SQL join table lower date and lower id - mysql

Question

I have got the following two tables
START AND REPEAT
START
INSPECID=======SCORE
1--------------3
2--------------1
3--------------4
REPEAT
ID========INSPECID========SCORE========DATE
1---------1---------------9------------12/01/2016
2---------1---------------1------------11/01/2016
3---------2---------------2------------29/01/2016
4---------2---------------4------------01/01/2016
5---------2---------------3------------22/01/2016
6---------2---------------5------------02/01/2016
7---------2---------------1------------11/01/2016
8---------2---------------1------------01/01/2016
9---------3---------------1------------02/01/2016
10--------3---------------2------------09/01/2016
I am expecting as below
INCREASED------1
DECREASED------2
EQUAL----------0
Rules
1) Join tables by INSPECID
2) When more than 1 INSPECID is found in REPEAT table consider the score from the lower date.
3) when both INSPECID is matched and date is matched than consider the lower ID in the REPEAT table, so ID 4 and ID 8 has same date and same INPECTID but consider the ID 4 score which is 4.

Answer 1

Do a self join with REPEAT table to pick the oldest row
select s.*,a.*
from `START` s
join `REPEAT` a on s.INSPECID = a.INSPECID
left join `REPEAT` b on a.INSPECID = b.INSPECID
and case when a.DATE = b.DATE
then a.ID > b.ID
else a.DATE > b.DATE
end
where b.INSPECID is null
For conflict when INSPECID and DATE is same use CASE to choose row with lowest ID
Demo
Updated for desired result set
select t.result,count(t1.result) cnt
from (
select 'Increased' result
union
select 'Decreased' result
union
select 'Equal' result
) t
left join (
select s.score,a.id,a.DATE,
case when s.SCORE > a.SCORE
then 'Increased'
when s.SCORE < a.SCORE
then 'Decreased'
else 'Equal'
end result
from `START` s
join `REPEAT` a on s.INSPECID = a.INSPECID
left join `REPEAT` b on a.INSPECID = b.INSPECID
and case when a.DATE = b.DATE
then a.ID > b.ID
else a.DATE > b.DATE
end
where b.INSPECID is null
) t1 using(result)
group by t.result
Demo

Answer 2

This is a bit tricky. The following uses the group_concat() trick for calculating the first and last scores. It then puts these into the categories that you want:
select w.which, count(r.INSPECID)
from (select 'DECREASING' as which union all
select 'INCREASING' as which union all
select 'EQUAL' as which
) w left join
(select r.INSPECID,
(substring_index(group_concat(score order by date), ',', 1) + 0) as first_score,
(substring_index(group_concat(score order by date desc), ',', 1) + 1) as last_score
from repeat r
group by INSPECID
) r
ON (last_score > first_score and w.which = 'INCREASING') or
(last_score < first_score and w.which = 'DECREASING') or
(last_score = first_score and w.which = 'INCREASING')
group by w.which;
Note that the first table is not necessary.