Idea use computed property to get difference between first day of month and current.
I use formula:
last("prtMarkerSuppliesLevel.1.2") - last("prtMarkerSuppliesLevel.1.2", dayofmonth("prtMarkerSuppliesLevel.1.2") )
first part work properly, but then i use dayofmonth i get error
Cannot evaluate expression: unexpected token at ")".
What is wrong?
Answer from zabbix forum thread link
Sorry, but you can not use last function in such way, it does not
support another last function as argument
the possible workaround - just create an item with scheduled interval
:
https://www.zabbix.com/documentation...stom_intervals
interval will be something like this: Code: md1h0m0 every 1st day of
each month at 0:00 This value will be collected only once a month and
will represent your prtMarkerSuppliesLevel at the begining of the
month.
then you can use last(your.current.item) - last(scheduled.item)
Regards, Kaspars
Related
I have a dataset with a column which has data in the form dd/mm/yyyy Now using the sparkSQL i want to add 1 day to the current date. I have tried with Date_add function but got an exception that the function doesnt exist
You are probably looking for this:
Check the documentation
There is also a possible duplicate :
How to get today -"1 day" date in sparksql?
If this does not get you anywhere please post the exact exception
I know that Gregorian calendar started on Oct 15th 1582, and during the transition from Julian calendar, 10 days had been dropped.
When I'm doing this query:
SELECT STR_TO_DATE('1582-10-05', '%Y-%m-%d')
I'm getting this result:
1582-10-15 (the 10 days difference).
But when I'm trying to match between such dates I'm getting the original date (Oct 5th and not 15th).
For example:
SELECT STR_TO_DATE('1582-10-05', '%Y-%m-%d') = STR_TO_DATE('1582-10-15', '%Y-%m-%d')
I'm getting a false response, although you would have expected to get a true since Oct 5th actually count as Oct 15th, as we saw in the first example.
Anyone can explain what's going on here?
On documentation it is stated that, TO_DAYS and FROM_DAYS functions must be called cautiously because of the transformation you noticed. Additionally, when I inspect the source codes of MySQL, I realized that STR_TO_DATE uses similar methodology with these functions. As I understand, cutover dates are completely unsafe to store or apply operations. Documentation says; "Dates during a cutover are nonexistent.", too.
Also for the inconsistency between different servers I may have an explanation. I have 2 different machines which have MySQL installed in Istanbul, Turkey and Frankfurt, Germany. They have same setup excluding localisation settings. First one shows 1, the other one shows 11 for the date substraction query. It means (in my humble opinion) there is unexplained sections about calendar cutover & localisation on official documentation.
Please see the following results:
SELECT STR_TO_DATE('1582-10-05', '%Y-%m-%d');
# Result #1: 1582-10-15
SELECT DATE_FORMAT(STR_TO_DATE('1582-10-05', '%Y-%m-%d'), '%Y-%m-%d');
# Result #2: 1582-10-05
SELECT DATE_FORMAT(STR_TO_DATE('1582-10-15', '%Y-%m-%d'), '%Y-%m-%d');
# Result #3: 1582-10-15
SQL fiddle demo.
These indicate the problem lies in the way the 1582-10-05 date is displayed rather than how it is stored. Result #2 shows that if the DATE_FORMAT function is used instead to explicitly convert the date into the same string format then the input date is displayed. This also explains why the comparison query in the question returns false: Behind the scenes, the two stored dates are different.
As you've discovered, this quirk occurs for all dates between 1582-10-05 and 1582-10-14 inclusive, i.e. the range of dates that don't really exist: The implicit conversion to text for all of these gives a date 10 days after. So if for some reason there is a need to display dates in this range (perhaps questionable), a simple workaround is to always use the DATE_FORMAT function.
Why is
TIMESTAMPDIFF(MONTH, '2015-12-25', '2016-02-24')
giving me 1? I would expect 2016-01-25 to be 1.
My guess is that it is actually returning something like 1.999 months and it is being simply rounded down.
How can I work around this? Or is there another function to use.
I tried PERIOD_DIFF but it does not take into account days
PERIOD_DIFF(DATE_FORMAT('2016-02-24','%Y%m'),DATE_FORMAT('2015-12-25','%Y%m'))
According to the documentation, the unit for the result is an integer, in your case it will return the whole number of months between the two dates, which is one (as the second month is not yet completed).
any advice appreciated
I have as a column heading the expression =WeekdayName(weekday(fields!date.value))
This returns the day of the week, however, it is returning a day of the week one day in advance, eg when I put Monday's dates in the parameter it shows as 'Tuesday' in the report.
My question is can the above expression be tweaked to show the WeekdayName one day before, eg =WeekdayName(weekday(fields!date.value -1)) ? I tried this but got an error.
Thanks.
So you want to subtract one day from the your incoming date then you can use the
= DateAdd("d", -1, yourdateField)
This way you can subtract the any number of days from your date.
But did you try to see why it is giving the day of previous date. Do check the system date time or else check with the
=WeekdayName(weekday(Today()))
and see if it gives you the correct day of week for current date.
Weekday and weekdayname functions have both another optional argument for defining the starting day of the week.
Problem is the 2 functions don' t default this argument to the same value so depending on your server settings you should explicitly set the second argument of these functions.
No need to invoke a date function. As the weekday() function returns and integer you can offset the result and use the Mod operator to keep it in bounds:
=WeekdayName((weekday(fields!date.value)+5) Mod 7)+1)
The parenthesis are important to ensure the addition comes first.
Just for reference:
OP asked again because of the weekday offset and this is the correct provided solution.
=WeekdayName(weekday(Today())) gives me tomorrow
=WeekdayName(Weekday(Today(),FirstDayOfWeek.System))
I need current month name as default perameter name in my ssrs report. How can I get current month name using an ssrs expression?
For example "27-09-2012" would become "September"
and one more i need....
27-09-2012 to previous month name as well (August)
First question:
=MonthName(Month(Fields!datefield.Value))
Second question:
=MonthName(Month(DateAdd("m", -1, Today())))
I think the second question answer might be something like that, first converting the date to month then subtracting 1 from the month value and then converting it to month name.
Further reading:
SSRS Reports get Month name from Month Index or from date
Converting month number to month name in reporting services
OFF: I would change the date format you are using to 2012-09-27 as it works in every setting and should give you peace of mind when converting date formats.
Don't subtract 1 b/c it won't work for January.
Use this:
MonthName(Month(DateAdd("m", -1, CDate(Today))))
As a note, I tried the suggestion of =MonthName(Month(today())). What I would get is #error for whatever field the expression was in. However, =MonthName(str(Month(today()))) worked for me. I am unsure of whether or not the MonthName method changed to require a string or if it is some issue with my program. Just figured I would post this in case anyone else was having the same issue.
For Previous Month i found universal way : =MonthName(Month(CDate(Today()))-1,False) for SEPTEMBER (Full Month Name) 'OR'
=MonthName(Month(CDate(Today()))-1,True) for SEP (Short Month Name)