I have two tables. One with amounts in quarterly increments, the other with amounts in annual increments. I want to join the two and sum FEES and COUNTS without double counting.
Table 1
CLM_NUM Year Quarter FEES
1234 2016 1 100
1234 2016 2 100
1234 2016 3 100
1234 2016 4 100
Table 2
CLM_NUM Year COUNT
1234 2016 10
Desired Result:
CLM_NUM Year FEES COUNT
1234 2016 400 10
However, my query causes the counts to be counted four times resulting in 40, not 10.
How do I resolve this?
SELECT Table1.CLM_NUM, Table1.YEAR, Sum(Table1.FEES) AS SumOfFEES,
Sum(Table2.COUNT) AS SumOfCOUNT
FROM Table1 INNER JOIN Table2 ON (Table1.CLM_NUM = Table2.CLM_NUM) AND (Table1.YEAR = Table2.YEAR)
GROUP BY Table1.CLM_NUM, Table1.YEAR;
You can use a sub-query. The SUM in the sub-query means it would work even if table 2 wasn't yearly (i.e. there were more rows per CLM_NUM/Year key).
SELECT
t1.clm_num,
t1.year,
sum(t1.fees),
(SELECT
sum(t2.count)
FROM
Table2 t2
WHERE t1.CLM_NUM = t2.CLM_NUM
AND t1.Year = t2.Year
GROUP BY
t2.CLM_NUM, t2.Year
) AS SumOfCount
FROM
Table1 t1
GROUP BY
t1.CLM_NUM, t1.Year
if access doesnt have max, use first
http://sqlfiddle.com/#!18/7ec1d/1
select t1.clm_num, t1.year,sum(t1.fees),max(t2.count)
from Table1 t1 inner join
Table2 t2 on t2.clm_num = t1.clm_num and (t1.YEAR = t2.YEAR)
GROUP BY t1.CLM_NUM, t1.YEAR
Related
The table A looks like
number
amount
date
100
122.3
30-JUN-21
100
152.3
31-DEC-21
100
122.3
20-JUN-21
100
122.3
30-JUN-22
122
132.3
30-JUN-21
122
142.3
31-DEC-21
142
132.3
20-JUN-21
142
152.3
30-JUN-22
and the output of query should look like..
number
amount
date
100
244.6
20-JUN-21
122
132.3
30-JUN-21
142
132.3
20-JUN-21
The agenda is to sum the amount by taking minimum of date group by number and if some other date exists in same minimum month that also has to be included.Can anyone help me with the query?
select sum(amount),min(date) from A group by number;
Write a subquery that gets the minimum date for each number. Then join that with the table to get all the rows in the same month and number, and sum the amounts.
SELECT t1.number, SUM(t1.amount) AS amount, t2.date
FROM A AS t1
JOIN (
SELECT number, MIN(date) AS date
FROM A
GROUP BY number
) AS t2 ON t1.number = t2.number AND YEAR(t1.date) = YEAR(t2.date) AND MONTH(t1.date) = MONTH(t2.date)
GROUP BY t1.number
DEMO
Let's say I have two tables, one storing accounts, one storing transactions :
id acct_name opening_bal
1 checking 1029.99
2 savings 2002.19
...
And
id date amount from_acct to_acct
...
99 2018-01-21 12.15 1 2
100 2018-01-21 9.99 4 1
101 2018-01-23 10.01 5 2
...
For example, row 99 in the transactions table is saying that 12.15 was transfered from checking to savings on 21 Jan 2018.
I would like to write a query that returns all accounts together with their balances on a given date (like today or 12 Oct 2018, etc), something like this :
acct balance
checking 1599.21
savings 2221.99
...
How would I write such a query?
Edit: Here's a solution, which is close enough to what I want (it just has an additional id column). You can replace CURDATE() with an arbitrary date to get the corresponding table of balances on that date.
SELECT id, acct_name, opening_bal+amt-amt2 as balance FROM accounts
INNER JOIN
(SELECT to_acct, sum(amount) AS amt
FROM transactions
WHERE date <= CURDATE()
GROUP BY to_acct) as T2
ON accounts.id=T2.to_acct
INNER JOIN
(SELECT from_acct, sum(amount) AS amt2
FROM transactions
WHERE date <= CURDATE()
GROUP BY from_acct) as T3
ON T2.to_acct = T3.from_acct
;
Something like this. If you'd provided more data, answer could be more precise. Table1 is your first table, Table2 is the second.
select acct_name as acct,
opening_bal - t1.put_money + t2.get_money as balance
from Table1
left join (select from_acct, ifnull(sum(amount),0) as put_money from Table2 group by from_acct) t1
on t1.from_acct = Table1.id
left join (select to_acct, ifnull(sum(amount),0) as get_money from Table2 group by to_acct) t2
on t2.to_acct = Table1.id;
I'm making a donation report, I have two tables tbldonation and tblpubdonation
I want to get their sum group by year.
tbldonation:
amount | received
100 : 2016-01-02 08:42:20
100 : 2015-12-01 09:20:00
tblpubdonation:
amount | received
100 : 2015-12-22 09:20:00
My query is :
SELECT * from
(
(SELECT YEAR(received) as YY, sum(amount) as AMT FROM tbldonation)
UNION ALL
(SELECT YEAR(received) as YY, sum(amount) as AMT FROM tblpubdonation)
) results
WHERE results.YY <= Curdate()
GROUP BY results.YY
ORDER BY results.YY DESC
I'm getting a result but it's not accurate.
It should be
YY | AMT
2016 : 100
2015 : 200
But my result is:
YY | AMT
2016 : 200
2015 : 100
The value is misplaced.
Try following for MySql (Since MySQL lacks support for FULL JOIN. we have to simulate It)
SELECT Yr , SUM(amountSum)
FROM ( SELECT SUM(ISNULL(t1.amount, 0)) AS amountSum ,
t1.year AS Yr
FROM tbldonation t1
GROUP BY t1.YEAR
UNION ALL
SELECT SUM(ISNULL(t2.amount, 0)) AS amountSum ,
t2.year AS Yr
FROM tblpubdonation t2
GROUP BY t2.YEAR
) Tbl
GROUP BY Tbl.Yr
Following works for T-SQL
SELECT SUM (ISNULL(t1.amount,0)) + SUM(ISNULL(t2.amount,0)), ISNULL(t1.YEAR,t2.YEAR)
FROM dbo.tbldonation t1
FULL OUTER JOIN dbo.tblpubdonation t2 ON t1.YEAR = t2.YEAR
GROUP BY t1.YEAR, t2.YEAR
You are using sum(amount) in the query .So in tbldonation the sum becomes .In pbldonationsum(amount)=100.At the end the order is given by years .So 2016 is at first and 2015 at the end.Year 2015 wont get the amount value 200 because union operator is used and both are having 2015 as common .So this is to chabged in the data itself as per me or else some data glitch.If I am wrong please suggest me also so that I can improve myself.
Thank you.
Regards, Raju.
For Example, I have table like this:
Date | Id | Total
-----------------------
2014-01-08 1 15
2014-01-09 3 24
2014-02-04 3 24
2014-03-15 1 15
2015-01-03 1 20
2015-02-24 2 10
2015-03-02 2 16
2015-03-03 5 28
2015-03-09 5 28
I want the output to be:
Date | Id | Total
---------------------
2015-01-03 1 20
2014-02-04 3 24
2015-03-02 2 16
2015-03-09 5 28
Here the distinct values are Id. I need latest Total for each Id.
You can use left join as
select
t1.* from table_name t1
left join table_name t2
on t1.Id = t2.Id and t1.Date >t2.Date
where t2.Id is null
http://dev.mysql.com/doc/refman/5.0/en/example-maximum-column-group-row.html
You can also use Max() in sql:
SELECT date, id, total
FROM table as a WHERE date = (SELECT MAX(date)
FROM table as b
WHERE a.id = b.id
)
You can do it as below
SELECT *
FROM YourTable D
WHERE date = (SELECT MAX(date) FROM YourTable WHERE ID = D.ID)
Another way is by using INNER JOIN
Find the latest date per ID then join result back to the table to get the value
select A.ID,A.Date,A.value
from yourtable A
INNER JOIN
(
select MAX(date) as Date,ID
from yourtable
group by ID
) B
ON A.ID =B.ID and A.Date = B.Date
The other answers didn't work for me. I found the following code, which worked great for me:
SELECT * FROM TABLE WHERE DATE IN (SELECT MAX(DATE) FROM TABLE)
I am using SSMS 2014, SQLServer
I have two tables
t1
id Name Total
1 Alex 100
2 Bob 100
1 Alex 100
t2
id Amount
1 2
1 3
1 4
2 12
2 13
I need to get sum of Total and Amount.
**select Name, sum(Total) as Total, sum(Amount) as Amount,day
from t1,t2
Where t1.id=t2.id
group by Name**
Result:
Alex 600 18
Bob 200 25
Incorrect sum of Amount!
**select Name, sum(distinct Total) as Total, sum(Amount) as Amount,day
from t1,t2
Where t1.id=t2.id
group by Name**
Result:
Alex100 18
Bob 100 25
Incorrect sum of Amount.
MySql use distinct by value, i need distinct by id
corect result that need be is
Alex 200 18
Bob 100 25
How to get to this result?
select t1.Name,
sum(t1.Total) as Total,
sum(t2.Amount) as Amount,
day
from t1
left join
(
select id, sum(Amount) as Amount
from t2
group by id
) t2 on t1.id = t2.id
group by t1.Name