DEMAND_ID, PHASE_ID, MAX(PRIORITY) AS PRIORITY
FROM DEMAND_STATE
GROUP BY DEMAND_ID, PHASE_ID
Next, to retrieve the set of phases for a given demand, just make an inner join on demand state:
SELECT S.* FROM DEMAND_STATE S
INNER JOIN (
SELECT
DEMAND_ID, PHASE_ID, MAX(PRIORITY) AS PRIORITY
FROM DEMAND_STATE
GROUP BY DEMAND_ID, PHASE_ID
) S2
USING (DEMAND_ID,PHASE_ID, PRIORITY)
WHERE DEMAND_ID = 1
If you want to limit the possible cases, include a where clause in the query S2:
SELECT S.* FROM DEMAND_STATE S
INNER JOIN (
SELECT
DEMAND_ID, PHASE_ID, MAX(PRIORITY) AS PRIORITY
FROM DEMAND_STATE
WHERE CASE_ID IN (1,2)
GROUP BY DEMAND_ID, PHASE_ID
) S2
USING (DEMAND_ID,PHASE_ID, PRIORITY)
WHERE DEMAND_ID = 1
However, your comments and update indicates that MAX(PRIORITY) does not seem very relevant after all. My understanding is that you have a base case, which may be overriden by another case in a given scenario (that scenario is the pair base case + some other case). Clarify that point in your question body if this is incorrect. If that is the case, you may change the above query by replacing PRIORITY by CASE_ID:
SELECT S.* FROM DEMAND_STATE S
INNER JOIN (
SELECT
DEMAND_ID, PHASE_ID, MAX(CASE_ID) AS CASE_ID
FROM DEMAND_STATE
WHERE CASE_ID IN (1,2)
GROUP BY DEMAND_ID, PHASE_ID
) S2
USING (DEMAND_ID,PHASE_ID, CASE_ID)
WHERE DEMAND_ID = 1
The only reason I see from having a priority is if you wish to combine more than 2 cases, and use priority to select which case will prevail depending on the phase.
You may of course prepend an inner join on DEMAND to include the related demand data.
Use of subqueries should be able to do as you wish, if I understand your question correctly. Something along the lines of the following:
SELECT
P.ID,
P.QUANTITY,
P.CASE_ID,
P.DEMAND_ID,
P.PHASE_ID
FROM DEMAND_STATE P
INNER JOIN (
-- Next level up groups it down and so gets the rows first returned for each PHASE_ID, which is the highest priority due to the subquery
SELECT
D.PHASE_ID,
D.PRIORITY,
D.DEMAND_ID
FROM (
-- Top level query to get all rows and order them in desc priority order
SELECT
S.PHASE_ID,
S.PRIORITY,
S.DEMAND_ID
FROM DEMAND_STATE S
WHERE S.DEMAND_ID IN (1) -- Update this to be whichever DEMAND_IDs you are interested in
AND S.CASE_ID IN (1,2)
ORDER BY
S.PHASE_ID ASC,
S.DEMAND_ID ASC,
S.PRIORITY DESC
) D
GROUP BY
D.PHASE_ID,
S.DEMAND_ID
) SUB
ON SUB.PHASE_ID = P.PHASE_ID
AND SUB.DEMAND_ID = P.DEMAND_ID
The top level subquery exists to get the rows you are interested in and order them in an order which allows predictable results when they are then grouped down by PHASE_ID and DEMAND_ID. This in turn allows a simple INNER JOIN to DEMAND_STATE hopefully (unless I have misunderstood your query)
This may still be expensive though depending on how much data is within that top level query.
Let's say I have the following data.
id name_id completed
1 10 1
2 10 0
3 15 1
4 10 0
5 20 1
6 15 0
7 20 1
8 15 0
I'm trying to find a count by the name id, which is pretty simple
SELECT name_id, COUNT(*) FROM db
GROUP BY name_id
Now, I have a second component which I want to include in the query.
For name_id 10, I want to count just those values where completed is 1. For the other name_id's, I want to select them regardless of whether they are 0 or 1.
So I should end up with:
name_id count(*)
10 1
15 3
20 2
Name_id 10 only has a count of 1 because it's just the 1 which is completed, while the other counts include both 0 and 1.
Can anyone help with this task.
Thanks!
You can use a CASE expression inside of your aggregate function.
SELECT name_id,
sum(case
when name_id = 10
then case when completed = 1 then 1 else 0 end
else 1 end) Total
FROM db
GROUP BY name_id;
See SQL Fiddle with Demo.
Exclude the rows where name_id = 10 and completed = 0:
SELECT name_id, COUNT(*) FROM db
WHERE NOT (completed = 0 AND name_id = 10)
GROUP BY name_id
SELECT name_id, COUNT(*) FROM db
WHERE name_id != 10 or completed = 1
GROUP BY name_id
Count when name_id is not 10. If it is 10, count when completed = 1:
SELECT
name_id,
COUNT(CASE WHEN name_id <> 10 or completed = 1 THEN 1 END)
FROM db
GROUP BY name_id