Custom auto-increment column - mysql

Question

I am making a C# project in which I need help to generate and insert fields like below on MySQL database.
161013001
Where:
16 is Year,
10 is Month,
13 is day
and 001 is auto-increment numbers that reset each days.
Eg.
161012-001
161012-002
161012-002
161013-001
161013-002
161014-001
161014-002
161014-003
161014-004
161014-005
161015-001
please guide me how to make this that ID reset each day and start from 1 after every day.

Answer 1

Here both MySQL & SQL Server Implementation are added,
MySQL:
DROP TEMPORARY TABLE TempDate;
CREATE TEMPORARY TABLE TempDate(
Id VARCHAR(50),
Comments VARCHAR(50)
);
INSERT INTO TempDate(Id,Comments)
SELECT '190630-001', '1'
UNION
SELECT '190630-002', '2'
UNION
SELECT '190701-001', '1'
UNION
SELECT '190701-002', '2'
UNION
SELECT '190701-003', '3';
SET #v_ToDay = '';
SET #v_ToDay = (SELECT date_format(current_date(),'%y%m%d'));
SET #v_TotalByDay = '' ;
SET #v_TotalByDay =(
SELECT CONCAT('000',CAST(CASE WHEN COUNT(1) = 0 THEN 1 ELSE COUNT(1)+1 END as CHAR))
FROM TempDate
WHERE LEFT(Id,6) = #v_ToDay);
SELECT CONCAT(#v_ToDay, '-', CASE WHEN CHAR_LENGTH(RTRIM(#v_TotalByDay)) > 3 THEN RIGHT(#v_TotalByDay,3) ELSE #v_TotalByDay END) as NewIdColumn
SQL Server:
DECLARE #TempDate TABLE(
Id NVARCHAR(50),
Comments NVARCHAR(MAX)
)
INSERT INTO #TempDate(Id,Comments)
SELECT '190630-001', '1'
UNION
SELECT '190630-002', '2'
UNION
SELECT '190701-001', '1'
UNION
SELECT '190701-002', '2'
UNION
SELECT '190701-003', '3'
DECLARE #ToDay NVARCHAR(20) = (SELECT CONVERT(NVARCHAR(6), GETDATE(), 12))
DECLARE #TotalByDay NVARCHAR(20) = ''
SELECT #TotalByDay = '000' + CAST(CASE WHEN COUNT(1) = 0 THEN 1 ELSE COUNT(1)+1 END as NVARCHAR(20) )
FROM #TempDate
WHERE LEFT(Id,6) = #ToDay
SELECT #ToDay + '-' + CASE WHEN LEN(#TotalByDay) > 3 THEN RIGHT(#TotalByDay,3) ELSE #TotalByDay END as NewIdColumn

Answer 2

my situation is little more different then this question ....
i have a legacy database (it's not operational only use for reporting
purpose..)
in this DB transaction table was a auto increment tranx id column.
like 1, 2, 3 ...... but now our new report need meaningful tranx id
(yyMMDD<count of that day>) like this question. so actually i need a
select query to solve this problem.
with the help of #Khairul 's logic i solve my problem ....
i share my solution for other's help....
SELECT
trnx_id, account_id, pay_amount,counter_id, trantime, trandate
FROM(
SELECT
#id:=IF(#prev != t.trandate, #rownum:=1, #rownum:=#rownum+1)
,#prev:=t.trandate
,CONCAT(
SUBSTR(YEAR(t.`trandate`),3) -- year
,IF(LENGTH(MONTH(t.`trandate`))=1,CONCAT('0',MONTH(t.`trandate`)),MONTH(t.`trandate`)) -- month
,IF(LENGTH(DAY(t.`trandate`))=1,CONCAT('0',DAY(t.`trandate`)),DAY(t.`trandate`)) -- day
,IF(LENGTH(#id)=1,CONCAT('000',#id),IF(LENGTH(#id)=2,CONCAT('00',#id),IF(LENGTH(#id)=3,CONCAT('0',#id),#id))) -- count
) AS trnx_id
,t.*
FROM tax_info t ORDER BY t.`trandate`, t.`trantime`
) AS te
and my query result is ..........
After solving my problem i try to solve this question .......
for this i use a trigger for input auto increment custom column ...
my code is below , here my payment column has a custom tranx id ....
DELIMITER $$
DROP TRIGGER tranxidGeneration$$
CREATE
TRIGGER tranxidGeneration BEFORE INSERT ON payment
FOR EACH ROW BEGIN
DECLARE v_tranx_id_on INT;
-- count total row of that day
select IFNULL(COUNT(tranx_id),0)+1 Into v_tranx_id_on from payment where SUBSTR(tranx_id,1,6) = DATE_FORMAT(NOW(), "%y%m%d");
-- set custom generate id into tranx_id column
SET NEW.tranx_id := CONCAT(DATE_FORMAT(NOW(), "%y%m%d"),LPAD(v_tranx_id_on,4,0)) ;
END;
$$
DELIMITER ;