Query builder - codeigniter - mysql

Question

I have problems building a query that uses three tables.
If I write the query as:
$query = "select domains.ID, domains.Name, domains.IP,
database_info.DB_Name, database_info.DB_User, database_info.DB_Pass,
ftp.FTP_User, ftp.FTP_Pass from domains
left join database_info on domains.ID = database_info.Domain_ID
left join ftp on domains.ID = ftp.Domain_ID
where domains.ID = $ID";
$query = $this->db->get();
if($query->num_rows()>0){
return $query->result();
}
I get error Number 1096 No tables used SELECT *
However is I write the query using the query builder:
$this->db->select('domains.ID','domains.Name','domains.IP',
'database_info.DB_Name','database_info.DB_User',
'database_info.DB_Pass','ftp.FTP_User','ftp.FTP_Pass');
$this->db->from('domains');
$this->db->join('database_info','domains.ID =
database_info.Domain_ID', 'left');
$this->db->join('ftp','domains.ID = ftp.Domain_ID','left');
$this->db->where('domains.ID',$ID);
$query = $this->db->get();
if($query->num_rows()>0){
return $query->result();
}
The query runs but only returns the domains.ID
Open to ideas and suggests

Answer 1

try this
$query = $this->db
->select('domains.ID,domains.Name,domains.IP, database_info.DB_Name,database_info.DB_User,database_info.DB_Pass,ftp.FTP_User,ftp.FTP_Pass')
->from('domains')
->join('database_info','domains.ID = database_info.Domain_ID', 'left')
->join('ftp','domains.ID = ftp.Domain_ID','left')
->where('domains.ID',$ID)
->get();
if($query->num_rows()>0)
{
return $query->result();
}
The point is in your select statement - the Query Builder only accepts one argument for your entire select statement not that many as you did
and please for the sake of security - never ever try to execute sql
statements without escaping them - CI's query builder will do this per
default - but your first example is pretty dangerous and widely open
to sql injections

Answer 2

Use db->query
$sql = "select domains.ID, domains.Name, domains.IP,
database_info.DB_Name, database_info.DB_User, database_info.DB_Pass,
ftp.FTP_User, ftp.FTP_Pass from domains
left join database_info on domains.ID = database_info.Domain_ID
left join ftp on domains.ID = ftp.Domain_ID
where domains.ID = $ID";
$query = $this->db->query($sql);
$result = $query->result_array();
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