I have a table named calcu
id date name s1 s2 s3 s4 min_value
1 02/10/2017 dicky 7 4 8 9 4
2 02/10/2017 acton 12 15 17 19 15
3 02/10/2017 adney 28 13 19 10 13
This is my table in SQL Fiddle
I need row wise total value. I means in a new column total, it will be (s1 + s2 + s3 + s4) i.e. (7+4+8+9) = 28 where id=1, (12+15+17+19)=63 where id=2, (28+13+19+10)=70 where id=3 respectively.
Result will be like below:
id date name s1 s2 s3 s4 min_value Total
1 02/10/2017 dicky 7 4 8 9 4 28
2 02/10/2017 acton 12 15 17 19 15 63
3 02/10/2017 adney 28 13 19 10 13 70
see my problem here
It results all total 161 and 3 rows become 1 row.
How to write SQL query?
The SUM() function is an aggregate function. As with other aggregates, use it only to compute values across multiple rows.
You want to add up values in one row, so just use the + operator (brackets are optional).
As for finding the minimum value in the row, use CASE WHEN with 3 tests, comparing S1, S2, S3 and S4.
This should work:
select
c.id, c.date, c.name, c.s1, c.s2, c.s3, c.s4,
(c.s1 + c.s2 + c.s3 + c.s4) as total,
case
when c.s1 <= c.s2 and c.s1 <= c.s3 and c.s1 <= c.s4 then c.s1
when c.s2 <= c.s1 and c.s2 <= c.s3 and c.s2 <= c.s4 then c.s2
when c.s3 <= c.s2 and c.s3 <= c.s1 and c.s3 <= c.s4 then c.s3
when c.s4 <= c.s2 and c.s4 <= c.s3 and c.s4 <= c.s1 then c.s4
end as min_value
from calcu c
;
See SQLFiddle
select c.id,
c.date, c.name, c.s1, c.s2, c.s3, c.s4,
least(s1,s2,s3,s4) Minvalue,
(s1+s2+s3+s4) Total
from calcu c
I tried simplifying the query. So you are looking for the minimum value among s1,s2,s3 and s4. You can achieve with least function. And you need a total of all four 's' columns. Just add them
SELECT *,s1+s2+s3+s4 as Total FROM calcu
Related
I have 3 tables that I have joined in the MySQL query below. All works well EXCEPT I would like the timeadj value with a 1 in column countingtime
to show from table 'data', not the first timeadj value the query finds.
I know this needs to be a query within a query but I am going around in circles and getting no where.
SELECT ttt_entries.tttid, ttt_teams.teamname, data.RacersInTeam,
ttt_entries.CoffeeClass, SEC_TO_TIME(data.timeadj),
COUNT(IF(data.division=5,1,NULL)) 'A+',
COUNT(IF(data.division=10,1,NULL)) A,
COUNT(IF(data.division=20,1,NULL)) B,
COUNT(IF(data.division=30,1,NULL)) C,
COUNT(IF(data.division=40,1,NULL)) D
FROM ttt_entries
INNER JOIN ttt_teams
ON ttt_entries.tttid = ttt_teams.tttid
INNER JOIN (SELECT * FROM data ORDER BY data.countingtime DESC) as data
ON ttt_entries.tttid = data.teamid
WHERE ttt_entries.eventDate = DATE_ADD(CURDATE(), INTERVAL (IF(DAYOFWEEK(CURDATE()) >4, -5, 2) + DAYOFWEEK(CURDATE())) * -1 DAY) -- last Thursday
AND data.wtrlid = '22'
GROUP BY ttt_teams.tttid
ORDER BY data.timeadj ASC
For example.... In Team 1 (data.teamid=1) there are 8 time values in timeadj. In the adjacent column (countingtime) is a value either 1 or 0 but only ever 1x 1 per team.
Table ttt_entries
ID tttid CoffeeClass
1 23 Mocha
2 52 Espresso
3 6 Frappe
Table ttt_teams
tttid Name
6 Team A
23 Team 1
52 Team 2
Table 'data'
id wtrlid teamid timeadj countingtime division
1 22 23 3467.123 0 10
2 22 23 3467.125 0 20
3 22 23 3467.432 0 10
4 22 23 3469.000 1 10
5 22 23 3469.112 0 10
6 22 23 3468.987 0 5
My code brings back
tttid teamname RacersInTeam CoffeeClass Time A+ A B C D
23 Team 1 6 Mocha 3467.123 1 4 1 0 0
I need it to bring back the same data but a different time:
tttid teamname RacersInTeam CoffeeClass Time A+ A B C D
23 Team 1 6 Mocha 3469.000 1 4 1 0 0
You can try below way -
SELECT ttt_entries.tttid, ttt_teams.teamname, data.RacersInTeam,
ttt_entries.CoffeeClass, SEC_TO_TIME(max(case when countingtime=1 then data.timeadj end)),
COUNT(IF(data.division=5,1,NULL)) 'A+',
COUNT(IF(data.division=10,1,NULL)) A,
COUNT(IF(data.division=20,1,NULL)) B,
COUNT(IF(data.division=30,1,NULL)) C,
COUNT(IF(data.division=40,1,NULL)) D
FROM ttt_entries
INNER JOIN ttt_teams
ON ttt_entries.tttid = ttt_teams.tttid
INNER JOIN (SELECT * FROM data ORDER BY data.countingtime DESC) as data
ON ttt_entries.tttid = data.teamid
WHERE ttt_entries.eventDate = DATE_ADD(CURDATE(), INTERVAL (IF(DAYOFWEEK(CURDATE()) >4, -5, 2) + DAYOFWEEK(CURDATE())) * -1 DAY) -- last Thursday
AND data.wtrlid = '22'
GROUP BY ttt_teams.tttid
ORDER BY data.timeadj ASC
I have a table named calcu
id date name s1 s2 s3 s4 min_value
1 10/10/2017 dicky 7 4 8 9 [4]
2 10/10/2017 acton 12 15 17 19 [15]
3 10/10/2017 adney 28 13 19 14 [13]
------------------------------------------------------------------
when total by date 47 32 44 42
Here as minimum column value is s2[32], that's why s2 value = min_value column.
check sqlfiddle here
Now there is no problem. But when any of the fields within s1, s2, s3, s4 value equals [see below example] with any field then min_value field doubles and all column doubles.
Example:
id date name s1 s2 s3 s4 min_value
1 10/10/2017 dicky 7 24 8 11 [8]/[11]
2 10/10/2017 acton 12 15 17 19 [17]/[19]
3 10/10/2017 adney 28 13 19 14 [19]/[14]
------------------------------------------------------------------
when total by date 47 52 44 44
Here minimum value columns are s3 ans s4,
I require any column within s3 or s4 it means either s3 or s4 column will be filled in the min_value column.
see the problem here with sqlfiddle
I am using MySQL.
Based on your sqlfiddle, you need to add a GROUP BY outside of the nested queries in order to achieve what you want.
select c.id, c.date, c.name, c.s1, c.s2, c.s3, c.s4,
case v.s
when 1 then c.s1
when 2 then c.s2
when 3 then c.s3
when 4 then c.s4
end as min_value
from calcu c
join (
select date, s, sum(val) val_sum
from ( #unpivot your data
select date, s1 as val, 1 as s
from calcu
union all
select date, s2 as val, 2 as s
from calcu
union all
select date, s3 as val, 3 as s
from calcu
union all
select date, s4 as val, 4 as s
from calcu
) x
group by date, s
) v on c.date = v.date
where not exists ( #we are only interested in the minimum val_sum above
select 1
from ( #note this is the same derived table as above
select date, s, sum(val) val_sum
from (
select date, s1 as val, 1 as s
from calcu
union all
select date, s2 as val, 2 as s
from calcu
union all
select date, s3 as val, 3 as s
from calcu
union all
select date, s4 as val, 4 as s
from calcu
) x
group by date, s
) v2
where v2.date = v.date
and v2.val_sum < v.val_sum
) GROUP BY c.id # This is the addition you need
See a running solution here
Given a column of strings (passwords) in MySQL and given a value N, i'm looking for an sql-way to count the frequency of each n-gram (substrings of length n).
It's important to keep the code inside MySQL, cause in other environments I have, it will result with memory overflow.
The only working approach I found meanwhile is by assuming limited length of the string (legit assumption), select separately by extracting different locations substrings ,union and then group by and count, like this (for 9-grams out of 13 chars):
Select
nueve,
count(*) as density,
avg(location) as avgloc
From
(select
mid(pass, 1, 9) as nueve, 1 as location
from
passdata
where
length(pass) >= 9 and length(pass) <= 13 UNION ALL select
mid(pass, 2, 9), 2 as location
from
passdata
where
length(pass) >= 10 and length(pass) <= 13 UNION ALL select
mid(pass, 3, 9), 3 as location
from
passdata
where
length(pass) >= 11 and length(pass) <= 13 UNION ALL select
mid(pass, 4, 9), 4 as location
from
passdata
where
length(pass) >= 12 and length(pass) <= 13 UNION ALL select
mid(pass, 5, 9), 5 as location
from
passdata
where
length(pass) = 13) as nueves
group by nueve
order by density DESC
The results are looking like this:
nueve density avgloc
123456789 1387 2.4564
234567890 193 2.7306
987654321 141 2.0355
password1 111 1.7748
123123123 92 1.913
liverpool 89 1.618
111111111 86 2.2791
where nueve is the 9-gram, density is the number of appearances, and avgloc is the mean starting location in the string
Any suggestions to improve the query? I'm doing the same for other n-grams too.
Thanks!
Create a table that contains all the numbers from 1 to the maximum length of passwords. You can then join with this to get the substring positions.
SELECT nueve, COUNT(*) AS density, AVG(location) as avgloc
FROM (
SELECT MID(p.pass, n.num, #N) AS nueve, n.num AS location
FROM passdata AS p
JOIN numbers_table AS n ON LENGTH(p.pass) >= (#N + n.num - 1)
) AS x
GROUP BY nueve
ORDER BY density DESC
How to select right value from joined table based on the value in more than one column.
I started sqlfiddle: http://sqlfiddle.com/#!9/f92daa/2
Main table:
id val
1 1
2 4
3 67
4 78
5 22
Joined table:
obs_id perc1 perc2 perc3 perc4 perc5 perc6 perc7 perc8 perc9 perc10
1 1 2 3 4 5 6 7 8 9 10
2 1 2 3 4 5 6 7 8 9 10
3 10 20 30 40 50 60 70 80 90 100
4 10 20 30 40 50 60 70 80 90 100
5 10 20 30 40 50 60 70 80 90 100
Expected result should be:
id val perc
1 1 1
2 4 4
3 67 70
4 78 80
5 22 30
perc - should be number from perc table (joined by ids) not greater than highest possible value form columns perc1-10
Table perc stores percentiles of observations. The goal is to find which interval hit the value from main table and take the upper band.
You can use a case expression to do this. This assumes perc1 < perc2 < perc3 < perc4 < ... and so on.
SELECT obs.id, obs.val,
case when val <= perc1 then perc1
when val <= perc2 then perc2
when val <= perc3 then perc3
when val <= perc4 then perc4
when val <= perc5 then perc5
when val <= perc6 then perc6
when val <= perc7 then perc7
when val <= perc8 then perc8
when val <= perc9 then perc9
when val <= perc10 then perc10
end
perc
FROM obs
INNER JOIN perc
ON obs.id = perc.obs_id
SQL Fiddle
If you are sure that perc table will have always the values in ascending order then
select
a.id, a.val,
case
when b.perc1 >= a.val then b.perc1
when b.perc2 >= a.val then b.perc2
when b.perc3 >= a.val then b.perc3
when b.perc4 >= a.val then b.perc4
when b.perc5 >= a.val then b.perc5
when b.perc6 >= a.val then b.perc6
when b.perc7 >= a.val then b.perc7
when b.perc8 >= a.val then b.perc8
when b.perc9 >= a.val then b.perc9
when b.perc10 >= a.val then b.perc10
end as perc
from idval a , perc b
where a.id = b.obs_id
In MySql I need to select top student in every class in a school in termid=10 to get discount for next term enrollment .
Please notice that total is not in table(I put in below for clearing problem)
I have this workbook table for all students workbook:
id studentid classid exam1 exam2 total termid
1 2 11 20 40 60 10
2 1 22 40 20 60 10
3 4 11 40 20 60 10
4 5 33 10 60 70 10
5 7 22 10 40 50 10
6 8 11 10 30 40 10
7 9 33 20 45 65 10
8 11 11 null null null 10
9 12 54 null null null 02
10 13 58 null null null 02
1st challenge is : exam1 and exam2 are VARCHAR and total is not in table (as i explained).
2nd challenge is : as you can see in id=8 std #11 has not numbers
3rd challenge is : may be two students have top level so they must be in result.
I need result as :
id studentid classid exam1 exam2 total termid
1 2 11 20 40 60 10
3 4 11 40 20 60 10
4 5 33 10 60 70 10
2 1 22 40 20 60 10
i have this query but not work good as i mention.
SELECT DISTINCT id,studentid,classid,exam1,exam2,total,termid ,(CAST(exam1 AS DECIMAL(9,2))+CAST(exam2 AS DECIMAL(9,2))) FROM workbook WHERE ClassId = '10';
You can get the total for the students by just adding the values (MySQL will convert the values to numbers). The following gets the max total for each class:
select w.classid, max(coalesce(w.exam1, 0) + coalesce(w.exam2, 0)) as maxtotal
from workbook w
group by w.classid;
You can then join this back to the original data to get information about the best students:
select w.*, coalesce(w.exam1, 0) + coalesce(w.exam2, 0) as total
from workbook w join
(select w.classid, max(coalesce(w.exam1, 0) + coalesce(w.exam2, 0)) as maxtotal
from workbook w
group by w.classid
) ww
on w.classid = ww.classid and (coalesce(w.exam1, 0) + coalesce(w.exam2, 0)) = ww.maxtotal;
Another approach is to join the table with itself. You find out the max for each class and then join all students of this class which match the class max:
max for each class (included in the final statement already):
SELECT classid, MAX(CAST(exam1 AS UNSIGNED) + CAST(exam2 AS UNSIGNED)) as 'maxtotal'
FROM students
WHERE NOT ISNULL(exam1)
AND NOT ISNULL(exam2)
GROUP BY classid
The complete statement:
SELECT s2.*, s1.maxtotal
FROM (SELECT classid, MAX(CAST(exam1 AS UNSIGNED) + CAST(exam2 AS UNSIGNED)) as 'maxtotal'
FROM students
WHERE NOT ISNULL(exam1)
AND NOT ISNULL(exam2)
GROUP BY classid) s1
JOIN students s2 ON s1.classid = s2.classid
WHERE s1.maxtotal = (CAST(s2.exam1 AS UNSIGNED) + CAST(s2.exam2 AS UNSIGNED));
SQL Fiddle: http://sqlfiddle.com/#!2/9f117/1
Use a simple Group by Statement:
SELECT
studentid,
classid,
max(coalesce(exam1,0)) as max_exam_1,
max(coalesce(exam2,0)) as max_exam_2,
sum(coalesce(exam1,0) + coalesce(exam2,0)) as sum_exam_total,
termid
FROM
workbook
WHERE
termid=10
GROUP BY
1,2
ORDER BY
5
Try something like this:
SELECT id,studentid,classid,exam1,exam2,(CAST(exam1 AS DECIMAL(9,2))+CAST(exam2 AS DECIMAL(9,2))) AS total,termid FROM `workbook` WHERE ((CAST(exam1 AS DECIMAL(9,2))+CAST(exam2 AS DECIMAL(9,2)))) > 50
Thanks all my friends
I think combine between 2 answer in above is best :
SELECT s2.*, s1.maxtotal
FROM (SELECT ClassId, MAX(
coalesce(exam1,0)+
coalesce(exam2,0)
) as 'maxtotal'
FROM workbook
WHERE
(
termid = '11'
)
GROUP BY ClassId) s1
JOIN workbook s2 ON s1.ClassId = s2.ClassId
WHERE s1.maxtotal = (
coalesce(exam1,0)+
coalesce(exam2,0)
) AND (s1.maxtotal >'75');
last line is good for s1.maxtotal=0 (some times student scores have not be entered and all equals 0 so all will shown as best students) or some times we need minimum score (to enroll in next term).
So thanks all