MySql. 'group by' by parts - mysql

Question

there is a table
CREATE TABLE geography_schedule (
id int(10) UNSIGNED NOT NULL,
geography_address_id int(10) UNSIGNED NOT NULL,
geography_city_id int(10) UNSIGNED NOT NULL,
sort int(5) UNSIGNED NOT NULL DEFAULT '500',
site varchar(5) NOT NULL DEFAULT 'site',
group_id int(10) NOT NULL DEFAULT '0',
day int(10) NOT NULL DEFAULT '1',
all_day tinyint(2) NOT NULL DEFAULT '0',
freeday int(10) NOT NULL DEFAULT '0',
from varchar(5) NOT NULL DEFAULT '09:00',
to varchar(5) NOT NULL DEFAULT '18:00',
timestamp timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
timestamp_update timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO geography_schedule (from, to, geography_address_id, day_from, day_to, group_id) VALUES
('09:00', '18:00', 533, 1, 1, 1),
('09:00', '18:00', 533, 2, 2, 1),
('11:00', '17:00', 533, 3, 3, 1),
('11:00', '17:00', 533, 4, 4, 1),
('09:00', '18:00', 533, 5, 5, 1),
('10:00', '17:00', 533, 6, 6, 1),
('09:00', '18:00', 533, 7, 7, 1);
I have a mysql query from this table enter image description here
SELECT `from`,`to`, `geography_address_id`, MIN(`day`) as `day_from`
,MAX(`day`) as `day_to`,`group_id`
FROM `geography_schedule`
WHERE `geography_address_id` = 533
GROUP BY `from`,`to`
ORDER BY `geography_schedule`.`day` ASC
result:
I need to group by lines 9:00 - 18:00 to save days day_from & day_to in proper order.
Is it possible to use GROUP BY in such a way it will give the result like this?