EDIT: See edit below for explanation of why min() and max() are NOT adequate.
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The MS documentation on the functions first() and last() says “Because records are usually returned in no particular order (unless the query includes an ORDER BY clause), the records returned by these functions will be arbitrary.”
Obviously, that makes these functions pretty useless for their intended purpose unless the query includes an ORDER BY. But including that in the query is not a straightforward thing to do because these are "aggregate" functions, so a query that SELECTs on them cannot ORDER BY any other field that is not also submitted to an aggregate function.
I have found that a query based on a single table generally returns results in the order of that table’s primary key. But apparently, that cannot be relied on to always be true and may fail under certain circumstances. There's an excellent discussion of this issue in an article, DFirst/DLast and the Myth of the Sorted Result Set.
That article offers two solutions to this problem:
Option one; you first use the DMin/DMax-Function to retrieve the value from the “sortable” column ... and use this as an additional criterion to your query to retrieve the target record.
Second option; you first create a query just containing the primary key and the max value of the sortable column (e.g. CustomerId and maximum of order date). Then you create a second query on the orders and join the first query in there on these two fields. The results will be all column from the orders table but only for the most recent order of each customer.
Those instructions are pretty complicated, so I'd need to see an example of them implemented in code in order to trust myself to use them myself.
This issue has got to be very common because a lot of businesses need to know the first or last order by a customer that meets some condition. But when I Google "Access query first last "order by"", there are several results that explain the problem, including on StackOverflow, but none that lay out a solution with sample SQL code.
What is the right way to do this, including sample code of doing it?
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Edit:
Many sources online, as well as the comment below by Gustav and the proposed answer by Albert D. Kallal, say you can just use min() and max() instead of first() and last(). Obviously, that's okay if what you want is the value of a field in the record in which that field has the smallest or largest value. That's a trivial problem. What I'm talking about is how to get the value of a field in the record in which some other field has the smallest or largest value.
For example, in the answer by Albert D. Kallal, he wants the first and last tour for each customer, so he can just use min() and max() on the dates of the tours. But what if I want to know the location of the first tour for each customer? Obviously, I can't use min(location). If first() would work in a sensible way and if table [Tours] has the primary key [Date], I should be able to use something like:
(SELECT first(location) from [Tours] where [Customer] = ID_Customer)
I am using code like that and it usually gives me the right answer, but not always. So that is what I need to fix. I understand that I may need to use min() instead of first(). But how do I use min() for this since, as I said, I obviously can't just use min(location)?
Never really grasped what first() and last() does in Access.
As you note, rather common to want say last invoice or whatever.
So, say we have a table of Tours. I want the first tour date, and the last tour date.
Well, this query works:
SELECT MAX(FromDate) as LastTourDate, min(FromDate) as FirstTourDate
FROM tblTours
WHERE FromDate is not null
When I run above, I get this:
So, that gets you the min, and max - and gets you this in one query.
No real need for a order by.
However, often there are more then one table involved.
So, I might in place of JUST the first and last tour date?
I probably want a list of customers, and their first tour they took, and say their last tour. But, then again, that's a different question.
But, you again can order your main table ANY way you want, and still pluck out
(pull the min and max).
So, you can do it this way:
Say, tblMain client (people - customers whatever).
Say, tblMyTours - a list of tours they took (child table).
So, the query can look like this:
SELECT tblMainClient.FirstName, tblMainClient.LastName,
(SELECT Min(FromDate) FROM tblMyTours
WHERE tblMyTours.main_id = tblMainClient.id)
AS FirstTourDate,
(SELECT MAX(FromDate) FROM tblMyTours
WHERE tblMyTours.main_id = tblMainClient.id)
AS LastTourDate
FROM tblMainClient
so, the main query is still tblMainClient - I can order, filter, sort by any column in that main table, but we used two sub-query to get the first tour date and the last tour date. So, it will look say like this:
So, typical, we can use a sub-query, pull the max (or min) value, but restrict the sub query to the one row from our parent/main table.
edit: Get last reocrd, but SOME OTHER column
Ok, so say in our simple example, we want the last tour, but NOT the date, but say some other column - like say the last Tour name.
Ok, so we just modify the sub query to return ONLY the last reocrd, but a different column.
And since dates (say 2 invoices on the same day, or yearly tours might have the SAME name, then we need to ensure that ONLY one reocrd is returned. We do this by using top 1, but ALSO add a order by to be 100%, 200%, 300% sure that ONLY ONE top record is returned.
So, our query to get the last tour name, but based on say most recent tour date?
We can do this:
SELECT FirstName, LastName,
(SELECT TOP 1 TourName FROM tblMyTours
WHERE tblMyTours.main_id = tblMainClient.id
ORDER BY tblMyTours.FromDate DESC, tblMyTours.ID DESC)
AS LastTour
FROM tblMainClient
And that will give us the tour name, but the last one.
This:
So, you ceratinly not limited to using "max()" in that sub query.
However, what happens if we want the Tour Name, Hotel Name, and City of that tour?
In other words, it certainly reasonable that we may well want multiple columns.
There are more ways to do this then flavors of ice cream.
However, I like using the query builder for the first part.
What I do is use the standard query builder, do a join to the table and simple slect all the columns I need.
So, for above tblMainClient, and their tours from tblMyTours?
I build a join - use query builder like this:
So, note how I added the columns TourName, FromDate, HotelName and city from that child table (tblMyTours).
Now, of course the above will return 10 rows for anyone who gone on 10 trips.
So, what we do is add a WHERE clause to the child table, get the LAST pk "id" from tblMyTours, and restrict that child table to the ONE row.
So, the above query builder gives us this:
SELECT tblMainClient.ID, tblMainClient.FirstName, tblMainClient.LastName,
tblMyTours.TourName, tblMyTours.FromDate, tblMyTours.HotelName, tblMyTours.City
FROM tblMainClient
INNER JOIN tblMyTours ON
tblMainClient.ID = tblMyTours.Main_id;
(but, I did not have to write above).
So, we add a where clause to that child table join - get the CHILD table "id" in place of TourName, or Tourdate).
So above becomes this:
SELECT tblMainClient.ID, tblMainClient.FirstName, tblMainClient.LastName,
tblMyTours.TourName, tblMyTours.FromDate, tblMyTours.HotelName,
tblMyTours.City
FROM tblMainClient
INNER JOIN tblMyTours ON tblMainClient.ID = tblMyTours.Main_id
WHERE tblMyTours.ID =
(SELECT TOP 1 ID FROM tblMyTours
WHERE tblMyTours.Main_id = tblMainClient.id
ORDER BY tblMyTours.FromDate DESC, tblMyTours.ID DESC)
Now, above is a bit advanced, but OFTEN we want SEVERAL columns. But, at least the first part of the query, the two tables, and the join was done using the query builder - I did not have to type that part in.
so, if you want JUST one column - differnt then the max() critera, then use top 1 with a order by. Do keep in mind that ONLY ONE RECORD can EVER be retunred by that query - if more then one reocrd is returned, the query enginer will fail and you get a message to this fact.
So, for a produce bought, invoice date? They could by the 1 product 2 times, or 2 invoices on the same day might occur. So, by introduction of the 2nd ORDER BY clause (by ID DESC), then that top 1 will ONLY ever return one row.
So, which of the above two?
Well, if just one column from the child table - easy. But, if you want multiple columns? Then you could probably write up a "messy" solution, but I perfect to just fire up query builder, join in the child table, click on the "several" child values I want. Get the query working - and hey, it all up to this point 100% GUI.
Then we toss in the EXTRA criteria to restrict that child table row to the ONE last row, be it simple last one based on ID DESC, or say TourDate, or whatever.
And now we get this:
I have the issue of using GROUP BY when select all the column from the table and in result with the poor performance in term of speed.
Select * from employee
group by customer_id;
The query above wouldn't be change,it is mandatory and fixed.It takes 17720ms is to long and the result must take shorter time, which is below 1 minute as my desired result.Since the table has many column and record, so it take much time in query searching.Is there any solution to solve this problem.Thanks.
For as simple as your query is, it appears almost pointless... You would not have duplicate employee IDs within an employee table, and doing a group by would still result in returning every row, every column.
However, that said, to optimize a GROUP BY, you would need an index on that column ... which I would think would already exist as the employee ID would probably be the primary key to the table.
Additionally, you don't have any aggregate columns what would warrant a group by. Are you instead just trying to LOOK for a specific employee? If so, that would be a different query using a WHERE clause for the criteria you are looking for.
FEEDBACK...
You updated your question and did a group by CUSTOMER ID (not employee ID). Ok, but what do you really mean to group by..
OR... Did you want to ORDER by a customer... In other words, I want a list of all employees, but want them sorted by the customer they are associated with... If this is the case, you would want something like...
select *
from employees
ORDER BY
customerID,
employeeLastName,
employeeFirstName
Without seeing your table structure(s), but if the employee table DOES have a column for the customer ID they are associated with, this query would put all employees for the same customer in a common PRE-SORT output by customer, then within that customer, sorted by the employees name (last, first).
If you have another table(s) with relationships between employees and customers, we would need to see that too to better offer an answer.
Column with heavy type LIKE BLOB, TEXT, NVARCHAR(200 or more) will slowdown your query by a lot if you have a lot of records. I suggest to check if it is really necessary to load them all from the start.
Also, you GROUP BY seem weird. What exactly are you trying to achieve with it?
The GROUP BY is not just weird, it is wrong. If you don't specify all the non-aggregate columns in the GROUP BY, you get seemingly random values for each column. Remove the GROUP BY or explain why you think you need it.
Or maybe the "*" is not correct. OK, you cannot show us your real column names, at least show us the real pattern to the SELECT, even if it has bogus column names.
I'm also confused as to why you call it a "search". There is no WHERE clause, which is where "search" criteria goes.
Hey guys I'm trying to create a query which sums one column and groups the result by another.
Let me show you what I mean by showing my tables!
This is my tickets table
Expect result
As you can see it groups the column app and issue and then SUMS the time per issue.
Currently I have something like this
SELECT app,issue,sum(time)
FROM tickets
GROUP BY issues
ORDER BY name ASC;
However it's not outputting the expected result. Any help would be appreciated.
You need to also group by app in addition to issues
SELECT app,issue,sum(time)
FROM tickets
GROUP BY app,issue
ORDER BY name ASC;
You only grouped by the issues, don't forget adding the app to the group by also.
This should work for you:
SELECT app,
issue,
Sum(time)
FROM tickets
GROUP BY app,
issues
ORDER BY name ASC;
Here is my case, I have a database table with below fields:
name
place_code
email
phone
address
details
estd
others
and example data
If you look at the above example table, first three records are talking about xyz and place code 1020.
I want to create a single record for these three records based on
substring(name,1,4)
place_code
(I am lucky here for all the similar records satisfies this condition and unique in the table.)
For the other columns which record column length has max. For example again for the above 3 records email should be test#te.com, phone should be 657890 and details should be "testdetails".
This should be done for all the table. (Some has single records and some has max 10 records.)
Any help on query that helps me to get the desired result?
Answer
Some one posted the below answer and deleted it . But that looks a good solution
SELECT max(name),
place_code,
max(email),
max(phone),
max(address),
max(details),
max(estd),
max(others)
FROM table_x
GROUP BY substring(name,1,4),place_code
Please let me know if you guys see any issues in it ?
Thank You all
Kiran
You need the awesome GROUP_CONCAT aggregate function.
SELECT place_code,
substring(name,1,4) name,
GROUP_CONCAT(email),
GROUP_CONCAT(Phone),
GROUP_CONCAT(details)
FROM table
GROUP BY place_code, substring(name,1,4)
It has options allowing you to control things like the order of items in the string and the separators. See http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat
SELECT max(name),
place_code,
max(email),
max(phone),
max(address),
max(details),
max(estd),
max(others)
FROM table_x
GROUP BY substring(name,1,4),place_code
Hi i have a columm in the table and i want to select the most common item from the selected column. The table is set up
publication:
id
Title
published
I want to beable to select the most recurring places where publications have been published. Is this possible to do?
Thanks in Advance
Dean
select published, count(*) nbr
from table1
group by published
order by nbr desc
limit 1
You don't really need the count, but if you wanted confirmation that the choice seemed reasonable, you could use it. Also, you didn't specifically say whether you wanted ONLY the one, or wanted to see which was the most frequent, along with frequencies of the other records. Take off the limit 1 if you want to see all records.