I want to display the data from now until one week ago.
i have query uses the where statement as
WHERE date
BETWEEN
(CURRENT_DATE() - INTERVAL 1 WEEK)
AND
CURRENT_DATE();
It shows data for past 1 week but does not include today. What am i doing wrong here?
current_date will wait till midnight i.e. till the day/date is over. Use now() to display data till the current timestamp.
Make sure the datatypes (date/datetime/timestamp) are consistent. Cast them where ever required.
Important: Avoid using operators with the datatype they are not meant for. I see, you're using - (minus) with date/timestamp. A better way would be : subdate(now(), interval 1 week)
Related
For some reason, I cannot wrap my head around the syntax and logic for this problem.
My most recent iteration of the code looks like this.
SELECT DATE_ADD(start, INTERVAL 15 MINUTE) >= NOW();
While this is true for the condition if start+15 mins is greater than NOW()
it is also true for the condition if start is older than NOW(). This the part of the code I am having an issue with.
Then I know I can add some operator AND, >= or, <= with respect to an upcoming timestamp called start or NOW() and also use DATE_ADD or DATE_SUB but I can not seem to find the correct combination of the above if NOW() is within an interval leading up into upcoming timestamp.
If you want to know if we are within 15 minutes of the start time (but only if we're before the time) this will work:
NOW() BETWEEN start - INTERVAL 15 minute AND start
SELECT DATE(STR_TO_DATE(CONCAT(CONCAT(YEAR('$uDate1'), week), ' Monday'), '%X%V %W') +
INTERVAL (7 - DAYOFWEEK(STR_TO_DATE(CONCAT(CONCAT(YEAR('$uDate1'), week), ' Monday'),
'%X%V %W'))) DAY)
as week_end_date
What this statement does is take the date I give it ($uDate1) and give me the week end date (Saturday) of that week. This works well and I am happy with it, kinda.
I was wondering if there were some things I missed that would either make this more efficient or even if I missed some shortcuts to this.
Any suggestions for me?
week >= WEEK('$uDate1') AND week <= WEEK('$uDate2')
This is in my WHERE clause. So basically if I use this...
DATE('$uDate1', INTERVAL 7 - DAYOFWEEK('$uDate1') DAY)
...then it returns the same day for all records. I need it to be able to go over a span of a few weeks.
I have a column in my database named 'week'. It simply stores an INT that corresponds to the week of the year. (ex. 21 for this week)
I then have two date picker boxes. The output gets the week end date based of each week that is BETWEEN and INCLUDES the days chosen.
5/10/2016 & 5/26/2016 outputs 5/14/2016, 5/21/2016, 5/28/2016
What gets exported to CSV file looks something like this..
WEEK END, LAST NAME, FIRST NAME, ...
5/10/2016, Smith, John, ...
5/26/2016, Jones, James, ...
It outputs anyone who had hours during the week, with the week end date.
SIDE NOTE: I do appreciate the comments and help. I don't want anyone to stress over this though! Just curious if better way. :)
I am not sure why your current SQL is so complicated.
You say it is just to take a date and give me the week end date (Saturday) of that week .
How you are doing this at the moment is:-
Yours is taking the year
Adding the week of the year (I assume - should be WEEK('$uDate1') I think)
Adding on the day as a string (so for example for today it would be 2016 21 Monday )
Changing that string back to a date a datetime value
Converting that datetime value back to a date.
Then taking the year again
Adding the week of the year again
Getting the day of the week of the resulting string. As you have concatenated Monday on to the date then the day of the week will always be 2.
Taking that resulting day of the week and subtracting it from 7. As the day of the week will always be 2 this will always result in 5
Adding on the day as a string (so for example for today it would be 2016 21 Monday ).
This value is then added on to the previously calculated date, taking the Monday date and adding 5 days.
My suggestion was to just use:-
DATE_ADD($uDate1, INTERVAL 7 - DAYOFWEEK($uDate1) DAY)
which is far simpler, and appears to cover your requirements.
EDIT
Looking at your edit you want a list of all the Saturdays for weeks all or partially between 2 passed dates.
If so I think the following will do it and hopefully be more efficient as there is no need to translate dates to and from string. Note it relies on your week table to add to the date, hence only copes with date ranges of up to that many weeks.
SELECT DATE_ADD(DATE_ADD('$uDate1', INTERVAL 7 - DAYOFWEEK('$uDate1') DAY), INTERVAL `week` WEEK) AS aDate
FROM `week`
HAVING aDate BETWEEN '$uDate1' AND DATE_ADD('$uDate2', INTERVAL 7 - DAYOFWEEK('$uDate2') DAY)
ORDER BY aDate
As I mentioned in comment you should move this transformation from mysql query to php code.
I see no reason to do this calculation on mysql side.
http://ideone.com/48zLvF
$week_day = intval(date('w',$uDate1));
if ($week_day<6) {
$end_of_week = $uDate1+(86400*(6-$week_day));
} else {
$end_of_week = $uDate1;
}
I have a column with timestamp, contain example value "2014-04-16 18:00:00","2014-04-17 18:00:00"....
Now, if I will call a page before "2014-04-17 12:00:00" I need this value-"2014-04-16 18:00:00"
And if I call my page after "2014-04-17 12:00:00" I need this value "2014-04-17 18:00:00".
I think my question is very complicated to understand, having complications in date & times, please check date & time properly.
I want to fetch this data from DB in mysql, The page I was saying is that where I'm going to add your mysql query.
Thanx in advance
Generalising what your asking for a bit the following will return dates from the previous day if it's before noon and dates from today if it's after noon:
SELECT date_column
FROM yourTable
WHERE DATE(DATE_SUB(NOW(), INTERVAL 12 HOUR)) = DATE(date_column);
Edit:
The WHERE clause First gets the current time (NOW()) and subtracts 12 hours. This wont affect the date unless the time is before 12. This means DATE_SUB(NOW(), INTERVAL 12 HOUR) gives us today if it's after noon and yesterday if it's before.
We then check if the date_column matches the date we've created (using the DATE function so that the time is ignored).
Adding some rows to the SELECT may help you see how these dates are built up.
Hi I am comparing two dates using mysql between function. My query looks like
select count(id) as total
from table
where user_id=111
and date_column BETWEEN DATE_SUB(NOW(), INTERVAL 1 DAY)
and NOW()
In between part of this query it is BETWEEN upperdate and lowerdate. It is working fine. But I went to verify this function on mysql documentation https://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html#operator_between . It says it should be
`BETWEEN LOWER AND UPPER`
Current I am doing in reverse and it is working fine but I just want to verify that is it rite and it will cause in problem in future and any hidden case.
It is working. Because:
DATE_SUB(NOW(), INTERVAL 1 DAY) -- a day less than now is yesterday
is LOWER THAN
NOW() -- it is now, means today with current time
So comparison would be like
between yes'day and today
which is valid
BETWEEN DATE_SUB(NOW(), INTERVAL 1 DAY) and NOW()
is in other words
BETWEEN yesterday AND today
So it is
BETWEEN lower AND upper
No wonder it's working :)
I have a report that is driven by a sql query that looks like this:
SELECT batch_log.userid,
batches.operation_id,
SUM(TIME_TO_SEC(ramses.batch_log.time_elapsed)),
SUM(ramses.tasks.estimated_nonrecurring + ramses.tasks.estimated_recurring),
DATE(start_time)
FROM batch_log
JOIN batches ON batch_log.batch_id=batches.id
JOIN ramses.tasks ON ramses.batch_log.batch_id=ramses.tasks.batch_id
JOIN protocase.tblusers on ramses.batch_log.userid = protocase.tblusers.userid
WHERE DATE(ramses.batch_log.start_time) > "2011-02-01"
AND ramses.batch_log.time_elapsed > "00:03:00"
AND DATE(ramses.batch_log.start_time) < now()
AND protocase.tblusers.active = 1
AND protocase.tblusers.userid NOT in ("ksnow","smanning", "dstapleton")
GROUP BY userid, batches.operation_id, date(start_time)
ORDER BY start_time, userid ASC
Since this is to be compared with the time from the current payperiod it causes an error.
Our pay periods start on a Sunday, the first pay period was 2011-02-01 and our last pay period started the 4th of this month. How do I put that into my where statement to strip the most recent pay period out of the query?
EDIT: So now I'm using date_sub(now(), INTERVAL 2 WEEK) but I really need a particular day of the week(SUNDAY) since it is wednesday it's chopping it off at wednesday.
You want to use DATE_SUB, and as an example.
Specifically:
select DATE_SUB(curdate(), INTERVAL 2 WEEK)
gets you two weeks ago. Insert the DATE_SUB ... part into your sql and you're good to go.
Edit per your comment:
Check out DAYOFWEEK:
and you can do something along the lines of:
DATE_SUB(DATE_SUB(curdate(), INTERVAL 2 WEEK), INTERVAL 2 + DAYOFWEEK(curdate()) DAY)
(I don't have a MySql instance to test it on .. but essentially subtract the number of days after Monday.)
Question isn't quite clear, especially after the edit - it isn't clear now is the "pay period" two weeks long or do you want just last two weeks back from last sunday? I assume that the period is two weeks... then you first need to know how many days the latest period (which you want to ignore, as it isn't over yet) has been going on. To get that number of days you can use expression like
DATEDIFF(today, FirstPeriod) % 14
where FirstPeriod is 2011-02-01. And now you strip that number of days from the current date in the query using date_sub(). The exact expression depends on how the period is defined but you should get the idea...