I need to execute a query with a relationnal division
What I have : 2 tables with a 3rd table for Many-to-Many relation
=> Meetings have multiple participants and participants can attend multiple meetings
What I need : get the meetings which have at least the given participants
Here a SQL query which do the job :
SELECT
m.meeting_id,
m.name,
m.status
FROM meetings As m
INNER JOIN meetings_participants AS mp ON m.meeting_id = mp.meeting_id
WHERE m.status <> 'temporary'
AND mp.participant_id IN (1, 2)
GROUP BY m.meeting_id
HAVING COUNT(DISTINCT mp.participant_id) >= 2
SQL Fiddle : http://sqlfiddle.com/#!9/8a331d/6/0
Question 1 : is there a way to select what I need without the 'HAVING COUNT...' part ?
Question 2 : and in a second query, I need the meetings with exactly the given participants, how to do it ?
Question 1 : is there a way to select what I need without the 'HAVING
COUNT...' part ?
Yes you can use multiple JOIN's but that isn't a very good solution.because you need a JOIN for every mp.participant_id... The Query you have is much more scalable
Query
SELECT
m.meeting_id
, m.name
, m.status
FROM
meetings AS m
INNER JOIN meetings_participants AS mp1 ON m.meeting_id = mp1.meeting_id AND m.status <> 'temporary' AND mp1.participant_id = 1
INNER JOIN meetings_participants AS mp2 ON m.meeting_id = mp2.meeting_id AND m.status <> 'temporary' AND mp2.participant_id = 2
Result
| meeting_id | name | status |
|------------|-----------|-----------|
| 1 | a meeting | active |
| 5 | e meeting | cancelled |
demo http://sqlfiddle.com/#!9/8a331d/54
Question 2 : and in a second query, I need the meetings with exactly
the given participants
You need to find the COUNT first for every meeting_participants HAVING two records
With
SELECT
meeting_id
FROM
meetings_participants
GROUP BY
meeting_id
HAVING COUNT(*) = 2
And use that within the main query like so.
Query
SELECT
meetings.*
FROM (
SELECT
meeting_id
FROM
meetings_participants
WHERE
participant_id IN(1, 2)
AND
meeting_id IN(
SELECT
meeting_id
FROM
meetings_participants
GROUP BY
meeting_id
HAVING COUNT(*) = 2
)
GROUP BY
meeting_id
HAVING COUNT(*) = 2
)
meetings_participants
INNER JOIN
meetings
ON
meetings_participants.meeting_id = meetings.meeting_id
Result
| meeting_id | name | status |
|------------|-----------|-----------|
| 5 | e meeting | cancelled |
demo http://sqlfiddle.com/#!9/8a331d/46
Related
Running into a seemingly simple JOIN problems here..
I have two tables, users and courses
| users.id | users.name |
| 1 | Joe |
| 2 | Mary |
| 3 | Mark |
| courses.id | courses.name |
| 1 | History |
| 2 | Math |
| 3 | Science |
| 4 | English |
and another table that joins the two:
| users_id | courses_id |
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 2 | 1 |
I'm trying to find distinct user names who are in course 1 and course 2
It's possible a user is in other courses, too, but I only care that they're in 1 and 2 at a minimum
SELECT DISTINCT(users.name)
FROM users_courses
LEFT JOIN users ON users_courses.users_id = users.id
LEFT JOIN courses ON users_courses.courses_id = courses.id
WHERE courses.name = "History" AND courses.name = "Math"
AND courses.name NOT IN ("English")
I understand why this is returning an empty set (since no single joined row has History and Math - it only has one value per row.
How can I structure the query so that it returns "Joe" because he is in both courses?
Update - I'm hoping to avoid hard-coding the expected total count of courses for a given user, since they might be in other courses my search does not care about.
Join users to a query that returns the user ids that are in both courses:
select u.name
from users u
inner join (
select users_id
from users_courses
where courses_id in (1, 2)
group by users_id
having count(distinct courses_id) = 2
) c on c.users_id = u.id
You can omit distinct from the condition:
count(distinct courses_id) = 2
if there are no duplicates in users_courses.
See the demo.
If you want to search by course names and not ids:
select u.name
from users u
inner join (
select uc.users_id
from users_courses uc inner join courses c
on c.id = uc.courses_id
where c.name in ('History', 'Math')
group by uc.users_id
having count(distinct c.id) = 2
) c on c.users_id = u.id
See the demo.
Results:
| name |
| ---- |
| Joe |
You can use in operator and use select to generate list of potential users_id attending the second course, to find matching ones in the first course. This is many times faster than using joins.
select distinct u.users_id, users.name
from users_courses u, users
where u.users_id in (select distinct users_id from users_courses where courses_id = 2)
and u.courses_id = 1
and users.users_id = u.users_id
Almost similar to what #Nae's solution.
select u.name from users u
where exists
(select 1
from users_courses uc
where uc.course_id in (1, 2)
and uc.user_id = u.id
group by uc.user_id
having count(0) = 2);
Your code is close. Just use GROUP BY and a HAVING clause:
SELECT u.name
FROM users_courses uc JOIN
users u
ON uc.users_id = u.id JOIN
courses c
ON uc.courses_id = c.id
WHERE c.name IN ('History', 'Math')
GROUP BY u.name
HAVING COUNT(DISTINCT c.name) = 2;
Notes:
This assumes that users cannot have the same name. You might want to use GROUP BY u.id, u.name to ensure that you are counting individual users.
If users cannot take the same course multiple times, then use COUNT(*) = 2 rather than COUNT(DISTINCT).
I'd write:
SELECT MAX(u.name)
FROM users_courses uc
LEFT JOIN users u ON uc.users_id = u.id
WHERE uc.courses_id IN (1, 2)
GROUP BY uc.users_id
HAVING COUNT(0) = 2
;
For more complex conditions (for example requiring the user to be in certain classes but also not in certain classes such as "Science") this should also work:
SELECT MAX(u.name)
FROM users_courses uc
LEFT JOIN users u ON uc.users_id = u.id
GROUP BY uc.users_id
HAVING (
SUM(uc.courses_id = 1) = 1
-- user enrolled exactly once in the course 2
AND SUM(uc.courses_id = 2) = 1
-- user enrolled in course 3, 0 times
AND SUM(uc.courses_id = 3) = 0
)
;
I have the following table structure with data
TABLE: USER
USER ID | USER NAME
1 | Joe
2 | Mary
TABLE : USER GROUP
USER ID | GROUP ID
1 | 1
1 | 2
TABLE : GROUP
GROUP ID | GROUP NAME
1 | Company 1
2 | Company 2
TABLE : ROLE
ROLE ID | ROLE NAME
1 | Administrator
2 | Users
TABLE : USER ROLE
USER ID | ROLE ID
1 | 1
2 | 1
As you can see user #2 does not belong to any group. Roles & Groups are optional forcing me to left joint but when I run a query as below
`SELECT a.user_id,
a.user_name
GROUP_CONCAT(r.role_name) AS role_names,
GROUP_CONCAT(g.group_name) AS group_names
FROM user a
LEFT JOIN role_map m ON a.user_id = m.user_id
INNER JOIN role r ON m.role_id = r.role_id
LEFT JOIN user_group s ON a.user_id = s.user_id
INNER JOIN group g ON s.group_id = g.group_id
GROUP BY a.user_id`
I get a cartesian product in the role_names column - the result looks like this
Joe | Administrators, Administrators | Company 1, Company 2
What am I doing wrong?
The easiest way to solve this is by using DISTINCT in your GROUP_CONCAT (SQL Fiddle). Also, you will need to add GROUP BY a.user_id in order to group per user:
SELECT a.user_id,
a.user_name,
GROUP_CONCAT(DISTINCT r.role_name) AS role_names,
GROUP_CONCAT(DISTINCT g.group_name) AS group_names
FROM `user` a
LEFT JOIN `user_role` m ON a.user_id = m.user_id
LEFT JOIN `role` r ON m.role_id = r.role_id
LEFT JOIN `user_group` s ON a.user_id = s.user_id
LEFT JOIN `group` g ON s.group_id = g.group_id
GROUP BY a.user_id;
Hi everyone I would like to count some entries, but I don't know if is possible to do it with joins. The situation is
I've got a tables
student_profile
Id | Name
---------
1 | Name1
2 | Name2
3 | Name3
student_application where profile_id is related to student_profile.id
Id | profile_id | Data
----------------------
1 2 data1
2 2 data2
3 2 data3
And table student_holiday
Id | app_id | date
-----------------------
1 2 2014-01-01
2 3 2014-02-02
So I'm getting all my student_application's with
Select sa.id, s.name From student_application sa
INNER JOIN student_profile s ON s.id = sa.profile_id
I would like to count how many holidays has a student, but I don't have profile_id in student_holiday table. There I've got app_id, so I can't do Left join student_holiday sh ON sh.app_id = sa.id, this wouldn't give the right number.
here sqlfiddle
Thanks in advance for any help.
SELECT student_profile.ID, student_profile.Name, student_holiday.ID
FROM (student_profile INNER JOIN student_holiday ON student_profile.ID = student_holiday.ID) INNER JOIN student_application ON student_holiday.ID = student_application.ID;
Here you go!!! Match ID in all the table as instructed above which is the key to get holidays.
OR match with profile_id
**SELECT student_profile.ID, student_profile.Name, student_holiday.ID
FROM (student_profile INNER JOIN student_holiday ON student_profile.ID = student_holiday.ID) INNER JOIN student_application ON Trim(student_holiday.ID) =
student_application.profile_id;**
Here is your data with the 3rd table joined:
Select s.name, sa.some_data as application_data,h.some_data as holiday_data
From student_application sa
INNER JOIN student_profile s ON s.id = sa.profile_id
INNER JOIN student_holiday h ON h.app_id = sa.id;
Note this will only return records that have an application with a holiday associated.
Then to count them, we just:
Select s.name, sa.some_data as application_data,count(h.some_data) as holiday_data
From student_application sa
INNER JOIN student_profile s ON s.id = sa.profile_id
INNER JOIN student_holiday h ON h.app_id = sa.id
GROUP BY s.name
Note this answer is based on the fieldnames you used in your sqlfiddle (Data = some_data and date = some_data)
I have a query join 2 table as below:
SELECT * FROM Staff s INNER JOIN Account a on s.AccNo = a.AccNo WHERE a.Status = 'Active'
The result as shown:
AccNo | Name | ID
------------------
1 | Alex | S01
2 | John | S02
After I get the staff ID,I write second query to find out the max sale as below:
SELECT s.ProductID,Max(s.Amount) from Sales s WHERE StaffID = 'S01' GROUP BY s.ProductID
The max sale for Staff 'S01' as below:
ProductID | Amount
------------------
Cloth | 2000
How to I combine these 2 queries and become result as below? Thanks
AccNo | Name | ID | Amount
--------------------------
1 | Alex | S01 | 2000
2 | John | S02 | 5000
You can create a subquery and join it:
SELECT a.AccNo, b.Name, b.ID, c.maximum
FROM transaction as a
INNER JOIN Account as b
ON a.AccNo = b.AccNo
LEFT JOIN (SELECT StaffID, Max(Amount) as maximum FROM Sales GROUP BY StaffID) as c
ON c.StaffID = b.ID
WHERE b.Status = 'Active'
See the SQLFiddle example (I've tried to guess the schema)
So what you want to do is join to sales on the staffId then group.
SELECT a.AccNo,a.Name,a.ID,Max(s.Amount)
FROM Transaction t
INNER JOIN Account a on t.AccNo = a.AccNo
INNER JOIN Sales s on s.staffId = a.ID
WHERE a.Status = 'Active'
GROUP BY a.AccNo,a.Name,a.ID
You could try something like this:
Select Account.*, Max(Sales.amount) from Sales
JOIN Account ON Sales.StaffID = Account.ID
where Account.status = 'Active'
group by Sales.ProductID, Account.AccNo, Account.Name, Account.ID
Honestly, I don't understand why do you use Transascation table in your queries, because you don't use it.
I think this should work
Just do a join and retrieve the max amount associated with each staff
SELECT t.AccNo , t.Name, t.ID, s.ProductID, Max(s.Amount) FROM Transaction t
INNER JOIN Account a ON t.AccNo = a.AccNo
INNER JOIN Sales s ON s.StaffID = a.ID
WHERE a.Status = 'Active';
Thanks
I have 3 tables as follows in my database. this is used to a application just like foursqure. i need help with the problem of writing the sql statement i have asked in the bottom of this.
thank you
user_details
user_id | fname
----------------
1 | Losh
8 | Dush
9 | Rosh
10 | NELL
friends
user_idf |user_idff
----------------
1 | 8
8 | 9
10 | 1
Check_in
check_in_id |user_id | place | date
--------------------------------------------
1 | 8 | Hotel | 01/01/2012
2 | 9 | Home | 05/01/2012
3 | 1 | Junction | 08/01/2012
4 | 1 | Rest | 11/01/2012
5 | 9 | Hotel | 15/01/2012
6 | 8 | Home | 15/01/2012
i get the user's who are friends with 8 and user 8 details AND the check in places as follows
SELECT a.`user_id`, a.`fname` , b.*
FROM `user_details` a, `check_in` b
WHERE (b.user_id = 8
OR b.user_id in (select user_idf from friends where user_idff = '8' union select user_idff from friends where user_idf = '8')) AND b.user_id = a.user_id
how do i write the sql to select who are friends with 8 and user 8 details AND the last check in place of those users
explanation::
i seeks for a answer such as
user id name place date
1 LOSH Rest 11/01/2012
8 DUSH HOME 15/01/2012
9 ROSH HOTEL 15/01/2012
Join it to the table returned by:
(SELECT `user_id`, `place` FROM Check_in GROUP BY user_id ORDER BY `date` DESC)
That should give you one entry per user, and since it's sorted in reverse by date, that entry should be the most recent.
But when i group by it gives me the first dates not the latest date
How about this:
(SELECT user_id, place
FROM (SELECT * FROM Check_in ORDER BY `date` DESC) tmp
GROUP BY user_id)
SELECT user_id, fname, c.place
FROM user_details u
INNER JOIN (SELECT IF(user_idff = 8, user_idf, user_idff) AS user_id
FROM friends
WHERE (user_idff = 8 OR user_idf = 8)
) f
ON u.user_id = f.user_id
LEFT JOIN (SELECT c1.user_id, place
FROM Check_in c1
LEFT JOIN Check_in c2
ON c1.user_id = c2.user_id AND
c1.date < c2.date
WHERE c2.date IS NULL
) c
ON u.user_id = c.user_id;
This doesn't break ties but it's a straighforward way of answering your question.
EDIT
I just re-read you question and I see that you want user 8 info also. It's not clear whether you want user 8 as a separate row or with info in line with the friends' rows.
select *
from
friends as f inner join check_in as ci on ci.user_id = f.user_idff
inner join user_details as ud on ud.user_id = f.user_idff
inner join user_details as ud8 on ud8.user_id = f.user_idf
where
f.user_idf = 8
and date = (
select max(date)
from friends as f2 inner join check_in as ci on ci.user_id = f2.user_idff
where f2.user_idf = f.user_idf
)
EDIT 2
You request may be a small bit unclear about determining which check-in location to return. Use this option if you want the latest location of each friend individually. The first query finds the most recent location among all friends. Obviously these are two variations on an identical theme.
select *
from
friends as f inner join check_in as ci on ci.user_id = f.user_idff
inner join user_details as ud on ud.user_id = f.user_idff
inner join user_details as ud8 on ud8.user_id = f.user_idf
where
f.user_idf = 8
and date = (
select max(date)
from check_in as ci
where ci.user_id = f.user_idff
)
(SELECT a.user_id, a.place, b.fname, a.date, a.time, a.check_in_id
FROM (SELECT * FROM check_in ORDER BY date DESC) as a, user_details as b
WHERE a.user_id = b.user_id AND (a.user_id in (select user_idf from friends where user_idff = '8' union select user_idff from friends where user_idf = '8') OR a.user_id = 8)
GROUP BY a.user_id)
above query gave me the required answer.
thank you all for the help given