Select and show according to the year/monts - mysql

Question

can you help me to select, and sum all the values from the table, and show them according to the months/this year?
Table looks as follow"
| ID | value | reg_date |
| 1 | 2 | 2017-01-11 02:26:22 |
| 2 | 2 | 2017-03-12 12:22:23 |
| 3 | 2 | 2017-04-13 08:26:33 |
| 4 | 3 | 2017-04-15 12:26:16 |
| 5 | 5 | 2017-05-15 19:26:13 |
| 6 | 2 | 2017-06-14 17:12:16 |
| 7 | 6 | 2017-07-12 14:26:16 |
| 8 | 1 | 2015-09-11 13:23:16 |
| 9 | 1 | 2016-09-05 12:26:34 |
| 10 | 1 | 2017-12-11 19:11:45 |
And I would like to get something like:
| value | reg_date |
| 2 | 2017-01 |
| 0 | 2017-02 |
| 2 | 2017-03 |
| 5 | 2017-04 |
| 5 | 2017-05 |
| 2 | 2017-06 |
| 6 | 2017-07 |
| 0 | 2017-08 |
| 2 | 2017-09 |
| 0 | 2017-10 |
| 0 | 2017-11 |
| 1 | 2017-12 |

Answer 1

I tried following approach to solve your problem:
--created sample table datte which will contain following records
create table datte (id int identity(1,1), value int, reg_date datetime);
insert into datte(value,reg_date) values (2,'2017-01-11 02:26:22');
insert into datte(value,reg_date) values (2,'2017-03-12 12:22:23');
insert into datte(value,reg_date) values (2,'2017-04-13 08:26:33');
insert into datte(value,reg_date) values (3,'2017-04-15 12:26:16');
insert into datte(value,reg_date) values (5,'2017-05-15 19:26:13');
insert into datte(value,reg_date) values (2,'2017-06-14 17:12:16');
insert into datte(value,reg_date) values (6,'2017-07-12 14:26:16');
insert into datte(value,reg_date) values (1,'2015-09-11 13:23:16');
insert into datte(value,reg_date) values (1,'2016-09-05 12:26:34');
insert into datte(value,reg_date) values (1,'2017-12-11 19:11:45');
then i created a table type to store the year list
create type [values] as table(
[year] int
);
You can also use temp table here.
-- create temp table to store the output
create table #tempdate([year] varchar(1000), [count] int);
--create a variable of table type values
declare #years as [values] ,
--create following variable to process the data
#year int, #minyear int,#maxyear int;
--insert years in table type variable #years
insert into #years
select YEAR(reg_date) from datte
group by YEAR(reg_date)
--store min year and max year value in variable for processing
select #minyear = min([year]) from #years;
select #maxyear = max([year]) from #years;
-- logic to create query to get desired output
while(#minyear <= #maxyear)
begin
SET #YEAR = #minyear;
IF EXISTS(SELECT 1 FROM DATTE WHERE REG_DATE LIKE '%'+CONVERT(VARCHAR,#YEAR)+'%')
BEGIN
--insert the yearly in temp table
insert into #tempdate
select cast(convert(varchar,#year) as varchar) + '-' +cast(m.number as varchar) , isnull(total_qty,0) as total_qty
from (
select number
from master.dbo.spt_values
where type = 'P' and number between 01 and 12
) m
left join (
select MONTH(reg_date) as mth, SUM(value) as total_qty
from datte
where YEAR(reg_date) = #year
group by MONTH(reg_date)
) s on m.number = s.mth ;
END
SET #MINYEAR = #MINYEAR + 1;
end
--print the data
select [count],[year] from #tempdate
hope this helps,
Jai

Answer 2

You can format how date is displayed and group by this results
SELECT count(ID), DATE_FORMAT(reg_date, "%Y-%m") AS rd FROM tablename GROUP BY rd

Answer 3

Also works something like:
SELECT start_date,
IFNULL(TIME_FORMAT(SEC_TO_TIME (sum(value)),'%l.%i' ),0)
as time01 FROM table WHERE YEAR(start_date) = YEAR(CURDATE())
and MONTH(start_date) = 01
SELECT start_date,
IFNULL(TIME_FORMAT(SEC_TO_TIME (sum(value)),'%l.%i' ),0)
as time02 FROM table WHERE YEAR(start_date) = YEAR(CURDATE())
and MONTH(start_date) = 02
....
Thanks guys a lot.