select all rows with distinct and condition in MySQL - mysql

Question

Hi guys I new in mySQL and I have problem with query. I was trying to write some Query which get me all records from table and if I have two records with the same date i need get only record between this two which have manual_selection = 1.
So result should be all records from my table except id = 1401 and id = 1549
my table
I tried to combine how can I get this records like this:
SELECT * FROM project.score WHERE project_id = 358
AND crawled_at IN(SELECT crawled_at FROM project.score WHERE project_id = 358
AND manual_selection = 1 GROUP BY crawled_at)
ORDER BY crawled_at;
SELECT * FROM project.score WHERE project_id = 358
GROUP BY crawled_at HAVING manual_selection = 1;
but all my way always get only rows with manual_selection = 1. I havent idea how can I distinct rows with duplicate "crawled_at" on case where manual_selection = 1. Can someone help me?

Answer 1

Try this:
select main.id, main.project_id, main.crawled_at, main.score, main.manual_selection
from dcdashboard.moz_optimization_keywords as main
left join dcdashboard.moz_optimization_keywords as non_manual_selection on non_manual_selection.crawled_at = main.crawled_at and non_manual_selection.manual_selection != 1
group by main.crawled_at;
Result with data set from question:
+------+------------+---------------------+-------+------------------+
| id | project_id | crawled_at | score | manual_selection |
+------+------------+---------------------+-------+------------------+
| 807 | 360 | 2016-02-06 00:00:00 | 76 | 0 |
| 1001 | 360 | 2016-02-20 00:00:00 | 76 | 0 |
| 223 | 360 | 2016-11-28 00:00:00 | 76 | 0 |
| 224 | 360 | 2016-12-05 00:00:00 | 76 | 0 |
| 670 | 360 | 2016-12-19 00:00:00 | 76 | 0 |
| 1164 | 360 | 2017-04-19 00:00:00 | 78 | 1 |
| 1400 | 360 | 2017-09-13 00:00:00 | 96 | 1 |
| 1548 | 360 | 2017-09-15 00:00:00 | 96 | 1 |
+------+------------+---------------------+-------+------------------+
8 rows in set (0.00 sec)