I have
jobs table with fields
jobId, jobTitle, jobDesc
jobQuotes Table with fields
id, user_id, quote
jobQuotes table has the quote of users who gave quote for the job.
I need those jobs for which a specific user has NOT given any quote.
Using LEFT JOIN I get all the jobs irrespective of the jobQuotes table.
And INNER JOIN only gives all the jobs that has a relevant jobQuote.
But I need those jobs for which a specific user has NOT given any quote.
My Query is
SELECT * FROM dummy_jobs J LEFT JOIN jobQuotes JQ ON J.jobId=JQ.jobId WHERE MATCH (J.jobTitle, J.jobDescription) AGAINST ('php, mysql');
How to filter this result set so that output doesn't have specific user_id in jobQuotes?
SELECT jobstable.jobid from jobstable inner join
(SELECT id from jobQuotes where userid = 953 and quote IS NULL) dummy_table
on dummy_table.id == jobstable.jobid;
The Answer is According to the comment you were given
"I want all jobs for which userId= 953 has not given any quote"
An approach might be to associate a specific user with all jobs by using a cross join and then left join to job quotes with a null test to find those not quoted for.
for example
users
+----+----------+
| id | username |
+----+----------+
| 1 | John |
| 2 | Jane |
| 3 | Ali |
| 6 | Bruce |
| 7 | Martha |
+----+----------+
Jobs
+-------+----------+---------+
| jobId | jobTitle | jobDesc |
+-------+----------+---------+
| 1 | a | a |
| 2 | b | b |
| 3 | c | c |
+-------+----------+---------+
Jobquotes
+------+---------+-------+
| id | user_id | quote |
+------+---------+-------+
| 1 | 3 | 10 |
| 2 | 2 | 10 |
+------+---------+-------+
select t.id,t.username,t.jobid,t.jobtitle,t.jobdesc
from
(
select u.id,u.username, s.jobid,s.jobtitle,s.jobdesc
from users u
cross join (select distinct jobid , jobtitle, jobdesc from jobs) s
where u.id = 3
) t
left join jobquotes jq on jq.id = t.jobid and jq.user_id = t.id
where jq.id is null
result
+----+----------+-------+----------+---------+
| id | username | jobid | jobtitle | jobdesc |
+----+----------+-------+----------+---------+
| 3 | Ali | 2 | b | b |
| 3 | Ali | 3 | c | c |
+----+----------+-------+----------+---------+
Related
I am using mysql and here is the schema that I have.
First Table: Domains
+-----------+--------------------+---------------+
| domain_id | domain_name | campaign_name |
+-----------+--------------------+---------------+
| 1 | test.org | campaign 1 |
| 2 | example.org | campaign 2 |
+-----------+--------------------+---------------+
Second Table: Users
+---------+-----------------+---------------+
| user_id | first_ame | last_name |
+---------+-----------------+---------------+
| 1 | John | Zimmer |
| 2 | Brian | Roberts |
| 3 | Jon | McNeill |
| 4 | Chris | Lambert |
| 5 | Vipul | Patel |
| 6 | Logan | Green |
+---------+-----------------+---------------+
Third Table: Emails
+----------+----------------------------------+-----------+---------+
| email_id | email | domain_id | user_id |
+----------+----------------------------------+-----------+---------+
| 1 | b1#test.org | 1 | 2 |
| 2 | b2#test.org | 1 | 1 |
| 3 | a1#example.org | 2 | 2 |
| 4 | a2#example.org | 2 | 3 |
| 5 | a3#example.org | 2 | 3 |
| 6 | a4#example.org | 2 | 4 |
+----------+----------------------------------+-----------+---------+
I want to get first_name, last_name and email of specific campaign i-e campaign 2 as shown follow.
Here is Online DB Query Editor
Kindly guide me how can I write SQL query to accomplish that. Thanks
If I am not missing anything, this is basically a join. You have the ids nicely matched between the tables, so you can do:
SELECT u.*, e.email, d.campaign_name
FROM Users u JOIN
Emails e
ON u.user_id = e.user_id JOIN
Domains d
ON e.domain_id = d.domain_id
WHERE d.campaign_name = 'campaign 2';
The email table is a so called bridge table between the other two. You have to perform a join between the three tables:
SELECT first_name, last_name, email
FROM Domains JOIN Emails ON Domains.domain_id = Emails.domain_id JOIN Users ON Emails.user_id = Users.user_id
WHERE Domains.campaign_name = ...
SELECT first_name as 'First Name',last_name as 'Last Name', email as 'email ID',campaign_name as 'Compaign Name'
FROM Users u
inner join Emails e
on e.user_id = u.user_id
inner join Domains d
on d.domain_id = e.domain_id
I am trying to create a query with a GROUP_CONCAT added as a new column in my current query, first here are my tables:
Users table
+----+----------+--------------+
| id | username | date_created |
+----+----------+--------------+
| 1 | user1 | 2000-03-16 |
| 2 | user2 | 2001-05-14 |
| 3 | user3 | 2002-01-13 |
| 4 | user4 | 2003-03-14 |
+----+----------+--------------+
Shifts table
+----+------------+--------------+
| id | shift_name | date_created |
+----+------------+--------------+
| 1 | shift1 | 2002-05-10 |
| 2 | shift2 | 2002-07-11 |
| 3 | shift3 | 2002-09-23 |
+----+------------+--------------+
Accounts table
+----+--------------+--------------+
| id | account_name | date_created |
+----+--------------+--------------+
| 1 | account1 | 2001-05-01 |
| 2 | account2 | 2001-05-02 |
| 3 | account3 | 2001-05-03 |
+----+--------------+--------------+
Shift Mapping table
+----+---------+----------+------------+
| id | user_id | shift_id | account_id |
+----+---------+----------+------------+
| 1 | 1 | 1 | 1 |
| 2 | 1 | 2 | 2 |
| 3 | 3 | 1 | 1 |
+----+---------+----------+------------+
basically, I want a query that gets all the user (to display in a table) with a custom column that shows all shift that is attach to that user(if there is no shift attach to that obviously has a null result)
Here is the query I've done so far:
SELECT users.id AS user_id, users.username, users.date_created,
GROUP_CONCAT(DISTINCT (t.shift_name)) AS shifts
FROM (`users`)
LEFT JOIN
(SELECT s.shift_name, sm.user_id FROM shift_map sm
LEFT JOIN shifts s ON sm.shift_id = s.id) t
ON users.id = t.user_id
GROUP BY user_id
ORDER BY `users`.`date_created` DESC;
Now there is no problem getting the users with a shift attach to it, my problem is that the users with no shifts attach to only returns 1 result which is caused by the GROUP BY user_id how can I exclude the users with no shift in the GROUP BY or how can I return all the users with attached shifts and with no attach shifts? Thanks.
Update
Here is the example result I want to see:
+---------+----------+--------------+----------------+
| user_id | username | date_created | shifts |
+---------+----------+--------------+----------------+
| 1 | user1 | 2000-03-16 | shift1,shift2 |
| 2 | user2 | 2001-05-14 | (NULL) |
| 3 | user3 | 2002-01-13 | shift1 |
| 4 | user4 | 2003-03-14 | (NULL) |
+---------+----------+--------------+----------------+
My problem in my query is that it only shows only 1 user with null shifts.
SELECT users.id AS user_id, users.username, users.date_created,
GROUP_CONCAT(DISTINCT (t.shift_name)) AS shifts
FROM (`users`)
LEFT JOIN
(SELECT s.shift_name, sm.user_id FROM mapping sm
LEFT JOIN shifts s ON sm.shift_id = s.id) t
ON users.id = t.user_id
GROUP BY username
ORDER BY user_id
+---------+----------+--------------+---------------+
| user_id | username | date_created | shifts |
+---------+----------+--------------+---------------+
| 1 | user1 | 2000-03-16 | shift1,shift2 |
| 2 | user2 | 2001-03-16 | NULL |
| 3 | user3 | 2002-03-16 | shift1 |
| 4 | user4 | 2003-03-16 | NULL |
+---------+----------+--------------+---------------+
My Bad, I can just use the simple LEFT JOIN:
SELECT users.id AS user_id, users.username, users.date_created,
GROUP_CONCAT(DISTINCT (shift.shift_name)) AS shifts
FROM (`users`)
LEFT JOIN shifts_map ON users.id = shifts_map.user_id
LEFT JOIN shifts ON shifts_map.shift_id = shift.id
GROUP BY user_id
ORDER BY `users`.`date_created` DESC;
I am just complicating the query, Forgot that the simple LEFT JOIN can do the trick. Thanks.
Lets say that I have something table like this:
<b>Name</b>
+---------+--------+
| name_id | name |
+---------+--------+
| 5 | Betti |
| 6 | Derry |
| 7 | Alfred |
| 8 | Elsie |
| 9 | Cinta |
+---------+--------+
<b>Goods</b>
+----------+-----------+
| goods_id | goods |
+----------+-----------+
| 1 | Computer |
| 2 | AC |
| 3 | Microwave |
| 4 | TV |
+----------+-----------+
<b>Transaction</b>
+-------+---------+----------+
| ai_id | name_id | goods_id |
+-------+---------+----------+
| 1 | 7 | 2 |
| 2 | 5 | 4 |
| 3 | 9 | 3 |
+-------+---------+----------+
I want to replace name_id column on Transaction table with name column on Name table with corresponding name_id column and so for goods_id to produce something similar to this table:
<b>Transaction</b>
+-------+--------+-----------+
| ai_id | name | goods |
+-------+--------+-----------+
| 1 | Alfred | AC |
| 2 | Betti | TV |
| 3 | Cinta | Microwave |
+-------+--------+-----------+
If you're looking to just display the information rather than actually "replacing" your tables with new ones, then you could use a SELECT query with a simple INNER JOIN. This way you can display columns from multiple tables.
SELECT T.ai_id, N.Name, G.goods
FROM Transaction T
INNER JOIN Name N ON N.name_id = T.name_id
INNER JOIN Goods G ON G.goods_id = T.goods_id;
Try with inner join
SELECT T.ai_id,N.name,G.goods
FROM Transaction as T
INNER JOIN Goods as G ON T.goods_id = G.goods_id
INNER JOIN Name as N ON N.name_id = T.name_id;
Try this one
select tb3.ai_id,tb2.name,tb1.goods from Goods tb1,Name tb2,Transaction tb3 where tb3.name_id=tb2.name_id and tb3.goods_id=tb1.goods_id order by tb3.ai_id
try this:
SELECT C.ai_id,A.name,B.goods
FROM Transaction C
INNER JOIN Name A
ON A.name_id=C.name_id
INNER JOIN Goods B
ON B.goods_id=C.goods_id;
http://sqlfiddle.com/#!2/3c5f3/8
I need to get emtpy fields where data is repeated
For example an customer can have two or more contact persons, so query return (just shorted qyery resul):
CUSTOMER_NAME| CONTACT_PERSON|ETC..
dell | Ighor |etc..
dell | Dima |etc..
but I'm need :
CUSTOMER_NAME| CONTACT_PERSON|etc...
dell | Ighor |etc..
NULL | Dima |etc..
SELECT
`contact`.*,
`branch_has_equipment`.*,
`branch_has_contact`.*,
`equipment`.*,
`customer_has_branch`.*,
`branch`.*,
`customer`.*,
`ip`.*
FROM `customer`
INNER JOIN `customer_has_branch`
ON `customer`.`customer_id` = `customer_has_branch`.`customer_id`
INNER JOIN `branch`
ON `customer_has_branch`.`branch_id` = `branch`.`branch_id`
INNER JOIN `branch_has_equipment`
ON `branch`.`branch_id` = `branch_has_equipment`.`branch_id`
INNER JOIN `equipment`
ON `branch_has_equipment`.`equipment_id` = `equipment`.`equipment_id`
INNER JOIN `branch_has_contact`
ON `branch`.`branch_id` = `branch_has_contact`.`branch_id`
INNER JOIN `contact`
ON `branch_has_contact`.`contact_id` = `contact`.`contact_id`
INNER JOIN `equipment_has_ip`
ON `equipment`.`equipment_id` = `equipment_has_ip`.`equipment_id`
INNER JOIN `ip`
ON `equipment_has_ip`.`equipment_id` = `ip`.`ip_id`
WHERE `customer`.`inservice` = 'Yes'
ORDER BY `customer`.`customer_name`
in additional, tables ^
Customer
customer_id
customer_name
inservice
service_type
comment
Branch
branch_id
city
address
Equipment
equipment_id
brand
model
connection_param
connection_type
serial_number
id
release
Contact
contact_id
name
surname
phone_mobile
phone_work
phone_other
position
customer_has_branch_id
customer_id
branch_id
Since I have no idea how any of those tables relate to one another, my only answer to you is to use an OUTER JOIN, which will keep NULL results.
I'm not seriously advocating this solution because really i think this sort of thing should be handled in application level code (e.g. a bit of PHP), but anyway, consider the following:
SELECT * FROM my_table;
+------+--------+--------+
| game | points | player |
+------+--------+--------+
| 1 | 5 | Adam |
| 1 | 8 | Alan |
| 1 | 7 | Brian |
| 1 | 6 | John |
| 2 | 2 | Adam |
| 2 | 3 | Alan |
| 2 | 4 | Brian |
| 2 | 6 | John |
+------+--------+--------+
SELECT IF(game= #prev,'',game)
, #prev := game
FROM my_table ORDER BY game,player;
+-------------------------+---------------+
| IF(game= #prev,'',game) | #prev := game |
+-------------------------+---------------+
| 1 | 1 |
| | 1 |
| | 1 |
| | 1 |
| 2 | 2 |
| | 2 |
| | 2 |
| | 2 |
+-------------------------+---------------+
Hi I trying to do query with couple INNER JOIN, Where is my fault?
SELECT job_tbl.id, accounts.username AS starter, accounts.username AS worker, job_tbl.comment, job_tbl.date, job_tbl.status
FROM job_tbl
INNER JOIN accounts ON job_tbl.starter = accounts.id
INNER JOIN accounts ON job_tbl.worker = accounts.id
job_tbl table here :
+----+---------+--------+---------+------+--------+
| id | starter | worker | comment | date | status |
+----+---------+--------+---------+------+--------+
| 1 | 1 | 3 | qwe | date | 10 |
+----+---------+--------+---------+------+--------+
| 2 | 2 | 1 | qwe | date | 10 |
+----+---------+--------+---------+------+--------+
accounts table here:
+----+------------+-----------+-------+
| id | username | extension | email |
+----+------------+-----------+-------+
| 1 | Julia | 100 | email |
+----+------------+-----------+-------+
| 2 | Eve | 101 | email |
+----+------------+-----------+-------+
| 3 | Max | 102 | email |
+----+------------+-----------+-------+
result I want it to be :
+----+---------+--------+---------+------+--------+
| id | starter | worker | comment | date | status |
+----+---------+--------+---------+------+--------+
| 1 | Julia | Max | qwe | date | 10 |
+----+---------+--------+---------+------+--------+
| 2 | Eve | Julia | qwe | date | 10 |
+----+---------+--------+---------+------+--------+
You're not specifying which accounts table instance to use as starter or worker.
Try this:
SELECT job_tbl.id, job_tbl.description, Starter.username AS starter, Worker.username AS worker, job_tbl.comment, job_tbl.date, job_tbl.status
FROM job_tbl
INNER JOIN accounts AS Starter ON job_tbl.starter = Starter.id
INNER JOIN accounts AS Worker ON job_tbl.worker = Worker.id
The problem is you are joining two table without specifying an ALIAS on table accounts causing ambiguous state.
SELECT a.*,
b.username StarterName,
c.userName WorkerName
FROM job_tbl a
INNER JOIN account b
ON a.starter = b.id
INNER JOIN account c
ON a.worker = c.ID
To further gain more knowledge about joins, kindly visit the link below:
Visual Representation of SQL Joins