How to count number of occurrence in a filed table - mysql

if I have a table with a field City like this:
City
------
London
Los Angeles
London
Athens
Rome
Paris
Paris
How could I get this result?
City | CityNumb
-------------------
London 2
Athens 1
Los Angeles 1
Paris 2
Rome 1


select City, count(*) as CityNumb
from your_table
group by City


Above image shows the SQL query and results for above task

Related

counting occurrences in an SSRS table

Working on SSRS. Have the following data set.
ID City Country
1 London England
2 Glasgow Scotland
3 Aberdeen Scotland
4 Swansea Wales
5 London England
6 Glasgow Scotland
7 Glasgow Scotland
8 Manchester England
Would like to have a table, grouped by the city and showing how many occurrences there have been for each city, see below?
City Country Total
Glasgow Scotland 3
London England 2
Manchester England 1
Swansea Wales 1
Aberdeen Scotland 1
How would i go about doing this please?

After creating a group of City use the following expression:
=COUNT(Fields!City.Value,"City")
Let me know if this helps.

It seems from your question that you don't want the detail in the report, only the summary data. If you do want detail, Alejandro Zuleta's answer will work. If you don't need the detail, you can do the grouping in your dataset:
select city, country, count(*) as total
from <yourtable>
group by city, country;

Grouping by and ordering by an aggregate column

I'm creating a SSRS report and have the following data set.
ID City Country
------------------------------
1 London England
2 Glasgow Scotland
3 Aberdeen Scotland
4 Swansea Wales
5 London England
6 Glasgow Scotland
7 Glasgow Scotland
8 Manchester England
I have a COUNT on the 'City' and grouped by City and Country. This is how I would like it to appear
City Country Total
--------------------------------------------
Glasgow Scotland 3
London England 2
Swansea Wales 1
Aberdeen Scotland 1
Manchester England 1
However, this is how it's appearing
City Country Total
--------------------------------------------
Swansea Wales 1
Glasgow Scotland 3
3
3
Aberdeen Scotland 1
Manchester England 1
London England 2
2
So I need to group by the aggregate total column and also order by that column but not sure how to do it. All help appreciated, thanks.
Have tried Sanjays answer below, unless I'm doing it wrong I'm getting this error.

here
we need to create city and country as group and delete detail section from row groups as like below
so table look like after above changes
and set Count(Fields!ID.Value,"CITY") sd sorting expression for first group city1 with order Z to A

There are multiple ways you could go about this. One option would be to handle the grouping in the query and simply display the results in SSRS. So your query would look something like this:
SELECT ID, City, Country, COUNT(*) as Total
FROM MyTable
GROUP BY ID, City, Country
Now in SSRS you can sort by the Total column since it's not being aggregated in the report.

MySQL - assort and count items

My table has three columns 'name', 'city' and 'country'.
Now I want to make a list with only those countries, which has at least 3 times the SAME city.
name city country
---- ---- -------
Smith Boston USA
Wayne St. Louis USA
Miller Houston USA
Joseph Houston USA
Obama Washington USA
Jones Houston USA
Sarkozy Paris France
Merle Paris France
Gabin Marseille France
Delon Avignon France
Deneuve Avignon France
Trappatoni Rome Italy
Linguini Milano Italy
Mastroianni Rome Italy
Meier Hamburg Germany
Müller Munich Germany
Schmidt Hamburg Germany
Böttcher Hamburg Germany
Kunau Hannover Germany
Wilhelm Munich Germany
-------------------------------
USA
Result:
Germany
I tried it with distinct, count, group by etc. But without results.

Group by country and city then take only those having at least 3 entries each.
select distinct country
from your_table
group by country, city
having count(*) >= 3

mysql: ORDER BY number of occurrences of an element in a column of mysql table

Can someone please help me to 'ORDER' a mysql table according to the no. of occurrences of a string in one of the columns of same table.
I want to rearrange the table according to the number of times a location has occurred.
Please see the example below:
id name location
-- ----- --------
1 Mark US
2 Mike US
3 Paul Australia
4 Pranshu India
5 Pranav India
6 John Canada
7 Rishab India
Expected result:
id name location
-- ----- --------
4 Pranshu India
5 Pranav India
7 Rishab India
1 Mark US
2 Mike US
3 Paul Australia
6 John Canada
I tried this query:
SELECT *, COUNT(location) AS count FROM `tablename` GROUP BY `location` ORDER BY count DESC;
But it showed me the following result omitting the repeating occurrence of location:
id name location
-- ----- --------
4 Pranshu India
1 Mark US
3 Paul Australia
6 John Canada

SELECT x.*
FROM my_table x
JOIN (SELECT location, COUNT(*) total FROM my_table GROUP BY location) y
ON y.location = x.location
ORDER
BY total DESC
, id;

MySQL query for grouping data

can anyone please guide me with writing MySQL query for following scenario.
The data in table is like this,
Table Name: user
user_id country city age
----------------------------------------------
1 India Mumbai 22
2 India Mumbai 22
3 India Delhi 22
4 India Delhi 23
5 India Chennai 23
6 China Beijing 20
7 China Beijing 20
8 China Shanghai 20
9 USA New York 30
10 USA New York 30
11 USA New York 30
12 USA Los Angeles 31
13 USA Los Angeles 31
14 USA Los Angeles 40
I want result to be like this which is basically sum of all users in particular country's city having same age.
country city age age_count
----------------------------------------------
India Mumbai 22 2
India Delhi 22 1
India Delhi 23 1
India Chennai 23 1
China Beijing 20 2
China Shanghai 20 1
USA New York 30 3
USA Los Angeles 31 2
USA Los Angeles 40 1

Try this :;
SELECT country,
city,
age,
count(user_id) AS age_count
FROM user
GROUP BY country,
city,
round(age)

select country, city, age, count(*) age_count
from user
group by country, city, age