table:tab1
id date_time zoneid accountid slotid trequest bidder width height
_50832 2017-09-04 15:41:06 153 1654 153x468x60 10 aaa 468 60
_50832 2017-09-04 15:41:06 152 1654 152x468x60 10 bbb 468 60
table:tab2
id date_time zoneid accountid slotid bidder count
_50832 2017-09-04 15:41:06 152 1654 152x468x60 bbb 6
_50832 2017-09-04 15:41:06 152 1654 152x468x60 bbb 4
_50832 2017-09-04 15:41:06 153 1654 153x468x60 aaa 9
_50832 2017-09-04 15:41:06 153 1654 153x468x60 aaa 1
below is my query:
SELECT SUM(req.trequest) as REQ, SUM(win.count) as IMP
FROM tab1 as req
JOIN tab2 as win ON (req.id=win.id AND req.zoneid=win.zoneid)
GROUP BY req.zoneid
I get below result,
REQ IMP
20 10
20 10
IMP count is correct but I get wrong REQ count. My expected result is
REQ IMP
10 10
10 10
How to get my expected result?
Lets find the sum of trequest and count separately based on zoneid and id.Then use these two results ( t1 and t2 ) in the inner join.
Count mismatch problem shown in the question occur due to multiple rows satisfying the joining conditions.
In this solution we will only have one entry for each zoneid in both the results ( t1 and t2 ). So the problem is avoided.
Note: You can remove the id column from the GROUP BY clause if it doesn't make any difference.
SELECT t1.id, t1.zoneid, t1.REQ, t2.IMP FROM
(SELECT id,zoneid,SUM(trequest) as REQ
FROM tab1 GROUP BY zoneid,id ) t1
INNER JOIN
(SELECT id,zoneid SUM(win.count) as IMP
FROM tab2 GROUP BY zoneid,id ) t2
ON t1.id = t2.id
AND t1.zoneid = t2.zoneid
Let's try first sumwin.count and group records in sub-query, after it join tables. Try in following:
SELECT SUM(req.trequest) as REQ, SUM(win.count) as IMP
FROM tab1 as req
JOIN (
SELECT SUM(win.count) as IMP, win.zoneid, win.id
FROM tab2 as win
GROUP BY win.zoneid, win.id) AS win ON req.id=win.id AND req.zoneid=win.zoneid
GROUP BY req.zoneid
Instead of req.zoneid. You should try win.zoneid. What seems is that the rows in table 1 are counted multiple times as zoneid in table 2 comes twice. So win.zoneid would group it and avoid the repetition.
Updated: The solution posted by #mayur panchal is the correct one as you don't need to SUM the rows in first table as they belong to different zoneid. If you SUM them you will obviously get the 20 repeated twice.
Related
I have two tables that I need to merge.
Table 1 is :
ID
Product code
Spend
1
101
100
1
102
200
1
103
300
2
201
400
3
301
500
3
302
600
Table 2 has
ID
Product code
Spend
Product tenure
1
101
100
20
1
102
200
30
3
302
600
40
I want to merge these such that only ID's present in table 2 are retained from table 1. Table 2 does not contain all the product codes for each ID, but I want my final table to have it.
Output must have
ID
Product code
Spend
Product tenure
1
101
100
20
1
102
200
30
1
103
300
3
301
500
3
302
600
40
Any help on this would be appreciated. I tried left join on ID, but it produces many duplicates.
SELECT *,
(
SELECT `product_tenure`
FROM `second_table`
WHERE `second_table`.`id` = `first_table`.`id`
AND `first_table`.`product_code` = `second_table`.`product_code`
) product_tenure
FROM `first_table`
WHERE `id` IN (SELECT DISTINCT `id` FROM `second_table`)
Explaination:
Select id from second table, which wanted to keep from first table.
Because the product_tenure only in second_table select them with combined id and product_code
Result:
Test this:
SELECT *
FROM t1
LEFT JOIN t2 AS t21 USING (ID, `Product code`)
WHERE EXISTS ( SELECT NULL
FROM t2 AS t22
WHERE t1.ID = t22.ID )
PS. The query will return 2 Spent columns (they're present in each table, and nothing prevents their values to be not equal...) - so replace an asterisk with definite columns list.
I have a table with the structure below with name table1
sid userid date result
1 169110 2020-01-03 (null)
2 178662 2020-01-06 (null)
3 165381 2020-01-07 (null)
5 368031 2020-01-08 (null)
7 163626 2020-01-09 (null)
Now I need to send each row values of cft.userid and cft.date to a mysql query (query is below) which gives the value of the result for each row
UPDATE collision_fact_table cft
SET cft.on_time_completion = (
SELECT DISTINCT
CONCAT(ROUND(NULLIF(SUM(facttable.compliant), 0) / NULLIF(SUM(facttable.Occurences), 0) * 100), '%') AS `Percentage Completed`
FROM fd_dw.ComplianceFactTable facttable
WHERE (CAST(facttable.`CourseModule_dueDateID` AS date) - cft.collision_date) <= 0
AND facttable.UserLicenseInUsing = 1
AND (facttable.`CourseModule_dueDateID` > 0)
AND facttable.UserId = cft.userid
GROUP BY facttable.`UserID`);
For example, when i send first row values of userid 169110 and date value to the above query, i will get result as 69 and i need to update 69 to the table1 like below
sid userid date result
1 169110 2020-01-03 69
Similarly it should iterate for all the rows and table1 should get updated like below
sid userid date result
1 169110 2020-01-03 69
2 178662 2020-01-06 55
3 165381 2020-01-07 64
5 368031 2020-01-08 48
7 163626 2020-01-09 56
But when i tried to execute the update query, its giving me error Unknown column 'cft.date' in field list
Please anyone help me
I think you basically want a correlated subquery:
update table1 t1
set result = (
select cd.result
from ...
where
cd.ScheduleDateID <= t1.date
and cd.CourseModuleComplete_DateID <= t1.date
and cd.UserId = t1.userid
)
You don't give much details about the subquery itself. It is critical that it should return one row, and one row only:
if it returns no rows, then the result of the corresponding row in table1 will be set to null (regardless of its original value) - this might, or might not be what you want
if it returns more than one row, then the query will error
I have 3 table relation using MYSQL;
Example first as riders table:
bib | series_id | point
202 3 200
219 3 140
202 2 200
219 2 110
10 1 90
Example second as series table:
series_id | series_no | season_id
1 1 2
2 2 1
3 1 1
Example third as seasons table:
season_id | year
1 2015
2 2016
How to GROUP_CONCAT point correctly? I'm trying like this
SELECT riders.bib, seasons.year, GROUP_CONCAT(DISTINCT riders.point ORDER BY series.series_no DESC) AS seriPoint
FROM series, riders, seasons
GROUP BY riders.bib
I'm getting output seriPoint for bib: 202 is 200 and bib: 219 is 140,110 when I'm using DISTINCT output like that. But when I'm not using DISTINCT getting output seriPoint for bib: 202 is 200,200,200,200 and bib: 219 is 140,110,140,110. What I want is output seriPoint for bib: 202 is 200,200 and bib: 219 is 140,110.
ADD: please help to add filter too, for season_id when different season_id its to be different row.
yes you are getting correct output since you have used DISTINCT. BTW, you should change your query to use proper JOINS
SELECT riders.bib,
seasons.year,
GROUP_CONCAT(DISTINCT riders.point ORDER BY series.series_no DESC) AS seriPoint
FROM riders
JOIN series ON series.series_id = riders.series_id
JOIN seasons ON series.season_id = seasons.season_id
GROUP BY riders.bib;
(OR) you can get the grouping first and then perform join like
select seasons.year, xx.bib, xx.seriPoint
FROM series
JOIN (
select series_id, bib
group_concat(point) as seriPoint
from riders
group by bib ) xx ON series.series_id = xx.series_id
JOIN seasons ON series.season_id = seasons.season_id
order by xx.seriPoint;
I have to do some reporting, involving various tables, and having couple of SUMs, COUNTs, etc and everything is OK. But the last thing I have to resolve is SUM by another which is not in the grouped columns.
I'll give you an example (stripped down from what I have) so you can understand the tongue-twister in the previous paragraph.
Suppose I have a query with a couple of joins that get me this result, or a temporary table, or whatever:
(this is a trimmed down version, in the original I have much more columns and groupbys)
APP_ID CAT_ID CAT_DESCRIP APP_START APP_END DETAIL_ID DET_QTY DETAIL_PRICE
1 1 Categ One 900 960 1 10 150.00
1 1 Categ One 900 960 2 8 20.00
1 1 Categ One 900 960 3 12 30.00
1 1 Categ One 900 960 4 5 100.00
2 2 Categ Two 600 720 5 12 150.00
2 2 Categ Two 600 720 6 10 50.00
3 2 Categ Two 1200 1260 7 5 20.00
I need to get something like this: (the bolded column is the important)
SELECT
CAT_ID,
CAT_DESCRIP,
SUM(DET_QTY) as TotalQTY,
SUM(DETAIL_PRICE) as TotalPrice,
COUNT(DISTINCT APP_ID) as CountOfApps,
(GET THE SUM OF (APP_END - APP_START) ONLY ONE TIME BY APP_ID INTO THIS CATEG) as TimeInMinutesByCategory
FROM
MyTable
GROUP BY
CAT_ID
And the result has to give me this:
CAT_ID CAT_DESCRIP TotalQTY TotalPrice CountOfApps TimeInMinutesByCategory
1 Categ One 35 300.00 1 60
2 Categ Two 27 220.00 2 180
Thanks for your help!
I think this will do the job... or if not, a little tweaking on the sytnax for max(app_start) - max(app_end) should do the job
The idea is, summarize the data in a subquery by app_id and cat_id. Select the max value of start and end, grouped by app_id and cat_id. Since there will only be one value per each distinct pair of app_id and cat_id, we're essentially just deduping.
Then, join the subquery to the main query and summarize by category id.
SELECT
a.CAT_ID,
a.CAT_DESCRIP,
SUM(a.DET_QTY) as TotalQTY,
SUM(a.DETAIL_PRICE) as TotalPrice,
COUNT(DISTINCT a.APP_ID) as CountOfApps,
SUM(b.TimeInMinutesByCategory) AS TimeInMinutesByCategory
FROM
MyTable AS a
INNER JOIN (
SELECT APP_ID, CAT_ID, max(app_start) - max(app_end) AS TimeInMinutesByCategory
FROM MyTable
GROUP BY APP_ID, CAT_ID) AS b
ON a.cat_id = b.cat_id
AND a.app_id = b.app_id
GROUP BY
a.CAT_ID
I have three tables: attendance, cv_target, and candidate. I need to find the candidate count for a specific user.
I am not an expert in MySQL. I have tried the query below, but I'm unable to find the exact value.
SELECT
attendance_date,
cv_target_date_for,
cv_requirement,
job_id,
cv_target,
achi,
recruiter_comment,
recruiter_rating
FROM
attendance f
RIGHT JOIN
(
SELECT
cv_requirement,
cv_target,
cv_target_date_for,
achi,
recruiter_comment,
recruiter_rating
FROM
cv_target a
LEFT JOIN
(
SELECT
COUNT(candidate_id) AS achi,
cv_target_date,
fk_job_id
FROM
candidate
GROUP BY
fk_job_id,
cv_target_date
) b
ON a.cv_requirement = b.fk_job_id
AND a.cv_target_date_for = b.cv_target_date
WHERE
cv_target_date_for BETWEEN '2014-02-01' AND '2014-03-01'
AND cv_recruiter = '36'
) c
ON f.attendance_date=c.cv_target_date_for
GROUP BY
cv_requirement,
cv_target_date_for
ORDER BY
c`.`cv_target_date_for` ASC
attendance
id fk_user_id attendance_date
1 44 2014-02-24
2 44 2014-02-25
3 44 2014-02-26
4 44 2014-02-27
5 36 2014-02-24
6 44 2014-02-28
cv_target
id cv_recruiter cv_requirement cv_target cv_target_date_for
1 44 1 3 2014-02-24
2 44 2 2 2014-02-24
3 44 3 2 2014-02-25
4 44 4 3 2014-02-25
4 44 4 3 2014-02-26
candidate
candidate_id fk_posted_user_id fk_job_id cv_target_date
1 44 1 2014-02-24
2 44 3 2014-02-25
3 44 3 2014-02-25
3 44 4 2014-02-25
4 44 4 2014-02-26
5 44 5 2014-02-28
5 44 5 2014-02-28
Desired result
attendance_date cv_target_date_for job_id cv_target achi(count)
2014-02-24 2014-02-24 1 3 1
2014-02-24 2014-02-24 2 2 null
2014-02-25 2014-02-25 3 2 2
2014-02-25 2014-02-25 4 3 1
2014-02-26 2014-02-26 4 3 1
2014-02-27 2014-02-27 null null null
2014-02-28 null 5 null 2
Output that I am getting
attendance_date cv_target_date_for job_id cv_target achi(count)
2014-02-24 2014-02-24 1 3 1
2014-02-24 2014-02-24 2 2 null
2014-02-25 2014-02-25 3 2 2
2014-02-25 2014-02-25 4 3 1
2014-02-26 2014-02-26 4 3 1
Date 27 and 28 are not showing. I want those values also.
Original Answer
I think I understand what you want. The following assumes you want all attendance dates within a specific range for a specific user. And for each of those attendance dates, you want all cv_target records, if any. And for each of those, you want a count of the candidates.
Use a subquery to get the count. That's the only part that needs to go in the subquery. Only use a GROUP BY expression in the subquery, not the outer query. Only select the fields you need.
Use LEFT JOIN to get all the records from the table on the left side of the expression and only matching records from the table on the right side. So all records from attendance (that match the WHERE expression), and matching records from cv_target (regardless of whether they have a match in the candidate subquery), and then matching records from the candidate subquery.
Try this:
SELECT
DATE_FORMAT(a.attendance_date, '%Y-%m-%d') AS attendance_date,
DATE_FORMAT(t.cv_target_date_for, '%Y-%m-%d') AS cv_target_date_for,
t.cv_requirement AS job_id,
t.cv_target,
c.achi AS `achi(count)`
FROM
attendance AS a
LEFT JOIN
cv_target AS t
ON a.fk_user_id = t.cv_recruiter
AND a.attendance_date = t.cv_target_date_for
LEFT JOIN
(
SELECT
COUNT(candidate_id) AS achi,
fk_job_id,
cv_target_date
FROM
candidate
WHERE
fk_posted_user_id = 44
AND cv_target_date BETWEEN '2014-02-01' AND '2014-03-01'
GROUP BY
fk_job_id,
cv_target_date
) AS c
ON t.cv_requirement = c.fk_job_id
AND t.cv_target_date_for = c.cv_target_date
WHERE
a.fk_user_id = 44
AND a.attendance_date BETWEEN '2014-02-01' AND '2014-03-01'
ORDER BY
ISNULL(t.cv_target_date_for), t.cv_target_date_for, t.cv_requirement
Note that the following line is not necessary for the correct result. However, depending on the database structure and amount of data, it may improve performance.
AND cv_target_date BETWEEN '2014-02-01' AND '2014-03-01'
The ISNULL function is being used to sort NULL to the bottom.
I've created an SQL Fiddle showing the output you request, except for cv_target_date_for. It's not possible to output values that do not exist in the data.
UPDATE
With the new data and new requirement of retrieving data where either cv_target or candidate has data for a particular attendance date, you need to add another table to get the job IDs. In your original question you had a table with ID numbers and job titles, but it had no dates.
You might want to rethink your database design. I'm not sure I understand how your tables relate to one another, but those two new records for the candidate table appear to be orphaned. All your joins are based on date, but you don't appear to have a table that links job ID numbers to dates.
You could create a derived table by doing a UNION of cv_target and candidate. Then use the derived table as the left side of the join.
Updated query:
SELECT
DATE_FORMAT(a.attendance_date, '%Y-%m-%d') AS attendance_date,
DATE_FORMAT(t.cv_target_date_for, '%Y-%m-%d') AS cv_target_date_for,
j.job_id,
t.cv_target,
c.achi AS `achi(count)`
FROM
attendance AS a
LEFT JOIN
(
SELECT
cv_requirement AS job_id,
cv_target_date_for AS job_date
FROM
cv_target
WHERE
cv_recruiter = 44
AND cv_target_date_for BETWEEN '2014-02-01' AND '2014-03-01'
UNION
SELECT
fk_job_id AS job_id,
cv_target_date AS job_date
FROM
candidate
WHERE
fk_posted_user_id = 44
AND cv_target_date BETWEEN '2014-02-01' AND '2014-03-01'
) AS j
ON a.attendance_date = j.job_date
LEFT JOIN
cv_target AS t
ON a.fk_user_id = t.cv_recruiter
AND j.job_id = t.cv_requirement
AND j.job_date = t.cv_target_date_for
LEFT JOIN
(
SELECT
COUNT(candidate_id) AS achi,
fk_job_id,
cv_target_date
FROM
candidate
WHERE
fk_posted_user_id = 44
AND cv_target_date BETWEEN '2014-02-01' AND '2014-03-01'
GROUP BY
fk_job_id,
cv_target_date
) AS c
ON j.job_id = c.fk_job_id
AND j.job_date = c.cv_target_date
WHERE
a.fk_user_id = 44
AND a.attendance_date BETWEEN '2014-02-01' AND '2014-03-01'
ORDER BY
ISNULL(t.cv_target_date_for), t.cv_target_date_for, j.job_id
I've created an updated SQL Fiddle showing the output you request, except for cv_target_date_for. It's not possible to output values that do not exist in the data (i.e. 2014-02-27).
If that's a typo and you meant 2014-02-28, then you'll need to select the date from the derived table instead of the cv_target table. And you should probably change the column heading in the result because it's no longer the cv_target_date_for date.
To get the date from either cv_target or candidate, change this line:
DATE_FORMAT(t.cv_target_date_for, '%Y-%m-%d') AS cv_target_date_for,
to this:
DATE_FORMAT(j.job_date, '%Y-%m-%d') AS job_date,
And you may need to tweak the order by expression to suit your needs.