I have a table which consists of 5000 rows. I need SQL command that could update each row by removing all values in "(...)" if only one couple of () is found.
Basically, if I have a name in a row:
Name surname (extra info)
I need to remove "(extra info)" and leave only Name surname
But if there is no additional couple of ()
If there is a row
Name Surname(data) (extra info)
The script should not amend this name
In simple words, I need to update a name where is only one ( or ) symbol
Many thanks
can you try to find first '(' and substring to it ?
don't forget to use case for none ( in string
update userlogin
set fullname = case position('(' in FullName)
when 0
then fullname
else substring(Fullname,1,position('(' in FullName) - 1)
end
This is an implementation of my question. I used select to let me check the result before applying it to update request. The script shows a table of
3 columns: Id, Name, UpdatedName, where Name is what we have and UpdatedName what we will obtain
SELECT `Id`,`Name`,
(case when ((LENGTH(`Name`)-LENGTH(REPLACE(`Name`, '(', ''))) = 1)
THEN
SUBSTRING_INDEX(`Name`, '(', 1)
ELSE
'-'
END)
as updated_name,
FROM table
WHERE (LENGTH(`Name`)-LENGTH(REPLACE(`Name`, '(', ''))) = 1
LIMIT 0,1500
P.S. I used Id to allow me to amend values
SELECT CASE
WHEN fname = 'correct' THEN 'your condition'
WHEN sname = 'correct' THEN 'your second condition'
ELSE 'baz'
END AS fullname
FROM `databasetable`
or you can do as like also
CASE
WHEN action = 'update' THEN
UPDATE sometable SET column = value WHERE condition;
WHEN action = 'create' THEN
INSERT INTO sometable (column) VALUES (value);
END CASE
Related
I need to split address column into streetName and streetNumber. The problem is sometimes the complete address in located in the streetName column , and sometimes too inside the streetNumber column. I am using this code to do the splitting
replace(streetName, substring_index(streetName, ' ', -1), '') as
street,substring_index(streetName, ' ', -1) as number
and
replace(streetNumber, substring_index(streetNumber, ' ', -1), '') as
street,substring_index(streetNumber, ' ', -1) as number.
What I want to do is run this section of my select query statement if streetName is null or empty execute the code with the streetNumber and vice versa.
I have to sections ifStreet() and IfStreetNumber() in a stored Procedure. But I get an error when I run it , and If I put the code directly inside the case statements it does not work as well.I get an error message, You have an error in your SQL Syntax. Is it possible to run a query base on condition or what is wrong with my approach? Thank you,
SELECT
firstName,
lastName,
D.email AS email,
streetName,
streetNumber,
zipCode,
city,
IF(length(zipCode) =5,'Germany','') As country,
registeredOn,
N.email AS matchedEmail,
CASE
WHEN gender = 'Frau' OR gender = 'f' THEN 'f'
WHEN gender = 'Herr' OR gender = 'm' THEN 'm'
ELSE ''
END AS Title,
CASE
WHEN gender = 'Frau' OR gender = 'f' THEN 'Frau'
WHEN gender = 'Herr' OR gender = 'm' THEN 'Herr'
ELSE ''
END AS Salutation,
CASE
WHEN streetName !='' THEN
call ifStreet()
ELSE
call ifStreetNumber()
END
FROM
matchFiles.TableA AS D
INNER JOIN
matchFiles.TableB AS N ON D.email = N.email
WHERE
registeredOn <= '2018-08-31';
Stored Procedures are not allowed within SELECT Statements. So your approach will not work.
Try to shift your logic from your stored procedure into adequate subquery.
I restructured the query and also dropped using a stored procedure . I using an IFNULL function to do the alternation to use either streetName or streetNumber depending on which column has a the full address string.
replace(IFNULL(streetName,streetNumber), substring_index(IFNULL(streetName,streetNumber), ' ', -1), '') as street,substring_index(IFNULL(streetName,streetNumber), ' ', -1) as number
I have a table with fullname column. I want to make a query for finding a person via his last name but his last name is in the full name column.
Would it matter if it accidentally returned someone whose first name matched your query?
A simple query would be:
SELECT *
FROM TABLE
WHERE fullname LIKE '%insertlastname%'
If you want to define the last name as the name after the last space:
SELECT substring_index(fullname, ' ', -1) as lastname
FROM TABLE
WHERE lastname='insertlastname'
Two suboptimal answers, but some answers at least.
enter code here You can use this if you want to fetch by query:
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX( `fullname` , ' ', 2 ),' ',1) AS b,
SUBSTRING_INDEX(SUBSTRING_INDEX( `fullname` , ' ', -1 ),' ',2) AS c FROM `users` WHERE `userid`='1'
But you can also try by PHP to fetch last name. You just use explode function to fetch last name.
Exm:
$full_name = "row moin";
$pieces = explode(" ", $fullname);
echo $first_name = $pieces[0]; // row
echo $last_name = $pieces[1]; // moin
A simple answer for this is like this suppose we have a name
Charles Dickens
:
SELECT * FROM TABLE_NAME WHERE SUBSTRING_INDEX(FULLNAME,' ',-1) like '%Dickens';
I have a table with Boolean values (0 and 1 only) that needs to be CSV-ed to a client. I know I can do 1 replace like this:
SELECT REPLACE(email, '%40', '#'),
REPLACE(name,'%20', ' '),
REPLACE(icon_clicked, 1, 'Yes')
FROM myTable
WHERE id > 1000;
This will convert all the values of 1 to 'Yes', but how to do this in a single query for both 1 => Yes and 0 => No so Boolean result is stored in a single column? I tried to do this:
SELECT REPLACE(email, '%40', '#'),
REPLACE(name,'%20', ' '),
REPLACE(icon_clicked, 1, 'Yes'),
REPLACE(icon_clicked, 0, 'No')
FROM myTable
WHERE id > 1000;
But this query created an additional column for the 'No' string replace (so final result had 4 columns, email, name, icon_clicked->yes, icon_clicked->no)
One way is to nest REPLACE:
SELECT REPLACE(REPLACE(icon_clicked, 0, 'No'), 1, 'Yes')), ...
FROM myTable
...
or use CASE WHEN (this will work for most RDBMS comparing to IF function which is MySQL related):
SELECT CASE WHEN icon_clicked THEN 'Yes' ELSE 'No' END, ...
FROM myTable
...
SqlFiddleDemo
EDIT:
There is also one nice way utilizing ELT:
SELECT icon_clicked,
ELT(FIELD(icon_clicked,0,1),'No','Yes'),
ELT(icon_clicked + 1, 'No', 'Yes')
FROM mytable
SqlFiddleDemo2
No need to use nested Replace or Case statement. Try using IF, which is way simpler
SELECT
icon_clicked,
IF(icon_clicked,'Yes','No')
FROM myTable
SQL FIDDLE DEMO
I have a sybase query that is structured like this:
SELECT
case
when isnull(a,'') <> '' then a
else convert(varchar(20), b)
end
FROM table_name
WHERE b=123
It used to return the results of the 'case' in a column named 'converted'. It now returns the results of the 'case' in a column with an empty string name ''.
How could this be? Could there be some database configuration that defaults the results of a 'case' with no name?
(I've fixed the broken query by adding " as computed" after 'end' but now I'd like to know how it used to return as 'computed' before I added the fix?)
Is this what you want?
SELECT (case when isnull(a, '') <> '' then a
else convert(varchar(20), b)
end) as converted
-------------^
FROM table_name
WHERE b = 123;
By the way, you could write the select more succinctly as:
SELECT coalesce(nullif(a, ''), b) as converted
I want to generate .sql file with the sql query output . I am doing this with concat statement in sql . I am using case statement in some queries this will be the problem for me.
select concat('insert into x values(',CASE a when B then 'Book' else 'NONE' end , ') on duplicate key update B = values(B)') from author;
select 'insert into x values('+CASE a when B then 'Book' else 'NONE' end +') on duplicate key update B = values(B)' from author;
It also not works because in mysql + used for adding only numbers not for strings .
Is there any way for doing this?.
The problem with the first version is the quotes of things within the string. For instance, you want your string to contain "'Book'"
select concat('insert into x values(',
(CASE a when 'B' then '''Book''' else '''NONE''' end) ,
') on duplicate key update B = values(''B'')'
)
from author;
I think this quotes al the strings as they should be. I'm guess column A is a character that should be compared to 'B' and not to column B.