Two of my EC2 instances have 3 IPs each. I managed to successfully grab a list of JSON objects:
aws ec2 describe-instances | jq '.Reservations[] | .Instances[] | (.Tags | { "iname": ( map ( select(.Value | contains("my-vm")))[] | .Value ) } ) + ( { "ip": ( .NetworkInterfaces[].PrivateIpAddress) } )' | jq -s .
Giving me the following result:
[
{
"iname": "my-vm-b",
"ip": "10.11.2.145"
},
{
"iname": "my-vm-b",
"ip": "10.11.1.146"
},
{
"iname": "my-vm-b",
"ip": "10.11.10.144"
},
{
"iname": "my-vm-a",
"ip": "10.11.1.9"
},
{
"iname": "my-vm-a",
"ip": "10.11.10.125"
},
{
"iname": "my-vm-a",
"ip": "10.11.2.85"
}
]
and then I added to the command the following:
... | jq ' group_by(.iname)[] | {(.[0].iname): [.[] | .ip]}' | jq -s .
To finally get the list of objects the way I wanted:
[
{
"my-vm-a": [
"10.11.1.9",
"10.11.10.125",
"10.11.2.85"
]
},
{
"my-vm-b": [
"10.11.2.145",
"10.11.1.146",
"10.11.10.144"
]
}
]
Notice I had to call jq like 4 times. I know I must be doing something wrong so I was wondering if I could do it with a single jq call.
Thanks!
You can easily eliminate the calls to jq -s by wrapping expressions as appropriately in square brackets, or maybe better, using map.
For example, your last pair of jq calls can be simplified to:
jq 'group_by(.iname) | map({(.[0].iname): [.[] | .ip]})'
The following should allow you to reduce the four calls to one:
[.Reservations[]
| .Instances[]
| (.Tags | { "iname": ( map ( select(.Value | contains("my-vm")))[] | .Value ) } )
+ ( { "ip": ( .NetworkInterfaces[].PrivateIpAddress) } ) ]
| group_by(.iname) | map({(.[0].iname): [.[] | .ip]})
However, I would advise against using contains here, unless you fully understand the complications.
Before you go into trying to simplify your jq calls, I think it would be more beneficial to first look at the source data and how it relates to the result you want.
Ignoring a lot of the other details in the data, I think we can agree that your data looks sorta like this:
{
"Reservations": [
{
"Instances": [
{
"NetworkInterfaces": [
{ "PrivateIpAddress": "10.11.2.145" },
{ "PrivateIpAddress": "10.11.1.146" },
{ "PrivateIpAddress": "10.11.10.144" }
],
"Tags": [
{ "Key": "Name", "Value": "my-vm-b" }
]
},
{
"NetworkInterfaces": [
{ "PrivateIpAddress": "10.11.1.9" },
{ "PrivateIpAddress": "10.11.10.125" },
{ "PrivateIpAddress": "10.11.2.85" }
],
"Tags": [
{ "Key": "Name", "Value": "my-vm-a" }
]
}
]
}
]
}
With something that looks like this, your jq query can simply be:
[.Reservations[].Instances[] |
{
(.Tags|from_entries.Name): [.NetworkInterfaces[].PrivateIpAddress]
}
]
No intermediate results needed. Just a few things of note here.
The tags are already an array of key/value pairs, you can easily read values from here converting them to an object first using from_entries
You are selecting instances based on an existence of a tag value containing "my-vm". I'm not sure you even need to do this, I don't know what your data looks like but they are likely in a fixed name so you should just use that name.
Related
I have a GraphQL schema file with deeply nested object metadata that I'd like to extract into arrays of child properties. The original file is over 75000 lines long but I was able to successfully extract the Types & fields for each object using this command:
jq '.data.__schema.types[] | {name: .name, fields: .fields[]?.name?}' schema.json > output.json
Output:
{
"name": "UsersConnection",
"fields": "nodes"
}
{
"name": "UsersConnection",
"fields": "edges"
}
{
"name": "UsersConnection",
"fields": "pageInfo"
}
{
"name": "UsersConnection",
"fields": "totalCount"
}
{
"name": "UsersEdge",
"fields": "cursor"
}
{
"name": "UsersEdge",
"fields": "node"
}
...
But the output I want looks more like this:
[{
"name": "UsersConnection",
"fields": [ "nodes", "edges", "pageInfo", "totalCount" ]
},
{
"name": "UsersEdge",
"fields": [ "cursor", "node" ]
}]
I was able to do this by comma-separating each object, surrounding the output with { "data": [ -OUTPUT- ]} & the command:
jq 'map(. |= (group_by(.name) | map(first + {fields: map(.fields)})))' output.json > output2.json
How can I do this with a single command?
Assuming .data.__schema.types is an array, and so is .fields, you could try map in both cases:
.data.__schema.types | map({name: .name, fields: (.fields | map(.name))})
I totally missed that I put the fields object inside brackets like this:
jq '.data.__schema.types[] | {name: .name, fields: [.fields[]?.name?]}'
Keeping this up for posterity in case someone else is trying to do the same thing
Update: I was able to get a cleaner, comma-separated result like this:
jq 'reduce .data.__schema.types[] as $d (null; .[$d.name] += [$d.fields[]?.name?])'
I am trying to use jq to filter the latest Docker Image version from a curl output. So far I could come up to here:
Command
curl https://docker.hub.example.net/api/v1.0/projects/myapp/repositories/artifacts | jq -r '(.[] | {digest, tags})'
Output:
Note: Some sub-keys have been removed and real values have been replaced with some example values in the output.
{
"digest": "sha256:.......",
"tags": [
{
"artifact_id": 123456,
"name": "latest",
},
{
"artifact_id": 123456,
"name": "1.0.1234567890.ab12cd3",
}
]
}
{
"digest": "sha256:.......",
"tags": [
{
"artifact_id": 234567,
"name": "1.0.1234567890.bc23de4",
}
]
}
{
"digest": "sha256:.......",
"tags": [
{
"artifact_id": 345678,
"name": "1.0.1234567890.cd34ef5",
}
]
}
As you can see in the above output, only one digest has two tags with the same contents except the name sub-key values are different. One is "name": "latest" and the other is the image version (e.g. "name": "1.0.1234567890.ab12cd3"). Other digests have only one tag.
I need to get the image version from the digest that has the other tag with "name": "latest". I prefer to avoid scripted loop, if possible, and just use the jq options.
How can I achieve this?
Use select in combination with any:
curl ... | jq -r '
.[] | select(.tags | any(.name == "latest"))
| first(.tags[] | select(.name != "latest")).name
'
1.0.1234567890.ab12cd3
Demo
I'm new to jq and I have a json response from a get request that looks like:
[
{
"vs": {
"name": "vs_name",
"pool": {
"p_id_name": "XYZ",
"members": [
{
"m_name": "XXX1",
"id_name": "YYY1",
"address": "ZZZ1"
},
{
"m_name": "XXX2",
"id_name": "YYY2",
"address": "ZZZ2"
}
]
}
}
}
]
I'm trying to get an output that looks like (repating the p_id_name for each m_name):
XYZ, XXX1
XYZ, XXX2
I tried the following but it didn't work.
$ jq '.[].vs.pool|[.members[].m_name,.p_id_name]' file
[
"XXX1",
"XXX2",
"XYZ"
]
Between square brackets, all products are collected into a single array. String interpolation doesn't have this effect.
.[].vs.pool | "\(.p_id_name), \(.members[].m_name)"
Online demo
If you want to output arrays, you need to create a separate array for each m_name.
.[].vs.pool | [.p_id_name] + (.members[] | [.m_name])
Online demo
I have to aggregate a few JSON results from a site. Because the site has a query concurrency limit and the queries timeout, the time frame for the queries have to be divided. So I am left with a JSON as follows:
{
"results": [
[
{
"field": "AccountId",
"value": "11352"
},
{
"field": "number_of_requests",
"value": "241398"
}
],
[
{
"field": "AccountId",
"value": "74923"
},
{
"field": "number_of_requests",
"value": "238566"
}
]
],
"statistics": {
"recordsMatched": 502870.0,
"recordsScanned": 165908292.0,
"bytesScanned": 744173091162.0
},
"status": "Complete"
}
{
"results": [
[
{
"field": "AccountId",
"value": "11352"
},
{
"field": "number_of_requests",
"value": "185096"
}
]
],
"statistics": {
"recordsMatched": 502870.0,
"recordsScanned": 165908292.0,
"bytesScanned": 744173091162.0
},
"status": "Complete"
}
I need to aggregate the results, match the values to the number of requests and print out the result in descending Order.
Desired Output:
AccountID : Number of Requests
11352 : 426494
74923 : 238566
Current Output:
AccountID : Number of Requests
11352 : 241398
11352 : 185096
74923 : 238566
The jq query I am running currently takes the file name as ResultDir:
list=$(jq -S '.results[] | map( { (.field) : .value} ) | add ' $ResultsDir |
jq -s -c 'sort_by(.number_of_requests|tonumber) | reverse[] ' |
jq -r '"\(.AccountId) : \(.number_of_requests)"')
How do I combine the results of the same accounts before printing it out? The results also need to be in descending order of number of requests.
When possible, it's generally advisable to minimize the number of calls to jq. In this case, it's easy enough to achieve the desired output with just one call to jq.
Assuming the input is a valid stream of JSON objects along the lines shown in the Q, the following produces the desired output:
jq -nr '
[inputs | .results[] | map( { (.field) : .value} ) | add]
| group_by(.AccountId)
| map([.[0].AccountId, (map(.number_of_requests|tonumber) | add)])
| sort_by(.[1]) | reverse
| .[]
| join(" : ")
'
I have a response from curl in a format like this:
[
{
"list": [
{
"value": 1,
"id": 12
},
{
"value": 15,
"id": 13
},
{
"value": -4,
"id": 14
}
]
},
...
]
Given a mapping between ids like this:
{
"12": "newId1",
"13": "newId2",
"14": "newId3"
}
I want to make this:
[
{
"list": {
"newId1": 1,
"newId2": 15,
"newId3": -4,
}
},
...
]
Such that I get a mapping from ids to values (and along the way I'd like to remap the ids).
I've been working at this for a while and every time I get a deadend.
Note: I can use Shell or the like to preform loops if necessary.
edit: Here's one version what I've developed so far:
jq '[].list.id = ($mapping.[] | select(.id == key)) | del(.id)' -M --argjson "mapping" "$mapping"
I don't think it's the best one, but I'm looking to see if I can find an old version that was closer to what I need.
[EDIT: The following response was in answer to the question when it described (a) the mapping as shown below, and (b) the input data as having the form:
[
{
"list": [
{
"value": 1,
"id1": 12
},
{
"value": 15,
"id2": 13
},
{
"value": -4,
"id3": 14
}
]
}
]
END OF EDIT]
In the following I'll assume that the mapping is available via the following function, but that is an inessential assumption:
def mapping: {
"id1": "newId1",
"id2": "newId2",
"id3": "newId3"
} ;
The following jq filter will then produce the desired output:
map( .list
|= (map( to_entries[]
| (mapping[.key]) as $mapped
| select($mapped)
| {($mapped|tostring): .value} )
| add) )
There's plenty of ways to skin a cat. I'd do it like this:
.[].list |= reduce .[] as $i ({};
($i.id|tostring) as $k
| (select($mapping | has($k))[$mapping[$k]] = $i.value) // .
)
You would just provide the mapping through a separate file or argument.
$ cat program.jq
.[].list |= reduce .[] as $i ({};
($i.id|tostring) as $k
| (select($mapping | has($k))[$mapping[$k]] = $i.value) // .
)
$ cat mapping.json
{
"12": "newId1",
"13": "newId2",
"14": "newId3"
}
$ jq --argfile mapping mapping.json -f program.jq input.json
[
{
"list": {
"newId1": 1,
"newId2": 15,
"newId3": -4
}
}
]
Here is a reduce-free solution to the revised problem.
In the following I'll assume that the mapping is available via the following function, but that is an inessential assumption:
def mapping:
{
"12": "newId1",
"13": "newId2",
"14": "newId3"
} ;
map( .list
|= (map( mapping[.id|tostring] as $mapped
| select($mapped)
| {($mapped): .value} )
| add) )
The "select" is for safety (i.e., it checks that the .id under consideration is indeed mapped). It might also be appropriate to ensure that $mapped is a string by writing {($mapped|tostring): .value}.