I have three mysql table named users,'clients' and 'products'. I want to count the 'id' field of every table in same query. Is it possible? please help me.
Thanks in advance.
Please this statement
SELECT u.total_users, c.total_clients, p.total_products (
SELECT COUNT(id) as total_users FROM users
) as u,
(
SELECT COUNT(id) as total_clients FROM clients
) as c,
(
SELECT COUNT(id) as total_products FROM products
) as p
Related
I am trying to group single user data which is spread in multiple row in mySQL.
I have tried using group by, Joining multiple times all 4 column but not able to achieve.
Below is my Table and Schema
and I Am trying to get it in the below form as Result
Can you please help me to form a query in MYSQL
Join to the table all the max columns you get after grouping by deviceid:
select distinct
t.date,
t.deviceid,
g.country,
g.affid,
g.accountid,
g.package
from tablename inner join (
select
deviceid,
max(country) country,
max(affid) affid,
max(accountid) accountid,
max(package) package
from tablename
group by deviceid
) g on g.deviceid = t.deviceid
You can do aggregation :
select deviceid, max(country), max(affid), max(accountid), max(package)
from table t
group by deviceid;
EDIT : If you are working with higher version then you can use window function :
select distinct t.Date, t.deviceid,
max(t.country) over (partition by t.deviceid) as country,
max(t.affid) over (partition by t.deviceid) as deviceid,
. . .
from table t;
I got a database named accounts and account table inside of this database, Also I got the database named players and player table inside of this database.
How can I get a rows count of this two tables in one query?
I've tried this:
SELECT
SUM(`account`.`account`.`id`) AS 'accounts',
SUM(`player`.`player`) AS 'players';
But it doesn't work.
If you need exactly rows count (not sum), than do something like this:
select
(select count(*) from accounts.account) as count1,
(select count(*) from players.player) as count2
or
select count(*) as `count`,"account" as `table` from accounts.account
union all
select count(*) as `count`,"player" as `table` from players.player
A simple UNION operation on two select statements will do:
SELECT COUNT(*), 'Accounts' FROM Accounts.Account
UNION
SELECT COUNT(*), 'Players' FROM Players.Player
And you have to qualify each table with the database name since they're in separate databases.
Try:
SELECT
COUNT(`account`.`id`) AS 'accounts',
COUNT(`player`.`player`) AS 'players'
FROM
`account`,
`player`
SELECT COUNT(*)
FROM (
SELECT Id
FROM accounts.account
UNION ALL
SELECT player
FROM players.player ) AS BothTables
with Value (nbr, name ) as
(
select count(*) amount, 'AccountsCount' as ab from accounts..account
union all
select count(*) amount, 'PlayersCount' as ab from players..player
)
select *
from value as s
PIVOT(sum(nbr) for name in (AccountsCount, PlayersCount) ) as pvt
I have a query like this, to select the most recent time someone was contacted:
SELECT `user_id`, `last_contact`
FROM `emails_sent`
group by `user_id`
order by `last_contact` desc
The above code gives a table with the last contact time for each user. Now, I have another table with contacts to users, a table with columns user_id and last_contact, among others.
How can I make my select use both tables and select the last contact time for each user from the two tables?
Summarize the union of two summary queries, something like this.
SELECT user_id,
MAX(user_date) user_date
FROM
(
SELECT user_id,
MAX(last_contact) user_date
FROM emails_sent
GROUP BY user_id
UNION ALL
SELECT whatever_user_id_column user_id,
MAX(whatever_date_column) user_date
FROM whatever_table
GROUP BY user_id
)a
GROUP BY user_id
How to do get distinct count(*) in MySQL.
for example, in table1 i have 10 million record, there are duplicate records in it.
I want to find out distinct count(*) from the table.
I know, I can do
select distinct * from table1
but, i don't want to fetch 10 million records, not even want to insert distinct records in other table like,
create table table2 select distinct * from table1
So, please help me with any other option.
Help from anyone welcome
SELECT COUNT(DISTINCT field) FROM table
or
SELECT COUNT(*) FROM table GROUP BY field;
(btw - this has been answered quite a few times elsewhere on this site)
Try using a subquery:
SELECT COUNT(*) FROM (SELECT DISTINCT * FROM table1) T1
Maybe like:
SELECT SUM(cnt) FROM ( SELECT COUNT(*) as cnt FROM tab GROUP BY some_value )
I need help returning a relevant result for this query. I have one table that I am hitting with three columns. trans_date, trans_amount and user_id
what I am trying to determine is this. For a given user_id when was the last trans_date and what was the trans_amount.
I'm having trouble returning the correct transaction_amount. Here is my code so far. It's returning the correct date but the amount is not right
select user_id, trans_date, trans_credit
from table
WHERE trans_credit =
(select max(trans_date) from inclick_account_act as f
where f.user_id = table.user_id);
Thanks in advance
If I understand you correctly you just want to get the most recent transaction for all users.
SELECT user_id, trans_date, trans_credit
FROM `table`
GROUP BY user_id
ORDER BY trans_date DESC;
How about something like
SELECT t.*
FROM table t INNER JOIN
(
SELECT user_id,
MAX(trans_date) max_trans_date
FROM table
GROUP BY user_id
) MaxDates ON t.user_id = MaxDates.max_trans_date