So i've got two models, Client and Project, and Client has a hasMany relationship with projects. I'm just trying to add the project count for the client into the JSON response but I can't get it to work.
My controller just returns all the projects;
public function index(Client $client)
{
return $client->all();
}
And my model contains the below;
protected $appends = ['client_projects_count'];
/**
* Create a relationship between this client and it's projects
*/
public function clientProjects() {
return $this->hasMany('App\Project');
}
public function getClientProjectsCountAttribute()
{
return $this->withCount('clientProjects');
}
This just adds client_projects_count to the response but it's an empty array. I'm close, if I dd($this->withCount('clientProjects')->get()) I can see the client_projects_count with the correct count, but if I remove the dd and keep the ->get() then I get an internal server error.
Also, it is possible to only load this for the index() method rather than every one?
From the Documentation
$clients = Client::withCount('projects')->get();
foreach ($clients as $client) {
echo $client->projects_count;
}
So I managed to resolve it myself, although I'm sure their must be a nicer way.
Client.php
protected $appends = ['client_projects_count'];
/**
* Create a relationship between this client and it's projects
*/
public function clientProjects() {
return $this->hasMany('App\Project');
}
public function clientProjectsCount()
{
return $this->clientProjects()->selectRaw('client_id, count(*) as aggregate')->groupBy('client_id')->get();
}
public function getClientProjectsCountAttribute()
{
return isset($this->clientProjectsCount()[0]) ? $this->clientProjectsCount()[0]->aggregate : 0;
}
Related
I need to be able to convert a hasMany() relation, which queries and return an array into a hasOne() relation which returns object|null.
Use case:
public function getItems() : \yii\db\ActiveQuery {
return $this->hasMany(Item::class, ['parent_id' => 'id']);
}
I want to create a relation which returns one specific Item object (or null if it does not exist).
I would like to do something like this:
public function getPrimaryItem() : \yii\db\ActiveQuery {
return $this->getItems()->andWhere(["primary"=>true])->toHasOne();
}
Please do not tell me to call ->one() on the original query, because that is not going to solve the problem. I need to be able to:
call $model->primaryItem and receive either Item or null
call $model->getPrimaryItem() and receive the relation's ActiveQuery
You can toggle it by multiple property of \yii\db\ActiveQuery
public function getPrimaryItem() : \yii\db\ActiveQuery {
$query = $this->getItems();
$query->multiple = false;
//Your logics
$query->andWhere(["primary"=>true])
return $query;
}
Current laravel models relations: ParentModel can have many documents, ChildModel can have many documents, same Documents can be belonged to any of ParentModel and ChildModel.
Also ChildModel always belongs to one ParentModel. ParentModel can have multiple ChildModels.
App\ParentModel relationships
...
public function childmodels()
{
return $this->hasMany('App\ChildModel');
}
public function documents()
{
return $this->morphToMany('App\Document', 'documentable');
}
...
App\ChildModel relationships
...
public function parentmodel()
{
return $this->belongsTo('App\ParentModel');
}
public function documents()
{
return $this->morphToMany('App\Document', 'documentable');
}
...
App\Document
...
public function parentmodels()
{
return $this->morphedByMany('App\ParentModel','documentable');
}
public function childmodels()
{
return $this->morphedByMany('App\ChildModel','documentable');
}
...
Now I'm trying to get all records of ChildModels (1) which have documents with specific type and (2) its ParentModel can also have documents.
The (1) first goal can be reached with such ChildModel method.
/* checking GET param to join this condition to final query */
if($request->has('report') && $request->input('report') == 'on') {
/* get all documents related to CurrentModel */
$query->whereHas('documents',function (Builder $query) {
$query->where('type', 1);
});
}
But this obviously doesnt include records of ChildModels, ParentModel of which has documents with specific type.
So the question is: how to include such condition into ChildModel query builder?
Found the easy way to access relations in builder
$query->whereHas('parentmodels.documents', function(Builder $query){
$query->where('type',1);
});
I have a customer table which has a field called 'policy_id', where policy_id points to policy table. It is a null-able field, ie. Some customers may not have a policy.
I have a relationship code like this in Customer.php
public function policy() {
return $this->hasOne('App\Models\Policy', "id", "policy_id");
}
But when I issue a search request I am getting error like this:
Illuminate\Database\Eloquent\ModelNotFoundException: No query results for model [App\Models\Policy]
If I modify the function like this:
public function policy() {
if ($this->getAttribute('policy_id')) {
return $this->hasOne('App\Models\Policy', "id", "policy_id");
} else {
return null
}
}
But I am getting an error like this:
Call to a member function getRelationExistenceQuery() on null
Here is my search code:
$c = new Customer();
return Customer::doesntHave('policy')->orWhere(function (Builder $query) use ($req) {
$query->orWhereHas('policy', function (Builder $query) use ($req) {
$p = new Policy();
$query->where($req->only($p->getFillable()))
->orWhereBetween("policy_period_from", [$req->policy_period_start_from, $req->policy_period_start_to])
->orWhereBetween("policy_period_to", [$req->policy_period_end_from, $req->policy_period_end_to])
->orWhereBetween("payment_date", [$req->payment_date_from, $req->payment_date_to]);
});
})->where($req->only($c->getFillable()))->get();
Am I missing something or are there any other ways to do this?
PS: While debugging the above search code is returning successfully, but the exception happening from somewhere inside Laravel after the prepareResponse call.
Thanks in advance.
return $this->hasOne('App\ModelName', 'foreign_key', 'local_key');
Change the order, put the foreign_key policy_id in front of id
In your Customer Model, you need to use belongsTo method:
public function policy() {
return $this->belongsTo('App\Models\Policy', "policy_id", "id");
}
And In your Policy Model, use hasOne:
public function customer() {
return $this->hasOne('App\Models\Customer', "policy_id", "id");
}
First of all, you placed the wrong params.
$this->belongsTo('App\Models\Policy', "FK", "PK");
public function policy() {
return $this->belongsTo('App\Models\Policy','policy_id', 'id');
}
And for null value of policy_id you can use withDefault();
public function policy() {
return $this->belongsTo('App\Models\Policy','policy_id', 'id')->withDefault([
'name' => 'test'
]);;
}
there's a number of problems there but can you perhaps specify the namespace and the class of both your models - Customer and Policy.
By default, the models you create with php artisan make:model will use the \App namespace e.g. \App\Customer and \App\Policy.
Just double check that.
Also, with regards to the relationship, if the Laravel conventions have been followed you could just:
In the Customer model
public function policy() {
return $this->belongsTo(Policy::class);
}
In the Policy model
public function customer() {
return $this->hasOne(Customer::class);
}
of if a multiple customers can be under one policy
public function customers() {
return $this->hasMany(Customer::class);
}
Good luck
I create a core class named MY_Model that extends CI_Model. In this class, I create a method chaining to get all record with pagination like this :
// Take record with paging.
public function get_all_paged()
{
// get argument that passed
$args = func_get_args();
// get_all_paged($offset)
if (count($args) < 2) {
$this->get_real_offset($args[0]);
$this->db->limit($this->_per_page, $this->_offset);
}
// get_all_paged(array('status' => '1'), $offset)
else {
$this->get_real_offset($args[1]);
$this->db->where($args[0])->limit($this->_per_page, $this->_offset);
}
// return all record
return $this->db->get($this->_tabel)->result();
}
So , I just used like this on my controller,
for example
public function index($offset = NULL) {
$karyawan = $this->karyawan->get_all_paged($offset); //get all
}
I am realy confuse to get all record using join, I know join in CI like this :
public function get_all_karyawan() {
$this->db->select('tb_1 , tb_2');
$this->db->from('tb_1');
$this->db->join('tb_2', "where");
$query = $this->db->get();
return $query->result();
}
How to make it into chain in MY_Model?
Any help it so appreciated ...
The good thing in query builder, you can chain your db methods, till get(). So you can define, selects, where queries, limits in different ways.
For example:
public function category($category)
{
$this->db->where('category_id', $category);
return $this;
}
public function get_posts()
{
return $this->db->get('posts')->result();
}
And you can get all posts:
$this->model->get_posts();
Or by category:
$this->model->category(2)->get_posts();
So upon this, in your model:
public function get_all_karyawan() {
$this->db->select('tb_1 , tb_2');
$this->db->join('tb_1', "where");
// Here you make able to chain the method with this
return $this;
}
In your controller:
public function index($offset = NULL) {
$karyawan = $this->karyawan->get_all_karyawan()->get_all_paged($offset);
}
I have this model for Author:
<?php
class Author extends Eloquent {
public function albums()
{
return $this->belongsToMany('Album')->withPivot('city');
}
}
And this model for Album:
<?php
class Album extends Eloquent {
public function artist()
{
return $this->belongsTo('Artist');
}
public function authors()
{
return $this->belongsToMany('Author')->withPivot('city');
}
}
To get a model I can easily do this:
$author = Author::where('name','=','Chester Bennington')->first()->toJson();
and it'll return something like this (as JSON):
{"id":3,"name":"Chester Bennington","created_at":"2014-06-29 16:10:21","updated_at":"2014-06-29 16:10:21"}
See that it won't return the albums related to it. To get the albums I would have to do this: $author->albums->toJson()
Since I'm doing an API and it returns everything as JSON, is there a way to get the model and ALL its attributes without specifying which ones to get??
If you eager load the relationships you want, it'll be included in your JSON:
Author::with('albums')->where('name', 'Chester Bennington')->first()->toJson();