Query based on 2 tables where duplicate id's amounts are calculated - mysql

Question

I Have 2 tables, table ONE consist of an category_id where each has its own not unique name attribute and each product_id would be unique in this table with no duplicates.
Table TWO consist of unique product_id just like table ONE and rank based on the biggest amount.
Table : ONE
+--------+---------+------------+--------+
| brd_id | cat_id | product_id | name |
+--------+---------+------------+--------+
| 1 | 1 | 333 | w |
| 2 | 1 | 444 | w |
| 3 | 1 | 555 | w |
| 4 | 2 | 666 | y |
| 5 | 2 | 777 | y |
| 6 | 3 | 888 | t |
+--------+---------+------------+--------+
Table: TWO
+--------+---------+------------+--------+--------+
| new_id | type | product_id | rank | amount |
+--------+---------+------------+--------+--------+
| 1 | all | 333 | 1 | 80 |
| 2 | all | 444 | 2 | 70 |
| 3 | all | 555 | 3 | 60 |
| 4 | all | 666 | 4 | 50 |
| 5 | all | 777 | 5 | 40 |
| 6 | all | 888 | 6 | 30 |
+--------+---------+------------+--------+--------+
What i want is to show name from table ONE only once based on the amount from table TWO WHERE in table ONE product_id has the same cat_id.
This i was able to achieve using this query basically straight from database so fields differ:
SELECT DISTINCT `cat`.`brand_name`
FROM `ps_product_brand` AS `cat`
INNER JOIN `ps_product_custom_statistics_weekly` AS `cat_p`
ON `cat_p`.`id_product` = `cat`.`id_product`
WHERE `cat_p`.`type` LIKE '%all%'
AND `cat_p`.`rank` <= 16
ORDER BY `cat_p`.`rank` ASC
PROBLEM
I get duplicate names, so i used DISTINCT which in the end ignores the duplicate values.
I want to calculate the amount where the product_id from table ONE is IN table TWO AND where they have the same category_id in table ONE.
EXPECTED OUTPUT
+---------+--------+
| cat_id | name | amount
+---------+--------+
| 1 | w | 210
| 2 | y | 90
| 3 | t | 30
+--------+---------+
Hope it makes sense. THANKS

Answer 1

I don't have a fiddle to work with, but I think this is right.
It MIGHT have typos.
The general idea is that we do the distinct FIRST nest it. Then, once we get the distinct, then we get the SUM of the distinct elements from the secondary table. The reason we do it this way is because otherwise the SUM (if done in the inside) would join multiple records and get an amount that is too high.
SELECT A.CAT_ID, A.BRAND_NAME,
(SELECT SUM(AMOUNT) FROM ps_product_custom_statistics_weekly P WHERE P.ID_PRODUCT=A.ID_PRODUCT) FROM
(
SELECT DISTINCT `cat`.`cat_id`, `cat`.`brand_name`, `cat_p`.`rank`
FROM `ps_product_brand` AS `cat`
INNER JOIN `ps_product_custom_statistics_weekly` AS `cat_p`
ON `cat_p`.`id_product` = `cat`.`id_product`
WHERE `cat_p`.`type` LIKE '%all%'
AND `cat_p`.`rank` <= 16
GROUP BY `cat`.`cat_id`, `cat`.`brand_name`
) A
ORDER BY A.RANK

Answer 2

Try the following:
SELECT `cat`.`brand_name`, `cat_p`.`amount`, SUM(`cat_p`.`amount`) AS `sum_amount`
FROM `ps_product_brand` AS `cat`
INNER JOIN `ps_product_custom_statistics_weekly` AS `cat_p` ON `cat_p`.`id_product` = `cat`.`id_product`
WHERE `cat_p`.`type` LIKE '%all%' AND `cat_p`.`rank` <= 16
GROUP BY `cat`.`brand_name`
ORDER BY `sum_amount` DESC, `cat`.`brand_name`
Note the difference in numbers between amount and sum_amount where the duplicates are. You might have to increase the rank and possibly add LIMIT to the end.