Comparing all data to the data of specifically selected user ID? - mysql

I have a mysql table that holds data for team games.
Objective:
Count the number of times other SquadID's have have shared the same Team value as SquadID=21
// Selections table
+--------+---------+------+
| GameID | SquadID | Team |
+--------+---------+------+
| 1 | 5 | A |
| 1 | 7 | B |
| 1 | 11 | A |
| 1 | 21 | A |
| 2 | 5 | A |
| 2 | 7 | B |
| 2 | 11 | A |
| 2 | 21 | A |
| 3 | 5 | A |
| 3 | 7 | B |
| 3 | 11 | A |
| 3 | 21 | A |
| 4 | 5 | A |
| 4 | 11 | B |
| 4 | 21 | A |
| 5 | 5 | A |
| 5 | 11 | B |
| 5 | 21 | A |
| 6 | 5 | A |
| 6 | 11 | B |
| 6 | 21 | A |
+--------+---------+------+
// Desired Result
+---------+----------+
| SquadID | TeamMate |
+---------+----------+
| 5 | 6 |
| 7 | 0 |
| 11 | 3 |
| 21 | 6 |
+----------+---------+
I've attempted to use a subquery specifying the specific player I wish to compare with and because this subquery has multiple rows, I've used in instead of =.
// Current Query
SELECT
SquadID,
COUNT(Team IN (SELECT Team FROM selections WHERE SquadID=21) AND GameID IN (SELECT GameID FROM selections WHERE SquadID=21)) AS TeamMate
FROM
selections
GROUP BY
SquadID;
The result I'm getting is the number of Games a user has played rather than the number of games a user has been on the same team as SquadID=21
// Current Result
+---------+----------+
| SquadID | TeamMate |
+---------+----------+
| 5 | 6 |
| 7 | 3 |
| 11 | 6 |
| 21 | 6 |
+---------+----------+
What am I missing?
// DESCRIBE selections;
+---------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+---------+---------+------+-----+---------+-------+
| GameID | int(11) | NO | PRI | 0 | |
| SquadID | int(4) | NO | PRI | NULL | |
| Team | char(1) | NO | | NULL | |
| TeamID | int(11) | NO | | 1 | |
+---------+---------+------+-----+---------+-------+

General rule is to avoid nested selects and look for a better way of logically arranging joins. Lets look at a cross join:
From selections s1
inner join selects s2 on s1.gameid = s2.gameid and s1.team = s2.team
This will produce a cross joined list of each squadID that participated with another squadID (IE: they were in the same game and on same team). We are only interested in the times where the squad participated with squad 21, so add a where clause:
where s2.squadid = 21
Then it's simply choosing the field/count you want:
select s1.squad, count(1) as teammate
any aggregate needs a group by
group by s1.squad
Combine it together and give a go. Oddly, this will produce a list where squad 21 will be showing as playing on it's own team all 6 times. Adding a where clause can eliminate this
where s1.squadid <> s2.squadid

SELECT SquadID, count(t1.team) as TeamMate
FROM selections as t1 join
(select distinct team, gameid from selections where SquadID=21) as t2
on t1.Team=t2.Team and t1.Gameid=t2.Gameid
GROUP BY SquadID

Related

How do I join 2 tables to a third one which contains the primary key?

I have 4 tables: the first is the client table, which has customer info, and client_id as an auto-increment primary key.
The second and third are identical in structure: they are used to track attendance to 2 different therapy programs. They each have a primary key, and a client_id column to track the client. One of the fields contains units, which I want to sum.
The last table contains the therapists' info.
Basically I want to extract total amount of units for each client from the two attendance tables.
I have tried LEFT JOINS to no avail. I also tried a UNION ALL, but couldn't get it to sum the units.
This is how the tables look:
client:
+---------------------------------------+
| client_id | f_name | l_name | th_id |
|-----------|----------|--------|-------|
| 1 | sherlock | holmes | 1 |
| 2 | john | watson | 4 |
| 3 | hercule | poirot | 3 |
| 4 | jane | marple | 2 |
+---------------------------------------+
therapist:
+--------------------------+
| th_id | f_name | l_name |
|-------|---------|--------|
| 1 | james | kirk |
| 2 | mr | spock |
| 3 | bones | mccoy |
| 4 | nyota | uhura |
+--------------------------+
attendance it:
+-------------------------------+
| it_id | client_id | units |
|-----------|-----------|-------|
| 1 | 1 | 4 |
| 2 | 1 | 4 |
| 3 | 1 | 0 |
| 4 | 1 | 2 |
| 5 | 4 | 0 |
| 6 | 4 | 4 |
| 7 | 4 | 0 |
| 8 | 4 | 2 |
+-------------------------------+
attendance psr:
+-------------------------------+
| it_id | client_id | units |
|-----------|-----------|-------|
| 1 | 1 | 16 |
| 2 | 1 | 16 |
| 3 | 1 | 0 |
| 4 | 1 | 12 |
| 5 | 4 | 0 |
| 6 | 4 | 14 |
| 7 | 4 | 8 |
| 8 | 4 | 10 |
+-------------------------------+
The result should look like this:
+------------------------------------------------------------+
| client_id | total_units_it | total_units_psr | therapist |
|-----------|----------------|-----------------|-------------|
| 1 | 10 | 44 | james kirk |
| 4 | 6 | 32 | mr spock |
+------------------------------------------------------------+
Please excuse the primitive representations, and please don't ask why the tables are designed like that... ;-) Also, I obviously ignored many other fields which are not relevant to the question, such as dates, etc.
Any advice would be appreciated.
Thanks!
You can't use join or you will create Cartesian product and duplicate the rows.
Instead you do a subquery:
SELECT c.*
, (SELECT SUM(units) FROM attendance_it a WHERE a.client_id = c.client_id ) as total_units_it
, (SELECT SUM(units) FROM attendance psr a WHERE a.client_id = c.client_id ) as total_units_psr
, t.*
FROM client c
JOIN therapist t
ON c.th_id = t.th_id
use group by client_id to get the sum of each client. and no need to use join as you have already the ids in column.

MySQL JOIN blindness

This query
SELECT station_id, station_name,
COUNT(event_station) as `total_visit_count`
FROM taps AS t
JOIN event_stations AS s
ON t.event_station = s.station_id
WHERE s.event_id=6
GROUP BY s.station_id
ORDER BY s.station_id;
returns
+------------+--------------+-------------------+
| station_id | station_name | total_visit_count |
+------------+--------------+-------------------+
| 5 | Station one | 24 |
| 6 | Station two | 35 |
| 7 | St. Pancras | 34 |
+------------+--------------+-------------------+
which is just fine.
However, there are some stations in taps which have not been visited and I would like them to be shown with a total_visit_count of zer0.
+------------+--------------+-------------------+
| station_id | station_name | total_visit_count |
+------------+--------------+-------------------+
| 5 | Station one | 24 |
| 6 | Station two | 35 |
| 7 | St. Pancras | 34 |
| 8 | Station four | 0 |
+------------+--------------+-------------------+
How do I rewrite my query to to that? I imagine some kind of JOIN is required, but I can't quite see it :-(
[Update]
describe event_Stations;
+--------------+------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+------------+------+-----+---------+----------------+
| station_id | int(11) | NO | PRI | NULL | auto_increment |
| event_id | int(11) | NO | | NULL | |
| station_name | text | NO | | NULL | |
| allocated | tinyint(1) | NO | | 0 | |
+--------------+------------+------+-----+---------+----------------+
4 rows in set (0.20 sec)
describe taps;
+---------------+-----------+------+-----+-------------------+-------+
| Field | Type | Null | Key | Default | Extra |
+---------------+-----------+------+-----+-------------------+-------+
| tag_id | int(11) | NO | | NULL | |
| time_stamp | timestamp | NO | | CURRENT_TIMESTAMP | |
| event_station | int(11) | NO | | NULL | |
| device_id | text | YES | | NULL | |
| device_type | text | YES | | NULL | |
| event_id | int(11) | NO | | NULL | |
+---------------+-----------+------+-----+-------------------+-------+
6 rows in set (0.00 sec)
select * from event_stations where event_id=6;
+------------+----------+-----------------+-----------+
| station_id | event_id | station_name | allocated |
+------------+----------+-----------------+-----------+
| 5 | 6 | Station one | 0 |
| 6 | 6 | Station two | 0 |
| 7 | 6 | St. Pancras | 0 |
| 8 | 6 | Station three | 0 |
| 9 | 6 | Station four | 0 |
| 10 | 6 | Station five | 0 |
| 11 | 6 | Station six | 0 |
| 12 | 6 | Station seven | 0 |
| 13 | 6 | Station eight | 0 |
| 14 | 6 | Station nine | 0 |
| 15 | 6 | Station ten | 0 |
| 16 | 6 | Station eleven | 0 |
+------------+----------+-----------------+-----------+
12 rows in set (0.00 sec)
First, swap the order of your join, so the primary table is sorted first (this is for organizational purposes only).
Then, use a LEFT JOIN to accomplish what you're looking for. This will ensure you pull all event_stations records (the left portion of the join), even if there is no corresponding record in the taps table (the right portion of the join). In place of the missing taps, you'll get NULL values.
COUNT will ignore nulls in aggregate, so will only return the count of non-null records. Thus, it will return 0 for your missing event_stations records.
SELECT
station_id,
station_name,
COUNT(event_station) as `total_visit_count`
FROM event_stations AS s
LEFT JOIN taps AS t
ON t.event_station = s.station_id
WHERE s.event_id = 6
GROUP BY s.station_id
ORDER BY s.station_id;
Alternatively, you could just use a RIGHT JOIN with your original join order. I personally don't like doing that, though, because I'm a LTR reader (first in order is more important).

Inequality in Mysql with count()

I have the following structure :
Table Author :
idAuthor,
Name
+----------+-------+
| idAuthor | Name |
+----------+-------+
| 1 | Renee |
| 2 | John |
| 3 | Bob |
| 4 | Bryan |
+----------+-------+
Table Publication:
idPublication,
Title,
Type,
Date,
Journal,
Conference
+---------------+--------------+------+-------------+------------+-----------+
| idPublication | Title | Date | Type | Conference | Journal |
+---------------+--------------+------+-------------+------------+-----------+
| 1 | Flower thing | 2008 | book | NULL | NULL |
| 2 | Bees | 2009 | article | NULL | Le Monde |
| 3 | Wasps | 2010 | inproceding | KDD | NULL |
| 4 | Whales | 2010 | inproceding | DPC | NULL |
| 5 | Lyon | 2011 | article | NULL | Le Figaro |
| 6 | Plants | 2012 | book | NULL | NULL |
| 7 | Walls | 2009 | proceeding | KDD | NULL |
| 8 | Juices | 2010 | proceeding | KDD | NULL |
| 9 | Fruits | 2010 | proceeding | DPC | NULL |
| 10 | Computers | 2010 | inproceding | DPC | NULL |
| 11 | Phones | 2010 | inproceding | DPC | NULL |
| 12 | Creams | 2010 | proceeding | DPC | NULL |
| 13 | Love | 2010 | proceeding | DPC | NULL |
+---------------+--------------+------+-------------+------------+-----------+
Table author_has_publication :
Author_idAuthor,
Publication_idPublication
+-----------------+---------------------------+
| Author_idAuthor | Publication_idPublication |
+-----------------+---------------------------+
| 1 | 1 |
| 2 | 2 |
| 3 | 3 |
| 4 | 4 |
| 1 | 5 |
| 2 | 5 |
| 3 | 5 |
| 3 | 6 |
| 4 | 7 |
| 4 | 8 |
| 4 | 9 |
| 4 | 10 |
| 3 | 11 |
| 3 | 12 |
| 2 | 13 |
+-----------------+---------------------------+
I want to obtain the list of all authors having published at least 2 times at conference DPC in 2010.
I achieved to get the list of autors that have published something, and the number of publication for each, but I can't get my 'at least 2' factor.
My following query
SELECT author.name, COUNT(name) FROM author INNER JOIN author_has_publication ON author.idAuthor=author_has_publication.Author_idAuthor INNER JOIN publication ON author_has_publication.Publication_idPublication=publication.idPublication AND publication.date=2010 AND publication.conference='DPC'GROUP BY author.name;
returns the following result (which is good)
+-------+-------------+
| name | COUNT(name) |
+-------+-------------+
| Bob | 2 |
| Bryan | 3 |
| John | 1 |
+-------+-------------+
but when I try to select only the one with a count(name)>=2, i got an error.
I tried this query :
SELECT author.name, COUNT(name) FROM author INNER JOIN author_has_publication ON author.idAuthor=author_has_publication.Author_idAuthor INNER JOIN publication ON author_has_publication.Publication_idPublication=publication.idPublication AND publication.date=2010 AND publication.conference='DPC'GROUP BY author.name WHERE COUNT(name)>=2;
When you use aggregation funcion you can filter with a proper operator named HAVING
Having worok on the result of the query (then pn the aggrgated result like count() ) instead of where that work on the original value of the tables rows
SELECT author.name, COUNT(name)
FROM author INNER JOIN author_has_publication
ON author.idAuthor=author_has_publication.Author_idAuthor
INNER JOIN publication
ON author_has_publication.Publication_idPublication=publication.idPublication
AND publication.date=2010 AND publication.conference='DPC'
GROUP BY author.name
HAVING COUNT(name)>=2;

MySQL, ordering GROUP BY

I have a table that has some values in it, along with the time that value was taken against an associated ID from another table.
I am looking to retrieve the latest value for every item in that table, and then order by those latest values.
Here is an SQL fiddle, http://www.sqlfiddle.com/#!2/0be99
And here is text output.
'hist' table
| HIST_ID | HIST_ITEM_ID | HIST_VALUE | HIST_TIME |
|---------|--------------|------------|------------|
| 1 | 1 | 1 | 1420291000 |
| 2 | 1 | 2 | 1420292000 |
| 3 | 1 | 3 | 1420293000 |
| 4 | 1 | 5 | 1420294000 |
| 5 | 1 | 10 | 1420295000 |
| 6 | 1 | 50 | 1420296000 |
| 7 | 1 | 60 | 1420297000 |
| 8 | 1 | 77 | 1420298000 |
| 9 | 1 | 90 | 1420299000 |
| 10 | 1 | 101 | 1420300000 |
| 11 | 2 | 1 | 1420291000 |
| 12 | 2 | 3 | 1420292000 |
| 13 | 2 | 7 | 1420293000 |
| 14 | 2 | 9 | 1420294000 |
| 15 | 2 | 15 | 1420295000 |
| 16 | 2 | 21 | 1420296000 |
| 17 | 2 | 33 | 1420297000 |
| 18 | 2 | 35 | 1420298000 |
| 19 | 2 | 55 | 1420299000 |
| 20 | 2 | 91 | 1420300000 |
'items' table
| ITEM_ID | ITEM_TITLE |
|---------|------------|
| 1 | ABCD |
| 2 | XYZ123 |
So, I can do something like...
select * from hist
inner join items on hist_item_id = item_id
group by hist_item_id
order by hist_value desc
However this returns me a grouping that I cannot order. How can I order this grouping? I had a look at other similar questions on here but was unable to apply their solutions successfully to my query to produce the desire result.
The desired result here would be to return.
HIST_ITEM_ID | ITEM_TITLE | HIST_VALUE |
|------------|------------|------------|
| 1 | ABCD | 101 |
| 2 | XYZ123 | 91 |
You can use a join to get the most recent history item. Then you can join back to the history table and the item table to get additional information:
select h.*, i.item_title
from (select hist_item_id, max(hist_id) as max_hist_id
from hist
group by hist_item_id
) hh join
hist h
on h.hist_id = hh.max_hist_id join
items i
on i.item_id = hh.hist_item_id;
Here is a SQL Fiddle.
You should use MAX function and group by the item id. That would look like this:
SELECT i.item_id, i.item_title, MAX(h.hist_value)
FROM items AS i
INNER JOIN hist AS h
ON i.item_id = h.hist_item_id
GROUP BY i.item_id

Creating a formulaic query with multiple columns and joined columns

I'm trying to produce a formula which pits our students' reward points against their negative behaviour flags.
Students are given LEAP points (in the transactions table) for their positive behaviour. They get more points depending on the category of their reward, i.e. Model Citizen gives the student 10 points.
On the other hand, students are given single Flags for negative behaviour. The category of the Flag is then weighted in a database table, i.e. the Aggressive Defiance category will have a high weighting of 4 whereas Low Level Disruption will only be worth 1.
The difficulty therefore is trying to factor in the Flag categories' weightings. They're stored in the categories table under the Weight column.
Here's the SQL fiddle: http://sqlfiddle.com/#!2/2e5756
In my head, the pseudo-SQL code would look something like this...
SELECT
CONCAT( stu.Surname, ", ", stu.Firstname ) AS `Student`,
SUM(t.Points) AS `LEAP Points`,
SUM(<<formula>>) AS `Flags`
( `LEAP Points` - `Flags` ) AS `Worked Out Points Thing`
FROM student stu
LEFT JOIN transactions t ON t.Recipient_ID = stu.id
LEFT JOIN flags f ON f.Student_ID = stu.id
LEFT JOIN categories c ON f.Category_ID = c.ID
GROUP BY stu.id
However, it's the <<formula>> that I have no idea how to implement in MySQL. It needs to be something like this:
SUM OF[ Each of Student's Flags * that Flag's Category Weighting ]
So, if a student has these flags...
#1 f.Reason "Being naughty", f.Category_ID "1", c.Title "Low Level Disruption", c.Weight "1"
#1 Reason "Aggressively naughty!", Category "Aggressive Defiance", Category Weighting "4"
#1 Reason "Missed detention", Category "Missed Detention", Category Weighting "3"
They would have a total of 1+4+3 = 9 points to use in the Worked Out Points Thing equation.
The desired output therefore is essentially...
Student LEAP Points Flags Equation Points LEAP Points minus Flag Points
D Wraight 1000 800 200
D Wraight2 500 800 -300
D Wraight3 1200 300 900
From the SQL fiddle above, here is the required output.. I've missed out some students because I had to work these out manually:
STUDENT FLAGS LEAP EQUATION
137608 4 (2+2) 12 (2+5+5) 8 (12-4)
139027 2 (2) 7 (2+5) 5 (7-2)
139041 4 (2+1+1+NULL) 8 (2+2+2+2) 4 (8-4)
139892 4 (4) 0 -4 (0-4)
138832 4 (4) 0 -4 (0-4)
34533 4 (4) 0 -4 (0-4)
137434 0 10 (2*5) 10 (10-0)
Which will help us to work out the choices we make available to each student when looking at end of year reward trips.
Hope that makes sense.. it's kinda boggled my head trying to explain it..
Thanks in advance,
figure out your 'formula' bit first because it's the deepest part. work outwards.
build a table of flags * weight per student
select sum(weight), student_id from flags f
join categories c
on f.category_id = c.id
group by student_id
so now you've got a table of flag values to minus from sum of transactions per student
select sum(points), recipient_id from transactions
group by recipient_id
so now we have two tables with positive and negative values by student id (assuming obviously that student id is recipient id)
you want those with transactions but without flags to appear in the result, so outer join.
and number minus null is null so ifnull function on the flags to get 0
select a.student, points - ifnull(penalties, 0) as netPoints
from
(select sum(points) as points, recipient_id as student from transactions
group by student) as a
left outer join
(select sum(weight) as penalties, student_id as student from flags f
join categories c
on f.category_id = c.id
group by student) as b
on
a.student = b.student
so with the name in there it's just
select
concat(firstname, ', ', surname) as name,
ifnull(points,0) as totalPoints,
ifnull(penalties,0) as totalPenalties,
ifnull(points,0) - ifnull(penalties, 0) as netPoints,
ifnull(countFlags, 0)
from
student
left join
(select sum(points) as points, recipient_id as student from transactions
group by student) as a
on student.id = a.student
left join
(select sum(weight) as penalties, count(f.id) as countFlags, student_id as student from flags f
join categories c
on f.category_id = c.id
group by student) as b
on
student.id = b.student
join condition is always from student's id column, which is never null.
there are probably more efficient ways, but who cares?
Returning to the question (and at the risk of repeating myself!), given the following data set, what would the desired result set look like...
SELECT * FROM flags;
+------+------------+----------+---------------------+-----------+-------------+--------------------------+---------------------+
| ID | Student_ID | Staff_ID | Datetime | Period_ID | Category_ID | Action_Taken_Category_ID | Action_Taken_Status |
+------+------------+----------+---------------------+-----------+-------------+--------------------------+---------------------+
| 8843 | 137608 | 35003 | 2014-03-11 08:31:00 | 8 | 16 | 7 | P |
| 8844 | 137608 | 35003 | 2014-03-11 08:31:00 | 8 | 16 | 7 | P |
| 8845 | 139027 | 35003 | 2014-03-11 08:31:00 | 8 | 16 | 7 | P |
| 8846 | 139041 | 35003 | 2014-03-11 08:31:00 | 8 | 16 | 7 | P |
| 8847 | 139041 | 34961 | 2014-03-11 09:01:02 | 2 | 12 | 26 | P |
| 8848 | 139041 | 34996 | 2014-03-11 09:23:21 | 3 | 12 | 27 | C |
| 8849 | 139041 | 35022 | 2014-03-11 11:07:46 | 4 | 34 | 28 | P |
| 8850 | 139892 | 138439 | 2014-03-11 11:12:47 | 4 | 21 | 7 | C |
| 8851 | 138832 | 138439 | 2014-03-11 11:12:48 | 4 | 21 | 7 | C |
| 8852 | 34533 | 138439 | 2014-03-11 11:12:48 | 4 | 21 | 7 | C |
+------+------------+----------+---------------------+-----------+-------------+--------------------------+---------------------+
SELECT * FROM categories;
+----+------+--------------------------------------+--------+----------+
| ID | Type | Title | Weight | Added_By |
+----+------+--------------------------------------+--------+----------+
| 10 | F | Low level disruption | 1 | NULL |
| 11 | F | Swearing directly at another student | 2 | NULL |
| 12 | F | Late | 1 | NULL |
| 13 | F | Absconded | 3 | NULL |
| 14 | F | Refusal to follow instruction | 3 | NULL |
| 15 | F | Smoking | 2 | NULL |
| 16 | F | No homework | 2 | NULL |
| 17 | F | Disruptive outside classroom | 2 | NULL |
| 18 | F | Eating/drinking in lesson | 1 | NULL |
| 19 | F | Incorrect uniform/equipment | 1 | NULL |
| 20 | F | Phone out in lesson | 3 | NULL |
| 21 | F | Aggressive defiance | 4 | NULL |
| 22 | F | Missed detention | 3 | NULL |
| 23 | F | Inappropriate behaviour/comments | 3 | NULL |
| 32 | F | IT Misuse | NULL | NULL |
| 34 | F | Inappropriate attitude towards staff | NULL | NULL |
| 35 | F | Care & Guidance | NULL | NULL |
+----+------+--------------------------------------+--------+----------+
SELECT * FROM transactions;
+----------------+------------+----------+--------------+--------+-------------+
| Transaction_ID | Datetime | Giver_ID | Recipient_ID | Points | Category_ID |
+----------------+------------+----------+--------------+--------+-------------+
| 34 | 2011-09-07 | 35019 | 137608 | 2 | 1 |
| 35 | 2011-09-07 | 35019 | 139027 | 2 | 1 |
| 36 | 2011-09-07 | 35019 | 139041 | 2 | 1 |
| 37 | 2011-09-07 | 35019 | 139041 | 2 | 1 |
| 38 | 2011-09-07 | 35019 | 139041 | 2 | 1 |
| 39 | 2011-09-07 | 35019 | 139041 | 2 | 1 |
| 40 | 2011-09-07 | 35019 | 137434 | 2 | 1 |
| 41 | 2011-09-07 | 35019 | 137434 | 2 | 1 |
| 42 | 2011-09-07 | 35019 | 137434 | 2 | 1 |
| 43 | 2011-09-07 | 35019 | 137434 | 2 | 1 |
| 44 | 2011-09-07 | 35006 | 137434 | 2 | 1 |
| 45 | 2011-09-07 | 35006 | 90306 | 2 | 1 |
| 46 | 2011-09-07 | 35006 | 90306 | 2 | 1 |
| 47 | 2011-09-07 | 35006 | 90306 | 2 | 1 |
| 48 | 2011-09-07 | 35023 | 137608 | 5 | 2 |
| 49 | 2011-09-07 | 35023 | 139027 | 5 | 2 |
| 50 | 2011-09-07 | 35023 | 139564 | 5 | 2 |
| 51 | 2011-09-07 | 35023 | 139564 | 5 | 2 |
| 52 | 2011-09-07 | 35023 | 139564 | 5 | 2 |
| 53 | 2011-09-07 | 35023 | 137608 | 5 | 3 |
+----------------+------------+----------+--------------+--------+-------------+
SELECT id,UPN,Year_Group,Tutor_Group,SEN_Status,Flags FROM student;
+--------+---------------+------------+-------------+------------+--------+
| id | UPN | Year_Group | Tutor_Group | SEN_Status | Flags |
+--------+---------------+------------+-------------+------------+--------+
| 137608 | A929238400044 | 11 | 11VID | A | |
| 139027 | A929238401045 | 10 | 10KS | | |
| 139041 | A929238402017 | 10 | 10RJ | A | FSM |
| 139892 | A929238403018 | 9 | 9BW | | |
| 139938 | A929238403020 | 9 | 9RH | | |
| 137434 | A929238500027 | 11 | 11VID | | |
| 138832 | A929238502002 | 10 | 10RY | A | FSM,PA |
| 34533 | A929238599028 | 0 | | | PA |
| 139564 | A929241500025 | 12 | | | PA |
| 90306 | A929253100006 | 12 | SLH | A | PA |
+--------+---------------+------------+-------------+------------+--------+