Unable to parse JSON from URL in tableview - json

Question

I am trying to pull car information from the following API.
but I can't seem to display the information in my tableview...
Any and all help is appreciated!
viewController
var hondaList: [HondaModel] = []
override func viewDidLoad() {
//let jsonUrl = "https://api.myjson.com/bins/149ex5"
let url = URL(string: "https://api.myjson.com/bins/149ex5")
URLSession.shared.dataTask(with: url!) { (data, urlrespone , error) in
do{
try self.hondaList = JSONDecoder().decode([HondaModel].self, from: data!)
for honda in self.hondaList {
print(honda.name)
}
DispatchQueue.main.async {
self.tableView.reloadData()
}
} catch{
print( "Error in fectching from https://api.myjson.com/bins/149ex5")
}
}.resume()
super.viewDidLoad()
}
Model
import Foundation
struct HondaModel: Decodable {
let name: String
let engine: String
let transmission: String
let ocolor: String
let icolor: String
let vin: String
}

Answer 1

This is a very common mistake: You are ignoring the root object (and both possible errors)
Add this struct
struct Root : Decodable {
private enum CodingKeys: String, CodingKey { case results = "Results", message = "Message" }
let results : [HondaModel]
let message : String
}
and decode
if let error = error { print(error); return }
do {
let root = try JSONDecoder().decode(Root.self, from: data!)
self.hondaList = root.results
...
and please, please, print the error rather than a meaningless literal string. The error tells you what's wrong.
catch {
print(error)
}
In your case you would get
"Expected to decode Array<Any> but found a dictionary instead."
which is a very significant hint.

Answer 2

try this
if let resultJSON = data?["Results"] as? [[String: Any]] {
do {
let _data = try JSONSerialization.data(withJSONObject: resultJSON, options: .prettyPrinted)
self.hondaList = try JSONDecoder().decode([HondaModel].self, from: _data)
// … same thing
}
}