Create a time series from from-to-entries - mysql

Question

I have some period data that look like this:
PName DtFrom DtTo Amount
Period_1 2018-01-01 2018-01-10 100
Period_2 2018-01-03 2018-01-08 10
Period_3 2018-01-05 2018-01-12 1
I would like to get the following time series adding the amounts that are inside the date frame of each period:
2018-01-01 100
2018-01-02 100
2018-01-03 110
2018-01-04 110
2018-01-05 111
2018-01-06 111
2018-01-07 111
2018-01-08 111
2018-01-09 101
2018-01-10 101
2018-01-11 1
2018-01-12 1
I have done a lot of research using DATE_ADD, DATEDIFF and so on, also using other StackOverflow questions. But without success. Any idea?

Answer 1

Although I'd really advocate handling this in application code, here's a solution which uses a little integer utility table. You could use a calendar table instead, or construct a sequence of integers on-the-fly...
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(Perid SERIAL PRIMARY KEY
,DtFrom DATE NOT NULL
,DtTo DATE NOT NULL
,Amount INT NOT NULL
);
INSERT INTO my_table VALUES
(1,'2018-01-01','2018-01-10',100),
(2,'2018-01-03','2018-01-08',10),
(3,'2018-01-05','2018-01-12',1);
SELECT * FROM ints;
+---+
| i |
+---+
| 0 |
| 1 |
| 2 |
| 3 |
| 4 |
| 5 |
| 6 |
| 7 |
| 8 |
| 9 |
+---+
SELECT dtfrom + INTERVAL y.i DAY dt
, SUM(x.amount) total
FROM my_table x
JOIN ints y
WHERE dtfrom + INTERVAL y.i DAY <= dtto
GROUP
BY dt;
+------------+-------+
| dt | total |
+------------+-------+
| 2018-01-01 | 100 |
| 2018-01-02 | 100 |
| 2018-01-03 | 110 |
| 2018-01-04 | 110 |
| 2018-01-05 | 111 |
| 2018-01-06 | 111 |
| 2018-01-07 | 111 |
| 2018-01-08 | 111 |
| 2018-01-09 | 101 |
| 2018-01-10 | 101 |
| 2018-01-11 | 1 |
| 2018-01-12 | 1 |
+------------+-------+
If the gap between dtfrom and dtto can be more than 10 days, you can expand the solution along these lines...
SELECT dtfrom + INTERVAL i2.i*10 + i1.i DAY dt
, SUM(x.amount) total
FROM my_table x
JOIN ints i1
JOIN ints i2
WHERE dtfrom + INTERVAL i2.i*10 + i1.i DAY <= dtto
GROUP
BY dt;

Answer 2

Try this:
SELECT A.`DATE`, B.Amount
FROM
(SELECT TO_DATE('2018-01-01','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-02','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-03','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-04','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-05','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-06','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-07','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-08','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-09','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-10','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-11','YYYY-MM-DD') `DATE` UNION ALL
SELECT TO_DATE('2018-01-12','YYYY-MM-DD') `DATE`
) A LEFT JOIN yourTable B ON A.`DATE` BETWEEN B.DtFrom AND b.DtTo;
That's the query if you must do it in sql, but it's easily getting the expected result in the application logic as #Strawberry indicated in his comment to your question.

Answer 3

Try this
select
sum(if(STR_TO_DATE(?, '%d-%m-%Y') >= so_period_date.dt_from and
STR_TO_DATE(?, '%d-%m-%Y') <= so_period_date.dt_to,
so_period_date.amount, 0)) as amount
from so_period_date