id text_1 text_2
1 おはよう おはよ
2 こんにちは ちわー
3 大丈夫 さよなら
4 でんわしたい でんわしよう
I have DB same above.
I want to search with input: おはよう大丈夫？
Expect result will match: id = 1 and id = 3.
Please help me how to query search in Mysql? Thanks you.
The following SQL query will fetch your 2 ids for exact string matching
select id from TABLENAME where text_1 in ('おはよう','大丈夫');
You can also use like operator with % to fetch approximately strings id.
You might face encoding issue (文字化け）depending on your DB settings, so you might have to convert SJIS <-> UTF-8
https://dev.mysql.com/doc/refman/5.7/en/faqs-cjk.html#faq-cjk-what-cjk-avail
Last but not least, if you want to use the full string as a comparison criteria to select the rows, then you can reuse the following code:
how to compute similarity between two strings in MYSQL
select id from TABLENAME where text_1 REGEXP "おはよう大丈夫"
Related
I am trying to write a Query to find if a string contains part of the value in Column (Not to confuse with the query to find if a column contains part of a string).
Say for example I have a column in a table with values
ABC,XYZ
If I give search string
ABCDEFG
then I want the row with ABC to be displayed.
If my search string is XYZDSDS then the row with value XYZ should be displayed
The answer would be "use LIKE".
See the documentation: https://dev.mysql.com/doc/refman/5.0/en/string-comparison-functions.html
You can do WHERE 'string' LIKE CONCAT(column , '%')
Thus the query becomes:
select * from t1 where 'ABCDEFG' LIKE CONCAT(column1,'%');
If you need to match anywhere in the string:
select * from t1 where 'ABCDEFG' LIKE CONCAT('%',column1,'%');
Here you can see it working in a fiddle:
http://sqlfiddle.com/#!9/d1596/4
Select * from table where #param like '%' + col + '%'
First, you appear to be storing lists of things in a column. This is the wrong approach to storing values in the database. You should have a junction table, with one row per entity and value -- that is, a separate row for ABC and XYZ in your example. SQL has a great data structure for storing lists. It is called a "table", not a "string".
If you are stuck with such a format and using MySQL, there is a function that can help:
where find_in_set('ABC', col)
MySQL treats a comma delimited string as a "set" and offers this function. However, this function cannot use indexes, so it is not particularly efficient. Did I mention that you should use a junction table instead?
Table
id name
--- ------
1 chinu
2 sanjib
3 chinmay
My MYSQL Query
SELECT * FROM users WHERE MATCH (name) AGAINST ('chi' IN BOOLEAN MODE)
In above query i am getting 0 record.
My output will be coming
1 chinu
3 chinmay
How to get my actual record using MATCH...AGAINST query?
EDIT - If i am searching chinu instead of chi i am getting 1 record.
You need to add an asterisk to the 'chi' to indicate that the query should match against all that contain the string and not just the string itself. Just using the string 'chi' will only match exactly 'chi' for example.
change your query to read
SELECT * FROM users WHERE MATCH (name) AGAINST ('chi*' IN BOOLEAN MODE)
and you should get the results you expect.
I think you forgot the + sign:
SELECT * FROM users WHERE MATCH (name) AGAINST ('+chi' IN BOOLEAN MODE)
Or if it is an exact phrase, use double quotes to surround the string:
SELECT * FROM users WHERE MATCH (name) AGAINST ('"chi"' IN BOOLEAN MODE)
I am the first to admit that this is not easy to find. MySQL full text search uses a system variable called ft_min_word_length. The default value is 4, as shown here.
Because you are searching for a 3-character word, it is not being indexed. Hence it is not found.
More information is available in the documentation on fine tuning the search. But the basic idea is that you need to change the value of the parameter and rebuild the index.
For your particular query, though, you just need to include wildcards, as explained in other answers.
If I have a database table that has one column that contains a regex pattern, is it possible to return rows (without systematically testing each row in turn) that a string matches?
for example, a table like this:
RowID RegExPattern
1 foo\.$
2 bar\.$
3 baz\.$
4 (foo|bar)\.$
and an input string like this:
foo.php
will return RowIDs 1 and 4
If I have a database table that has one column that contains a regex pattern, is it possible to return rows [...] that a string matches?
Yes, that's possible.
SELECT RowID
FROM yourtable
WHERE 'foo.php' REGEXP RegExPattern
Note though that your regular expressions won't match. If you omit the $ then they will.
See it working online: sqlfiddle
(without systematically testing each row in turn)
Err... no. You need to test each row.
I have this table under user_name='high'
function_description :
akram is in a date
test
akram is studying
test4
kheith is male
test3
I want a query that returns results of field that have at least an 'akram'
SELECT *
FROM functions
WHERE 'isEnabled'=1
AND 'isPrivate'=1
AND user_name='high'
AND function_description LIKE '%akram%'
and this returns absolutely nothing!
Why?
You are listing the column names as if they are strings. This is why it returns nothing.
Try this:
SELECT *
FROM functions
WHERE user_name='high'
AND function_description LIKE '%akram%'
edit: After trying to re-read your question... are isEnabled and isPrivate columns in this table?
edit2: updated.. remove those unknown columns.
You are comparing strings 'isEnabled' with integer 1, which likely leads to the integer being converted to a string, and the comparison then fails. (The alternative is that the string is converted to an integer 0 and the comparison still fails.)
In MySQL, you use back-quotes, not single quotes, to quote column and table names:
SELECT *
FROM `functions`
WHERE `isEnabled` = 1
AND `isPrivate` = 1
AND `user_name` = 'high'
AND `function_description` LIKE '%akram%'
In standard SQL, you use double quotes to create a 'delimited identifier'; in Microsoft SQL Server, you use square brackets around the names.
Please show the schema more carefully (column names, sample values, types if need be) next time.
This question already has answers here:
MySQL query finding values in a comma separated string
(11 answers)
Closed 5 years ago.
I work with a system that used comma separated values as a one-2-many relation. It is stored in as a blob.
I try to use the MySQL IN (LIST), but only ends up with the rows where the uid is first in the list or only one in the list.
mytable
uid categories
1 24,25,26
2 25
3 22,23,25
4 25,27
run sql:
SELECT * FROM mytable WHERE 25 IN (categories)
Result:
uid categories
2 25
4 25,27
Missing (should have been selected but are not)
uid categories
1 24,25,26
3 22,23,25
Any idea why a string has to start with 25 and not just contain 25? I guess it is a string issue rather than an IN (LIST) issue
UPDATE - based on answers below:
When using th IN (LIST) on a blob, the blob is converted to an int and commas and "digits" are lost.
In stead use FIND_IN_SET(needle, haystack) that will work also on a blob containing comma separated values.
I think you are looking for FIND_IN_SET
SELECT * FROM mytable WHERE FIND_IN_SET(25,category)
This should give you your asnwer:
SELECT * FROM mytable WHERE CONCAT(',', categories, ',') LIKE '%,25,%'
But it would make more sense to create a connecting table, with each comma separated value as a new row.
What's happening is that MySQL is converting the blob to an integer (not a list of integers) for comparison. So '24,25,26' becomes the value 24. You can confirm this by running the query
SELECT CAST(categories AS signed) FROM mytable
This is not how IN (nor the blob data type) is meant to be used. Is there a reason you're not using another table for this?
Yes, it's astring issue. Your 'list' is just a string to mysql, meaning nothing.
You would have to use RegEx.
But you might think about normalizing your tables instead.