I have a table, named rendeles_termekek.(In english, ordered_products)
I would like to count, that each product how many times was ordered.
With the SQL below, I get 4 as ennyi. I upload a picture, and I wrote the correct number to each rows.
SELECT DISTINCT
rendeles_termekek.termek_id,
termek.termek_id,
termek.termek_nev,
( SELECT COUNT(rendeles_termekek.termek_id) FROM rendeles_termekek ) AS ennyi
FROM rendeles_termekek
LEFT JOIN termek ON rendeles_termekek.termek_id = termek.termek_id
ORDER BY termek.termek_nev ASC
**r1** is the alias of your table rendeles_termekek so you have to access those columns through alias name "r1" like I did in below query. try below
SELECT DISTINCT
r1.termek_id,
termek.termek_id,
termek.termek_nev,
( SELECT COUNT(r.termek_id) FROM rendeles_termekek r where r.termek_id = r1.termek_id ) AS ennyi
FROM rendeles_termekek r1
LEFT JOIN termek ON r1.termek_id = termek.termek_id
ORDER BY termek.termek_nev ASC
I think you have only four rows in your table "rendeles_termekek".
I have updated your query. try this
SELECT DISTINCT
rendeles_termekek.termek_id,
termek.termek_id,
termek.termek_nev,
( SELECT COUNT(rendeles_termekek.termek_id) FROM rendeles_termekek r where r.termek_id = r1.termek_id ) AS ennyi
FROM rendeles_termekek r1
LEFT JOIN termek ON rendeles_termekek.termek_id = termek.termek_id
ORDER BY termek.termek_nev ASC
Note that I have changed the sub-query and added a where condition in it
`( SELECT COUNT(rendeles_termekek.termek_id) FROM rendeles_termekek r where r.termek_id = r1.termek_id ) AS ennyi`
Related
i have two table galang_dana and donasi, and then i'm try to count all data inside the galang_dana table, and donasi table. The data in galang_dana table is there 6 data, when i'm try this query it's show the data correctly there 6 data
select count(galang_dana.id_galang_dana) as jumlah_galang_dana
from galang_dana
but when i'm try to inner join that both table using this query to count and sum the other data, the data of query select count(galang_dana.id_galang_dana) as jumlah_galang_dana its showing 8 data.
select count(galang_dana.id_galang_dana) as jumlah_galang_dana,
count( distinct donasi.id_user) as jumlah_donatur,
SUM(donasi.jumlah_dana) as total_dana_terkumpul
from `galang_dana` left join
`donasi`
on `galang_dana`.`id_galang_dana` = `donasi`.`id_galang_dana`
I think you want to aggregate before joining:
select gd.jumlah_galang_dana,
d.jumlah_donatur, d.total_dana_terkumpul
from (select count(*) as jumlah_galang_dana
from `galang_dana` gd
) gd cross join
(select count(distinct d.id_user) as jumlah_donatur,
sum(d.jumlah_dana) as total_dana_terkumpul
from donasi d
) d;
DB::table('galang_dana')
->selectRaw('
COUNT(*) jumlah_galang_dana,
(SELECT COUNT(*) FROM donasi WHERE donasi.id_galang_dana = galang_dana.id_galang_dana) jumlah_donatur,
(SELECT SUM(`jumlah_dana`) FROM donasi WHERE donasi.id_galang_dana = galang_dana.id_galang_dana) total_dana_terkumpul
')
->groupBy('id')
->get();
Hi i have a problem of how to output the latest data of "reading_timesent" by using max(Date), And Also Include the other column where the latest date, and remove redundant data using distinct or group i don't know whats my problem here's the sample img and data
Patient table
Reading Table
Inner Join table
Expected Output
JSFIDDLE SAMPLE
SELECT * FROM Patients P
INNER JOIN Reading R ON R.patient_ID = P.patient_ID
Try this
SELECT * FROM
(
SELECT *,
(
SELECT reading_ID
FROM Reading
WHERE Reading.patient_ID = p.patient_ID
ORDER BY reading_timesent DESC
LIMIT 1
) AS newestReadingID
FROM Patients p
) AS subquery
JOIN Reading ON subquery.newestReadingID = Reading.reading_ID
You can use a correlated subquery for a condition in the ON clause:
SELECT *
FROM Patients P
INNER JOIN Reading R
ON R.patient_ID = P.patient_ID
AND R.reading_timesent = (
SELECT MAX(R2.reading_timesent)
FROM Reading R2
WHERE R2.patient_ID = P.patient_ID
)
Another way:
SELECT P.*, R.*
FROM (
SELECT patient_ID, MAX(reading_timesent) as reading_timesent
FROM Reading
GROUP BY patient_ID
) X
JOIN Patients P USING (patient_ID)
JOIN Reading R USING (patient_ID, reading_timesent)
Usually I would use the AUTO_INCREMENT column instead of a TIMESTAMP column for similar tasks. But that is not always applicable.
The following query always outputs SUM for all rows instead of per userid. Not sure where else to look. Please help.
SELECT * FROM assignments
LEFT JOIN (
SELECT SUM(timeworked) AS totaltimeworked
FROM time_entries
) assignments ON (userid = assignments.userid AND ticketid = ?)
WHERE ticketid = ?
ORDER BY assigned,scheduled
If you want to keep the SELECT *, you would have to add a group by clause in the subquery. Something like this
SELECT * FROM assignments
LEFT JOIN (
SELECT SUM(timeworked) AS totaltimeworked
FROM time_entries
GROUP BY userid
) time_entriesSummed ON time_entriesSummed.userid = assignments.userid
WHERE ticketid = ?
ORDER BY assigned,scheduled
But a better way would be to change the SELECT * to instead select the fields you want a add a group by clause directly. Something like this
SELECT
assignments.id,
assignments.assigned,
assignments.scheduled,
SUM(time_entries.timeworked) AS totalTimeworked
FROM assignments
LEFT JOIN time_entries
ON time_entries.userid = assignments.userid
GROUP BY assignments.id, assignments.assigned, assignments.scheduled
Edit 1
Included table names in query 2 as mentioned in chameera's comment below
Some sql query gives me the following result:
As you can see, it already has GROUP BY.
So what I need? I need to group it again (by treatment_name) and count rows for each group. See more details on screenshot.
Here is full query:
SELECT
treatment_summaries.*
FROM `treatment_summaries`
INNER JOIN
`treatments`
ON
`treatments`.`treatment_summary_id` = `treatment_summaries`.`id`
AND
(treatment <> '' and treatment is not null)
INNER JOIN
`treatment_reviews`
ON
`treatment_reviews`.`treatment_id` = `treatments`.`id`
INNER JOIN
`conditions_treatment_reviews`
ON
`conditions_treatment_reviews`.`treatment_review_id` = `treatment_reviews`.`id`
INNER JOIN
`conditions` ON `conditions`.`id` = `conditions_treatment_reviews`.`condition_id`
INNER JOIN `conditions_treatment_summaries` `conditions_treatment_summaries_join`
ON
`conditions_treatment_summaries_join`.`treatment_summary_id` = `treatment_summaries`.`id`
INNER JOIN `conditions` `conditions_treatment_summaries`
ON `conditions_treatment_summaries`.`id` = `conditions_treatment_summaries_join`.`condition_id`
WHERE
`conditions`.`id` = 9
AND `conditions`.`id` IN (9)
AND (latest_review_id is not null)
GROUP BY
treatment_reviews.id
ORDER BY
treatment_summaries.reviews_count desc
LIMIT 20 OFFSET 0
Maybe there is another issue, cause GROUP BY should not leave same lines (for given column), but anyway you can wrap it like this:
SELECT * FROM ( YOUR_SQL_SELECT_WITH_EVERYTHING ) GROUP BY id
So the result you get will behave as another table and you can do all operations like GROUP BY again.
Currently I am using the following query to display the following result.
SELECT * FROM RouteToGrowthRecord, GradeMaster,MileStoneMaster
WHERE MemberID = 'ALV01L11034A06' AND
RouteToGrowthRecord.GradeID=GradeMaster.GradeID AND
RouteToGrowthRecord.MileStoneID=MileStoneMaster.MileStoneID
ORDER BY CheckupDate DESC
Now I have another table named RouteToGrowthRecord_st that has same
columns as RouteToGrowthRecord with some additional fields.
I need to display result that are present in both the table. ie . if RouteToGrowthRecord_st has 3 records with the given menberID,then output must contain 3 more records along with the above query result.(fr ex above its 9+3=12 records in total).
You can use Union here to merge the results getting from both queries. Use default values for the unmapped additional fields.
You can write above query in following way
SELECT * FROM RouteToGrowthRecord
INNER JOIN GradeMaster ON RouteToGrowthRecord.GradeID=GradeMaster.GradeID
INNER JOIN MileStoneMaster ON RouteToGrowthRecord.MileStoneID=MileStoneMaster.MileStoneID
LEFT JOIN RouteToGrowthRecord_st ON RouteToGrowthRecord_st.memberID=RouteToGrowthRecord.memberID
WHERE
RouteToGrowthRecord.MemberID = 'ALV01L11034A06'
order by CheckupDate DESC
this is my answer
SELECT CheckUpDate,AgeInMonths,PresentWeight,Height,Diagnosis,growthstatus,GradeName,MilestoneName,MemberID
FROM RouteToGrowthRecord, GradeMaster,MileStoneMaster WHERE
MemberID = 'ALV01L56107A11 ' and
RouteToGrowthRecord.GradeID=GradeMaster.GradeID and
RouteToGrowthRecord.MileStoneID=MileStoneMaster.MileStoneID
union
SELECT CheckUpDate,AgeInMonths,PresentWeight,Height,Diagnosis,growthstatus,GradeName,MilestoneName,MemberID
FROM RouteToGrowthRecord_st, GradeMaster,MileStoneMaster WHERE
MemberID = 'ALV01L56107A11 ' and
RouteToGrowthRecord_st.GradeID=GradeMaster.GradeID and
RouteToGrowthRecord_st.MileStoneID=MileStoneMaster.MileStoneID
order by CheckupDate DESC
SELECT * FROM RouteToGrowthRecord a inner join GradeMaster b inner
join MileStoneMaster c inner join RouteToGrowthRecord_st d on
a.GradeID=b.GradeID AND a.MileStoneID=c.MileStoneID and
d.GradeID=b.GradeID AND d.MileStoneID=c.MileStoneID
WHERE a.MemberID = 'ALV01L11034A06'
ORDER BY CheckupDate DESC