I need print out players who have 2 trophies, and I need sum their all matches earned points. There i need use 3 tables from my DB
1.I need got trophy_count , I can this with this step ->
select surname, count(t.player_id) as trophy_count
from dbo.Players p
left join Trophies t on t.player_id=p.id
group by p.surname
So, SQL gave me this
2.Print out all earned points ->
select name, sum(points) as points
from dbo.Players p
inner join dbo.Stats s on s.player_id=p.id
group by p.name
SQL gave me this:
I want do this in one query:
select name, sum(points) as points, COUNT(t.player_id) as trophy_count
from dbo.Players p
inner join dbo.Stats s on s.player_id=p.id
inner join dbo.Trophies t on t.player_id=p.id
group by p.name
and SQL gave me this, SQL multiplies x 2 all my info, it is wrong
And , at this fail, I dont know what i need write, for select players who have 2 trophies and sum their earned points. (Lonzo ball 21 point 2trophies,Kristaps Porzingis 17points 2trophies).
For safer result, wrap all your current query in a subquery.
SELECT p.id, p.name, p.surname,
IFNULL(trop.trophy_count, 0),
IFNULL(pts.points, 0)
FROM dbo.Players p
LEFT JOIN
(
select p.id, count(t.player_id) as trophy_count
from dbo.Players p
left join Trophies t on t.player_id=p.id
group by p.id
) trop ON p.id = trop.id
LEFT JOIN
(
select p.id,sum(points) as points
from dbo.Players p
inner join dbo.Stats s on s.player_id = p.id
group by p.id
) pts ON p.id = pts.id
Can you check this:
SELECT P.name,
(SELECT CASE WHEN (SUM(S.points) IS NULL) THEN 0 ELSE SUM(S.points) END FROM Stats S WHERE S.player_id = P.id ) as points,
(SELECT COUNT(T.player_id) FROM Trophies T WHERE T.player_id = P.id ) as trophy_count
FROM Players P
I do not have specified dbo. in front of Tables in query, if you need that please add & test.
SQL Fiddle
It will works well to your question
SELECT dbo.Players.name, dbo.Players.surname, ISNULL(s.points, 0) points, ISNULL(t.trophy_count, 0) trophies_count FROM dbo.Players
LEFT JOIN (
SELECT player_id, SUM(points) points FROM dbo.Stats
GROUP BY player_id
) s ON s.player_id = dbo.Players.id
LEFT JOIN (
SELECT player_id, COUNT(*) trophy_count FROM dbo.Trophies
GROUP BY player_id
) t ON t.player_id = dbo.Players.id
WHERE t.trophy_count = 2
Related
I've the above dataset, I need to report for each year the percentage of movies in that year with only female actors, and the total number of movies made that year. For example, one answer will be: 1990 31.81 13522 meaning that in 1990 there were 13,522 movies, and 31.81%
In order to get the moves with only female actors, wrote the following code:
SELECT a.year as Year, COUNT(a.title) AS Female_Movies, a.title
FROM Movie a
WHERE a.title NOT IN (
SELECT b.title from Movie b
Inner Join M_cast c
on TRIM(c.MID) = b.MID
Inner Join Person d
on TRIM(c.PID) = d.PID
WHERE d.Gender='Male'
GROUP BY b.title
)
GROUP BY a.year,a.title
Order By a.year asc
The total movies in each year , can be found using the following:
SELECT a.year, count(a.title) AS Total_Movies
FROM Movie a
GROUP BY a.year
ORDER BY COUNT(a.title) DESC
Combinig the both I wrote, the following code:
SELECT z.year as Year, count(z.title) AS Total_Movies, count(x.title) as Female_movies, count(z.title)/ count(x.title) As percentage
FROM Movie z
Inner Join (
SELECT a.year as Year, COUNT(a.title) AS Female_Movies, a.title
FROM Movie a
WHERE a.title NOT IN (
SELECT b.title from Movie b
Inner Join M_cast c
on TRIM(c.MID) = b.MID
Inner Join Person d
on TRIM(c.PID) = d.PID
WHERE d.Gender='Male'
GROUP BY b.title
)
GROUP BY a.year,a.title
Order By a.year asc
)x
on x.year = z.year
GROUP BY z.year
ORDER BY COUNT(z.title) DESC
However, in th output I'm seeing the years with only female movies correctly, but the count of total movies is equal to female_movies so I'm getting 1%, I tried debugging the code, but not sure where this is going wrong. Any insights would be appreciated.
You assume that your 'z' contains all movies but since you do an inner join on the female movies, they'll also only contain female movies. You could fix that with a 'left join'.
Assuming your two queries are correct, you can join on them with a 'WITH' like this:
WITH allmovies (year, cnt) as
(SELECT a.year, count(a.title) AS Total_Movies
FROM Movie a
GROUP BY a.year
ORDER BY COUNT(a.title) DESC)
,
femalemovies (year, cnt, title) as
(SELECT a.year as Year, COUNT(a.title) AS Female_Movies, a.title
FROM Movie a
WHERE a.title NOT IN (
SELECT b.title from Movie b
Inner Join M_cast c
on TRIM(c.MID) = b.MID
Inner Join Person d
on TRIM(c.PID) = d.PID
WHERE d.Gender='Male'
GROUP BY b.title
)
GROUP BY a.year,a.title
Order By a.year asc)
select * from allmovies left join femalemovies on allmovies.year = femalemovies.year
You can use conditional aggregation. In a CASE expression check if no cast member that isn't female exists with a correlated subquery. If the check is successful, return something not NULL and count() that to get the number of movies with only female cast members (or none at all).
SELECT m.year,
count(*) count_all,
count(CASE
WHEN NOT EXISTS (SELECT *
FROM m_cast c
INNER JOIN person p
ON p.pid = c.pid
WHERE c.mid = m.mid
AND p.gender <> 'Female') THEN
1
END)
/
count(*)
*
100 percentage_only_female
FROM movie m
GROUP BY m.year;
Since in MySQL Boolean expressions in numerical context evaluate to 1 if true and to 0 otherwise, you could also use a sum() over the NOT EXISTS.
SELECT m.year,
count(*) count_all,
sum(NOT EXISTS (SELECT *
FROM m_cast c
INNER JOIN person p
ON p.pid = c.pid
WHERE c.mid = m.mid
AND p.gender <> 'Female'))
/
count(*)
*
100 percentage_only_female
FROM movie m
GROUP BY m.year;
That however isn't compatible with most other DBMS in contrast to the first one.
I would use two levels of aggregation:
SELECT m.MID, m.title, m.year,
COUNT(*) as num_actors,
SUM(gender = 'Female') as num_female_actors
FROM Movie m JOIN
M_cast c
ON c.MID = b.MID JOIN
Person p
ON p.PID = c.PID
GROUP BY m.MID, m.title, m.year;
Then a simple outer aggregation:
SELECT year,
COUNT(*) as num_movies,
SUM( num_actors = num_female_actors ) as num_female_only,
AVG( num_actors = num_female_actors ) as female_only_ratio
FROM (SELECT m.MID, m.title, m.year,
COUNT(*) as num_actors,
SUM(gender = 'Female') as num_female_actors
FROM Movie m JOIN
M_cast c
ON c.MID = b.MID JOIN
Person p
ON p.PID = c.PID
GROUP BY m.MID, m.title, m.year
) m
GROUP BY year;
Notes:
Use meaningful table aliases, rather than arbitrary letters. You'll note that the table aliases are abbreviations for the table names.
Do not use functions when filtering or JOINing unless necessary. I removed the TRIM(). If you need it use it. Or better yet, fix the data.
SELECT m.Year,COUNT(m.Year),x.t,
(COUNT(m.Year)*1.0/x.t*1.0)*100
FROM Movie m LEFT JOIN
(SELECT Year,COUNT(Year) AS t FROM Movie GROUP BY year) AS x
ON m.Year=x.Year
WHERE m.MID IN
(SELECT MID FROM M_Cast WHERE PID in
(SELECT PID FROM Person WHERE Gender='Female')
AND m.MID NOT IN
(SELECT MID FROM M_Cast WHERE PID in
(SELECT PID FROM Person WHERE Gender='Male'))) GROUP BY m.year
Check if this is what you're looking for.
select movie.year, count(movie.mid) as Year_Wise_Movie_Count,cast(x.Female_Cast_Only as real) / count(movie.mid) As Percentage_of_Female_Cast from movie
inner join
(
SELECT Movie.year as Year, COUNT(Movie.mid) AS Female_Cast_Only
FROM Movie
WHERE Movie.MID NOT IN (
SELECT Movie.MID from Movie
Inner Join M_cast
on TRIM(M_cast.MID) = Movie.MID
Inner Join Person
on TRIM(M_cast.PID) = Person.PID
WHERE Person.Gender!='Female'
GROUP BY Movie.MID
)
GROUP BY Movie.year
Order By Movie.year asc
) x
on x.year = movie.year
GROUP BY movie.year
ORDER BY movie.year
Output:
year Year_Wise_Movie_Count Percentage_of_Female_Cast
---- --------------------- -------------------------
1939 2 0.5
1999 66 0.0151515151515152
2000 64 0.015625
2018 104 0.00961538461538462
Note:
This was executed in SQLIte3
I have reports table that aggregates data each product quantity each day.
SELECT r.year, r.month, c.id, c.client_name, p.product_name, cc.country_name, sum(r.quantity) units FROM
client c
join report r on c.id = r.client_id
join product p on r.product_id = p.id
join country cc on r.country_id = c.id
WHERE r.year = year(now())
group by r.year, r.month, c.id, p.product_name, cc.country_name
I'm trying to figure out how group units sum by month, client, product and country where query shows sum for top 5 countries and rest is sum from bottom countries. Something like this:
case
when sum(r.quantity) = 'Top 1' then cc.country_name
when sum(r.quantity) = Top 2' then cc.country_name
.....
when sum(r.quantity) = 'Top 2' then cc.country_name
else 'Other'
How can I do this?
Many thanks in advance
you can try this. Here i sort the result from most quantity to less and add a row number. so the first 6 are the top.
please try it, but i cant tested.
SELECT
#nr := ( #nr +1) AS nr,
IF ( #nr < 7, CONCAT('Top ',#nr), 'other' ) AS top,
r.* FROM (
SELECT r.year, r.month, c.id, c.client_name, p.product_name, cc.country_name, sum(r.quantity) units
FROM CLIENT c
JOIN report r ON c.id = r.client_id
JOIN product p ON r.product_id = p.id
JOIN country cc ON r.country_id = c.id
WHERE r.year = YEAR(now())
GROUP BY r.year, r.month, c.id, p.product_name, cc.country_name
ORDER BY sum(r.quantity) DESC
) AS r
CROSS JOIN ( SELECT #nr:=0 ) AS params;
Here is my database. Every photo have some points and is taken by specific user. Each photo is also assigned to the event. I want to find a picture with the highest number of points for each event. I also want to count how many events you won ( eg. For the user with id = 10 ). Could you please help me? I don't know how to solve this problem.
Here are two queries to achieve what you need:
picture with the highest number of points for each event.
SELECT e.id event_id,
e.name event_name,
ph.id photo_id,
ph.title photo_title,
u.id user_id,
u.login user_login,
COUNT(*) points
FROM events e
INNER JOIN photos ph
ON ph.event_id = e.id
AND ph.id = (
SELECT ph.id
FROM photos ph
INNER JOIN points p
ON p.photo_id = ph.id
WHERE ph.event_id = e.id
GROUP BY ph.id
ORDER BY COUNT(*) DESC
LIMIT 1
)
-- optional if you need to know the points
INNER JOIN points p
ON p.photo_id = ph.id
-- optional if you need to know the owner of the photo
INNER JOIN users u
ON u.id = ph.user_id
GROUP BY e.id,
e.name,
ph.id,
ph.title
See SQL fiddle.
count how many events you won
SELECT u.id user_id,
u.login user_login,
COUNT(distinct e.id) events_won
FROM events e
INNER JOIN photos ph
ON ph.event_id = e.id
AND ph.id = (
SELECT ph.id
FROM photos ph
INNER JOIN points p
ON p.photo_id = ph.id
WHERE ph.event_id = e.id
GROUP BY ph.id
ORDER BY COUNT(*) DESC
LIMIT 1
)
INNER JOIN users u
ON u.id = ph.user_id
GROUP BY u.id,
u.login
See SQL fiddle
I spent so much time googling today but i don't even know which keywords to use. So …
The project is an evaluation of a betting game (Football). I have 2 SQL Queries:
SELECT players.username, players.userid, matchdays.userid, matchdays.points, SUM(points) AS gesamt
FROM players INNER JOIN matchdays ON players.userid = matchdays.userid AND matchdays.season_id=5
GROUP BY players.username
ORDER BY gesamt DESC
And my second query:
SELECT max(matchday) as lastmd, points, players.username from players INNER JOIN matchdays ON players.userid = matchdays.userid WHERE matchdays.season_id=5 AND matchday=
(select max(matchday) from matchdays)group by players.username ORDER BY points DESC
The first one adds up the points of every matchday and shows the sum.
The second shows the points of the last gameday.
My Goal is to merge those 2 queries/tables so that the output is a table like
Rank | Username | Points last gameday | Overall points |
I don't even know where to start or what to look for. Any help would be appreciated ;)
use both query with join....use inner join if each userid have value in 2nd query also.also add userid in 2nd query also for join
SET #rank = 0;
SELECT #rank := rank + 1,
t1.username,
t2.points,
t1.gesamt
FROM (
SELECT players.username, players.userid puserid, matchdays.userid muserid, matchdays.points, SUM(points) AS gesamt
FROM players INNER JOIN matchdays ON players.userid = matchdays.userid AND matchdays.season_id=5
GROUP BY players.username
)t1
INNER JOIN
(
SELECT players.userid, max(matchday) as lastmd, points, players.username
from players INNER JOIN matchdays ON players.userid = matchdays.userid
WHERE matchdays.season_id=5 AND matchday=
(select max(matchday) from matchdays)group by players.username
)t2
ON t1.puserid = t2.userid
ORDER BY t1.gesamt
You can use conditional aggregation, i.e. sum the points only when the day is the last day:
SELECT
p.username,
SUM(case when m.matchday = (select max(matchday) from matchdays) then m.points end)
AS last_day_points,
SUM(m.points) AS total_points
FROM players p
INNER JOIN matchdays m ON p.userid = m.userid AND m.season_id = 5
GROUP BY p.userid
ORDER BY total_points DESC;
Or with a join instead of a non-correlated subquery (MySQL should come to the same execution plan):
SELECT
p.username,
SUM(case when m.matchday = last_day.matchday then m.points end) AS last_day_points,
SUM(m.points) AS total_points
FROM players p
INNER JOIN matchdays m ON p.userid = m.userid AND m.season_id = 5
CROSS JOIN
(
select max(matchday) as matchday
from matchdays
) last_day
GROUP BY p.userid
ORDER BY total_points DESC;
I have the following:
SELECT DISTINCT s.username, COUNT( v.id ) AS cnt
FROM `instagram_item_viewer` v
INNER JOIN `instagram_shop_picture` p ON v.item_id = p.id
INNER JOIN `instagram_shop` s ON p.shop_id = s.id
AND s.expirydate IS NULL
AND s.isLocked =0
AND v.created >= '2014-08-01'
GROUP BY (
s.id
)
ORDER BY cnt DESC
Basically I have an instagram_item_viewer with the following structure:
id viewer_id item_id created
It tracks when a user has viewed an item and what time. So basically I wanted to find shops that has the most items viewed. I tried the query above and it executed fine, however it doesn't seem to give the appropriate data, it should have more count than what it is. What am I doing wrong?
First, with a group by statement, you don't need the DISTINCT clause. The grouping takes care of making your records distinct.
You may want to reconsider the order of your tables. Since you are interested in the shops, start there.
Select s.username, count(v.id)
From instagram_shop s
INNER JOIN instagram_shop_picture p ON p.shop_id = s.shop_id
INNER JOIN instagram_item_viewer v ON v.item_id = p.id
AND v.created >= '2014-08-01'
WHERE s.expirydate IS NULL
AND s.isLocked = 0
GROUP BY s.username
Give thata shot.
As mentioned by #Lennart, if you have a sample data it would be helpful. Because otherwise there will be assumptions.
Try run this to debug (this is not the answer yet)
SELECT s.username, p.id, COUNT( v.id ) AS cnt
FROM `instagram_item_viewer` v
INNER JOIN `instagram_shop_picture` p ON v.item_id = p.id
INNER JOIN `instagram_shop` s ON p.shop_id = s.id
AND s.expirydate IS NULL
AND s.isLocked =0
AND v.created >= '2014-08-01'
GROUP BY (
s.username, p.id
)
ORDER BY cnt DESC
The problem here is the store and item viewer is too far apart (i.e. bridged via shop_picture). Thus shop_picture needs to be in the SELECT statement.
Your original query only gets the first shop_picture count for that store that is why it is less than expected
Ultimately if you still want to achieve your goal, you can expand my SQL above to
SELECT x.username, SUM(x.cnt) -- or COUNT(x.cnt) depending on what you want
FROM
(
SELECT s.username, p.id, COUNT( v.id ) AS cnt
FROM `instagram_item_viewer` v
INNER JOIN `instagram_shop_picture` p ON v.item_id = p.id
INNER JOIN `instagram_shop` s ON p.shop_id = s.id
AND s.expirydate IS NULL
AND s.isLocked =0
AND v.created >= '2014-08-01'
GROUP BY (
s.username, p.id
)
ORDER BY cnt DESC
) x
GROUP BY x.username