Inserting one MySQL row with values from multiple, nested SELECT statements - mysql

I'm trying to combine the following two statements into one SELECT statement, so that I can insert the returned values into one and the same row with one statement.
SELECT ROUND(AVG(pressure),1) FROM rawinput WHERE timestamp >= SUBDATE(timestamp(now()), INTERVAL 1 HOUR);
SELECT ROUND((SELECT AVG(hourly_average_pressure) FROM hour_numbers WHERE timestamp >= CURTIME() - INTERVAL 1 HOUR)-(SELECT AVG(hourly_average_pressure) FROM hour_numbers WHERE timestamp >= CURTIME() - INTERVAL 2 HOUR AND timestamp < CURTIME() - INTERVAL 1 HOUR),1);
I already tried to format like below (basically adding parentheses around both SELECT statements and replace the semicolon with a comma) but I got syntax error. Is the only way to do this using a UNION ALL or am I missing something in the format? Thanks for the help.
(SELECT ROUND(AVG(pressure),1) FROM rawinput WHERE timestamp >=SUBDATE(timestamp(now()), INTERVAL 1 HOUR)), (SELECT ROUND((SELECT AVG(hourly_average_pressure) FROM hour_numbers WHERE timestamp >= CURTIME() - INTERVAL 1 HOUR)-(SELECT AVG(hourly_average_pressure) FROM hour_numbers WHERE timestamp >= CURTIME() - INTERVAL 2 HOUR AND timestamp < CURTIME() - INTERVAL 1 HOUR),1));


If you format your code properly, it's easy to see that you are missing SELECT statement in front of your code.
(
SELECT ROUND(AVG(pressure),1)
FROM rawinput
WHERE timestamp >=SUBDATE(timestamp(now()), INTERVAL 1 HOUR)
)
, (
SELECT ROUND((SELECT AVG(hourly_average_pressure) FROM hour_numbers WHERE timestamp >= CURTIME() - INTERVAL 1 HOUR)-(SELECT AVG(hourly_average_pressure)
FROM hour_numbers
WHERE timestamp >= CURTIME() - INTERVAL 2 HOUR AND timestamp < CURTIME() - INTERVAL 1 HOUR),1)
);
With SELECT
SELECT (
SELECT ROUND(AVG(pressure),1)
FROM rawinput
WHERE timestamp >=SUBDATE(timestamp(now()), INTERVAL 1 HOUR)
)
, (
SELECT ROUND((
SELECT AVG(hourly_average_pressure)
FROM hour_numbers
WHERE timestamp >= CURTIME() - INTERVAL 1 HOUR
) - (
SELECT AVG(hourly_average_pressure)
FROM hour_numbers
WHERE timestamp >= CURTIME() - INTERVAL 2 HOUR AND timestamp < CURTIME() - INTERVAL 1 HOUR
), 1)
);

Related

MySQL - SELECT rows between Yesterday 3pm and Today 7:30am

I'm trying to return rows between yesterday 15:00 and today 07:30, but can't seem to get it work.
I've tried the following two methods, but they haven't worked.
Note:
Getdate() should be CURDATE() in MySQL
TIMESERIAL is denied to my user account in the database
Code Examples:
where dateadd(dd, datediff(dd,0,Getdate()),0)- 1
and dateadd(dd, datediff(dd,0,Getdate()),0)- 1) + '23:59:59'
where [Table].[Date Time] Between Date()-1 + TimeSerial(18,0,0)
And Date() + TimeSerial(18,0,0)

you need to use the DATE_ADD and then INTERVAL n HOUR OR MINUTE.
Please check the attached fiddle. http://rextester.com/JIXU4144
select DATE_ADD(current_date, INTERVAL -9 HOUR);
select DATE_ADD(current_date, INTERVAL 450 minute);
select * from temp
where createdOn between '2018-08-28 15:00:00' and '2018-08-29 07:30:00';
select * from temp
where createdOn between DATE_ADD(current_date, INTERVAL -9 HOUR) and DATE_ADD(current_date, INTERVAL 450 minute)

If you are using MySQL, you can do:
where col >= curdate() - interval 1 day + interval 15 hour and
col < curdate() + interval 7.5 * 60 minute
You can also write this a bit more readably as:
where col >= curdate() - interval 1 day + interval 15 hour and
col < curdate() + interval '7:30' hour_minute

Get number of entries per multiple date intervals using single query

SELECT COUNT(*) FROM `table` WHERE `datetime` > SUBDATE(NOW(), INTERVAL 1 DAY)
This will get number of entries during last day. But is it possible to get number of entries for multiple intervals without having to send variation of this query multiple times (INTERVAL 1 DAY, INTERVAL 1 WEEK, INTERVAL 1 MONTH, ...)?

You need CASE WHEN expression to accomplish that.
SELECT
COUNT(CASE WHEN DATE(`datetime`) >= CURDATE() - INTERVAL 1 DAY AND DATE(`datetime`) < CURDATE() THEN 1 END) AS lastDay,
COUNT(CASE WHEN DATE(`datetime`) >= CURDATE() - INTERVAL 7 DAY AND DATE(`datetime`) < CURDATE() THEN 1 END ) AS lastSevenDays,
COUNT(*) AS lastThirtyDays
FROM `table`
WHERE
DATE(`datetime`) >= CURDATE() - INTERVAL 30 DAY
How to use CASE WHEN expression
Note: If your requirement is to get result of last day, last 7 days and last 30 days then go with this query.
EDIT:
If you have an index on datetime field then the above query will fail to use that index. Please use the query given below in order to utilize the index on datetime.
SELECT
COUNT(CASE WHEN DATE(`datetime`) >= CURDATE() - INTERVAL 1 DAY AND DATE(`datetime`) < CURDATE() THEN 1 END) AS lastDay,
COUNT(CASE WHEN DATE(`datetime`) >= CURDATE() - INTERVAL 7 DAY AND DATE(`datetime`) < CURDATE() THEN 1 END ) AS lastSevenDays,
COUNT(*) AS lastThirtyDays
FROM `table`
WHERE
`datetime` >= (NOW() - INTERVAL 30 DAY - INTERVAL HOUR(NOW()) HOUR - INTERVAL MINUTE(NOW()) MINUTE - INTERVAL SECOND(NOW()) SECOND)

MYSQL 30 days query

i have this kind of query:
SELECT COUNT( * )
FROM `reportinc`
WHERE `Data/ora apertura` >= '21/01/13 00:00:00'
AND `Data/ora apertura` <= '21/01/13 18:00:00'
I have to repeat this query for 30 days past from today.
How automate it?
Instead of daytime: 21/01/13 i have to insert something like TODAY -1, TODAY -2 etc etc but my own specified timestamp.
How to?

SELECT TO_DAYS(NOW()) - TO_DAYS(your_table_column_name) <= 30;
Or use DATEDIFF
mysql> SELECT DATEDIFF('1997-12-31 23:59:59','1997-12-30');
-> 1

You could use BETWEEN
SELECT COUNT( * )
FROM `reportinc`
WHERE `Data/ora apertura`
BETWEEN
CURRENT_DATE - INTERVAL 2 DAY
AND
CURRENT_DATE - INTERVAL 1 DAY + '18:00:00'

Something like this:
WHERE `Data/ora apertura` >= CURRENT_DATE - INTERVAL 2 DAY
AND `Data/ora apertura` <= CURRENT_DATE - INTERVAL 1 DAY
+ INTERVAL '18:00:00' HOUR_SECOND

select dates that are between current date and 3 month from the current date in mysql

I want to select all dates that are between the current date and 3 months before.
I tried using this query but it isn't working right.
$sql = mysql_query("
SELECT *
FROM date
WHERE d_date BETWEEN NOW() AND NOW() - INTERVAL 3 MONTH
");
Please if you could help me write the right syntax.

You need to swap your bounaries, and it will work:
SELECT * FROM date
WHERE d_date BETWEEN now() - INTERVAL 3 MONTH AND now()
For example, this query returns true (SQLFiddle):
SELECT (now() - interval 1 month)
BETWEEN now() - interval 3 month AND now()

SELECT * FROM Table
WHERE anydate_col BETWEEN NOW() AND DATE_ADD( NOW() , INTERVAL +3 MONTH)

Query to get all rows from previous month

I need to select all rows in my database that were created last month.
For example, if the current month is January, then I want to return all rows that were created in December, if the month is February, then I want to return all rows that were created in January. I have a date_created column in my database that lists the date created in this format: 2007-06-05 14:50:17.

SELECT * FROM table
WHERE YEAR(date_created) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(date_created) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)

Here's another alternative. Assuming you have an indexed DATE or DATETIME type field, this should use the index as the formatted dates will be type converted before the index is used. You should then see a range query rather than an index query when viewed with EXPLAIN.
SELECT
*
FROM
table
WHERE
date_created >= DATE_FORMAT( CURRENT_DATE - INTERVAL 1 MONTH, '%Y/%m/01' )
AND
date_created < DATE_FORMAT( CURRENT_DATE, '%Y/%m/01' )

If there are no future dates ...
SELECT *
FROM table_name
WHERE date_created > (NOW() - INTERVAL 1 MONTH);
Tested.

Alternatively to hobodave's answer
SELECT * FROM table
WHERE YEAR(date_created) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(date_created) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)
You could achieve the same with EXTRACT, using YEAR_MONTH as unit, thus you wouldn't need the AND, like so:
SELECT * FROM table
WHERE EXTRACT(YEAR_MONTH FROM date_created) = EXTRACT(YEAR_MONTH FROM CURDATE() - INTERVAL
1 MONTH)

SELECT *
FROM yourtable
where DATE_FORMAT(date_created, '%Y-%m') = date_format(DATE_SUB(curdate(), INTERVAL 1 month),'%Y-%m')
This should return all the records from the previous calendar month, as opposed to the records for the last 30 or 31 days.

Even though the answer for this question has been selected already, however, I believe the simplest query will be
SELECT *
FROM table
WHERE
date_created BETWEEN (CURRENT_DATE() - INTERVAL 1 MONTH) AND CURRENT_DATE();

WHERE created_date >= DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 2 MONTH)), INTERVAL 1 DAY)
AND created_date <= DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 1 MONTH)), INTERVAL 0 DAY)
This worked for me (Selects all records created from last month, regardless of the day you run the query this month)

Alternative with single condition
SELECT * FROM table
WHERE YEAR(date_created) * 12 + MONTH(date_created)
= YEAR(CURRENT_DATE) * 12 + MONTH(CURRENT_DATE) - 1

select fields FROM table
WHERE date_created LIKE concat(LEFT(DATE_SUB(NOW(), interval 1 month),7),'%');
this one will be able to take advantage of an index if your date_created is indexed, because it doesn't apply any transformation function to the field value.

Here is the query to get the records of the last month:
SELECT *
FROM `tablename`
WHERE `datefiled`
BETWEEN DATE_SUB( DATE( NOW( ) ) , INTERVAL 1
MONTH )
AND
LAST_DAY( DATE_SUB( DATE( NOW( ) ) , INTERVAL 1
MONTH ) )
Regards
- saqib

if you want to get orders from last month, you can try using
WHERE MONTH(order_date) = MONTH(CURRENT_DATE()) -1

One more way to do this in:
MYSQL
select * from <table_name> where date_created >= DATE_ADD(NOW(), INTERVAL -30 DAY);

SELECT * FROM table
WHERE YEAR(date_created) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH)
AND MONTH(date_created) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)