What is the problem with the format.
This is working fine:
/sitecore/content/Test/Healthy Living/*[##templateid='{8297A5DB-42B1-434F-9A2F-85DF7BC57E24}']
But this one not:
/sitecore/content/Test/Aging and Wellness/*[##templateid='{8297A5DB-42B1-434F-9A2F-85DF7BC57E24}']
I'm getting the next issue
Sitecore.Data.Query.ParseException: 'End of string expected at
position 36.'
It's because of and word in your query.
You need to escape your query with # characters like that:
/sitecore/content/Test/#Aging and Wellness#/*[##templateid='{8297A5DB-42B1-434F-9A2F-85DF7BC57E24}']
More to read here: Escape characters / words in a Sitecore query
Related
I have written regex and tested it online, works fine. When I test in terminal, MySQL console, it doesn't match and I get an empty set. I believe MySQL regexp syntax is somehow different but I cannot find the right way.
This is data I use:
edu.ba;
medu.ba;
edu.ba;
med.edu.ba;
edu.com;
edu.ba
I should get only edu.ba matches including; if there is some. Works fine except in actual query.
(\;+|^)\bedu.ba\b(\;+|$|\n)
Is there anything I could change to get the same results?
You want to match edu.ba in between semi-colons or start/end of string. The word boundaries are redundant here (although if you want to experiment, the MySQL regex before MySQL v8 used [[:<:]] / [[:>:]] word boundaries, and in MySQL v8+, you need to use double backslashes with \b - '\\b').
Use
(;|^)edu[.]ba(;|$)
Details
(;|^) - ; or start of string
edu[.]ba - edu.ba literal string (dot inside brackets always matches a literal dot)
(;|$) - ; or end of string.
I'm trying to build a search query which searches for a word in a string and finds matches based on the following criteria:
The word is surrounded by a combination of either a space, period or comma
The word is at the start of the string and ends with a space, period or comma
The word is at the end of the string and is followed by a space, period or comma
It's a full match, i.e. the entire string is just the word
For example, if the word is 'php' the following strings would be matches:
php
mysql, php, javascript
php.mysql
javascript php
But for instance it wouldn't match:
php5
I've tried the following query:
SELECT * FROM candidate WHERE skillset REGEXP '^|[., ]php[., ]|$'
However that doesn't work, it returns every record as a match which is wrong.
Without the ^| and |$ in there, i.e.
SELECT * FROM candidate WHERE skillset REGEXP '[., ]php[., ]'
It successfully finds matches where 'php' is somewhere in the string except the start and end of the string. So the problem must be with the ^| and |$ part of the regexp.
How can I add those conditions in to make it work as required?
Try '\bphp\b', \b is a word boundary and might just be exactly what you need because it looks for the whole word php.
For MySQL, word boundaries are represented with [[:<:]] and [[:>:]] instead of \b, so use the query '[[:<:]]php[[:>:]]'. More info on word boundaries here.
Well, you can play around a bit with regex101.com
Something I found that works for you but doesn't exactly follow your rules is:
/(?=[" ".,]?php[" ".,]?)(?=php[\W])/
This uses the lookahead operator, ?=, to do AND
The first portion of the regex is
[" ".,]?php[" ".,]?
This will match anything that has a space, period, or comma before or after the php, but at most only one.
The section portion of the regex is
php[\W]
This will match anything that is php, followed by a non-character. In other words, it will NOT match php followed by a character, digit, or underscore.
It's not the perfect answer for your set of rules, but it does work with your sample data set. Play around on regex101.com and try to make a perfect one.
please look here:
UPDATE cars_tbl
SET description = '{\rtf1'
WHERE (ID=1)
Description field is "blob", where my RTF document is to be stored.
When I check updated data I always find
{
tf1
\r simply disapears. I tried to find solution on the web, but no success. My rtf files are corrupted on many places, because the escape characters used in the string are substituted. How to suppress this substitution and update field with string as is?
Thanx for advice
Lyborko
Backslash is an escape character, so to keep it you need a double backslash:
UPDATE cars_tbl
SET description = '{\\rtf1'
WHERE (ID=1)
As an aside \r is a carriage return.. and it hasn't disappeared in your data; it is responsible for tf1 appearing on the line below the {.
You can achieve this with a more generic approach
use of QUOTE() in mysql
MySQL QUOTE() produces a string which is a properly escaped data value in an SQL statement, out of an user supplied string as argument.
The function achieve this by enclosing the string with single quotes, and by preceding each single quote, backslash, ASCII NUL and control-Z with a backslash.
example
UPDATE cars_tbl
SET description = QUOTE('{\rtf1')
WHERE (ID=1)
UPDATE
to escape your RTF you can also just use REPLACE this way all your \ will become \\
Example
UPDATE cars_tbl
SET description = REPLACE('{\rtf1', '\', '\\')
WHERE (ID=1)
I'm attempting to query our MSSQL database but I'm getting no data when there clearly is data there.
First I query
SELECT id, instruction_link FROM work_instructions WHERE instruction_link LIKE "%\\\\cots-sbs%";
Which returns 100+ lines.
http://tinypic.com/r/ief8td/8
(sorry couldn't post as actual picture, don't have enough rep :(
However if I query
SELECT id, instruction_link FROM work_instructions WHERE instruction_link LIKE "%\\\\cots-sbs\\%";
http://tinypic.com/r/33ksw3q/8
I get no results with the 2nd query. I have no idea what I'm doing wrong here. Seems pretty simple but I can't make any sense of it..
Thanks in advance.
As documented under LIKE:
Note
Because MySQL uses C escape syntax in strings (for example, “\n” to represent a newline character), you must double any “\” that you use in LIKE strings. For example, to search for “\n”, specify it as “\\n”. To search for “\”, specify it as “\\\\”; this is because the backslashes are stripped once by the parser and again when the pattern match is made, leaving a single backslash to be matched against.
\\% is parsed as a string containing a literal backslash followed by a percentage character, which is then interpreted as a pattern containing only a literal percentage sign.
I've been trying to get a table row with this query:
SELECT * FROM `table` WHERE `field` LIKE "%\u0435\u0442\u043e\u0442%"
Field itself:
Field
--------------------------------------------------------------------
\u0435\u0442\u043e\u0442 \u0442\u0435\u043a\u0441\u0442 \u043d\u0430
Although I can't seem to get it working properly.
I've already tried experimenting with the backslash character:
LIKE "%\\u0435\\u0442\\u043e\\u0442%"
LIKE "%\\\\u0435\\\\u0442\\\\u043e\\\\u0442%"
But none of them seems to work, as well.
I'd appreciate if someone could give a hint as to what I'm doing wrong.
Thanks in advance!
EDIT
Problem solved.
Solution: even after correcting the syntax of the query, it didn't return any results. After making the field BINARY the query started working.
As documented under String Comparison Functions:
Note
Because MySQL uses C escape syntax in strings (for example, “\n” to represent a newline character), you must double any “\” that you use in LIKE strings. For example, to search for “\n”, specify it as “\\n”. To search for “\”, specify it as “\\\\”; this is because the backslashes are stripped once by the parser and again when the pattern match is made, leaving a single backslash to be matched against.
Therefore:
SELECT * FROM `table` WHERE `field` LIKE '%\\\\u0435\\\\u0442\\\\u043e\\\\u0442%'
See it on sqlfiddle.
it can be useful for those who use PHP, and it works for me
$where[] = 'organizer_info LIKE(CONCAT("%", :organizer, "%"))';
$bind['organizer'] = str_replace('"', '', quotemeta(json_encode($orgNameString)));