I need to search words that contain multiple number prefixes.
Example:
0119
0129
0139
0149
But there is other prefixes, 0155859, 0128889
Etc.
If i search 0%9 it'll come up with all the results i don't want, it'll include the 0155859, 0128889 ones
I need to search and list ONLY the ones that have 0119, etc
How do i do it ?
0XX9 ( Where XX is any strings that matches, so 0119, 0129, etc. % Lists all other characters till a 9 appears, i don't want that. )
I'm trying on my english, correct me if i did'nt expressed myself right !
In a LIKE pattern, the _ character matches any single character. So you can do:
WHERE word LIKE '0__9%'
This matches a word that begins with 0, then any two characters, then 9, then anything after that.
My gut feeling at seeing your question was to consider using REGEXP, which is MySQL's regex matching operator. Try the following query:
SELECT *
FROM yourTable
WHERE word REGEXP '0[0-9][0-9]9'
The pattern used would match any word containing a zero, followed by any two numbers, followed by a 9.
Related
So I'm trying to find what "special characters" have been used in my customer names. I'm going through updating this query to find them all one-by-one, but it's still showing all customers with a - despite me trying to exlude that in the query.
Here's the query I'm using:
SELECT * FROM customer WHERE name REGEXP "[^\da-zA-Z\ \.\&\-\(\)\,]+";
This customer (and many others with a dash) are still showing in the query results:
Test-able Software Ltd
What am I missing? Based on that regexp, shouldn't that one be excluded from the query results?
Testing it on https://regex101.com/r/AMOwaj/1 shows there is no match.
Edit - So I want to FIND any which have characters other than the ones in the regex character set. Not exclude any which do have these characters.
Your code checks if the string contains any character that does not belong to the character class, while you want to ensure that none does belong to it.
You can use ^ and $ to check the while string at once:
SELECT * FROM customer WHERE name REGEXP '^[^\da-zA-Z .&\-(),]+$';
This would probably be simpler expressed with NOT, and without negating the character class:
SELECT * FROM customer WHERE name NOT REGEXP '[\da-zA-Z .&\-(),]';
Note that you don't need to escape all the characters within the character class, except probably for -.
Use [0-9] or [[:digit:]] to match digits irrespective of MySQL version.
Use the hyphen where it can't make part of a range construction.
Fix the expression as
SELECT * FROM customer WHERE name REGEXP "[^0-9a-zA-Z .&(),-]+";
If the entire text should match this pattern, enclose with ^ / $:
SELECT * FROM customer WHERE name REGEXP "^[^0-9a-zA-Z .&(),-]+$";
- implies a range except if it is first. (Well, after the "not" (^).)
So use
"[^-0-9a-zA-Z .&(),]"
I removed the + at the end because you don't really care how many; this way it will stop after finding one.
I dont want rows to be returned where the LIKE is matching a partial word. I am splitting strings on whitespace and then generating a query that will find a match, but its returning matches for partial words. Here is an example
SELECT ID from VideoGames WHERE Title Like "%GI%" AND Title Like "%JOE%"
Returns a match where title = "Yu-Gi-Oh! Power of Chaos: Joey the Passion".
I know only matching full words wont completely resolve the issue, but it will hugely increase accuracy. What can i do to return what i want rather than this.
You can use RLIKE, the regular expression version of LIKE to get more flexibility with your matching.
SELECT ID from VideoGames
WHERE Title RLIKE "[[:<:]]GI[[:>:]]" AND Title RLIKE "[[:<:]]JOE[[:>:]]"
The [[:<:]] and [[:>:]] markers are word boundaries marking the start and and of a word respectively. You could build a single regex rather than the AND but I have made this match your original question.
I would like to find all records from 'mytable' which in the field 'name' used only characters listed below:
Ø-*³`!/-;$€"“- „”\ø,Ø:’.#*+_/? !œ³¥Φ?+#=–()<>ąĄćĆęĘłŁńŃóÓśŚż ŻźŹàáâåéÉêéíıñçãėÊèÈçßœŒæğîïİşúūýōòÒô
regular letters from a to z (and A to Z)
number 0,1,3,4,5,6,7,8,9
spaces and some 'tab' signs
This query does not work:
SELECT name
FROM mytable
WHERE name not regexp '[^a-zA-Z0-9Ø-*³`!/-;$€"“- „”\ø,Ø:’.#*+_/? !œ³¥Φ?+#=–()<>ąĄćĆęĘłŁńŃóÓśŚż ŻźŹàáâåéÉêéíıñçãėÊèÈçßœŒæğîïİşúūýōòÒô]'
I know that this solution is far from good :) but I've tried different methods - this one returns the result closest to the required. Can you please give me some hint?
You can take advantage of character classes.
For example, instead of [ąĄóÓōòÒô...] use [[=A-Za-z=]].
This will match any letters from a through z igoring case and ignoring if the letter has accent.
Check the documentation for additional characters classes that will match your missing characters.
I'm using a regexp for fetching a set of words that accomplish the next syntax:
SELECT * FROM words WHERE word REGEXP '^[dcqaahii]{5}$'
My first impression gave me the sensation that it was good till I realized that some letters were used more than contained in the regexp.
The question is that I want to get all words (i.e. of 5 letters) that can be formed with the letters within the brackets, so if I have two 'a' resulting words can have no 'a', one 'a' or even two 'a', but no more.
What should i add to my regexp for avoiding this?
Thanks in advance.
It would probably be better to retrieve all candidates first and post-process, as others have suggested:
SELECT * FROM words WHERE word REGEXP '^[dcqahi]{5}$'
However, nothing is stopping you from doing multiple REGEXPs. You can select 0, 1, or 2 incidences of the letter 'a' with this grungy expression:
'^[^a]*a?[^a]*a?[^a]*$'
So do the pre-filter first and then combine additional REGEXP requirements with AND:
SELECT * FROM words
WHERE word REGEXP '^[dcqahi]{5}$'
AND word REGEXP '^[^a]*a?[^a]*a?[^a]*$'
AND word REGEXP '^[^i]*i?[^i]*i?[^i]*$'
[edit] As an afterthought, I have inferred that for the non-vowels you also want to restrict to 0 or 1 occurrance. So if that's the case, you'd keep going...
AND word REGEXP '^[^d]*d?[^d]*$'
AND word REGEXP '^[^c]*c?[^c]*$'
AND word REGEXP '^[^q]*q?[^q]*$'
AND word REGEXP '^[^h]*h?[^h]*$'
Yuck.
Only solution I can think of would be to use the above SQL you have to get an initial filtered set of data but then loop through it and further filter with some server side code (PHP etc.) which is better suited to doing that kind of logic.
In regular expressions, square brackets [] are merely a character class, like a list of allowed characters. Specifying the same letter twice within the brackets is therefore redundant.
For example the pattern [sed] will match sed, and seed because e is part of the allowed characters. Specifying a character count afterward in braces {} is merely a total count of characters previously allowed by the character class.
The pattern [sed]{3} therefore will match sed but not seed.
I would recommend moving the logic for testing the validity of words from SQL into your program.
I have table with rows of strings.
I'd like to search for those strings that consists of only
two words.
I tried few ways with [[:space:]] etc but mysql was returning
three, four word strings also
try this:
select * from yourTable WHERE field REGEXP('^[[:alnum:]]+[[:blank:]]+[[:alnum:]]+$');
more details in link :
http://dev.mysql.com/doc/refman/5.1/en/regexp.html
^\w+\s\w+$ should do well.
Note; what I experience more often in the last days is that close to nobody uses the ^$-operators.
They are absolutely needed if you want to tell if a string starts or ends with something or want to match the string exactly, word for word, as you. "Normal" strings, like you used (I assume you used something like \w[:space]\w match in the string, what means that they also match if the condition is true anywhere within the string!
Keep that in mind and Regex will serve you well :)
REGEXP ('^[a-z0-9]*[[:space:]][a-z0-9]*$')