Radio button with text field into SQL - html

Question

I'm making a website where users can insert data into a database and keep track of their medicine intake.
I have a simple form that submits to an SQL database:
<form method='post'>
<b>Dato:</b> <input type="date" name='date' id='date' value="<?php echo date('Y-m-d'); ?>" /><br /><br \>
<b>Tid:</b> <input type="time" name='time' id='time' value="<?php echo " $hour:$minute "; ?>" /><br /><br \>
<b>Medicin:</b><br /> <input type="radio" name="medicin" value="Medicin1" checked> Medicin1 <br />
<input type="radio" name="medicin" value="medicin2"> Medicin2 <br />
<input type="radio" name="medicin" value="other"> Other <input type="text" name="otherMedicin"><br /><br />
<b>Kommentar:</b><br /><textarea name='comment' id='comment'></textarea><br /> <hr \>
<input type='submit' value='Send' />
</form>
To submit it to the database I found a previous question about the same thing that I follow. Unfortunately I just can't get it to work!
html radio button with an "other" selection that has a text box
Here is the important part of my code:
$users_date = mysqli_real_escape_string($con, $_POST['date']);
$users_time = mysqli_real_escape_string($con, $_POST['time']);
$users_medicin = mysqli_real_escape_string($con, $_POST['medicin']);
$otherMedicin = mysqli_real_escape_string($db, $_POST['otherMedicin']);
if ($users_medicin == 'otherMedicin') {
$medicinField = $otherMedicin;
} else {
$medicinField = $users_medicin;
}
$users_comment = mysqli_real_escape_string($con, $_POST['comment']);
$query = "
INSERT INTO `myDatabase`.`medi_list` (`id`, `dato`, `tid`, `medicin`, `kommentar`) VALUES (NULL, '$users_date',
'$users_time', '$medicinField', '$users_comment');";
I'm still quite new to SQL so I'd appreciate any help you can throw my way :)

Answer 1

I see some basic problems in your code:
When you are populating the field "$otherMedicin", you are using $db instead of $con like the other statements.
$_POST[medicin] is NEVER going to be "otherMedicin", because that is the name of your text input field, not the radio button name. You should have this as your conditional:
if ($users_medicin == 'other') {
That should help a bit.