Yii2 log in form works only when ajaxvalidation is false - yii2

Question

I have a log in form which works only when i turn of my ajaxValidation. If i enable itenableAjaxValidation = true` it dies. What is the problem? Is it something with the model rules? On the previous projects i used the same form and all was fine. Can't realize. Can you guys give an advice and quick explanation. Thank you in advance!
<div class="row">
<div class="col-xs-12">
<h3 class="contact-page-title"><?= Yii::t('app', 'app.Login') ?></h3>
<?php if (Yii::$app->user->isGuest): ?>
<?php $form = ActiveForm::begin([
'id' => 'login-widget-form',
'action' => Url::to(['/user/security/login']),
/*'enableAjaxValidation' => true,*/
'enableClientValidation' => false,
'validateOnBlur' => false,
'validateOnType' => false,
'validateOnChange' => false,
]) ?>
<?= $form->field($model, 'login')->textInput() ?>
<?= $form->field($model, 'password')->passwordInput() ?>
<?= $form->field($model, 'rememberMe')->checkbox() ?>
<input type="hidden" name="checkoutLogin" value="1">
<?= Html::submitButton(Yii::t('user', Yii::t('app','app.Login')) , ['class' => 'btn-1 shadow-0 full-width']) ?>
<?php ActiveForm::end(); ?>
<?php else: ?>
<?= Html::a(Yii::t('user', 'Logout'), ['/user/security/logout'], [
'class' => 'btn btn-danger btn-block',
'data-method' => 'post'
]) ?>
<?php endif ?>
</div>
</div>
And these are the rules:
public function rules()
{
$rules = [
'loginTrim' => ['login', 'trim'],
'requiredFields' => [['login'], 'required'],
'confirmationValidate' => [
'login',
function ($attribute) {
if ($this->user !== null) {
$confirmationRequired = $this->module->enableConfirmation
&& !$this->module->enableUnconfirmedLogin;
if ($confirmationRequired && !$this->user->getIsConfirmed()) {
$this->addError($attribute, Yii::t('user', 'You need to confirm your email address'));
}
if ($this->user->getIsBlocked()) {
$this->addError($attribute, Yii::t('user', 'Your account has been blocked'));
}
}
}
],
'rememberMe' => ['rememberMe', 'boolean'],
];
if (!$this->module->debug) {
$rules = array_merge($rules, [
'requiredFields' => [['login', 'password'], 'required'],
'passwordValidate' => [
'password',
function ($attribute) {
if ($this->user === null || !Password::validate($this->password, $this->user->password_hash)) {
$this->addError($attribute, Yii::t('user', 'Invalid login or password'));
}
}
]
]);
}
return $rules;
}
EDIT Action:
public function actionLogin() {
if (!Yii::$app->user->isGuest) {
$this->goHome();
}
$register = new RegistrationForm();
if(Yii::$app->request->isAjax){
return 1;
}
/** #var LoginForm $model */
$model = Yii::createObject(LoginForm::className());
$event = $this->getFormEvent($model);
$this->performAjaxValidation($model);
$this->trigger(self::EVENT_BEFORE_LOGIN, $event);
if ($model->load(Yii::$app->getRequest()->post()) && $model->login()) {
$this->trigger(self::EVENT_AFTER_LOGIN, $event);
//return $this->goBack();
if (Yii::$app->request->baseUrl == "" and !isset($_POST["checkoutLogin"])) {
$session = Yii::$app->session;
return $this->redirect('/');
} elseif(isset($_POST["checkoutLogin"]) and $_POST["checkoutLogin"] == 1) {
$lang = \frontend\models\Lang::getCurrent();
$checkout = Page::findOne(91);
if($checkout){
return $this->redirect('/'.$lang->url.'/'.$checkout->url);
}else{
return $this->goBack();
}
} else {
return $this->goBack();
}
}
return $this->render('login', [
'model' => $model,
'module' => $this->module,
'register' => $register
]);
}

Answer 1

Try with the code of performAjaxValidation() moved to the action:
// instead of $this->performAjaxValidation($model);
if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) {
Yii::$app->response->format = Response::FORMAT_JSON;
return ActiveForm::validate($model);
}