Trying to get Column type in my json (laravel project), but not working ?, can anyone se whats wrong?
protected function getType()
{
return Schema::getColumnType($this->builder->getModel()->getTable() , $this->getUpdatableColums());
}
enter code here
protected function getRecords(Request $request)
{
// return $this->builder->limit($request->limit)->orderBy('id', 'asc')->get($this->getDisplayableColums());
return $this->builder
->limit($request->limit)
->orderBy('id', 'asc')
->get($this->getDisplayableColums())
->getType();
}
In your getType method you seem to be passing an array instead of a string
protected function getType()
{
return Schema::getColumnType($this->builder->getModel()->getTable() , $this->getUpdatableColums());
}
The laravel 5.5 docs say "string getColumnType(string $table, string $column)"
https://laravel.com/api/5.5/Illuminate/Database/Schema/Builder.html#method_getColumnType
You might be able to change your getType method to expect a column name. And do a loop in your code
foreach ($this->getUpdatableColumns() as $column) {
$this->getType($column);
}
Related
I need to be able to convert a hasMany() relation, which queries and return an array into a hasOne() relation which returns object|null.
Use case:
public function getItems() : \yii\db\ActiveQuery {
return $this->hasMany(Item::class, ['parent_id' => 'id']);
}
I want to create a relation which returns one specific Item object (or null if it does not exist).
I would like to do something like this:
public function getPrimaryItem() : \yii\db\ActiveQuery {
return $this->getItems()->andWhere(["primary"=>true])->toHasOne();
}
Please do not tell me to call ->one() on the original query, because that is not going to solve the problem. I need to be able to:
call $model->primaryItem and receive either Item or null
call $model->getPrimaryItem() and receive the relation's ActiveQuery
You can toggle it by multiple property of \yii\db\ActiveQuery
public function getPrimaryItem() : \yii\db\ActiveQuery {
$query = $this->getItems();
$query->multiple = false;
//Your logics
$query->andWhere(["primary"=>true])
return $query;
}
I have a customer table which has a field called 'policy_id', where policy_id points to policy table. It is a null-able field, ie. Some customers may not have a policy.
I have a relationship code like this in Customer.php
public function policy() {
return $this->hasOne('App\Models\Policy', "id", "policy_id");
}
But when I issue a search request I am getting error like this:
Illuminate\Database\Eloquent\ModelNotFoundException: No query results for model [App\Models\Policy]
If I modify the function like this:
public function policy() {
if ($this->getAttribute('policy_id')) {
return $this->hasOne('App\Models\Policy', "id", "policy_id");
} else {
return null
}
}
But I am getting an error like this:
Call to a member function getRelationExistenceQuery() on null
Here is my search code:
$c = new Customer();
return Customer::doesntHave('policy')->orWhere(function (Builder $query) use ($req) {
$query->orWhereHas('policy', function (Builder $query) use ($req) {
$p = new Policy();
$query->where($req->only($p->getFillable()))
->orWhereBetween("policy_period_from", [$req->policy_period_start_from, $req->policy_period_start_to])
->orWhereBetween("policy_period_to", [$req->policy_period_end_from, $req->policy_period_end_to])
->orWhereBetween("payment_date", [$req->payment_date_from, $req->payment_date_to]);
});
})->where($req->only($c->getFillable()))->get();
Am I missing something or are there any other ways to do this?
PS: While debugging the above search code is returning successfully, but the exception happening from somewhere inside Laravel after the prepareResponse call.
Thanks in advance.
return $this->hasOne('App\ModelName', 'foreign_key', 'local_key');
Change the order, put the foreign_key policy_id in front of id
In your Customer Model, you need to use belongsTo method:
public function policy() {
return $this->belongsTo('App\Models\Policy', "policy_id", "id");
}
And In your Policy Model, use hasOne:
public function customer() {
return $this->hasOne('App\Models\Customer', "policy_id", "id");
}
First of all, you placed the wrong params.
$this->belongsTo('App\Models\Policy', "FK", "PK");
public function policy() {
return $this->belongsTo('App\Models\Policy','policy_id', 'id');
}
And for null value of policy_id you can use withDefault();
public function policy() {
return $this->belongsTo('App\Models\Policy','policy_id', 'id')->withDefault([
'name' => 'test'
]);;
}
there's a number of problems there but can you perhaps specify the namespace and the class of both your models - Customer and Policy.
By default, the models you create with php artisan make:model will use the \App namespace e.g. \App\Customer and \App\Policy.
Just double check that.
Also, with regards to the relationship, if the Laravel conventions have been followed you could just:
In the Customer model
public function policy() {
return $this->belongsTo(Policy::class);
}
In the Policy model
public function customer() {
return $this->hasOne(Customer::class);
}
of if a multiple customers can be under one policy
public function customers() {
return $this->hasMany(Customer::class);
}
Good luck
I have some silly column names in my database, is there an easy way to alias a column name so it's always used for example:
public function columnAlias(){
return ['id'=>'ID', 'foo'=>'Bar'];
}
$model->id === $model->ID
$model->foo === $model->Bar
If it's only for accessing the attributes on the model you can write a get function.
So adding:
public function getId() {
return $this->ID;
}
public function getFoo() {
return $this->Bar;
}
will enable you to access ID and Bar like
$model->id;
$model->foo;
This works because of Yii2's use of the magic method __get: https://github.com/yiisoft/yii2/blob/master/framework/base/Component.php#L134
4 and i have a form when submitted i want to validate its fields, what happened is when i submit the form this is what it gets
(1/1) FatalErrorException
Call to a member function all() on null
This is my code below
$validator = app('validator')->make($this->request->all(),[
'postTitle' => 'required',
'postContent' =>'required']);
In laravel 5.2 this validator works well but in laravel 5.4 it returns null
can someone help me figured this thing out?
Any help is muchly appreciated. TIA
this is my full code
<?php
namespace App\Repositories;
use App\Repositories\Contracts\addPostRepositoryInterface;
use Validator;
use Illuminate\Http\Request;
use DB;
use Session;
use Hash;
class addPostRepository implements addPostRepositoryInterface{
protected $request;
// Intialize request instance
public function __contruct(Request $request){
$this->request = $request;
}
public function addPosts(Request $request){
//validate posts
echo "test";
$validator = Validator::make($request->all(), [
'postTitle' => 'required',
'postContent' =>'required',
]);
//if validation fails return error response
if($validator->fails())
return redirect()->route('get.addPost')->withErrors($validator)->withInput();
try{
}catch(\Exception $e){
return redirect()->route('get.addPost')->withErrors(["error"=>"Could not add details! Please try again."])->withInput();
}
}
public function postCreate($screen){
switch($screen){
case 'add':
return $this->addPosts($screen);
break;
}
}
//getAddPost View
public function getAddPost(){
return view('addPost');
}
}
Seems an issue with the method injection (in the constructor) or something.
You may try creating the request object on the local(addPosts()) function.
Please try below alternative solution.
<?php
namespace App\Repositories;
use App\Repositories\Contracts\addPostRepositoryInterface;
use Validator;
use DB;
use Session;
use Hash;
class addPostRepository implements addPostRepositoryInterface{
public function addPosts(Request $request){
//validate posts
$reqeust = new \Illuminate\Http\Request;
$validator = Validator::make($request->all(), [
'postTitle' => 'required',
'postContent' =>'required',
]);
//if validation fails return error response
if($validator->fails())
return redirect()->route('get.addPost')->withErrors($validator)->withInput();
try{
}catch(\Exception $e){
return redirect()->route('get.addPost')->withErrors(["error"=>"Could not add details! Please try again."])->withInput();
}
}
public function postCreate($screen){
switch($screen){
case 'add':
return $this->addPosts($screen);
break;
}
}
//getAddPost View
public function getAddPost(){
return view('addPost');
}
// REST OF THE CODE GOES HERE...
}
Given the information you gave, I will demonstrate you how to validate a request properly in Laravel 5.4
public function store(Request $request)
{
$validator = Validator::make($request->all(), [
'postTitle' => 'required',
'postContent' =>'required',
]);
if ($validator->fails()) {
return redirect('your.view')
->withErrors($validator)
->withInput();
}
// Store the blog post...
}
This will successfully validate the request for you wherever need be. If the validation fails, you will be forwarded to your view with the according errors.
Make sure you use Validator; on top of your file.
For more information, you can read up on https://laravel.com/docs/5.4/validation
is there any reason eloquent $casts wouldnt be working?
I am storing json, json column type, and
protected $casts = [
'fields' => 'array'
];
But..
\App\Lead::find(1)->fields
still returns json
"{"first_name":"Brian","last_name":"Dillingham","email":"brian#gmail.com"}"
Doesn't even work when I mutate
public function getFieldsAttribute($value)
{
return json_decode($value, true);
}
But works when I
dd(json_decode(\App\Lead::find(1)->fields, true));
Just type cast it from your mutator function:
public function getFieldsAttribute($value)
{
return (array) json_decode($value, true);
}