SELECT SampleSheet.Id,SampleSheet.Sample_Complete,SampleSheet.SampleName,"
+ "count(Job.sampleId) AS NumberOfSamples FROM (SampleSheet "
+ "LEFT JOIN Job ON SampleSheet.Id = Job.sampleId) "
+ "WHERE SampleSheet.Sample_Complete=?"
+ "GROUP BY SampleSheet.Id
Can anynone please tell me whats wrong in this query. I am getting syntax error.
It works Fine if I dont use the Where Condition. But I need to get the rows for the ones where the sample is complete.
SELECT SampleSheet.Id,SampleSheet.Sample_Complete,SampleSheet.SampleName,count(Job.sampleId) AS NumberOfSamples FROM (SampleSheet LEFT JOIN Job ON SampleSheet.Id = Job.sampleId) GROUP BY SampleSheet.Id
There are couple of suggestions. It seems to be space issue after WHERE clause
+ "WHERE SampleSheet.Sample_Complete=?"
+ "GROUP BY SampleSheet.Id
instead
+ "WHERE SampleSheet.Sample_Complete=? "
+ "GROUP BY SampleSheet.Id
You could also remove ( just after FROM and obviously ) as well. It is not required.
FROM (SampleSheet "
+ "LEFT JOIN Job ON SampleSheet.Id = Job.sampleId) "
Related
native Query I Wrote in My Repository
If i remove order by condition in the below query , it is giving some records but i want it in some order so i added order by condition then it not showing records only . but the same mysql query with order by condition is giving some records in mysql workbench.
#Query(value = "SELECT l.id AS id,l.first_name AS firstName,l.last_name AS lastName,"
+ " l.email AS email,l.phone AS phone,l.place AS place,l.course_id AS courseId,"
+ " c.name AS courseName,l.source AS source,l.enquiry_for AS enquiryFor,"
+ " l.appointment_date AS appointmentDate,l.description AS description,"
+ " l.discount AS discount,l.status AS status,l.assignee_id AS assigneeId,"
+ " ase.first_name AS assigneeFirstName,ase.last_name AS assigneeLastName,"
+ " l.assignor_id AS assignorId,asr.first_name AS assignorFirstName,"
+ " asr.last_name AS assignorLastName,l.active AS active,l.created_date AS createdDate,"
+ " l.updated_date AS updatedDate,(SELECT comments FROM reviews where created_date IN"
+ " (SELECT MAX(created_date) from reviews where lead_id=l.id)) AS latestComment FROM "
+ " leads l JOIN users AS ase ON l.assignee_id = ase.id JOIN users AS asr ON "
+ " l.assignor_id = asr.id JOIN courses AS c ON l.course_id =c.id WHERE l.status!='Draft'"
+ " AND (l.first_name LIKE '%:keyword%' OR l.last_name LIKE '%:keyword%' OR l.phone LIKE"
+ " '%:keyword%') ORDER BY -l.appointment_date DESC,l.created_date ASC", nativeQuery=true)
List<Leads> searchLeadsForAdmin(#Param("keyword") String searchKeyword);
i don't know Where am i going wrong , attached image below mysql query result came in workbench.
I found the answer to my question. It was a concatenation issue. In the second last line of my query after 'l.phone LIKE' I added the value in the next line.
+ " AND l.first_name LIKE %:keyword% OR l.last_name LIKE %:keyword% OR "
+ " l.phone LIKE %:keyword% ORDER BY -l.appointment_date DESC,"
+ " l.created_date ASC", nativeQuery = true)
The above query works.
My goal is to re-use the result from a SELECT statement to be used in SQL EXISTS statement.
The general idea looks like this:
SELECT *
FROM table
WHERE col1=1
OR EXISTS (
SELECT 1 // this is an exact copy of the SELECT statement above.
FROM table
WHERE col=1
)
The actual SQL statement I am trying to reduce:
"SELECT user_detail.user, user_detail.name, channel_member.role " +
"FROM user_detail " +
"JOIN channel_member ON user_detail.user=channel_member.user " +
"AND channel_member.uuid=#{channelUuid} " +
"WHERE user_detail.user=#{username} " +
"OR EXISTS ( " +
" SELECT 1" +
" FROM user_detail " +
" JOIN channel_member ON user_detail.user=channel_member.user " +
" AND channel_member.uuid=#{channelUuid} " +
" WHERE user_detail.user=#{username} " +
")"
You can only do this if your version of MySQL supports window functions, ie. version >= 8.0
You can use conditional window aggregation, like this:
SELECT *
FROM (
SELECT *, COUNT(CASE WHEN col1 = 1 THEN 1 END) OVER () AS CountMatches
FROM table
) t
WHERE CountMatches > 0;
Depending on the number of rows matching to non-matching, this may be more or less performant. You need to test.
This query:
SELECT *
FROM table
WHERE col1 = 1 OR
EXISTS (SELECT 1 // this is an exact copy of the SELECT statement above.
FROM table
WHERE col=1
)
Doesn't really make sense. It is saying to return all rows if col = 1 is in the table -- but then it filters to check if any row has col = 1. So it is equivalent to:
SELECT *
FROM table
WHERE (SELECT 1 FROM table t2 WHERE t2.col = 1);
I strongly suspect that you intend NOT EXISTS -- so get everything with 1. If there is no 1 then return everything:
SELECT *
FROM table
WHERE col1 = 1 OR
NOT EXISTS (SELECT 1 // this is an exact copy of the SELECT statement above.
FROM table
WHERE col = 1
);
This should work fine with tables -- and is in fact probably optimal with the right indexes.
If "table" is really a complex query, then you might consider window functions:
select t.*
from (select t.*,
sum( col = 1 ) as num_1s
from t
) t
where col = 1 or num_1s = 0;
If you want to use any conditional statement on the query you are running you will need to wrap the query and put it in a FROM statement and then run the conditional outside of the query, like so....
SELECT aliasName.*
FROM
(SELECT *
FROM table
WHERE col1=1) aliasName
WHERE EXISTS aliasName //this is the conditionl statement OUTSIDE of the query you built.
Let me know how you do...
For Mr./Ms. Barmar:
The idea
// Idea:
// If one of the row have col1 with value 1.
// Then return all of the row, or return empty []
// SELECT *
// FROM table
// WHERE col1=1
// OR EXISTS (
// SELECT 1
// FROM table
// WHERE col=1
// )
The solution
"WITH temp AS (" +
" SELECT user_detail.user, user_detail.name, channel_member.role " +
" FROM user_detail " +
" JOIN channel_member ON user_detail.user=channel_member.user " +
" AND channel_member.uuid=#{channelUuid} " +
") " +
"SELECT * " +
"FROM temp " +
"WHERE user=#{username} " +
" OR EXISTS ( " +
" SELECT 1" +
" FROM temp " +
" WHERE user=#{username} " +
" )"
The solution above use WITH clause as recommended by Mr./Ms. Barmar, I am posting this, so you can inspect whether this is logical or not.
My Query:
entityManager.createQuery("SELECT " +
"q.id, " +
"q.title, " +
"q.user.fullName, " +
"q.user.reputationCount, " +
"q.viewCount, " +
"q.countValuable, " +
"q.persistDateTime, " +
"t.id, " +
"t.name, " +
"t.description, " +
"(SELECT COUNT (a) FROM Answer a WHERE a.question.id = q.id), " +
"(SELECT a.isHelpful FROM Answer a WHERE a.question.id = q.id) " +
"FROM Question q JOIN q.tags t")
Here I get the error - [21000][1242] Subquery returns more than 1 row
By the method of exceptions, I determined that the error in this query string:
"(SELECT a.isHelpful FROM Answer a WHERE a.question.id = q.id) "
How to make the correct request so that there is no this error? Thank!
Two common ways are aggregation and limiting:
(SELECT MAX(a.isHelpful) FROM Answer a WHERE a.question.id = q.id)
(SELECT a.isHelpful FROM Answer a WHERE a.question.id = q.id LIMIT 1)
However, those are really just hacks to get around an "issue" with the data. I put issue in quotes, but the real issue is probably your understanding of data and not the data itself.
You should understand why there are duplicates. Then decide which value you want. And implement the correct logic for what you want.
Subquery returns more than 1 row, this simply means that your query is not returning a single row for the outer select statement to work.
"(SELECT a.isHelpful FROM Answer a WHERE a.question.id = q.id) "
you have to apply a set of conditions to filter out your data uniquely or use joins to combine your table Answer and Question and then filter data accordingly.
you can also group each row data in one column by GROUP_CONCAT Mysql function like this :
"(SELECT GROUP_CONCAT(a.isHelpful) FROM Answer a WHERE a.question.id = q.id) "
Although GROUP_CONCAT is not available in Mysql, for that you can also bind SQL function in hibernate as described in this post.
After a day of various trial and error, I found the following solution, I hope someone will broaden their horizons and help in solving their problem:
entityManager.createQuery("SELECT " +
"q.id, " +
"q.title, " +
"q.user.fullName, " +
"q.user.reputationCount, " +
"q.viewCount, " +
"q.countValuable, " +
"q.persistDateTime, " +
"t.id, " +
"t.name, " +
"t.description, " +
"(SELECT COUNT (a) FROM Answer a WHERE a.question.id = q.id), " +
"(SELECT CASE WHEN MAX (a.isHelpful) > 0 THEN true ELSE false END FROM Answer a WHERE a.question.id = q.id) " +
"FROM Question q JOIN q.tags t")
I would like to give extra parameter with join condition in hql.
In sql query I write
select a.*,ur.fname,ur.lname
from
atom as a
left join user as ur
on
a.id=ur.id
left join album as al
on
a.id=al.aid
and al.name='Profile'
left join post_images as pi
on
a.id=pi.aid
and pi.is_album_cover='yes'
where
(ur.fname like '%n%'
or ur.fname like '%n%')
and a.status='active';
which work propery and give desired result.
In hql I dont know how to give extra parameter with join
for fetching data I write(without extra parameter)
feeds = (List<Atom>) session.createQuery(
"select distinct atom from Atom as atom "
+ "left join fetch atom.albums as album "
+ "left join fetch album.postImageses as coverImage "
+ "left join fetch atom.user as user "
+ "where "
+ "(atom.user.fname like :name "
+ "or atom.user.lname like :name )"
+ "and album.name=:albumName "
+ "and coverImage.isAlbumCover=:isCover "
+ "and atom.status=:status ")
.setParameter("albumName", "Profile")
.setParameter("name", '%' + name + '%')
.setParameter("name", '%' + name + '%')
.setParameter("isCover", "yes")
.setParameter("status", "active")
.setFirstResult(0)
.setMaxResults(30)
.list();
Which is not giving any result how can I give extra parameter with join
In HQL, You may supply extra join conditions using the HQL with keyword.
Chech Associations and joins in HQL
Try this:
Your HQL::
select distinct atom
from Atom as atom
left join atom.albums as album with album.name= "Profile"
left join atom.postImageses as coverImage with coverImage.isAlbumCover="yes"
left join atom.user as user
where (user.fname like name or user.lname like name) and atom.status="active";
Your CODE::
feeds = (List<Atom>) session.createQuery(
"select distinct atom from Atom as atom "
+ "left join atom.albums as album with album.name=:albumName "
+ "left join atom.postImageses as coverImage with coverImage.isAlbumCover=:isCover "
+ "left join atom.user as user "
+ "where (user.fname like :name or user.lname like :name) "
+ "and atom.status=:status ")
.setParameter("albumName", "Profile")
.setParameter("name", '%' + name + '%')
.setParameter("isCover", "yes")
.setParameter("status", "active")
.setFirstResult(0)
.setMaxResults(30)
.list();
I need help.... I am not good at SQL I get this error when I try to apply a JOIN:
[ Token line number = 1,Token line offset = 66,Token in error = JOIN ]
This is My SQL:
var query = "SELECT Team.TeamName, Fixtures.HomeTeam" +
"FROM Team" +
"LEFT JOIN Fixtures" +
"ON Team.TeamId=Fixtures.HomeTeam" +
"ORDER BY Team.TeamName";
Team Table Has PK: TeamId
Fixture Table Has FK: HomeTeam
I am using WebMatrix 2. Razor WebPages
No spaces between line concatenations. Change every line to include space at the end.
var query = "SELECT Team.TeamName, Fixtures.HomeTeam " +
"FROM Team " +
"LEFT JOIN Fixtures " +
"ON Team.TeamId=Fixtures.HomeTeam " +
"ORDER BY Team.TeamName";
As pointed by Charles Brentana, you have missed the spaces in your SQL command.
Maybe a better solution is to you use a verbatim string literal, i.e. a string created with an # character before the double-quote character, that can span multiple lines:
var query = #"SELECT Team.TeamName, Fixtures.HomeTeam
FROM Team
LEFT JOIN Fixtures
ON Team.TeamId=Fixtures.HomeTeam
ORDER BY Team.TeamName";
You need spaces between your strings.
I avoid this by putting the space as the first character, so it's really obvious when you forget to code it:
var query = "SELECT Team.TeamName, Fixtures.HomeTeam" +
" FROM Team" +
" LEFT JOIN Fixtures" +
" ON Team.TeamId=Fixtures.HomeTeam" +
" ORDER BY Team.TeamName";
If you consistently code this way you'll be able to spot any missing spaces instantly.