This question already has answers here:
Got error 'invalid repetition count(s)' from regexp
(1 answer)
MySql Regex Expression test
(1 answer)
Closed 5 years ago.
I'm having an issue with a query I'm running on MySQL that contains some regex, here it is: SELECT * FROM dump WHERE Hours REGEXP '^\d{337}1{8}'
When I test my regex separately it's working fine, here's some sample data that it matches with:
000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000011111111111111111111111111111111111111111111111100000000000000000000000000000000000000000000000011111111111111111111111111111111111111111111111100000000000000000000000000000000000000000000000011111111111111111111111111111111111111111111111100000000000000000000000000000000000000000000000011111111111111111111111111111111111111111111111100000000000000000000000000000000000000000000000011111111111111111111111111111111111111111111111100000000000000000000000000000000000000000000000011111111111111111111111111111111111111111111111100000000
Any idea where it fails?
Related
This question already has answers here:
using (-) dash in mysql table name
(2 answers)
Closed 9 months ago.
username:admintest
password:' or 1=1#
(and it works perfectly)
But here is the problem
username:a-dmintest
password:' or 1=1#
(and it doesnt work)
when the username have a dash it don't work
Why ?
Maybe you just dont have a user called "a-dmintest"
The dash is not a operator in SQL
This question already has an answer here:
How to match a fixed string ending with a number using regex [duplicate]
(1 answer)
Closed 2 years ago.
I'm trying to select, from mysql, some specific tables that matches a pattern.
The specific pattern I'm looking for is like 'my_table_number'. For example, my_table_436814 or my_table_35413. The thing is that there are other tables that looks like my_table_old_14353 or my_table_351434_times. I just want to filter out the ones that are my_table_number.
I have tried different patterns, but failed to get what I really need.
The most closest approach was with this:
select table_name from
information_schema.columns ca
where ca.table_name REGEXP '[0-9]$'
How can I achieve what I'm looking for?
Use
REGEXP '^my_table_[0-9]+$'
See proof
NODE
EXPLANATION
^
the beginning of the string
my_table_
'my_table_'
[0-9]+
any character of: '0' to '9' (1 or more times (matching the most amount possible))
$
before an optional \n, and the end of the string
This question already has answers here:
What special characters must be escaped in regular expressions?
(13 answers)
What is a word boundary in regex?
(13 answers)
Closed 2 years ago.
I've a table like this,
values
-------------------
male,female
PHP 30
PHP (30)
PHP ($30),CSS ($20)
PHP {$30},CSS {$20}
PHP [$30],CSS [$20]
PHP (€30),CSS (20)
I've prepared the sql like this,
SELECT mytable.values FROM mytable WHERE mytable.values REGEXP '[[:<:]]PHP ($30)[[:>:]]'
It should match one row (4th), but it's not working.
It's also not working with
() / {} / [] or any types of symbols like $ / €
I want to mention here that,
MYSQL LIKE isn't the right thing for me I think, because it won't work if we want to match male.
REGEXP is working for PHP 30 here and it's working for only strings.
Could anyone please inform me what will be the best solution to match the exact word or sentence?
Thanks in advance.
This question already has answers here:
STRING to DATE in BIGQUERY
(4 answers)
Closed 4 years ago.
I have query that uses the following:
STR_TO_DATE(JSON_EXTRACT_SCALAR(fb.p_dataforanalytics,'$.birthday'), '%m/%d/%Y'),
STR_TO_DATE(JSON_EXTRACT_SCALAR(g.p_dataforanalytics,'$.birthday'), '%Y-%m-%d'),
date_format(p_birthday, '%Y-%m-%d')
This syntax works in MySQL but it doesn't work in BigQuery.
I somehow needs to convert it using PARSE_DATE(?) but I can't find the proper syntax for this.
EDIT:
PARSE_DATE('%m/%d/%Y', JSON_EXTRACT_SCALAR(fb.p_dataforanalytics,'$.birthday') ),
PARSE_DATE('%Y-%m-%d', JSON_EXTRACT_SCALAR(g.p_dataforanalytics,'$.birthday')),
PARSE_DATE('%Y-%m-%d', p_birthday)
Dosent work.
I get:
Invalid result from parsing function
and also
on the p_birthday row:
No matching signature for function PARSE_DATE for argument types:
STRING, INT64. Supported signature: PARSE_DATE(STRING, STRING) at
[15:33]
Easy one, with standard SQL:
#standardSQL
SELECT PARSE_DATE('%m/%d/%Y', '6/22/2017')
2017-06-22
https://cloud.google.com/bigquery/docs/reference/standard-sql/functions-and-operators#supported-format-elements-for-date
JSON_EXTRACT_SCALAR should work unchanged.
This question already has answers here:
MySQL Select Query - Get only first 10 characters of a value
(3 answers)
Truncate a string to first n characters of a string and add three dots if any characters are removed
(20 answers)
Closed 6 years ago.
I need to take only three characters from the string stored in MYSQL and output must be the first 3 character and the login date of customer
I am beginner kindly help me to code in PHP.
SELECT LEFT(string , 3) , logindate FROM tbl;
Hope this will help you.