Why data does not match when JOIN same table? [closed] - mysql

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I'm trying to display the table like this
Desired Result:
With the conditions:
tgl1, kondisi_1, kondisi_2, kondisi_3, kondisi_4 is latest condition group by kd_item
tgl2, kond1, kond2, kond3, kond4 is latest data where date <= CURDATE()-INTERVAL 7 DAY group by kd_item
SQL:
http://sqlfiddle.com/#!9/661f7/2
I try to write the query like this,
Query:
SELECT a.kd_item, MAX(a.tanggal) as tgl1, a.kondisi_1, a.kondisi_2, a.kondisi_3, a.kondisi_4,
-- I know min is not the right query
MIN(b.tanggal) as tgl2, b.kondisi_1 as kond1, b.kondisi_2 as kond2, b.kondisi_3 as kond3, b.kondisi_4 as kond4
FROM status_item as a
LEFT JOIN status_item as b ON a.kd_item = b.kd_item
GROUP BY a.kd_item LIMIT 10
When I am joining same table, with the above query, why is the displayed data not related with the date?
How to display date with condition latest date where date less then or equal with 7 days ago?
How to display point 2 at left side of the table?

Answer 1

you should select the max date, join with the data for get column non involved in group by and then join the two different query toghter
select * from (
select a.kd_item, a.tanggal as tgl1, a.kondisi_1, a.kondisi_2, a.kondisi_3, a.kondisi_4
from status_item a
inner join (
SELECT kd_item, MAX(tanggal) as max_tanggal
FROM status_item
group by kd_item
) t1 on t1.max_tanggal = a.tanggal and t1.kd_item = a.kd_item
) t3
inner join (
select b.kd_item, b.tanggal as b_tgl1, b.kondisi_1 as b_kondisi_1, b.kondisi_2 as b_kondisi_2 , b.kondisi_3 as b_kondisi_3, b.kondisi_4 as b_kondisi_4
from status_item b
inner join (
SELECT kd_item, MAX(tanggal) as max_tanggal
FROM status_item
where tanggal <= date_sub(CURDATE(), INTERVAL 7 DAY )
group by kd_item
) t2 on t2.max_tanggal = b.tanggal and t2.kd_item = b.kd_item
) t4 on t3.kd_item= t4.kd_item

Answer 2

Is this what you are looking for?
select
a.kd_item,
a.tanggal as tgl1,
a.kondisi_1,
a.kondisi_2,
a.kondisi_3,
a.kondisi_4,
b.tanggal as tgl2,
b.kondisi_1 as kond1,
b.kondisi_2 as kond2,
b.kondisi_3 as kond3,
b.kondisi_4 as kond4
from
status_item as a
left join
status_item as b
on
a.kd_item = b.kd_item and
b.tanggal <= date_sub(a.tanggal, interval 7 day);
The results are:
+---------+------------+-----------+-----------+-----------+-----------+------------+-------+-------+-------+-------+
| kd_item | tgl1 | kondisi_1 | kondisi_2 | kondisi_3 | kondisi_4 | tgl2 | kond1 | kond2 | kond3 | kond4 |
+---------+------------+-----------+-----------+-----------+-----------+------------+-------+-------+-------+-------+
| 1 | 2017-10-22 | 4 | 0 | 0 | 0 | 2017-10-07 | 3 | 0 | 1 | 0 |
| 1 | 2017-10-17 | 3 | 1 | 0 | 0 | 2017-10-07 | 3 | 0 | 1 | 0 |
| 2 | 2017-12-22 | 3 | 0 | 1 | 0 | 2017-12-12 | 2 | 1 | 0 | 1 |
| 2 | 2017-12-22 | 3 | 0 | 1 | 0 | 2017-10-22 | 4 | 0 | 0 | 0 |
| 2 | 2017-12-12 | 2 | 1 | 0 | 1 | 2017-10-22 | 4 | 0 | 0 | 0 |
| 3 | 2017-12-12 | 4 | 0 | 0 | 0 | 2017-10-22 | 1 | 1 | 1 | 1 |
| 8 | 2017-12-06 | 4 | 0 | 0 | 0 | 2017-11-28 | 0 | 0 | 4 | 0 |
| 1 | 2017-10-07 | 3 | 0 | 1 | 0 | null | null | null | null | null |
| 2 | 2017-10-22 | 4 | 0 | 0 | 0 | null | null | null | null | null |
| 3 | 2017-10-22 | 1 | 1 | 1 | 1 | null | null | null | null | null |
| 4 | 2017-10-22 | 4 | 0 | 0 | 0 | null | null | null | null | null |
| 5 | 2017-10-27 | 4 | 0 | 0 | 0 | null | null | null | null | null |
| 5 | 2017-10-22 | 3 | 0 | 1 | 0 | null | null | null | null | null |
| 6 | 2017-10-22 | 4 | 0 | 0 | 0 | null | null | null | null | null |
| 7 | 2017-10-22 | 4 | 0 | 0 | 0 | null | null | null | null | null |
| 8 | 2017-11-28 | 0 | 0 | 4 | 0 | null | null | null | null | null |
+---------+------------+-----------+-----------+-----------+-----------+------------+-------+-------+-------+-------+
16 rows in set (0.00 sec)
For point 3 in your question, you could add
date_sub(a.tanggal, interval 7 day)
as the first result column:
select
date_sub(a.tanggal, interval 7 day) as week_ago,
a.kd_item,
a.tanggal as tgl1,
...