Onenote page hierarchy - onenote

Let's say I have a notebooks with name 'MyNotebook'. Now this notebook have a section group 'Group1' and now 'Group1' have another section group 'Group2'. Now inside 'Group2' I have section 'Section1' which has a page 'Page1'.
If we look this at like a directory structure the path to page will be -MyNotebook/Group1/Group2/Section1/Page1
When I try to get page using get page api I am able to get only immediate parent i.e Section1. So let's say I want get this complete hierarchy how I can get that ?

What API specifically are you using to get pages?
If you are using GET https://www.onenote.com/api/v1.0/me/notes/pages, this will give you all the pages, though that API has limitations (For example, it is paginated, so it will only give you the most recent 20 pages. In addition, it won't work if the user has a big number of sections).
https://blogs.msdn.microsoft.com/onenotedev/2017/07/21/a-few-performance-tips-for-using-the-onenote-api/
See the section "When getting all pages for a user, do so for each section separately"
I recommend you make a call like:
GET https://www.onenote.com/api/v1.0/me/notes/Notebooks?$expand=sections,sectionGroups($expand=sections,sectionGroups($levels=max;$expand=sections))
To obtain all the sections, and then make a call like:
GET https://www.onenote.com/api/v1.0/me/notes/sections/{id}/pages
To obtain each section's pages.

In addition to what Jorge said, if you specifically want the upwards hierarchy (and not downwards), you could do:
GET https://www.onenote.com/api/v1.0/me/notes/pages?$expand=parentSection($expand=parentSectionGroup($expand=parentSectionGroup($expand=parentNotebook)))
But as Jorge said, be careful when using the GET pages API since it has some limitations

Related

Send and receive data to and from a website using the TWebbrowser component in Delphi

I'm creating a VCL Application with Delpi 10.3 and want to support some web functionality by having the user enter the ISBN of a book into a TEdit component and from there passing/sending this value to a search field on this website: https://isbnsearch.org after which the website looks up the ISBN and displays the Author of the book. I want to somehow access the information (i.e Author) presented by the search result and again use it in my application.
This is my GUI, for a better idea of what I want to accomplish:
What code can I use for this? Any other feasible suggestions or approaches are acceptable.
When performing a search on that website, it simply loads a page with a specific URL query string...
https://isbnsearch.org/search?s=suess
The above example is when I search for "suess", so you can easily concatenate a search URL.
You can use any HTTP component, such as TIdHTTP, to load this search page, then use an HTML parser to scrape the page and read what you need. Much, much easier than trying to read through the TWebBrowser.
In the end, you won't actually display the HTML (I mean you can if you want to), but the idea is to read the data and display it in your own format.
On that specific page, start by locating the ul element with id searchresults. Then, each li element contains individual results. Unfortunately, this website uses pagination, and only shows 10 results per page. To do this, call this page again with another parameter &p=2 for the 2nd page, &p=3 for the 3rd page, and so on.
On the other hand, that is the worst way to acquire such information. What you should be doing is using a proper API which gives you machine-friendly data. The service you are referencing doesn't appear to have an option, but here's an example of one which does:
https://openlibrary.org/dev/docs/api/books - this also appears to provide you MUCH more information than the one you're using.

Wiktionary API call get specific data on page

I am looking to make a call to the wiktionary API (the Russian one in specific) and I would like to try and get particular pieces of information on the page. In my case, I would like to target the table on the right, here right above the picture of the map.
I can use any form of the url to get the data, I just am not sure how to target that particular element.
I think it is impossible (at this moment) to get a declension table by using the Wiktionary API.

Wikipedia API - get random page(s)

I'm trying to get a JSON result with a set of random pages from Wikipedia, including their titles, content and images.
I've played around with their API sandbox, and so far the best I've got is this:
https://en.wikipedia.org/w/api.php?action=query&list=random&format=json&rnnamespace=0&rnlimit=10
But this only includes the namespace, id, and title of ten random pages. I would like to get the content as well as images as well.
Do anyone know how?
Alternatively I could do with the title, content and image url's of a single random page.
Best I've got here is:
https://en.wikipedia.org/w/api.php?action=query&generator=random&format=json
You're close. generator=random is the right way to go. You can then use various prop values to get the info you want:
Page title is always included.
To get the text, use prop=revisons along with rvprop=content.
To get all images used on the page, use prop=images.
Note that this will often include images you're probably not interested in, like icons and flags. To fix that, you might try instead prop=pageimages, though it doesn't seem to work always. Or you could try using both.
So, the final query could look like this:
https://en.wikipedia.org/w/api.php?format=json&action=query&generator=random&grnnamespace=0&prop=revisions|images&rvprop=content&grnlimit=10
If you'd rather use their REST api,
curl -X GET "https://en.wikipedia.org/api/rest_v1/page/random/summary"
Documentation

mediawiki api. how to chose page from response

When I make api query sometimes I have list with few pages. For example
http://en.wikipedia.org/wiki/Ask gives a lot of pages, I need website "Ask.com, a web search engine, formerly Ask Jeeves"
can I make query only for some category ("websites")?
How I can check category for each page in response?
Thanks
There is no trivial way to do what you're asking. You could do something like this:
Get the list of pages the disambiguation page list. You could do this by listing the links on that page (action=query&prop=links).
Get the categories of all the pages from the previous step and use that to decide which one is the one you're looking for. This is not that simple, because Ask.com is not directly in Category:Websites, it's in one of its subcategories.
I have list with few pages, for example http://en.wikipedia.org/wiki/Ask
The problem is that you're not getting a list of pages, you just are getting an ordinary page which is in the disambiguation pages category. To get the list, you need to get the links in that page.
can I make query only for some category ("websites")?
No, mediawiki does not support that.
How I can check category for each page in response?
Use the links property as a title list generator and get the categories of each page in the response. In your case, that would be http://en.wikipedia.org/w/api.php?action=query&titles=Ask&generator=links&prop=categories (don't forget to continue the query).
If you are OK with "full-text search" for "ask",
you can do that like this:
http://en.wikipedia.org/w/api.php?format=json&action=query&generator=search&gsrsearch=ask%20incategory:%22Online%20companies%22&prop=info
As you can see, "search" text is [ask incategory:"Online companies"]
The same solution also can be seen at:
Wikipedia API: how to search for a term in a specific category

URL Masking in .Net / HTML

I have a website in which I have many categories, many sub-categories within each one and many products within each of those. Since the URLs are very user-unfriendly (they contain a GUID!!!), I would like to use a method which I think is called URL Masking. For example instead of going to catalogue.aspx?ItemID=12343435323434243534, they would go to notpads.htm. This would display the same as going to catalogue.aspx?ItemID=12343435323434243534 would display, somehow.
I know I could do this by creating a file for each category / sub-category (individual products cannot be accessed individually as it is a wholesale site - customers cannot purchase directly from the site). This would be a lot of work as the server would have to update each relevant file whenever a category / sub-category / product visibility changes, or a description changes, a name changes... you get the idea...
I have tried using server-side includes but that doesn't like it when a .aspx file is specified in an html file.
I have also tried using an iframe set to 100% width / height and absolutely positioned left 0 and top 0. This works quite well, but I know there are reasons you should not use this method such as some search engines not coping with it well. I also notice that the title of the "parent" page (notepads.htm) is not the title set in the iframe (logically this is correct - but another issue I need to solve if I go ahead and use this method).
Can anyone suggest another way I could do this, or tell me whether I am going along the right lines by using iframes? Thanks.
Regards,
Richard
PS If this is the wrong name for what I am trying to do then please let me know what it actually is so I can rename / retag it.
Look into URL Rewrites. You can create a regular expression and map it to your true url. For example
http://mysite.com?product=banana
could map to
http://mysite.com?guid=lakjdsflkajkfj3lj3l4923892&asfd=9234983920894893
I believe you mean URL Rewriting.
IIS 7+ has a rewrite module built in that you can use for this kind of thing.
URL Rewriters solve the problem you are describing - When someone requests page A, display page B - in a general way.
But yours is not a general requirement. You seem to have a finite uuid-to-shortname mapping requirement. This is the kind of thing you could or should set up in your app, yourself, rather than inserting a new piece of machinery into your system.
Within a default .aspx page, You'd simply do a lookup on the shortname from the url in a persistent table stored somewhere, and then call Server.Transfer() to the uuid-named page associated to that shortname.
It should be easy to prototype this.