Is it possible to partially update rows using sequelize? - mysql

Suppose I have a table like this:
and an array of objects which contains [
{ID: '0', Name: 'Leo', Age: 21, CurrentState: 5},
{ID: '1', Name: 'George', Age: 26, , CurrentState: 6},
{ID: '2', Name: 'Diana', Age: 27, , CurrentState: 4}
].
How can I update the columns ID, Name, Age, and CurrentState without affecting the values of IsAdmin column?
If I run the following code
Table.bulkCreate([
{ID: '0', Name: 'Leo', Age: 21, CurrentState: 5},
{ID: '1', Name: 'George', Age: 26, , CurrentState: 6},
{ID: '2', Name: 'Diana', Age: 27, , CurrentState: 4}
], {
updateOnDuplicate: true
})
All the values of IsAdmin of the updated rows will be set to FALSE, which is its default value.
How can I avoid this problem?

Just passe an array of only the attributes that need to be updated
Table.bulkCreate([
{ID: '0', Name: 'Leo', Age: 21, CurrentState: 5},
{ID: '1', Name: 'George', Age: 26, , CurrentState: 6},
{ID: '2', Name: 'Diana', Age: 27, , CurrentState: 4}
], {
updateOnDuplicate: ['Name','CurrentState']
})
options.updateOnDuplicate
Array
optional
Fields to update if row key already exists (on duplicate key update)? (only supported by mysql). By default, all fields are updated.

Related

trying to group by artist using Sequelize and NodeJs

I have a simple Mysql table like the following fields:
Id, songName, ArtistName, siglosID
example data:
1 My Way Frank Sinatra 1
2 Big Balls ACDC 2
3 New York Frank Sinatra 3
4 Highway To Hell ACDC 4
I want to return an object to return to graphql where data is grouped by artistName
something like the following:
[ artistName: 'ACDC':[
{ id: 2, songName: 'Big Balls', artistName: 'ACDC', siglosId: '2' },
{ id: 4, songName: 'Highway To Hell', artistName: 'ACDC', siglosId: '4' },],
[ artistName: 'Frank Sinatra':[
{ id: 3, songName: 'New York', artistName: 'Frank Sinatra', siglosId: '3' },
{ id: 1, songName: 'My Way', artistName: 'Frank Sinatra', siglosId: '1' },],
]
What I actually get back:
[
{ id: 2, songName: 'Big Balls', artistName: 'ACDC', siglosId: '2' },
{
id: 1,
songName: 'My Way',
artistName: 'Frank Sinatra',
siglosId: '1'
}
Not sure how to use group properly or do I need to use a join?
My code:
getAllSongs: {
type: new GraphQLList(SongType),
async resolve() {
const mytest = await dbSong.findAll({
order: ["artistName"],
group: ["artistName"],
raw: true,
});
console.log("test Songs grouped by artist: ", mytest);
// return dbSong.findAll({ raw: true });
return dbSong.findAll({
order: ["artistName"],
group: ["artistName"],
raw: true,
});
},
},
},
});`

Is such a result possible with a query from an SQL database?

I want to fire a query to get such a result:
[{
id: 1,
brandName: "x"
brandModels: [
{id: 1, modelName: "abc", createdAt: "yyyy-mm-dd"},
{id: 2, modelName: "def", createdAt: "yyyy-mm-dd"},
]
},
{
id: 2,
brandName: "y"
brandModels: [
{id: 4, modelName: "ghi", createdAt: "yyyy-mm-dd"},
{id: 5, modelName: "jkl", createdAt: "yyyy-mm-dd"},
]
}]
Tables Schema
BrandsTable
{id, brandName, brand_id}
ModelsTable
{id, modelName, createdAt}
I guess it's not possible like that? I don't have any experience with text-based databases, but I can well imagine that this can be achieved with a MongoDB. Because ultimately I want to have a js object at the end of the day.
Here's an example but I have not tested it:
SELECT JSON_ARRAYAGG(
JSON_OBJECT(
'id', b.id,
'brandName', b.brandName,
'brandModels', m.modelArray
)
) AS joined_result
FROM BrandTable AS b
JOIN (
SELECT brand_id, JSON_ARRAYAGG(
JSON_OBJECT(
'id', id,
'modelName', modelName,
'createdAt', createdAt
)
) AS modelArray
FROM ModelsTable
GROUP BY brand_id
) AS m USING (brand_id);
Note that I had to assume the ModelsTable also contains a column for brand_id, otherwise there is nothing to use in the join condition.
Read documentation for JSON_OBJECT() and JSON_ARRAYAGG() for more information about how these functions work.

How can I get a joined value in sequelize?

joined column come out like this (the last one - 'Perfume.name').
How can I get this in Thunk??
{
id: 1,
male: '50',
female: '50',
value: '70',
useYn: 'Y',
createdAt: 2021-12-05T18:55:34.000Z,
updatedAt: 2021-12-05T18:55:34.000Z,
'Perfume.name': 'Eros'
},
It doesn't work like item.Perfume.name...
help me out
thank you

For JSON results

Sorry for the basic of this question, I just cannot wrap my head around this one.
I need the output from SQL Server to look like this.
In a little more human readable format:
var data = [
{
name: '2017', id: -1,
children: [
{ name: '01-2017', id: 11 },
{ name: '02-2017', id: 12 },
{ name: '03-2017', id: 13 },
{ name: '04-2017', id: 14 },
{ name: '05-2017', id: 15 },
]
},
{
name: '2018', id: -1,
children: [
{ name: '01-2018', id: 6 },
{ name: '02-2018', id: 7 },
{ name: '03-2018', id: 8 },
{ name: '04-2018', id: 9 },
{ name: '05-2018', id: 10 },
]
}
];
This is a snapshot of the data:
The group I will be working with is userid = 1.
My first thought was to use a cursor to loop through all the distinct reportYear for userid = 1, then a select based on the year and the userid to fill in the sub-query.
There has to be a way without using a cursor.
You can achieve the desired output joining your table to a query that extracts all the years to be used at the top level elements and then generating the json using FOR JSON AUTO:
declare #tmp table (monthlyReportID int, userID int, reportMonth int, reportYear int)
insert into #tmp values
( 6, 1, 1, 2018),
( 7, 1, 2, 2018),
( 8, 1, 3, 2018),
( 9, 1, 4, 2018),
(10, 1, 5, 2018),
(11, 1, 1, 2017),
(12, 1, 2, 2017),
(13, 1, 3, 2017),
(14, 1, 4, 2017),
(15, 1, 5, 2017)
select years.[name], children.[name], children.[id] from
(
select distinct reportYear as [name] from #tmp
) as years
left join
(
select monthlyReportID as [id]
,right('0' + cast(reportMonth as varchar(2)),2) + '-' + cast(reportYear as varchar(4)) as [name]
,reportYear as [year]
from #tmp
) as children
on children.[Year] = years.[name]
for json auto
I omitted the ID field because in your desired output it is always set to -1 and I was not able to understand the logic behind it.
Nonetheless you should be able to easily edit the script above to obtain the value you need.
Here are the results:
[
{
"name": 2017,
"children": [
{"name": "01-2017", "id": 11},
{"name": "02-2017", "id": 12},
{"name": "03-2017", "id": 13},
{"name": "04-2017", "id": 14},
{"name": "05-2017", "id": 15}
]
},
{
"name": 2018,
"children": [
{"name": "01-2018", "id": 6},
{"name": "02-2018", "id": 7},
{"name": "03-2018", "id": 8},
{"name": "04-2018", "id": 9},
{"name": "05-2018", "id": 10}
]
}
]

import csv to json/dict with additional keywords/organization

I'm trying to convert a .csv to json/dict such that the data in its current form:
cat1,cat2,cat3,name
1,2,3,a
4,5,6,b
7,8,9,c
I'm currently using something like this(as well as importing using pandas.df bc it will be used for graphing from json file):
with open('Data.csv') as f:
reader = csv.DictReader(f)
rows = list(reader)
print (rows)
[{'cat1': '1', 'name': 'a', 'cat3': '3', 'cat2': '2'},
{'cat1': '4', 'name': 'b', 'cat3': '6', 'cat2': '5'},
{'cat1': '7', 'name': 'c', 'cat3': '9', 'cat2': '8'}]
and I want it to look like this in json/dict format:
{"data: [{"all_cats": {"cat1": 1}, {"cat2": 2}, {"cat3": 3}}, "name": a},
{"all_cats": {"cat1": 4}, {"cat2": 5}, {"cat3": 6}}, "name": b},
{"all_cats": {"cat1": 7}, {"cat2": 8}, {"cat3": 8}}, "name": c}]}
Importing directly doesn't allow me to include: 'cat1', 'cat2', 'cat3' under 'all_cats' and keep 'name' separate.
Any help would be appreciated.
Since it's space separated and not comma separated you have to add delimiter=" ". Additionally since some of your rows have whitespace beforehand, that means you also have to add skipinitialspace=True.
reader = csv.DictReader(f, delimiter=" ", skipinitialspace=True)
rows = list(dict(row) for row in reader)
Thus if you now do:
for row in rows:
print(row)
The output will be:
{'cat1': '1', 'cat2': '2', 'cat3': '3', 'name': 'a'}
{'cat1': '4', 'cat2': '5', 'cat3': '6', 'name': 'b'}
{'cat1': '7', 'cat2': '8', 'cat3': '9', 'name': 'c'}
As already mentioned in the other answer you don't specify valid JSON format for what you want to achieve. You can check if a string contains valid JSON format using json.loads(jsonDATAstring) function:
import json
jsonDATAstring_1 = """
{"data: [{"all_cats": {"cat1": 1}, {"cat2": 2}, {"cat3": 3}}, "name": a},
{"all_cats": {"cat1": 4}, {"cat2": 5}, {"cat3": 6}}, "name": b},
{"all_cats": {"cat1": 7}, {"cat2": 8}, {"cat3": 8}}, "name": c}]}
"""
json.loads(jsonDATAstring_1)
what in case of the by you specified expected JSON format results in:
json.decoder.JSONDecodeError: Expecting ':' delimiter: line 2 column 12 (char 12)
From what is known to me from your question I assume, that the JSON string you want to get is a following one:
jsonDATAstring_2 = """
{"data": [{"all_cats": {"cat1": 1, "cat2": 2, "cat3": 3}, "name": "a"},
{"all_cats": {"cat1": 4, "cat2": 5, "cat3": 6}, "name": "b"},
{"all_cats": {"cat1": 7, "cat2": 8, "cat3": 8}, "name": "c"}]}
"""
json.loads(jsonDATAstring_2)
This second string loads OK, so assuming:
rows = [{'cat1': '1', 'name': 'a', 'cat3': '3', 'cat2': '2'},
{'cat1': '4', 'name': 'b', 'cat3': '6', 'cat2': '5'},
{'cat1': '7', 'name': 'c', 'cat3': '9', 'cat2': '8'}]
you can get what you want as follows:
dctData = {"data": []}
lstCats = ['cat1', 'cat2', 'cat3']
for row in rows:
dctAllCats = {"all_cats":{}, "name":"?"}
for cat in lstCats:
dctAllCats["all_cats"][cat] = row[cat]
dctAllCats["name"] = row["name"]
dctData["data"].append(dctAllCats)
import pprint
pp = pprint.PrettyPrinter()
pp.pprint(dctData)
what gives:
{'data': [{'all_cats': {'cat1': '1', 'cat2': '2', 'cat3': '3'}, 'name': 'a'},
{'all_cats': {'cat1': '4', 'cat2': '5', 'cat3': '6'}, 'name': 'b'},
{'all_cats': {'cat1': '7', 'cat2': '8', 'cat3': '9'}, 'name': 'c'}]}
Now it is possible to serialize the Python dictionary object to JSON string (or file):
jsonString = json.dumps(dctData)
print(jsonString)
what gives:
{"data": [{"all_cats": {"cat1": "1", "cat2": "2", "cat3": "3"}, "name": "a"}, {"all_cats": {"cat1": "4", "cat2": "5", "cat3": "6"}, "name": "b"}, {"all_cats": {"cat1": "7", "cat2": "8", "cat3": "9"}, "name": "c"}]}