Yii2 - How to modify controller action param using a behavior? - yii2

I'm trying to change the $id param in my controller methods on the fly using beforeAction and a behavior. FYI, I'm going to use HashIds and need to convert anywhere I have a $_GET['id'] that may be hashed back into an integer.
How can I use a behavior to automatically modify my $_GET['id'] on the fly using a behavior?
An example action in my controller:
public function actionView($id){
// run code to process $id here back to integer using a behavior
echo $id; //should be an integer
}
My sample url: http://mydomain/posts/view?id=3QhLp
(Alternatively, perhaps the better way to do this is to create a custom url rule?)

you should implement a class that extends from the \yii\base\Behavior like below
<?php
namespace backend\models;
use Yii;
use yii\base\Behavior;
use yii\web\Controller;
class Transformer extends Behavior
{
public $id = '';
public function events()
{
return [Controller::EVENT_BEFORE_ACTION => 'transform']; //mounting the handler to the 'beforeAction' event on the controller.
}
public function transform()
{
$_GET['id'] = $this->id . "transformed"; //mock method here
return true;
}
}
Then in your controller, adding the code as follow:
public function behaviors()
{
return [
'transformer' => [
'class' => \backend\models\Transformer::className(), //Modify the path to your real behavior class.
'id' => Yii::$app->request->get('id'),
],
];
}
then access the Yii::$app->request->get('id') in your action, you will see the transformed url param.

Related

How to check input data in YII2 for REST API?

How to check input data in YII2 for REST API?
Here's how it's done in a non-REST API:
Controller
<?php
namespace app\controllers;
use Yii;
use yii\web\Controller;
use app\models\Index__GET;
class SiteController extends Controller
{
public function actionIndex($ch_name_url = null)
{
$model = new Index__GET();
$model->ch_name_url = $ch_name_url;
if($model->validate()){
return $this->render('index');
}
}
}
Model
<?php
namespace app\models;
use Yii;
use yii\base\Model;
class Index__GET extends Model
{
public $ch_name_url;
public function rules()
{
return [
['ch_name_url', 'trim'],
['ch_name_url', 'required'],
];
}
}
And now in the controller call $model->validate() for data validation. How to do validation incoming data in the REST API, using yii\rest\Controller and yii\rest\ActiveController?
I try but data validation fails:
I want a GET request to include two required fields.
But if I use /users/123 I will receive data, while I should not receive it, because of the model [['id', 'ch_name_url'], 'required'],.
Me need /users?id=123&ch_name_url=myname
Controller
namespace app\controllers;
use yii\rest\ActiveController;
class IndexController extends ActiveController
{
public $modelClass = 'app\models\Index__GET';
}
Model
<?php
namespace app\models;
use Yii;
use yii\db\ActiveRecord;
class Index__GET extends ActiveRecord
{
public $id;
public $ch_name_url;
public $email;
public static function tableName()
{
return 'user';
}
public function fields()
{
return ['id', 'ch_name_url', 'email'];
}
public function rules()
{
return [
[['id', 'ch_name_url'], 'required'],
];
}
}
Just create a controller extending from \yii\rest\ActiveController, then validate will run automatically. Do something like this:
namespace app\controllers;
use yii\rest\ActiveController;
class IndexController extends ActiveController
{
public $modelClass = 'app\models\Index__GET';
}
$model->validate() is called by default when you call $model->save(), but if you need to validate a model in an action, do it like you did on your question example code.
Just remember that the actions from REST are used a bit different from normal call, where actionIndex usually is not needed.
For more information, follow the original docs: REST Quick Start

Make every functions in all controller execute code some code before execute the functions without add the code in every functions in Yii2

I have a code for checking a session isset or not in Yii2, I added the code inside a function in a controller, this is the code
if(!isset($session['selectedMonth'])){
return $this->redirect(['select-period/month']);
return false;
}
I have over than 50 functions in 10 controllers, I want every function use that code, how do I can make it without put that code in every function one by one?
You could create base controller for your app, and extend all other controllers from it. Then you could add beforeAction() method in this base controller, so it will be used by all controllers that inherit from base controller:
public function beforeAction($action) {
// initialize $session here
if(!isset($session['selectedMonth'])){
Yii::$app->response->redirect(['select-period/month']);
return false;
}
return parent::beforeAction($action);
}
You can create simple behavior that will handle 'before action' event, for example:
use Yii;
use yii\base\Behavior;
use yii\base\Controller;
class RedirectBehavior extends Behavior
{
public function events()
{
return [
Controller::EVENT_BEFORE_ACTION => 'beforeAction',
];
}
public function beforeAction($event)
{
if (Yii::$app->session->has('selectedMonth')){
return;
}
Yii::$app->getResponse()->redirect(['select-period/month'])->send();
}
}
and attach it to your controllers
public function behaviors()
{
return [
'redirect' => [
'class' => RedirectBehavior::className(),
],
];
}

Having a challenge with Laravel 5.4 requests namespace

I'm trying to reference the Requests class in Laravel, I've tried so many fixes with the keyword "use" but each time I keep getting Reflection exception
that says app\path\specified doesn't exist. I'm confused.
Here is my code:`
<?php
namespace App\Http\Controllers;
//namespace App\Http\Request;
//use Illuminate\Http\Requests;
//use app\Http\Requests\ContactFormRequest;
use App\Message;
use App\Mail\SendMessage;
use Session;
//use App\Requests;
class AboutController extends Controller
{
public function create()
{
return view ('about.contact');
}
public function store(App\Requests\SendMessageRequest $request)
{
$message = $request->message;
Mail::to('myemail')
->send(new SendMessage($message, $request->email,$request->name));
THE REQUESTS CLASS
<?php
namespace App\Http\Requests;
use Illuminate\Foundation\Http\FormRequest;
class SendMessageRequest extends FormRequest
{
/**
* Determine if the user is authorized to make this request.
*
* #return bool
*/
public function authorize()
{
return false;
}
/**
* Get the validation rules that apply to the request.
*
* #return array
*/
public function rules()
{
return [
//
'name' => 'required',
'email' => 'required|email',
"message" => 'required',
];
}
}
The commented line(//) are what I've tried
SendMessageRequest is the name of my Request class.
Sorry, I canĀ“t comment your post. However can you also send the SendMessageRequest Class? Is that a subclass of the Request in Laravel?

How to extend a model that is part of an Yii2 extension?

In my application I'm using an extension (which I own and may modify). This extension has an ActiveRecord based class that I want to extend in the application with another property. Can I do this somehow? Can a Factory help anyhow or Yii behaviour?
Class in extension:
namespace extension;
/**
* #property integer $id
* #property string $name
*/
class Product extends ActiveRecord {
public static function tableName() {
return 'product';
}
/**
* #inheritdoc
*/
public function rules() {
return [
[['id', 'name'], 'required'],
[['id'], 'integer'],
[['name'], 'string'],
];
}
}
There is also a ProductController and the corresponding view files (index, create, update, view, _form) in the extension which were regularly produced with gii. I just would like to add another property $description (string, required) to the Product. A migration in order to add the required column is available.
Do I have to overwrite the model and controller class and the view files? Or is the a more elegant solution?
E.g., consider the standard object creation that takes place within the extension:
public function actionCreate() {
$model = new Product();
if ($model->load(Yii::$app->request->post()) && $model->save()) {
return $this->redirect(['view', 'language' => $model->language]);
} else {
return $this->render('create', [
'model' => $model,
]);
}
}
From my understanding I cannot influence the creation. Or am I wrong?
My impression is that I have to override everything (also the view files since the property has to be displayed) and then change controllerNamespace.
As far as extending a class, just go ahead and add the property. Your new class will have inherited everything from the parent class plus have your new property.
Concerning overwriting the generated files, there is a diff option in gii when you generate the files, so you can preview and decide what to keep and what to overwrite. Be aware that you have to merge any changes manually however.

Create behavior in yii2

I am using Advanced Template in Yii 2. I want to create behavior for user id, so I made folder in common\components\behavior and created one class,
class UidBehavior extends Behavior
{
public function encryptUid($id)
{
$id = md5($id);
return $this->$id;
}
}
then in user.php =>
'mybehavior' => [
'class' => 'common\components\behavior\UidBehavior',
'encryptUid' => 'id'
],
but error has occurred which is
Setting unknown property: common\components\behavior\UidBehavior::encryptUid
can any one help me ?
You try to init encryptUid property on User.php, Where that is not exist, You can rewrite code like this then all thing work fine:
class UidBehavior extends Behavior
{
public $encryptUid;
public function encryptUid($id)
{
$encryptUid = md5($encryptUid);
return $this->$encryptUid;
}
}
Check Refer Link