SQL JSON array sort - mysql

Question

record in DB:
id info
0 [{"name":"a", "time":"2017-9-25 17:20:21"},{"name":"b", "time":"2017-9-25 23:23:41"},{"name":"c", "time":"2017-9-25 12:56:78"}]
my goal is to sort json array column info base on time, like:
id info
0 [{"name":"c", "time":"2017-9-25 12:56:78"},{"name":"a", "time":"2017-9-25 17:20:21"},{"name":"b", "time":"2017-9-25 23:23:41"},]
I use sparkSQL, having no clue

Answer 1

You can do this by converting the json array into a sql result set, extract the sorting column, and finally convert it back to a json array:
DECLARE #json NVARCHAR(MAX);
SET #json = '[
{"name":"a", "time":"2017-09-25 17:20:21"},
{"name":"b", "time":"2017-09-25 23:23:41"},
{"name":"c", "time":"2017-09-25 12:56:59"}
]';
WITH T AS (
SELECT [Value] AS array_element
, TRY_CAST(JSON_VALUE(Value, 'strict $.time') AS DATETIME) AS sorting
FROM OPENJSON(#json, 'strict $')
)
SELECT STRING_AGG(T.array_element, ',') WITHIN GROUP (ORDER BY sorting)
FROM T
Notice:
I changed the sample data slightly, due to invalid months and seconds.
The STRING_AGG() function is only available from SQL 2017/Azure SQL Database. For older versions, use the classic "FOR XML PATH" method, which I will leave as an exercise to the reader.
If you want to apply it to a full sql table, use CROSS APPLY as follows:
DECLARE #json NVARCHAR(MAX);
SET #json = '[
{"name":"a", "time":"2017-09-25 17:20:21"},
{"name":"b", "time":"2017-09-25 23:23:41"},
{"name":"c", "time":"2017-9-25 12:56:59"}
]';
WITH dat AS (
SELECT * FROM (VALUES (1,#json), (2,#json)) AS T(id, info)
)
, T AS (
SELECT id, [Value] AS array_element
, TRY_CAST(JSON_VALUE(Value, 'strict $.time') AS DATETIME) AS sorting
FROM dat
CROSS APPLY OPENJSON(info, 'strict $')
)
SELECT id
, STRING_AGG(T.array_element, ',') WITHIN GROUP (ORDER BY sorting) AS info
FROM T
GROUP BY id

Answer 2

What I Suggest
Alternate Database Storage System
I would not recommend storing data in this manner. It simply makes your data less accessible and malleable as you are experiencing now. If you store your data like this:
id name time
0 a 2017-9-25 17:20:21
0 b 2017-9-25 23:23:41
0 c 2017-9-25 12:56:71
1 ... ...
Then you can select the data in time order using the ORDER BY method at the end of a select query. For example:
SELECT name, time FROM table_name where id=0 ORDER BY time asc;
If you have more columns in this table that you did not show, you may need a another table to efficiently store the information, but the performance benefits of foreign keys and joins between these types of tables would outweigh having all the data in one table as inconvenient JSON arrays.