we have two columns id and monthid.
The output what I'm looking for is to divide year from month Id based on quarter . The output column should be from quarter. If id is active output should be 1 else 0 .If id comes in any of the 1st quarter (eg:only 1) the output is still 1 .
Like this:
id month
-----------------------------------
100 2012-03-01 00:00:00.0
100 2015-09-01 00:00:00.0
100 2016-10-01 00:00:00.0
100 2015-11-01 00:00:00.0
100 2014-01-01 00:00:00.0
100 2013-04-01 00:00:00.0
100 2014-12-01 00:00:00.0
100 2015-02-01 00:00:00.0
100 2014-06-01 00:00:00.0
100 2013-01-01 00:00:00.0
100 2014-05-01 00:00:00.0
100 2016-05-01 00:00:00.0
100 2013-07-01 00:00:00.0
result should be something like
ID YEAR QTR output (1 or 0)
--------------------------------------------------
100 2012 1 1
100 2012 2 0
100 2012 3 0
100 2012 4 0
100 2013 1 1
100 2013 2 1
100 2013 3 1
100 2013 4 0
Below is the one I tried but it doesn't return the expected results. Please help me achieve this.I want when the ouput is 0 as well.
select a.id,a.year,a.month,
CASE WHEN a.month BETWEEN 1 AND 4 THEN 1
ELSE 0 END as output
from
(select id,trim(substring(claim_month_id,1,4)) as year,(INT((MONTH(monthid)-1)/3)+1) as month from test) a
group by a.id,a.year,a.month
Any help would be appreciated.
#Ani; there is no hierarchical query in Hive to create four quarters (1,2,3,4) so I create a small table for it. Then I get all patient_id, year and month that exists in ims_patient_activity_diagnosis table. Finally, I did a right join on all possible patient id, year and quarters (1,2,3,4); If the id or year or quarter does not exists in the right join, then there is no activity for that id, year and quarter. I assign activity=0 for those rows.
I also inserted patient id=200 to test if there are more patient id in the table. Hope this helps. Thanks.
create table dbo.qtrs(month int);
insert into qtrs values (1),(2),(3),(4);
select DISTINCT NVL(ims.id, qtr.id) as patient_id,
qtr.year as year,
qtr.month as month,
CASE WHEN ims.id > 0 THEN 1 ELSE 0 END as activity
from sandbox_grwi.ims_patient_activity_diagnosis ims
right join (select distinct ims.id,YEAR(ims.month_dt) as year,qtrs.month from sandbox_grwi.ims_patient_activity_diagnosis ims join dbo.qtrs qtrs) qtr
on (ims.id=qtr.id and YEAR(ims.month_dt)=qtr.year and INT((MONTH(month_dt)-1)/3)+1=qtr.month)
sort by patient_id, year, month;
Sample Result:
p_id year month activity
100 2012 1 1
100 2012 2 0
100 2012 3 0
100 2012 4 0
100 2013 1 1
100 2013 2 1
100 2013 3 1
100 2013 4 0
100 2014 1 1
100 2014 2 1
100 2014 3 0
100 2014 4 1
100 2015 1 1
100 2015 2 0
100 2015 3 1
100 2015 4 1
100 2016 1 0
100 2016 2 1
100 2016 3 0
100 2016 4 1
200 2012 1 1
200 2012 2 0
200 2012 3 0
200 2012 4 0
200 2013 1 0
200 2013 2 1
200 2013 3 0
200 2013 4 0
additional sample data:
insert into sandbox_grwi.ims_patient_activity_diagnosis values
(200, '2012-03-01'),
(200, '2013-04-01');
Related
I have a set of data that looks like this
Cust Id order date Ordered Product
1 Jan 2 1
1 Jan 5 2
1 March 14 1
1 September 9 1
1 December 12 2
2 Jan 5 1
2 Feb 13 2
3 March 12 2
3 April 5 3
3 June 10 2
and my output should look like this
Cust Id order Date Order product
1 Jan 31 3
1 feb 29 0
1 Mar31 1
1 Apr 30 0
1 May 31 0
1 June 30 0
1 July 31 0
1 Aug 31 0
1 Sept 30 1
1 oct 31 0
1 Nov 30 0
1 Dec 31 2
and I have got this far
1 January 31 3
1 March 31 1
1 September 30 1
1 December 31 2
and my code is
select customer_id,
date_format(last_day(order_date), '%M %d') as new_months,
sum(products_ordered) as total
from amazon_test
where customer_id =1
group by new_months, customer_id;
I currently stuck at the part where I need to have all the months and '0' as the output since no orders were made.
If you are running MySQL 8.0, one option is to use a recursive query to generate the months, and then bring the table with a left join:
with recursive months as (
select customer_id, date_format(min(order_date), '%Y-%m-01') order_date, max(order_date) max_order_date
from amazon_test
group by customer_id
union all
select customer_id, order_date + interval 1 month, max_order_date
from months
where order_date + interval 1 month < max_order_date
)
select
m.customer_id,
date_format(last_day(m.order_date), '%M %d') new_months,
coalesce(sum(t.products_ordered), 0) ordered_products
from months m
left join amazon_test t
on t.customer_id = m.customer_id
and t.order_date >= m.order_date
and t.order_date < m.order_date + interval 1 month
where m.customer_id = 1
group by m.customer_id, m.order_date
order by m.customer_id, m.order_date
I phrased the query so it actually operates on all customer_ids - if you remove the where clause in the outer query, you do get the results for all customers. If you really want the results for only one customer, you can optimize the query by pushing the where filter to the anchor of the recusive query.
Demo on DB Fiddle:
customer_id | new_months | ordered_products
----------: | :----------- | ---------------:
1 | January 31 | 3
1 | February 29 | 0
1 | March 31 | 1
1 | April 30 | 0
1 | May 31 | 0
1 | June 30 | 0
1 | July 31 | 0
1 | August 31 | 0
1 | September 30 | 1
1 | October 31 | 0
1 | November 30 | 0
1 | December 31 | 2
hi i am trying to solve this problem from 2 days please help. I have a table like below. i am trying to get crosstab display
expenditures
id name
1 exp1
2 exp2
3 exp3
4 exp4
5 exp5
stations
id name
1 station1
2 station2
3 station3
4 station4
expenses
expenditure_id station_id year month expense
1 1 2015 1 10
1 2 2015 1 20
1 3 2015 1 15
1 4 2015 1 10
1 1 2015 2 20
1 1 2015 3 30
1 1 2015 4 40
2 1 2015 1 20
2 1 2015 2 10
2 1 2015 3 20
I am trying get result like this
for year 2015
expenditure station1 station2 station3 station4
exp1 100 20 15 0
exp2 50 0 0 0
where value of station1 station2 will be the sum of month expense
This is the mysql query as your requirement, use Laravel query builder to run this query as raw query, if you donot know how to run raw query in laravel let me know, in the mean while run the query in phpmyadmin/mysql client and see whether its give you the desired output .
SELECT y.expenditure,
MAX(CASE y.station WHEN 'station1' THEN y.totalexpense END) 'station1',
MAX(CASE y.station WHEN 'station2' THEN y.totalexpense END) 'station2',
MAX(CASE y.station WHEN 'station3' THEN y.totalexpense END) 'station3',
MAX(CASE y.station WHEN 'station4' THEN y.totalexpense END) 'station4'
FROM (
SELECT exp.name AS expenditure,st.name AS station,x.totalexpense
FROM expenditures AS exp
LEFT JOIN
(SELECT expenditure_id,station_id,SUM(expense) as totalexpense
FROM expenses
WHERE year = '2015'
GROUP by expenditure_id,station_id
)
AS x ON exp.id = x.expenditure_id
LEFT JOIN stations AS st ON x.station_id = st.id
) AS y
GROUP BY y.expenditure
I assume you have only 4 stations, if stations are unknown numbers then you can use a prepared statement and create this dynamically:
I'm trying to display zero on missing month, but didn't succeed.
Table:
clicks | impressions | ctr | position | month | year
111 2709 4 20 3 2015
101 2695 3 20 6 2015
76 2714 2 21 7 2015
.
.
.
64 1212 4 25 11 2015
81 1905 4 24 12 2015
Required output:
clicks | impressions | ctr | position | month | year
0 0 0 0 1 2015
0 0 0 0 2 2015
111 2709 4 20 3 2015
0 0 0 0 4 2015
0 0 0 0 5 2015
101 2695 3 20 6 2015
.
.
.
64 1212 4 25 11 2015
81 1905 4 24 12 2015
Like #jarlh suggested ,you can do it like this: creating a 'table' that contains all month availabe(you will have to populate it your self, add which month and years you want) and then left join to the original table and when value not exists, put 0.
select coalese(s.clicks,0) as clicks,
coalese(s.impressions ,0) as impressions,
coalese(s.ctr ,0) as ctr ,
coalese(s.position ,0) as position ,
t.month,
t.year
from(
SELECT 1 as month_num,2015 as year_num
union SELECT 2,2015
union select 3,2015
union select 4,2015 ....) t
LEFT OUTER JOIN YourTable s
ON(t.month_num = s.month and t.year_num = s.year)
Now I have a table like the one below:
Year | Month | Day | Hour | Value
2014 1 1 0 111
2014 1 1 1 222
2014 1 1 2 333
2014 1 1 4 444
(no 3:00am on 2014-1-1)
... ... ... ... ...
2014 1 2 0 555
2014 1 2 1 666
2014 1 2 2 777
2014 1 2 3 888
... ... ... ... ...
How can I get a list of the average of the values associated with a specific Hour value?
SELECT AVG(Value), Hour
FROM tableA
GROUP BY Hour
Hmm, you know there is an AVG() function right?
SELECT hour, AVG(value) avg_value
FROM table1
GROUP BY hour
If you want the missing hours to count as zero you'll have to do something a bit more fancy. Adding the zeros would probably be a lot easier however.
My table votes contains votes that have been made by users at different times:
id item_id position user_id created_at
1 2 0 1 11/21/2013 11:27
26 1 1 1 11/21/2013 11:27
27 3 2 1 11/21/2013 11:27
42 2 2 1 12/7/2013 2:20
41 3 1 1 12/7/2013 2:20
40 1 0 1 12/7/2013 2:20
67 2 2 1 12/13/2013 1:13
68 1 1 1 12/13/2013 1:13
69 3 0 1 12/13/2013 1:13
84 2 0 1 12/28/2013 2:29
83 3 2 1 12/28/2013 2:29
82 1 1 1 12/28/2013 2:29
113 3 0 1 1/17/2014 22:08
114 1 1 1 1/17/2014 22:08
115 2 2 1 1/17/2014 22:08
138 2 0 1 1/20/2014 16:49
139 1 1 1 1/20/2014 16:49
140 3 2 1 1/20/2014 16:49
141 1 1 11 1/20/2014 16:51
142 3 2 11 1/20/2014 16:51
143 2 0 11 1/20/2014 16:51
I need to tally the results on a monthly basis but here's the tricky part: the start/end of the month does not necessarily fall on the first day of the month. So if the votes are due on the 10th day of every month, I need a vote that was cast on the 10th to be in a different group from a vote that was cast on the 11th. Using the data above, I want to get three groups:
Group 1: 6 votes (11/21 and 12/7)
Group 2: 6 votes (12/13, 12/28)
Group 3: 9 votes (1/17, 1/20)
I've tried a lot of approaches but to no avail. This is my query right now:
select created_at, ADDDATE(DATE_FORMAT(created_at, '%Y-%m-01'),interval 10 day) as duedate,count("id") from votes where list_id = 2 group by duedate
I am getting group sizes of 3, 9, and 9, not 6, 6 and 9. Any help you can provide would be much appreciated. Thanks.
Your query is close. You just need to subtract 9 days (10 - 1) from the current day to get the month:
select created_at, date_sub(created_at, interval 9 day) as duedate,
count(id)
from votes
where list_id = 2
group by duedate;
date_format() converts a date to a string. There is no need to convert a date value to a character value for this query.
EDIT:
To group by month:
select date_format(date_sub(created_at, interval 9 day), '%Y-%m') as YYYYMM,
count(id)
from votes
where list_id = 2
group by YYYYMM;